2. The Physics of

3. The Physics of

4. The Physics of

6. Preview
• History

7. Preview
• History
• Concepts:

8. Preview
• History
• Concepts:
• #1 Pokeball Throwing

9. Preview
• History
• Concepts:
• #1 Pokeball Throwing
• #2 Pikachu’s Thunderbolt

10. Preview
• History
• Concepts:
• #1 Pokeball Throwing
• #2 Pikachu’s Thunderbolt
• #3 Charmander’s FLamethrower

11. Preview
• History
• Concepts:
• #1 Pokeball Throwing
• #2 Pikachu’s Thunderbolt
• #3 Charmander’s FLamethrower
• Review

12. Preview
• History
• Concepts:
• #1 Pokeball Throwing
• #2 Pikachu’s Thunderbolt
• #3 Charmander’s FLamethrower
• Review
• Closing

14. History of Pokemon

15. History of Pokemon
• Contrary to popular belief, the Pokemon TV series isn't how the craze
was started. It was actually started with the Game Boy game called
"Pocket Monsters" in Japan in 1995. It was an instant hit and it
eventually got it's own TV series of the same name in April of 1997.

16. History of Pokemon
• Contrary to popular belief, the Pokemon TV series isn't how the craze
was started. It was actually started with the Game Boy game called
"Pocket Monsters" in Japan in 1995. It was an instant hit and it
eventually got it's own TV series of the same name in April of 1997.
• The first Pokemon game released was “Pokemon Red.” It was released
on February 27th, 1996.

17. History of Pokemon
• Contrary to popular belief, the Pokemon TV series isn't how the craze
was started. It was actually started with the Game Boy game called
"Pocket Monsters" in Japan in 1995. It was an instant hit and it
eventually got it's own TV series of the same name in April of 1997.
• The first Pokemon game released was “Pokemon Red.” It was released
on February 27th, 1996.
• The first show of Pokemon aired in Japan on April 1st, 1997.

18. History of Pokemon
• Contrary to popular belief, the Pokemon TV series isn't how the craze
was started. It was actually started with the Game Boy game called
"Pocket Monsters" in Japan in 1995. It was an instant hit and it
eventually got it's own TV series of the same name in April of 1997.
• The first Pokemon game released was “Pokemon Red.” It was released
on February 27th, 1996.
• The first show of Pokemon aired in Japan on April 1st, 1997.
• There are currently 17 Pokemon handheld games out, and another 2
on the way.

20. Concept
#1

22. P keball Thr wing

23. P keball Thr wing
• When throwing a pokeball, Ash uses
projectile motion
Video

25. So to break it down:
• Projectile motion occurs when an object is
thrown obliquely near the earth’s surface, as it
moves along a curved path.

26. So to break it down:
• Projectile motion occurs when an object is
thrown obliquely near the earth’s surface, as it
moves along a curved path.
• The path followed by a projectile is called its
trajectory, which is directly influenced by
gravity.

27. So to break it down:
• Projectile motion occurs when an object is
thrown obliquely near the earth’s surface, as it
moves along a curved path.
• The path followed by a projectile is called its
trajectory, which is directly influenced by
gravity.
• Newtons First law (Law of Inertia) states: an
object in motion, stays in motion.

28. So to break it down:
• Projectile motion occurs when an object is
thrown obliquely near the earth’s surface, as it
moves along a curved path.
• The path followed by a projectile is called its
trajectory, which is directly influenced by
gravity.
• Newtons First law (Law of Inertia) states: an
object in motion, stays in motion.
• Without gravity, a projectile would just be
considered an object that travels at a constant
speed in the same direction.

36. Word
Problems

38. Variables
• V= Initial velocity (m/s)
• A= Launch angle (degrees)
• g= Acceleration due to gravity (9.8 m/s^2)
• M = Meters (?)

39. Variables
• V= Initial velocity (m/s)
• A= Launch angle (degrees)
• g= Acceleration due to gravity (9.8 m/s^2)
• M = Meters (?)
Horizontal Distance= (V^2 x sine (2 x A)) /g

41. So...If Ash threw a pokeball at a Meowth with an
initial velocity of 10 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?

42. So...If Ash threw a pokeball at a Meowth with an
initial velocity of 10 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?
Horizontal Distance= (V^2 x sine (2 x A)) /g

43. So...If Ash threw a pokeball at a Meowth with an
initial velocity of 10 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?
Horizontal Distance= (V^2 x sine (2 x A)) /g
=(10^2 x sine (2 x 45))/9.8
=(100 x sine (90))/9.8
=100/9.8
=10.2 meters,
which was not far enough to capture Meowth

45. Sadly, Ash was a little to weak to throw his pokeball
all the way to the Meowth. So instead...If
Mr.Zaucha threw a pokeball at a Meowth with an
initial velocity of 20 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?

46. Sadly, Ash was a little to weak to throw his pokeball
all the way to the Meowth. So instead...If
Mr.Zaucha threw a pokeball at a Meowth with an
initial velocity of 20 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?
Horizontal Distance= (V^2 x sine (2 x A)) /g

47. Sadly, Ash was a little to weak to throw his pokeball
all the way to the Meowth. So instead...If
Mr.Zaucha threw a pokeball at a Meowth with an
initial velocity of 20 m/s, and at an angle of 45
degrees, how far would the pokeball travel if you
were to exclude air resistance?
Horizontal Distance= (V^2 x sine (2 x A)) /g
(20^2 x sine (2 x 45)) /9.8
(400 x sine (90)) /9.8
400/9.8
=40.82 meters,
which was just enough to capture Meowth!

49. Graph
Pokeball Throwing Projectiles
100
91.84
80
60
distance
(m)
40.82
40
20
10.2
0
0
0 10 20 30
velocity (m/s)
There is a direct relationship between the distance
and velocity of the projectile. As one increases, so
does the other.

51. Concept
#2

53. Pikachu’s
Thunderbolt

54. Pikachu’s
Thunderbolt
• In the tv series and video games, pokemon are
used to fight, or vs., other pokemon. They use
specialized attacks that usually include one of
the many well-known elements of our world.

55. Pikachu’s
Thunderbolt
• In the tv series and video games, pokemon are
used to fight, or vs., other pokemon. They use
specialized attacks that usually include one of
the many well-known elements of our world.
• Pikachu, is considered to be an “electric type.”

56. Pikachu’s
Thunderbolt
• In the tv series and video games, pokemon are
used to fight, or vs., other pokemon. They use
specialized attacks that usually include one of
the many well-known elements of our world.
• Pikachu, is considered to be an “electric type.”
• To defeat most of his many foes, Pikachu uses a
very well-known attack called “lightning.”

58. An Example of Pikachu’s
Lightning Attack
Video

60. How?
In order to create some sort of truth behind
Pikachu and his lightning attack, we must look at
him as if he is an electrostatic storm cloud.
=

62. Before any and all lightning strikes, polarization
takes place. The polarization of positive and
negative charges takes place within the storm
cloud, creating a “stage” for a stepped leadder.
A stepped ladder is a path of ionized air which extends downward from a thunderstorm
during the initial stages of a lightning strike. Multiple branches, or steps, travel downward
until the final step leader reaches the ground, a tall object on the ground, or a positive
streamer extending upward from a ground object. The lightning strike begins when a large
negative electric current flows along the path defined by the step leaders from the
thundercloud to the ground.

65. Video

67. So to break it down:
• Pikachu is like a storm cloud, with his upper half
made up of positive charges, and his lower half
made up of negative ones.

68. So to break it down:
• Pikachu is like a storm cloud, with his upper half
made up of positive charges, and his lower half
made up of negative ones.
• So when Pikachu is ready to attack another
pokemon, he uses the negative charges in him, to
create a stepped leader. (Like the cloud)

69. So to break it down:
• Pikachu is like a storm cloud, with his upper half
made up of positive charges, and his lower half
made up of negative ones.
• So when Pikachu is ready to attack another
pokemon, he uses the negative charges in him, to
create a stepped leader. (Like the cloud)
• The stepped leader connects with the positive
stepped leader that his opponent creates, thus
resulting in his “Lightning attack.”

70. So to break it down:
• Pikachu is like a storm cloud, with his upper half
made up of positive charges, and his lower half
made up of negative ones.
• So when Pikachu is ready to attack another
pokemon, he uses the negative charges in him, to
create a stepped leader. (Like the cloud)
• The stepped leader connects with the positive
stepped leader that his opponent creates, thus
resulting in his “Lightning attack.”
• Pikachu is an electric type, so the lightning will not
affect him, but it will greatly affect his opponent.

71. So to break it down:
• Pikachu is like a storm cloud, with his upper half
made up of positive charges, and his lower half
made up of negative ones.
• So when Pikachu is ready to attack another
pokemon, he uses the negative charges in him, to
create a stepped leader. (Like the cloud)
• The stepped leader connects with the positive
stepped leader that his opponent creates, thus
resulting in his “Lightning attack.”
• Pikachu is an electric type, so the lightning will not
affect him, but it will greatly affect his opponent.
• His natural negative charge is the reason why his
attacks are super effective against water types.

73. Word
Problems

75. Variables
• I = Current of Lightning Bolt
• C = Coulombs
• T = Seconds (s)
• A = Amperes (?)

76. Variables
• I = Current of Lightning Bolt
• C = Coulombs
• T = Seconds (s)
• A = Amperes (?)
I=CxT

78. So...If Pikachu used his “Lightning attack” on Emma,
how much current would she receive if the bolt
delivered a charge of 35 coulombs to her in a time
of 1/1000 second?

79. So...If Pikachu used his “Lightning attack” on Emma,
how much current would she receive if the bolt
delivered a charge of 35 coulombs to her in a time
of 1/1000 second?
I=CxT

80. So...If Pikachu used his “Lightning attack” on Emma,
how much current would she receive if the bolt
delivered a charge of 35 coulombs to her in a time
of 1/1000 second?
I=CxT
I = (35 C)(0.001 s)
I = 35,000 amps
...Emma would be fried...

82. BUT, if Pikachu used his “Lightning attack” on Eric,
how much current would he receive if the bolt
delivered a charge of 70 coulombs to him in a time
of 1/1000 second?

83. BUT, if Pikachu used his “Lightning attack” on Eric,
how much current would he receive if the bolt
delivered a charge of 70 coulombs to him in a time
of 1/1000 second?
I=CxT

84. BUT, if Pikachu used his “Lightning attack” on Eric,
how much current would he receive if the bolt
delivered a charge of 70 coulombs to him in a time
of 1/1000 second?
I=CxT
I = (70 C)(0.001 s)
I = 70,000 amps
Sorry Eric...but you’ve been vaporized...

86. Graph
Pikachu's Thunderbolt
12,500
10,500
10,000
7,500 7,000
Amperage
5,000
3,500
2,500
0
0
0 35 70 105
Couloumbs

88. Concept
#3

90. Charmader’s
Flamethrower
• In the Pokemon series, Charmander is
considered to be a “fire type.”

91. Charmader’s
Flamethrower
• In the Pokemon series, Charmander is
considered to be a “fire type.”
• Charmander uses a move called
“flamethrower” which causes his enemies to
ignite on fire, burning them to defeat!

92. Charmader’s
Flamethrower
• In the Pokemon series, Charmander is
considered to be a “fire type.”
• Charmander uses a move called
“flamethrower” which causes his enemies to
ignite on fire, burning them to defeat!
• Charmander’s tail is constantly on fire, which
is also gauges how strong his attacks will be.
The bigger the flame, the stronger he gets.

94. An Example of Charmander’s
Flamethrower
Video

96. How?
In order for Charmander’s Flamethrower attack
to have any sort of real life application, we must
visualize Charmander to be somewhat of a
human fire breather.

97. How?
In order for Charmander’s Flamethrower attack
to have any sort of real life application, we must
visualize Charmander to be somewhat of a
human fire breather.
=

98. How?
In order for Charmander’s Flamethrower attack
to have any sort of real life application, we must
visualize Charmander to be somewhat of a
human fire breather.
=

100. Fire breathing is an art that involves
the use of fuel, fire, and breathing. Fire
breathing occurs when a fire breather
takes in a mouthful of fuel, and spits
it out onto an open flame, creating a
fireball.

101. Video

103. So to break it down:
• The fire that is seen in Charmnder’s attack, is actually
the result of an exothermic reaction, because it releases
heat (energy).

104. So to break it down:
• The fire that is seen in Charmnder’s attack, is actually
the result of an exothermic reaction, because it releases
heat (energy).
• What causes that heat, is the spontaneous combustion
of a fuel and oxygen, which ends up creating a large
amount of heat that is released.

105. So to break it down:
• The fire that is seen in Charmnder’s attack, is actually
the result of an exothermic reaction, because it releases
heat (energy).
• What causes that heat, is the spontaneous combustion
of a fuel and oxygen, which ends up creating a large
amount of heat that is released.
• In this case, Charmander must contain some sort of fluid
within him such as Kerosene.

106. So to break it down:
• The fire that is seen in Charmnder’s attack, is actually
the result of an exothermic reaction, because it releases
heat (energy).
• What causes that heat, is the spontaneous combustion
of a fuel and oxygen, which ends up creating a large
amount of heat that is released.
• In this case, Charmander must contain some sort of fluid
within him such as Kerosene.
• He uses it to ignite a fire in his body, which he
continuously blows outward, creating a line of fire.

107. So to break it down:
• The fire that is seen in Charmnder’s attack, is actually
the result of an exothermic reaction, because it releases
heat (energy).
• What causes that heat, is the spontaneous combustion
of a fuel and oxygen, which ends up creating a large
amount of heat that is released.
• In this case, Charmander must contain some sort of fluid
within him such as Kerosene.
• He uses it to ignite a fire in his body, which he
continuously blows outward, creating a line of fire.
• The oxygen in the air helps support the reaction between
the fuel and heat, causing the fire to last longer, and
burn stronger.

109. Fire Triangle

111. Word
Problems

113. Variables
• M = Mass (in grams)
• C = Specific heat (4.184 j/degree/g)
• T = Change in temperature
• L = Latent Heat of Vaporization (2600 kJ/kg)
• Q = Added heat

114. Variables
• M = Mass (in grams)
• C = Specific heat (4.184 j/degree/g)
• T = Change in temperature
• L = Latent Heat of Vaporization (2600 kJ/kg)
• Q = Added heat
Q = (M x C x T) + (L x M)

116. So...If Charmander got hungry and used his
flamethrower attack to pop a single corn of
popcorn that contained 0.14grams of water in it,
and needed to change the temperature from 30
degrees Celsius to 100 degrees celsius, how much
heat would it take?

117. So...If Charmander got hungry and used his
flamethrower attack to pop a single corn of
popcorn that contained 0.14grams of water in it,
and needed to change the temperature from 30
degrees Celsius to 100 degrees celsius, how much
heat would it take?
Q = (M x C x T) + (L x M)

118. So...If Charmander got hungry and used his
flamethrower attack to pop a single corn of
popcorn that contained 0.14grams of water in it,
and needed to change the temperature from 30
degrees Celsius to 100 degrees celsius, how much
heat would it take?
Q = (M x C x T) + (L x M)
= (0.14 x 4.184 x 70) + (2260 x .014)
= (41) + (362)
= 357 J

120. Unfortunately, Charmander was still hungry, so if
he used his flamethrower attack to pop another
single corn of popcorn that contained 0.28grams
of water in it, and needed to change the
temperature from 30 degrees Celsius to 100
degrees celsius, how much heat would it take?

121. Unfortunately, Charmander was still hungry, so if
he used his flamethrower attack to pop another
single corn of popcorn that contained 0.28grams
of water in it, and needed to change the
temperature from 30 degrees Celsius to 100
degrees celsius, how much heat would it take?
Q = (M x C x T) + (L x M)

122. Unfortunately, Charmander was still hungry, so if
he used his flamethrower attack to pop another
single corn of popcorn that contained 0.28grams
of water in it, and needed to change the
temperature from 30 degrees Celsius to 100
degrees celsius, how much heat would it take?
Q = (M x C x T) + (L x M)
= (0.28 x 4.184 x 70) + (2260 x 0.28)
= (82) + (633)
= 715 J

124. Graph
Charmander's Flamethrower
1,250
1,072
1,000
750 715
Added
Heat
500
357
250
0
0
0 0.14 0.28 0.42
Grams of water

125. Review
• Brief History of the Pokemon Franchise
• Concepts:
• #1 Projectile Motion and some examples of
where it is used in our lives
• #2 Pikachu’s Thunderbolt and how lightning
occurs
• #3 Charmander’s Flamethrower and how fire
breathing works
• Today I hoped to have educated you all on the
physics of Pokemon and how physics can be
found in even the most strange things.