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COMPETENCIA: REALIZAR MANTENIMIENTO PREVENTIVO Y PREDICTIVO QUE
PROLONGUE EL FUNCIONAMIENTO DE LOS EQUIPOS DE COMPUTO.
RESULTADOS DE APRENDIZAJE:
• EJECUTAR EL MANTENIMIENTO FÍSICO INTERNO Y EXTERNO DE LOS EQUIPOS
DE CÓMPUTO APLICANDO LAS TÉCNICAS, INSUMOS, MANUALES Y
PROCEDIMIENTOS ESTABLECIDOS.
• ENSAMBLAR Y DESENSAMBLAR LOS COMPONENTES HARDWARE DE LOS
DIFERENTES TIPOS DE EQUIPOS, DE ACUERDO CON LA COMPLEJIDAD DE LA
ARQUITECTURA, LAS HERRAMIENTAS REQUERIDAS, LA NORMATIVIDAD,
MANUALES TÉCNICOS, Y LOS PROCEDIMIENTOS.
Taller Principios Eléctricos
1. Para los siguientes circuitos calcula la resistencia total
A.
RT=R1+R2+R3+R4 RT=220000Ω+1000000Ω+130000Ω+820000Ω
R1= 220k = 220000 Ω RT= 2170000 Ω
R2= 1M = 1000000 Ω
R3= 130k = 130000 Ω
R4= 820k = 820000 Ω
B
.
RT=R1+R2+R3+R4
R1= 720 Ω = 720 Ω RT=720Ω+1100Ω+130000Ω+1820Ω+1620Ω
R2= 1, 1 k = 1100 Ω
R3= 130 k = 130000 Ω RT= 135260Ω
R4= 1820 Ω =1820 Ω
R5= 1, 62 k = 1620 Ω
C.
RT=R1+R2+R3+R4+R5 RT=7700Ω+11100Ω+1230Ω+1820Ω+7060Ω
R1= 7, 7 k = 7700 Ω RT= 28910 Ω
R2= 11, 1 k = 11100 Ω
R3= 1230 Ω = 1230 Ω
R4= 1820 Ω = 1820 Ω
R5= 7, 06 k = 7060 Ω
D.
1 1 1
― = ― = ―
R1 12, 5 k 12500 Ω
1 1 1
― = ― = ―
R2 25 k 25000 Ω
1 1 1
― = ― = ―
R3 12, 5 k 12500 Ω
1 1 1 1
― = ― + ― + ―
RT 12500Ω 25000Ω 12500Ω
1 2 + 1 + 2
― =
RT 25000
1 5
― =
RT 25000
25000
RT =
5
RT= 5000 Ω
E.
1 1
― = ―
R1 500 Ω
1 1 1
― = ― = ―
R2 25k 25000Ω
1 1 1
― = ― = ―
R3 25k 25000Ω
1 1 1
― = ― = ―
R4 1k 1000Ω
1 1 1 1 1
― = ― + ― + ― + ―
RT 500Ω 25000Ω 12500Ω 1000Ω
1 50 + 1 + 2 + 25
― =
RT 25000
1 78
― =
RT 25000
25000
RT =
78
RT= 320, 51 Ω
2. Identifique cada uno de los siguientes símbolos:
Si alguno de los símbolos no ha sido visto en clase consultarlo
Símbolo Dispositivo
TRANSFORMADOR
INDUCTANCIA
VOLTIMETRO
AMPERIMETRO
LAMPARA INCANDECENTE
DIODO SENTIDO PERMITIDO
(CONVENCIONAL)
RESISTENCIAVARIABLE
POTENCIMETRO
DIODO LED
CRUCE CON CONEXIÓN
3. Calcule la corriente para los siguientes circuitos
A.
1 1 1
― = ― = ―
R1 12, 5 k 12500 Ω
1 1 1
― = ― = ―
R2 25 k 25000 Ω
1 1 1
― = ― = ―
R3 12, 5 k 12500 Ω
1 1 1 1
― = ― + ― + ―
RT 12500Ω 25000Ω 12500Ω
1 2 + 1 + 2
― =
RT 25000
1 5
― =
RT 25000
25000
RT =
5
RT= 5000 Ω
V 10V
I = ― = ― = 0, 002 A = 2 mA
RT 5000Ω
B.
1 1 1
― = ― = ―
R2 25k 25000Ω
1 1 1
― = ― = ―
R3 12,5 k 12500Ω
1 1 1
― = ― + ―
RT 2500Ω 12500Ω
1 1+2
― =
RT 25000
1 3
― =
RT 25000
25000
RT =
3
RT= 8333, 3 Ω
V 10V
I = ― = ― = 0, 0012
RT 8333, 3
I = 0,0012A= 1,2mA
.
V 6V 6V
I = ― = ― = ― = 0,00024
R2 R2 25k 25000Ω
I= 0,00024A= 0,24mA
D..
1 1 1
― = ― = ―
R3 25k 25000Ω
1 1 1
― = ― = ―
R4 1k 1000Ω
1 1 1
― = ― + ―
RT 2500Ω 1000Ω
1 1+25
― =
RT 25000
1 26
― =
RT 25000
25000
RT =
26
RT= 961,538 Ω
V 6V
I = ― = ― = 0, 0062
RT 961,538
I = 0,0062A= 6,2mA
E.
1 1
― = ―
R1 500 Ω
1 1 1
― = ― = ―
R2 25k 25000Ω
1 1 1
― = ― = ―
R3 25k 25000Ω
1 1 1
― = ― = ―
R4 1k 1000Ω
1 1 1 1 1
― = ― + ― + ― + ―
RT 500Ω 25000Ω 12500Ω 1000Ω
1 50 + 1 + 2 + 25
― =
RT 25000
1 78
― =
RT 25000
25000
RT =
78
RT= 320,51 Ω
V 6V
I = ― = ― = 0,018
RT 320, 51
I = 0,0187A= 18,7mA
4. Calcule el voltaje para los siguientes circuitos
A.
V=I*R
V 10V
I= ― = ― = 3,71A
RT 26940Ω
RT=R1+R2+R3+R4+R5
R1= 7, 7 k = 7700 Ω
R2= 11, 12 k =11120 Ω
R3= 120Ω
R4=1 k =1000Ω
R5= 7, 0 k = 7000 Ω
RT= 7700Ω+11120Ω+120Ω+1000Ω+7000Ω
RT= 26940 Ω
V=I*R
V=3, 71*1000
V= 3710
B.
V=I*R
V 5V
I= ― = ― = 3,59A
RT 13920Ω
RT=R1+R2+R3+R4+R5
R1= 1700 Ω
R2= 11 k =11000 Ω
R3= 320Ω
R4=222Ω
R5= 678Ω
RT= 1700Ω+11000Ω+320Ω+222Ω+678Ω
RT= 13920Ω
V=I*R
V=3, 59*11000
V= 39490
C.
V=I*R
V 5V
I= ― = ― = 1,057A
RT 4730200Ω
RT=R1+R2+R3+R4
R1= 1, 2 M =1200000Ω
R2= 110 k =110000 Ω
R3= 3, 2 M =3200000Ω
R4=220, 2 k =220200Ω
RT= 1200000Ω+110000Ω+3200000Ω+220200Ω
RT= 4730200Ω
V=I*R
V=1,057*1200000
V= 8, 80

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solicion Taller principios electricos

  • 1. COMPETENCIA: REALIZAR MANTENIMIENTO PREVENTIVO Y PREDICTIVO QUE PROLONGUE EL FUNCIONAMIENTO DE LOS EQUIPOS DE COMPUTO. RESULTADOS DE APRENDIZAJE: • EJECUTAR EL MANTENIMIENTO FÍSICO INTERNO Y EXTERNO DE LOS EQUIPOS DE CÓMPUTO APLICANDO LAS TÉCNICAS, INSUMOS, MANUALES Y PROCEDIMIENTOS ESTABLECIDOS. • ENSAMBLAR Y DESENSAMBLAR LOS COMPONENTES HARDWARE DE LOS DIFERENTES TIPOS DE EQUIPOS, DE ACUERDO CON LA COMPLEJIDAD DE LA ARQUITECTURA, LAS HERRAMIENTAS REQUERIDAS, LA NORMATIVIDAD, MANUALES TÉCNICOS, Y LOS PROCEDIMIENTOS. Taller Principios Eléctricos 1. Para los siguientes circuitos calcula la resistencia total A. RT=R1+R2+R3+R4 RT=220000Ω+1000000Ω+130000Ω+820000Ω R1= 220k = 220000 Ω RT= 2170000 Ω R2= 1M = 1000000 Ω R3= 130k = 130000 Ω R4= 820k = 820000 Ω B . RT=R1+R2+R3+R4
  • 2. R1= 720 Ω = 720 Ω RT=720Ω+1100Ω+130000Ω+1820Ω+1620Ω R2= 1, 1 k = 1100 Ω R3= 130 k = 130000 Ω RT= 135260Ω R4= 1820 Ω =1820 Ω R5= 1, 62 k = 1620 Ω C. RT=R1+R2+R3+R4+R5 RT=7700Ω+11100Ω+1230Ω+1820Ω+7060Ω R1= 7, 7 k = 7700 Ω RT= 28910 Ω R2= 11, 1 k = 11100 Ω R3= 1230 Ω = 1230 Ω R4= 1820 Ω = 1820 Ω R5= 7, 06 k = 7060 Ω D. 1 1 1 ― = ― = ― R1 12, 5 k 12500 Ω
  • 3. 1 1 1 ― = ― = ― R2 25 k 25000 Ω 1 1 1 ― = ― = ― R3 12, 5 k 12500 Ω 1 1 1 1 ― = ― + ― + ― RT 12500Ω 25000Ω 12500Ω 1 2 + 1 + 2 ― = RT 25000 1 5 ― = RT 25000 25000 RT = 5 RT= 5000 Ω E. 1 1 ― = ― R1 500 Ω
  • 4. 1 1 1 ― = ― = ― R2 25k 25000Ω 1 1 1 ― = ― = ― R3 25k 25000Ω 1 1 1 ― = ― = ― R4 1k 1000Ω 1 1 1 1 1 ― = ― + ― + ― + ― RT 500Ω 25000Ω 12500Ω 1000Ω 1 50 + 1 + 2 + 25 ― = RT 25000 1 78 ― = RT 25000 25000 RT = 78 RT= 320, 51 Ω 2. Identifique cada uno de los siguientes símbolos: Si alguno de los símbolos no ha sido visto en clase consultarlo Símbolo Dispositivo TRANSFORMADOR INDUCTANCIA
  • 5. VOLTIMETRO AMPERIMETRO LAMPARA INCANDECENTE DIODO SENTIDO PERMITIDO (CONVENCIONAL) RESISTENCIAVARIABLE POTENCIMETRO DIODO LED CRUCE CON CONEXIÓN 3. Calcule la corriente para los siguientes circuitos A. 1 1 1 ― = ― = ― R1 12, 5 k 12500 Ω 1 1 1 ― = ― = ― R2 25 k 25000 Ω 1 1 1 ― = ― = ― R3 12, 5 k 12500 Ω
  • 6. 1 1 1 1 ― = ― + ― + ― RT 12500Ω 25000Ω 12500Ω 1 2 + 1 + 2 ― = RT 25000 1 5 ― = RT 25000 25000 RT = 5 RT= 5000 Ω V 10V I = ― = ― = 0, 002 A = 2 mA RT 5000Ω B. 1 1 1 ― = ― = ― R2 25k 25000Ω
  • 7. 1 1 1 ― = ― = ― R3 12,5 k 12500Ω 1 1 1 ― = ― + ― RT 2500Ω 12500Ω 1 1+2 ― = RT 25000 1 3 ― = RT 25000 25000 RT = 3 RT= 8333, 3 Ω V 10V I = ― = ― = 0, 0012 RT 8333, 3 I = 0,0012A= 1,2mA .
  • 8. V 6V 6V I = ― = ― = ― = 0,00024 R2 R2 25k 25000Ω I= 0,00024A= 0,24mA D.. 1 1 1 ― = ― = ― R3 25k 25000Ω 1 1 1 ― = ― = ― R4 1k 1000Ω 1 1 1
  • 9. ― = ― + ― RT 2500Ω 1000Ω 1 1+25 ― = RT 25000 1 26 ― = RT 25000 25000 RT = 26 RT= 961,538 Ω V 6V I = ― = ― = 0, 0062 RT 961,538 I = 0,0062A= 6,2mA E.
  • 10. 1 1 ― = ― R1 500 Ω 1 1 1 ― = ― = ― R2 25k 25000Ω 1 1 1 ― = ― = ― R3 25k 25000Ω 1 1 1 ― = ― = ― R4 1k 1000Ω 1 1 1 1 1 ― = ― + ― + ― + ― RT 500Ω 25000Ω 12500Ω 1000Ω 1 50 + 1 + 2 + 25 ― = RT 25000 1 78 ― = RT 25000
  • 11. 25000 RT = 78 RT= 320,51 Ω V 6V I = ― = ― = 0,018 RT 320, 51 I = 0,0187A= 18,7mA 4. Calcule el voltaje para los siguientes circuitos A. V=I*R V 10V I= ― = ― = 3,71A RT 26940Ω RT=R1+R2+R3+R4+R5 R1= 7, 7 k = 7700 Ω R2= 11, 12 k =11120 Ω R3= 120Ω R4=1 k =1000Ω
  • 12. R5= 7, 0 k = 7000 Ω RT= 7700Ω+11120Ω+120Ω+1000Ω+7000Ω RT= 26940 Ω V=I*R V=3, 71*1000 V= 3710 B. V=I*R V 5V I= ― = ― = 3,59A RT 13920Ω RT=R1+R2+R3+R4+R5 R1= 1700 Ω R2= 11 k =11000 Ω R3= 320Ω R4=222Ω R5= 678Ω RT= 1700Ω+11000Ω+320Ω+222Ω+678Ω RT= 13920Ω V=I*R
  • 13. V=3, 59*11000 V= 39490 C. V=I*R V 5V I= ― = ― = 1,057A RT 4730200Ω RT=R1+R2+R3+R4 R1= 1, 2 M =1200000Ω R2= 110 k =110000 Ω R3= 3, 2 M =3200000Ω R4=220, 2 k =220200Ω RT= 1200000Ω+110000Ω+3200000Ω+220200Ω RT= 4730200Ω V=I*R V=1,057*1200000 V= 8, 80