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The coffee cup bomb calorimeter
  By:Dr. Robert D. Craig, Ph.D
Page 287 only
• A set of nested coffee cups is a good constant
  pressure calorimeter
• http://smithecta.weebly.com/chapter-9---
  heat.html
• http://snapguide.com/david-shipp/
• http://web.lemoyne.edu/~giunta/chm151L/ca
  lorimetry.html
Today’sAgenda
• To determine the specific heat of a metal
• To determine the enthalpy of neutralization
  for a strong acid-strong base reaction
• To determine the enthalpy of solution for the
  dissolution of a salt
Introduction from Your text
• Accompanying all chemical and physical
  changes is a transfer of heat (energy); heat
  may be either evolved (exothermic) or
  absorbed (endotherminc) .
heat (energy) evolved (exothermic)
heat (energy) absorbed
   (endotherminc) .
NH4NO3 (c, IV) in water at 298.15 K to be
         ΔHo = 25.41 kJ mol−1.
A calorimeter . . . .hold heat well
• A calorimeter is the laboratory apparatus that
  is used to measure the quantity and direction
  of heat flow accompanying a chemical or
  physical change.
A professional one used in industry
Measures heat content . .
Entalphy . . A function of state
• The heat change in chemical reactions is
  quantitatively expressed as the enthalpy (or
  Heat) of reaction H, at constant pressure
negative for exothermic
•     H values are negative for exothermic
    reactions and positive for endothermic
    reactions.
a state function –independent of path
a state function –independent of path
The classic things today . .
• Three quantitative measurements of heat are
  detailed in this experiment:
• 1. Measurements of the specific heat of a
  metal,
• 2. the heat change accompanying an acid-base
  reaction,
• 3. and the heat change associated with the
  dissolution of a salt in water.
in joules,J
The energy (heat, expressed in joules,J) required
to change the temperature of one gram of a
substance by 1oC is the specific heat of that
substance SI units:
The specific is specific to all metals
Intensive properties-How much ???
• Intensive properties (temperature, pressure)
  do not depend upon the sample size.
Extensive-not how much
Confusing. . .must check units
• Intensive
  property**
• Specific heat capacity
  at constant volume ======J/(kg·K)
• extensive
  property**
• heat capacity
  at constant volume ======J/K
heat capacity as an intensive property
• heat capacity as an intensive
  property, i.e., independent of the size of a
  sample, are the molar heat capacity, which is
  the heat capacity per mole of a pure
  substance, and the specific heat
  capacity, often simply called specific
  heat, which is the heat capacity per unit mass
  of a material.
(25.2)
• Or rearranging for energy,
T is the temperature change
• T is the temperature change of the substance.
• Although the specific heat of a substance changes
  slightly with temperature, for our purposes, we
  assume it is constant over the temperature changes
  of this experiment.
• The specific heat of a metal that does not
  react with water is determined by heating a
  measured mass of the metal, M to a known
  (higher) temperature placing it into a
  measured amount of water at a known (lower)
  temperature measuring the final equilibrium
  temperature after the two are combined.
final equilibrium temperature after the
            two are combined
Page 288
• The following equations, based on the law of
  conservation of energy (insert NoW-
  Rob!!!!!!!!!)
•
specific heat of a metal
• Show the calculations for determining the
  specific heat of a metal. Considering the
  direction of energy flow by the conventional
  sign notation energy loss being “negative” and
  energy gain being “positive” then
(25.3)
--Energy Lost (-J) by the metal =
                  Energy (+J) gained by water
specific heat of a metal
Substituting and rearranging, We have

-specific heat x mass(M) x DT = specific heat
(H20) x mass (H20) x DT (H20)
This is (25.4)

This is equation (25.4) Rearranging equation
(25.4) , we solve for the specific heat of the
Metal as:
(25.5)
+specific heat x mass(M) x DT =
(-) specific heat (H20) x mass (H20) x DT (H20)
•                            mass(M) x DT
(25.6)
• In the equation, the temperature change for
  either substance is defined as the difference
  between the final temperature Tf, and the
  initial temperature, Ti, of the substance

 T-= Tf - Ti
T-= Tf - Ti

• These equations assume no heat lost to the
  calorimeter when the metal and the water are
  combined. The specific heat of water in 4.184
  J/g.oC
.
• In addition to using the calorimeter
  properly, key techniques for obtaining
  accurate results are starting with a dry
  calorimeter, measuring solution volumes
  precisely, and determining T accurately.
  Careful experimenters deal with the first two
  items easily.
• The last is somewhat more difficult. The
  change in temperature is determined by
  measuring the initial temperature, T1, of the
  reactants, and the maximum
  temperature, T2, of the contents of the
  calorimeter during the exothermic reaction.
.
• . The determination of a precise value for T2 is
  complicated by the fact that a small heat
  exchange occurs between the surroundings and
  the contents of the calorimeter, both during the
  reaction and after its completion. The rate of
  exchange depends on the insulating properties of
  the calorimeter and on the rate of stirring. A
  correction for this heat loss is made by an
  extrapolation of a temperature vs. time curve
  (see Figure 1 in your lab manual).
.
• The rate of exchange depends on the
  insulating properties of the calorimeter and
  on the rate of stirring. A correction for this
  heat loss is made by an extrapolation of a
  temperature vs. time curve (see Figure 1 in
  your lab manual).
Calorimeter video one-
           peterjackson118
• http://www.youtube.com/watch?v=WfO2sY-
  GJec&list=UUSnmgHe14lSSjaUfrtFdPGA&inde
  x=5&feature=plcp
Figure 2. Graph of temperature as a function of time for an
       exothermic reaction in a perfect calorimeter   .
no calorimeter is perfect!!!!

• Unfortunately, no calorimeter is perfect, and
  instantaneous mixing and reaction are not
  always achieved (even with efficient
  mixing). In this case, the graph of
  temperature as a function of time looks more
  like the figure above
.
• We can still find ΔT, but now we must
  extrapolate back to when the solutions were
  mixed (time, t, equals zero). This is most
  easily done by performing a linear regression
  on the sloped portion of the graph (where, for
  exothermic reactions, heat is leaking out of
  the calorimeter) and obtaining Tfinal from the
  y-intercept.
Put 3 caution slides here
Part B

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This is part one entalphy

  • 1. The coffee cup bomb calorimeter By:Dr. Robert D. Craig, Ph.D
  • 2. Page 287 only • A set of nested coffee cups is a good constant pressure calorimeter • http://smithecta.weebly.com/chapter-9--- heat.html • http://snapguide.com/david-shipp/ • http://web.lemoyne.edu/~giunta/chm151L/ca lorimetry.html
  • 3. Today’sAgenda • To determine the specific heat of a metal • To determine the enthalpy of neutralization for a strong acid-strong base reaction • To determine the enthalpy of solution for the dissolution of a salt
  • 4. Introduction from Your text • Accompanying all chemical and physical changes is a transfer of heat (energy); heat may be either evolved (exothermic) or absorbed (endotherminc) .
  • 5. heat (energy) evolved (exothermic)
  • 6. heat (energy) absorbed (endotherminc) .
  • 7. NH4NO3 (c, IV) in water at 298.15 K to be ΔHo = 25.41 kJ mol−1.
  • 8. A calorimeter . . . .hold heat well • A calorimeter is the laboratory apparatus that is used to measure the quantity and direction of heat flow accompanying a chemical or physical change.
  • 9. A professional one used in industry
  • 11. Entalphy . . A function of state • The heat change in chemical reactions is quantitatively expressed as the enthalpy (or Heat) of reaction H, at constant pressure
  • 12. negative for exothermic • H values are negative for exothermic reactions and positive for endothermic reactions.
  • 13. a state function –independent of path
  • 14. a state function –independent of path
  • 15. The classic things today . . • Three quantitative measurements of heat are detailed in this experiment: • 1. Measurements of the specific heat of a metal, • 2. the heat change accompanying an acid-base reaction, • 3. and the heat change associated with the dissolution of a salt in water.
  • 16. in joules,J The energy (heat, expressed in joules,J) required to change the temperature of one gram of a substance by 1oC is the specific heat of that substance SI units:
  • 17. The specific is specific to all metals
  • 18. Intensive properties-How much ??? • Intensive properties (temperature, pressure) do not depend upon the sample size.
  • 20. Confusing. . .must check units • Intensive property** • Specific heat capacity at constant volume ======J/(kg·K) • extensive property** • heat capacity at constant volume ======J/K
  • 21. heat capacity as an intensive property • heat capacity as an intensive property, i.e., independent of the size of a sample, are the molar heat capacity, which is the heat capacity per mole of a pure substance, and the specific heat capacity, often simply called specific heat, which is the heat capacity per unit mass of a material.
  • 23. T is the temperature change • T is the temperature change of the substance. • Although the specific heat of a substance changes slightly with temperature, for our purposes, we assume it is constant over the temperature changes of this experiment.
  • 24. • The specific heat of a metal that does not react with water is determined by heating a measured mass of the metal, M to a known (higher) temperature placing it into a measured amount of water at a known (lower) temperature measuring the final equilibrium temperature after the two are combined.
  • 25. final equilibrium temperature after the two are combined
  • 26. Page 288 • The following equations, based on the law of conservation of energy (insert NoW- Rob!!!!!!!!!) •
  • 27. specific heat of a metal • Show the calculations for determining the specific heat of a metal. Considering the direction of energy flow by the conventional sign notation energy loss being “negative” and energy gain being “positive” then
  • 28. (25.3) --Energy Lost (-J) by the metal = Energy (+J) gained by water
  • 29. specific heat of a metal Substituting and rearranging, We have -specific heat x mass(M) x DT = specific heat (H20) x mass (H20) x DT (H20)
  • 30. This is (25.4) This is equation (25.4) Rearranging equation (25.4) , we solve for the specific heat of the Metal as:
  • 31. (25.5) +specific heat x mass(M) x DT = (-) specific heat (H20) x mass (H20) x DT (H20) • mass(M) x DT
  • 32. (25.6) • In the equation, the temperature change for either substance is defined as the difference between the final temperature Tf, and the initial temperature, Ti, of the substance T-= Tf - Ti
  • 33. T-= Tf - Ti • These equations assume no heat lost to the calorimeter when the metal and the water are combined. The specific heat of water in 4.184 J/g.oC
  • 34. . • In addition to using the calorimeter properly, key techniques for obtaining accurate results are starting with a dry calorimeter, measuring solution volumes precisely, and determining T accurately. Careful experimenters deal with the first two items easily.
  • 35. • The last is somewhat more difficult. The change in temperature is determined by measuring the initial temperature, T1, of the reactants, and the maximum temperature, T2, of the contents of the calorimeter during the exothermic reaction.
  • 36. . • . The determination of a precise value for T2 is complicated by the fact that a small heat exchange occurs between the surroundings and the contents of the calorimeter, both during the reaction and after its completion. The rate of exchange depends on the insulating properties of the calorimeter and on the rate of stirring. A correction for this heat loss is made by an extrapolation of a temperature vs. time curve (see Figure 1 in your lab manual).
  • 37. . • The rate of exchange depends on the insulating properties of the calorimeter and on the rate of stirring. A correction for this heat loss is made by an extrapolation of a temperature vs. time curve (see Figure 1 in your lab manual).
  • 38. Calorimeter video one- peterjackson118 • http://www.youtube.com/watch?v=WfO2sY- GJec&list=UUSnmgHe14lSSjaUfrtFdPGA&inde x=5&feature=plcp
  • 39. Figure 2. Graph of temperature as a function of time for an exothermic reaction in a perfect calorimeter .
  • 40. no calorimeter is perfect!!!! • Unfortunately, no calorimeter is perfect, and instantaneous mixing and reaction are not always achieved (even with efficient mixing). In this case, the graph of temperature as a function of time looks more like the figure above
  • 41. . • We can still find ΔT, but now we must extrapolate back to when the solutions were mixed (time, t, equals zero). This is most easily done by performing a linear regression on the sloped portion of the graph (where, for exothermic reactions, heat is leaking out of the calorimeter) and obtaining Tfinal from the y-intercept.
  • 42. Put 3 caution slides here