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CONE
CONE




The net   The examples in daily life
2 ∏r
                                                       Area of Circle
                                                       ∏l2
                                               l
                       l
             h
                           r

                   r
B=∏ r
        2   C= 2 ∏ r                        C= 2 ∏ l
                               B = Base area of circle
                               C = Circumference of circle
                               h = height of cone
                               r = radius of circle
                               l = slant height of cone
The example of cones in daily life




    CONES                   ANAK KRAKATAU
                              MOUNTAIN




             TRAFFIC CONE
The Formula of Cone
           Lateral Area / Curved Surface :              2 ∏r



                                                                 l
                          l
                 h
                                               r                         Area of Circle
                                                                         ∏l2
                      r
               C= 2 ∏ r                                       C= 2 ∏ l
            area of sector     Perimeter of sector / perimeter of cone’s base
B=∏ r
        2
                           =
             area of circle               perimeter of circle
             area of sector    2∏ r
                          =
    ∏l2         ∏l2            2∏ l 2
             area of sector     r   ∏l2
                          =
                ∏l  2
                                l
            Area of sector =        ∏rl
 Total Surface Area :
 T = Area of sector + Area of cone’s base
 T = Cs + Ba
 T = (∏ r l) + (∏ r2 )

 Volume Of Cone :

   V=    Ba . h


   V=    (∏ r2 ) h
Example
A cone has a base diameter of 10 cm and height of 12 cm. For
∏ = 3.14
Find : a. the curved surface area
       b. the base area
       c. the surface area
       d. the volume




     h = 12cm



         r = 5cm
Solution
Given that : r = 5 cm              a. The curved surface area :
                  h = 12 cm           Cs = ∏ r l
                 ∏ = 3. 14                 = 3.14 x 5 cm x 13 cm
                                          = 204.1 cm2
    l 2 = h2 + r 2                  So, the curved surface area of cone is
     l =                              204.1 cm 2

     l =                           b. The base area :
                                        Ba = ∏r 2
     l =
                                           = 3.14 x 5 cm x 5 cm
     l =             l = 13 cm           = 78.5 cm 2
So, the slant height of cone is    So, the base area of cone is 78.5 cm 2
     13 cm.
c. the surface area = ?



the surface area = Cs + Ba
                 = 204.1 cm2 + 78.5 cm2
                 = 285.6 cm2
 so, the surface area of cone is 285.6 cm2
d. volume =    Ba . h

          =   78.5 cm2 x 12 cm

           = 314 cm3
  So, the volume of cone is 314 cm3
EXERCISE
Given that the curved surface
of cone beside is 550 cm2 and
the radius is 7 cm

Find :
a. The slant height
b. The surface area     of the
   cone
c. The height of cone
Glory twinkle
Glory twinkle

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Glory twinkle

  • 1.
  • 3. CONE The net The examples in daily life
  • 4.
  • 5. 2 ∏r Area of Circle ∏l2 l l h r r B=∏ r 2 C= 2 ∏ r C= 2 ∏ l B = Base area of circle C = Circumference of circle h = height of cone r = radius of circle l = slant height of cone
  • 6.
  • 7. The example of cones in daily life CONES ANAK KRAKATAU MOUNTAIN TRAFFIC CONE
  • 8. The Formula of Cone  Lateral Area / Curved Surface : 2 ∏r l l h r Area of Circle ∏l2 r C= 2 ∏ r C= 2 ∏ l area of sector Perimeter of sector / perimeter of cone’s base B=∏ r 2 = area of circle perimeter of circle area of sector 2∏ r = ∏l2 ∏l2 2∏ l 2 area of sector r ∏l2 = ∏l 2 l Area of sector = ∏rl
  • 9.  Total Surface Area : T = Area of sector + Area of cone’s base T = Cs + Ba T = (∏ r l) + (∏ r2 )  Volume Of Cone : V= Ba . h V= (∏ r2 ) h
  • 10. Example A cone has a base diameter of 10 cm and height of 12 cm. For ∏ = 3.14 Find : a. the curved surface area b. the base area c. the surface area d. the volume h = 12cm r = 5cm
  • 11. Solution Given that : r = 5 cm a. The curved surface area : h = 12 cm Cs = ∏ r l ∏ = 3. 14 = 3.14 x 5 cm x 13 cm = 204.1 cm2 l 2 = h2 + r 2 So, the curved surface area of cone is l = 204.1 cm 2 l = b. The base area : Ba = ∏r 2 l = = 3.14 x 5 cm x 5 cm l = l = 13 cm = 78.5 cm 2 So, the slant height of cone is So, the base area of cone is 78.5 cm 2 13 cm.
  • 12. c. the surface area = ? the surface area = Cs + Ba = 204.1 cm2 + 78.5 cm2 = 285.6 cm2 so, the surface area of cone is 285.6 cm2
  • 13. d. volume = Ba . h = 78.5 cm2 x 12 cm = 314 cm3 So, the volume of cone is 314 cm3
  • 14. EXERCISE Given that the curved surface of cone beside is 550 cm2 and the radius is 7 cm Find : a. The slant height b. The surface area of the cone c. The height of cone