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Tommy was a full-term baby but weighed only
4.5 pounds (2 kg) at birth. At about 9 months of age,
an unusual and persistent rash appeared on his face,
and he frequently caught colds and infections. The
illnesses caused no serious problems; so his parents
were not concerned.
       Throughout childhood, Tommy remained small;
by age 18, he was only 4 feet 6 inches (137 cm) in
height. Tommy’s first major health problem arose
shortly after he turned 22—he was diagnosed with
intestinal cancer. The tumor was surgically removed
but     additional,   unrelated    tumors   appeared
spontaneously over the next 10 years.
       Their appearance startled Tommy’s doctors;
the chance of multiple, independent cancers arising
in the same person is generally remote.
The propensity of Tommy’s cells to become
cancerous hinted at a high mutation rate in his genes.
Indeed,   when      pathologists    studied   Tommy’s
chromosomes, they observed a wide range of
abnormalities. Tommy had inherited BLOOM
SYNDROME.
      Bloom syndrome is a rare autosomal recessive
condition characterized by short stature, a facial
rash induced by sun exposure, a small narrow head,
and a predisposition to cancers of all types.
      The disorder is extremely rare; only several
hundred cases have been reported worldwide. Cells
from persons with Bloom syndrome exhibit excessive
mutations in all genes, and numerous gaps and breaks
occur in chromosomes that lead to extensive genetic
exchange in cell division. Rates of DNA synthesis are
retarded.
The characteristics of Bloom syndrome suggest
that its underlying cause is a defect in DNA replication.
In 1995, researchers at the New York Blood Center
traced Bloom syndrome to a gene on chromosome 15 that
encodes an enzyme called DNA helicase. A variety of
helicase enzymes are responsible for unwinding double-
stranded DNA during replication and repair.
       The cells of a person with Bloom syndrome carry
two mutated copies of the gene and possess little or no
activity for a particular helicase. Normal DNA
replication is disrupted, leading to chromosome breaks
and numerous mutations. The genetic damage resulting
from faulty DNA replication leads to tumors.
       It is not yet clear whether the basic defect in
DNA synthesis is associated with replication or DNA
repair or both.
To understand Tommy’s case, we need to answer
             the following questions:

 What models of DNA replication exist among life
  forms?
 Where is the origin of replication in the DNA
  strand?
 What is the direction of replication at this site?
 How does the chain grow in length?
 How does the chain terminate?
 What is the enzymology behind DNA replication?
 Are there other protein factors that must be
  present?
 What is the role of DNA replication in the
  expression of disease?
MODELS OF DNA REPLICATION




  These models may differ with respect to the
initiation and progression of replication, but all
      produce new DNA molecules by semi-
            conservative replication.
http://highered.mcgraw-

THETA REPLICATION: E. coli
                             hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites
                             /dl/free/0072437316/120073/micro03.swf::Bidirectional%
                             20Replication%20of%20DNA
ROLLING CIRCLE:
Viruses and F factor of E. Coli
L
I
N
E
A
R

R
E
P
L
I
C
A
T
I
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N
FUNDAMENTAL RULES OF DNA REPLICATION
           1. Replication is semi-conservative
   Meselson and Stahl convincingly demonstrated that
   each E. coli DNA strand serves as a template for the
            synthesis of a new DNA molecule.




     http://highered.mcgraw-
hill.com/olc/dl/120076/bio22.swf
2. Replication
                                      begins at an
                                       origin- the
                                    replication fork




http://highered.mcgraw-hill.com/olc/dl/120076/micro04.swf
3. DNA replication is bi-directional,
     and proceeds in a 5’-3’ direction




 DNA synthesis takes place simultaneously but
in opposite directions on the 2 template strands.
4. DNA Replication is Semi-discontinuous

         Replication fork




       lagging strand         Replication fork



    Leading strand
The polarity
   of DNA
  synthesis
 creates an
 asymmetry
between the
   leading
 strand and
 the lagging
strand at the
 replication
     fork
Requirements of Replication

 Although the process of replication includes
many components, they can be combined into
              three major groups:
1. a template consisting of single-stranded
   DNA,
2. raw materials (substrates) to be assembled
   into a new nucleotide strand, and
3. enzymes and other proteins that “read” the
   template and assemble the substrates into a
   DNA molecule.
New DNA is synthesized from deoxyribonucleotide triphosphates
(dNTPs). Since the 5’ end does not get added to and the 3’ end
repeatedly does, the DNA strand is said to grow in a 5’- 3’ manner.
D
N
A

P
o
l
y
m
e
r
a
s
e
DNA Polymerases in E. coli




                       DNA Polymerase III
Topoisomerase




Protein complexes of
 the replication fork
DNA helicase
     unwinds
 the DNA duplex
  ahead of DNA
   polymerase
 creating single
  stranded DNA
that can be used
  as a template
ssDNA binding proteins bind to the sugar phosphate backbone
leaving the bases exposed for DNA polymerase. The binding of
  SSB to newly formed ssDNA prevents reassociation of the
       single strands and “iron out” the unwound DNA.
Since DNA polymerase
requires a template and a
 free 3’ OH group to add
  nucleotides on to, RNA
 primers are required to
        initiate DNA
polymerization. Primase,
 an enzyme which is part
   of a large complex of
     proteins called the
 primosome, synthesizes
  a small stretch of RNA
    (the primer) of 3-10
   nucleotide in length,
     which will act as a
 starting site for the DNA
        polymerase.
DNA polymerase
   falls off the DNA
   easily. A “sliding
 clamp” is required to
keep DNA polymerase
      on and allow
  duplication of long
   stretches of DNA
A “clamp
  loader:”
complex is
  required
 to get the
clamp onto
  the DNA
Ahead of the
        replication
      fork the DNA
         becomes
       supercoiled



 The supercoiling needs
to be relieved or tension
   would build up (like
  coiling as spring) and
 block fork progression.
Supercoiling is relieved by the action of
              Topoisomerases.

1. Type I topoisomerases:
    Make nicks in one DNA strands
    Can relieve supercoiling
2. Type II topoisomersases or DNA gyrase
    Make nicks in both DNA strands (double
      strand break)
    Can relieve supercoiling and untangle
      linked DNA helices
 Both types of enzyme form covalent
   intermediates with the DNA
Type I Topoisomerase
Type II Topoisomerase
Topoisomerases as drug targets
1. Dividing cells require greater
   topoisomerase activity due to increased
   DNA synthesis
2. Topoisomerase inhibitors which act by
   stablilizing the DNA-topoisomerase
   complex are used as chemotherapeutic
   agents:
    camptothecin -Topo I inhibitor
      doxorubicin -- Topo II inhibitor
    Some antibiotics are inhibitors of the
      bacterial-specific topoisomerase DNA
      gyrase: e.g. ciprofloxacin
D
N
A

L
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A
S
E
, with less than one error per
billion nucleotides. This accuracy results from the processes
 of nucleotide selection, proofreading, and mismatch repair.
DNA mismatch repair corrects errors made during DNA
    replication.(A) If uncorrected, the mismatch will lead to a
permanent mutation in one of the two DNA molecules produced
   by the next round of DNA replication. (B) If the mismatch is
    “repaired” using the newly synthesized DNA strand as the
  template, both DNA molecules produced by the next round of
  DNA replication will contain a mutation. (C) If the mismatch is
     corrected using the original template (old) strand as the
template, the possibility of a mutation is eliminated. The scheme
       shown in (C) is used by cells to repair mismatches.
Chemical modifications of nucleotides, if left unrepaired, produce mutations.
  (A) Deamination of cytosine, if uncorrected, results in the substitution of one base for
  another when the DNA is replicated. Deamination of cytosine produces uracil. Uracil
  differs from cytosine in its base-pairing properties and preferentially base-pairs with
adenine. The DNA replication machinery therefore inserts an adenine when it encounters
  a U on the template strand. (B) Depurination, if uncorrected, can lead to the loss of a
   nucleotide pair. When the replication machinery encounters a missing purine on the
template strand, it can skip to the next complete nucleotide, thus producing a nucleotide
deletion in the newly synthesized strand. In other cases, the replication machinery places
   an incorrect nucleotide across from the missing base, again resulting in a mutation.
1. Helicase enzyme unwinds DNA. This reaction needs ATP. At each replicating
   fork, the exposed single-stranded DNA is protected by single-strand binding
   proteins (ssb). Primase enzyme binds, preparing to make RNA primers.
2. Primase enzyme makes RNA primer molecules. Each primer hybridizes (base
   pairs) with DNA, at the origin of replication. The 3' OH end will attach new deoxy
   nucleotides (dNTPs). The primers will each start a leading strand,
3. DNA polymerase III attaches new dNTPs to the 3' OH end of the growing chain of
   the leading strand, which elongates toward the replicating fork, 5' to 3'. (For each
   origin, there are TWO leading strands) For each NTP, a pyrophosphate (PP) is
   released, providing the necessary energy.
4. More primers hybridize to the opposite strand of DNA. Pol III starts elongating 5'
   to 3' but it keeps running into the back of an RNA primer. This is the lagging
   strand. There are TWO lagging strands.
5. DNA polymerase I (Pol I) starts at “nicks” in the growing strands. It edits the
   strand by removing bases ahead of it (5' end), including RNA and mismatched
   bases, while elongating the strand "behind" 5' to 3'. It replaces all RNA
   nucleotides with dNTPs.
6. Ligase seals the phosphate bonds at all “nicks” in the DNA.
7. Editing endonucleases excise mismatched nucleotides, replacing with the proper
   match. How do they know which is old DNA vs. new DNA? The old DNA contains
   methyl groups on some of its cytosine bases.
8. Gyrase restores negative superturns in DNA. ATP is needed.
9. Methylases add methyl groups to the new DNA, at the same positions as the
   original strands. Now the two daughter helices are indistinguishable from each
   other, and from the original helix.
THE EUKARYOTIC REPLICON
 Time for DNA replication is limited in the S phase of
eukaryotes (6-8 hrs in mammals. Such RFs move only
       about 1/10th of the prokaryotic forks, and
chromosomes can be in excess of 108 bp. Completion
  of replication at the allotted time requires multiple
     RFs called replicons. The Origin Recognition
 Complex (ORC) is a complex of 6 ATPases which is
           the functional equivalent of DnaA.
http://highered.mcgraw-
hill.com/olc/dl/120076/bio23.swf
EUKARYOTIC DNA POLYMERASES
How does a
    linear
chromosome
    close
 replication
  at its two
   ends?
As DNA synthesis
    requires a RNA
    primer that will
     eventually be
    digested away,
     standard DNA
   replication would
    result in linear
  chromosomes that
   would shrink with
    every round of
  replication. This is
 resolved in bacteria
    by the circular
 genome which does
  not have an end. In
linear chromosomes,
 the telomere solves
      the DNA end
 replication problem.
 Telomeres have
  highly repeated DNA
  sequences 5'-
  TTAGGG-3'.
 Human
  chromosomes have
  between 100 and
  1500 copies of this
  sequence.
 Telomerase, a
  special DNA
  polymerase, can add
  additional copies of
  the 5'-TTAGGG-3' to
  the end of a
  chromosome.
 The telomerase
  enzyme is actually a
  complex containing
  protein and RNA (a
  "ribozyme").
 The RNA portion has a 5'-CCCTAA-3' region that acts
  as a template for adding the DNA repeat to the
  chromosome ends.
 The telomerase enzyme is found mostly in the germ
  cells of multicellular organisms.
 In somatic cells, the absence of telomerase results in
  shorter chromosomal ends with each division and may
  be the limiting factor in an organism's life span.
TELOMERASE
AND DISEASE
Errors of DNA Replication and Disease
 Origins or replication are strictly controlled
  so that they “fire” only once per cell cycle
 Errors lead to over-replication of specific
  chromosomal regions = gene amplification
   This is commonly seen in cancer cells
     and can be an important prognostic
     indicator.
   It can also contribute to acquired drug
     resistance, e.g. Methotrexate induces
     amplification of the dihydrofolate
     reductase locus.
 The rate of misincorporation of bases by DNA
  polymerase is extremely low, however repeated
  sequences can cause problems.
 In particular, trinucleotide repeats cause difficulties
  which can lead to expansion of these sequences.
 Depending where the repeat is located, expansion of
  the sequence can have severe effects on the
  expression of a gene or the function of a protein.




   Looping out of repeats
     before replication.
Several inherited diseases are associated with
expansion of trinucleotide repeat sequences.




    Very different disorders, but they share the
    characteristic of becoming more severe in
    succeeding generations due to progressive
              expansion of the repeats
http://highered.mcgraw-hill.com/olc/dl/120076/bio21.swf
http://highered.mcgraw-hill.com/olc/dl/120076/bio22.swf
http://highered.mcgraw-hill.com/olc/dl/120076/micro04.swf
http://highered.mcgraw-hill.com/olc/dl/120076/bio23.swf
http://highered.mcgraw-
hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0
072437316/120076/micro04.swf::DNA%20Replication%20Fork
http://highered.mcgraw-
hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0
072437316/120076/bio23.swf::How%20Nucleotides%20are%20Ad
ded%20in%20DNA%20Replication

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cw/index.html

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Replication

  • 1.
  • 2. Tommy was a full-term baby but weighed only 4.5 pounds (2 kg) at birth. At about 9 months of age, an unusual and persistent rash appeared on his face, and he frequently caught colds and infections. The illnesses caused no serious problems; so his parents were not concerned. Throughout childhood, Tommy remained small; by age 18, he was only 4 feet 6 inches (137 cm) in height. Tommy’s first major health problem arose shortly after he turned 22—he was diagnosed with intestinal cancer. The tumor was surgically removed but additional, unrelated tumors appeared spontaneously over the next 10 years. Their appearance startled Tommy’s doctors; the chance of multiple, independent cancers arising in the same person is generally remote.
  • 3. The propensity of Tommy’s cells to become cancerous hinted at a high mutation rate in his genes. Indeed, when pathologists studied Tommy’s chromosomes, they observed a wide range of abnormalities. Tommy had inherited BLOOM SYNDROME. Bloom syndrome is a rare autosomal recessive condition characterized by short stature, a facial rash induced by sun exposure, a small narrow head, and a predisposition to cancers of all types. The disorder is extremely rare; only several hundred cases have been reported worldwide. Cells from persons with Bloom syndrome exhibit excessive mutations in all genes, and numerous gaps and breaks occur in chromosomes that lead to extensive genetic exchange in cell division. Rates of DNA synthesis are retarded.
  • 4. The characteristics of Bloom syndrome suggest that its underlying cause is a defect in DNA replication. In 1995, researchers at the New York Blood Center traced Bloom syndrome to a gene on chromosome 15 that encodes an enzyme called DNA helicase. A variety of helicase enzymes are responsible for unwinding double- stranded DNA during replication and repair. The cells of a person with Bloom syndrome carry two mutated copies of the gene and possess little or no activity for a particular helicase. Normal DNA replication is disrupted, leading to chromosome breaks and numerous mutations. The genetic damage resulting from faulty DNA replication leads to tumors. It is not yet clear whether the basic defect in DNA synthesis is associated with replication or DNA repair or both.
  • 5. To understand Tommy’s case, we need to answer the following questions:  What models of DNA replication exist among life forms?  Where is the origin of replication in the DNA strand?  What is the direction of replication at this site?  How does the chain grow in length?  How does the chain terminate?  What is the enzymology behind DNA replication?  Are there other protein factors that must be present?  What is the role of DNA replication in the expression of disease?
  • 6. MODELS OF DNA REPLICATION These models may differ with respect to the initiation and progression of replication, but all produce new DNA molecules by semi- conservative replication.
  • 7. http://highered.mcgraw- THETA REPLICATION: E. coli hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites /dl/free/0072437316/120073/micro03.swf::Bidirectional% 20Replication%20of%20DNA
  • 8. ROLLING CIRCLE: Viruses and F factor of E. Coli
  • 10.
  • 11. FUNDAMENTAL RULES OF DNA REPLICATION 1. Replication is semi-conservative Meselson and Stahl convincingly demonstrated that each E. coli DNA strand serves as a template for the synthesis of a new DNA molecule. http://highered.mcgraw- hill.com/olc/dl/120076/bio22.swf
  • 12.
  • 13. 2. Replication begins at an origin- the replication fork http://highered.mcgraw-hill.com/olc/dl/120076/micro04.swf
  • 14.
  • 15.
  • 16.
  • 17. 3. DNA replication is bi-directional, and proceeds in a 5’-3’ direction DNA synthesis takes place simultaneously but in opposite directions on the 2 template strands.
  • 18. 4. DNA Replication is Semi-discontinuous Replication fork lagging strand Replication fork Leading strand
  • 19.
  • 20. The polarity of DNA synthesis creates an asymmetry between the leading strand and the lagging strand at the replication fork
  • 21. Requirements of Replication Although the process of replication includes many components, they can be combined into three major groups: 1. a template consisting of single-stranded DNA, 2. raw materials (substrates) to be assembled into a new nucleotide strand, and 3. enzymes and other proteins that “read” the template and assemble the substrates into a DNA molecule.
  • 22. New DNA is synthesized from deoxyribonucleotide triphosphates (dNTPs). Since the 5’ end does not get added to and the 3’ end repeatedly does, the DNA strand is said to grow in a 5’- 3’ manner.
  • 23.
  • 25. DNA Polymerases in E. coli DNA Polymerase III
  • 26. Topoisomerase Protein complexes of the replication fork
  • 27. DNA helicase unwinds the DNA duplex ahead of DNA polymerase creating single stranded DNA that can be used as a template
  • 28. ssDNA binding proteins bind to the sugar phosphate backbone leaving the bases exposed for DNA polymerase. The binding of SSB to newly formed ssDNA prevents reassociation of the single strands and “iron out” the unwound DNA.
  • 29. Since DNA polymerase requires a template and a free 3’ OH group to add nucleotides on to, RNA primers are required to initiate DNA polymerization. Primase, an enzyme which is part of a large complex of proteins called the primosome, synthesizes a small stretch of RNA (the primer) of 3-10 nucleotide in length, which will act as a starting site for the DNA polymerase.
  • 30. DNA polymerase falls off the DNA easily. A “sliding clamp” is required to keep DNA polymerase on and allow duplication of long stretches of DNA
  • 31. A “clamp loader:” complex is required to get the clamp onto the DNA
  • 32.
  • 33.
  • 34. Ahead of the replication fork the DNA becomes supercoiled The supercoiling needs to be relieved or tension would build up (like coiling as spring) and block fork progression.
  • 35. Supercoiling is relieved by the action of Topoisomerases. 1. Type I topoisomerases:  Make nicks in one DNA strands  Can relieve supercoiling 2. Type II topoisomersases or DNA gyrase  Make nicks in both DNA strands (double strand break)  Can relieve supercoiling and untangle linked DNA helices  Both types of enzyme form covalent intermediates with the DNA
  • 38. Topoisomerases as drug targets 1. Dividing cells require greater topoisomerase activity due to increased DNA synthesis 2. Topoisomerase inhibitors which act by stablilizing the DNA-topoisomerase complex are used as chemotherapeutic agents:  camptothecin -Topo I inhibitor doxorubicin -- Topo II inhibitor  Some antibiotics are inhibitors of the bacterial-specific topoisomerase DNA gyrase: e.g. ciprofloxacin
  • 40.
  • 41.
  • 42.
  • 43. , with less than one error per billion nucleotides. This accuracy results from the processes of nucleotide selection, proofreading, and mismatch repair.
  • 44. DNA mismatch repair corrects errors made during DNA replication.(A) If uncorrected, the mismatch will lead to a permanent mutation in one of the two DNA molecules produced by the next round of DNA replication. (B) If the mismatch is “repaired” using the newly synthesized DNA strand as the template, both DNA molecules produced by the next round of DNA replication will contain a mutation. (C) If the mismatch is corrected using the original template (old) strand as the template, the possibility of a mutation is eliminated. The scheme shown in (C) is used by cells to repair mismatches.
  • 45. Chemical modifications of nucleotides, if left unrepaired, produce mutations. (A) Deamination of cytosine, if uncorrected, results in the substitution of one base for another when the DNA is replicated. Deamination of cytosine produces uracil. Uracil differs from cytosine in its base-pairing properties and preferentially base-pairs with adenine. The DNA replication machinery therefore inserts an adenine when it encounters a U on the template strand. (B) Depurination, if uncorrected, can lead to the loss of a nucleotide pair. When the replication machinery encounters a missing purine on the template strand, it can skip to the next complete nucleotide, thus producing a nucleotide deletion in the newly synthesized strand. In other cases, the replication machinery places an incorrect nucleotide across from the missing base, again resulting in a mutation.
  • 46. 1. Helicase enzyme unwinds DNA. This reaction needs ATP. At each replicating fork, the exposed single-stranded DNA is protected by single-strand binding proteins (ssb). Primase enzyme binds, preparing to make RNA primers. 2. Primase enzyme makes RNA primer molecules. Each primer hybridizes (base pairs) with DNA, at the origin of replication. The 3' OH end will attach new deoxy nucleotides (dNTPs). The primers will each start a leading strand, 3. DNA polymerase III attaches new dNTPs to the 3' OH end of the growing chain of the leading strand, which elongates toward the replicating fork, 5' to 3'. (For each origin, there are TWO leading strands) For each NTP, a pyrophosphate (PP) is released, providing the necessary energy. 4. More primers hybridize to the opposite strand of DNA. Pol III starts elongating 5' to 3' but it keeps running into the back of an RNA primer. This is the lagging strand. There are TWO lagging strands. 5. DNA polymerase I (Pol I) starts at “nicks” in the growing strands. It edits the strand by removing bases ahead of it (5' end), including RNA and mismatched bases, while elongating the strand "behind" 5' to 3'. It replaces all RNA nucleotides with dNTPs. 6. Ligase seals the phosphate bonds at all “nicks” in the DNA. 7. Editing endonucleases excise mismatched nucleotides, replacing with the proper match. How do they know which is old DNA vs. new DNA? The old DNA contains methyl groups on some of its cytosine bases. 8. Gyrase restores negative superturns in DNA. ATP is needed. 9. Methylases add methyl groups to the new DNA, at the same positions as the original strands. Now the two daughter helices are indistinguishable from each other, and from the original helix.
  • 47. THE EUKARYOTIC REPLICON Time for DNA replication is limited in the S phase of eukaryotes (6-8 hrs in mammals. Such RFs move only about 1/10th of the prokaryotic forks, and chromosomes can be in excess of 108 bp. Completion of replication at the allotted time requires multiple RFs called replicons. The Origin Recognition Complex (ORC) is a complex of 6 ATPases which is the functional equivalent of DnaA.
  • 50. How does a linear chromosome close replication at its two ends?
  • 51. As DNA synthesis requires a RNA primer that will eventually be digested away, standard DNA replication would result in linear chromosomes that would shrink with every round of replication. This is resolved in bacteria by the circular genome which does not have an end. In linear chromosomes, the telomere solves the DNA end replication problem.
  • 52.  Telomeres have highly repeated DNA sequences 5'- TTAGGG-3'.  Human chromosomes have between 100 and 1500 copies of this sequence.  Telomerase, a special DNA polymerase, can add additional copies of the 5'-TTAGGG-3' to the end of a chromosome.  The telomerase enzyme is actually a complex containing protein and RNA (a "ribozyme").
  • 53.  The RNA portion has a 5'-CCCTAA-3' region that acts as a template for adding the DNA repeat to the chromosome ends.  The telomerase enzyme is found mostly in the germ cells of multicellular organisms.  In somatic cells, the absence of telomerase results in shorter chromosomal ends with each division and may be the limiting factor in an organism's life span.
  • 55. Errors of DNA Replication and Disease  Origins or replication are strictly controlled so that they “fire” only once per cell cycle  Errors lead to over-replication of specific chromosomal regions = gene amplification  This is commonly seen in cancer cells and can be an important prognostic indicator.  It can also contribute to acquired drug resistance, e.g. Methotrexate induces amplification of the dihydrofolate reductase locus.
  • 56.  The rate of misincorporation of bases by DNA polymerase is extremely low, however repeated sequences can cause problems.  In particular, trinucleotide repeats cause difficulties which can lead to expansion of these sequences.  Depending where the repeat is located, expansion of the sequence can have severe effects on the expression of a gene or the function of a protein. Looping out of repeats before replication.
  • 57. Several inherited diseases are associated with expansion of trinucleotide repeat sequences. Very different disorders, but they share the characteristic of becoming more severe in succeeding generations due to progressive expansion of the repeats
  • 58.