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Topic: the distance between two points.

TRADITIONAL APPROACH:
Distance-formula:
                  y
                                  Q
                                       (x2,y2)

                           P (x ,y )
                               1 1




                   0                         x




 The distance between P and Q ( PQ ) is
  (x 2 −1 )2 +y 2 − 1 )2
        x     ( y

Example: Find the distance between the points with
coordinates (-3,4) and (5,-3).
Solution: ( (−3) − 5) 2 + ( 4 − (−3) ) 2 = 64 + 49 = 113 ≈ 10.6


ALTERNATIVE APPROACH:
Start:
Find the distance between the points with coordinates (-3,4)
and (5,-3).

STEP 1: Draw the situation! (The situation will get more
meaning)
y

     (-3,4)


              1
               0   1              x



                             (5,-3)


STEP 2: So, what do you think the distance between the two
points will be? 3? Or 5? Or greater ? Why?
(ESTIMATE!!)

STEP 3: We are going to find out. We will use a right
triangle, and Pythagorean theorem.
               y
      C
     (-3,4)


              1
               0   1              x


                                  B
      A                      (5,-3)

Recall:Pythagorean Theorem for the right triangle above:
AB2+AC2=BC2
  • What is the distance between A and B? (You can just
    count: 8) (USE OF COMMON SENSE, OF WHAT YOU
    ALREADY KNOW)
     (If you want to express it already in terms of the x-coordinates: |
     5-(-3)|=8; but maybe better to first show that you don’t need any
     ‘complex’ notations…)
•   What is the distance between A and C? (You can just
      count: 7) (USE OF COMMON SENSE, OF WHAT YOU
      ALREADY KNOW)
    (If you want to express it already in terms of the y-coordinates: |
    (-3)-4|=7; but maybe better to first show that you don’t need any
    ‘complex’ notations…)
  • So what is the distance between B and C? With use of
      Pythagorean theorem:
      (BC)2= 82+72 = 64+49 = 113, so the distance between B and C
      is 113 = 10.6
(CALCULATE!!)

STEP 4: From your first estimation and the drawing, you
think 10.6 could be the correct answer? So you did not make
any mistakes?
(REFLECTION!!)

After this, you can give one other example, or you can
already let them work. You could even ask the students to
give a general formula of the distance between two points, if
they have practised enough exercises.

You can also ask a CONTEXT-problem in which distance is
concerned, for instance:
Mark lives 3 km from school and Rona lives 5 km from
school.
  a) What is the maximum possible distance between their
     two houses and what is the minimum possible distance
     between their two houses?
  b) If the situation is as illustrated below, how far do Mark
     and Rona live apart?
                          Rona




                 school          Mark




  c)   If you know that Rona and Mark live 4 km apart, draw in
       the graph below the possible locations for Mark’s
       house:
                          Rona




                 school




       How did you find the locations?

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Distance between two points

  • 1. Topic: the distance between two points. TRADITIONAL APPROACH: Distance-formula: y Q (x2,y2) P (x ,y ) 1 1 0 x The distance between P and Q ( PQ ) is (x 2 −1 )2 +y 2 − 1 )2 x ( y Example: Find the distance between the points with coordinates (-3,4) and (5,-3). Solution: ( (−3) − 5) 2 + ( 4 − (−3) ) 2 = 64 + 49 = 113 ≈ 10.6 ALTERNATIVE APPROACH: Start: Find the distance between the points with coordinates (-3,4) and (5,-3). STEP 1: Draw the situation! (The situation will get more meaning)
  • 2. y (-3,4) 1 0 1 x (5,-3) STEP 2: So, what do you think the distance between the two points will be? 3? Or 5? Or greater ? Why? (ESTIMATE!!) STEP 3: We are going to find out. We will use a right triangle, and Pythagorean theorem. y C (-3,4) 1 0 1 x B A (5,-3) Recall:Pythagorean Theorem for the right triangle above: AB2+AC2=BC2 • What is the distance between A and B? (You can just count: 8) (USE OF COMMON SENSE, OF WHAT YOU ALREADY KNOW) (If you want to express it already in terms of the x-coordinates: | 5-(-3)|=8; but maybe better to first show that you don’t need any ‘complex’ notations…)
  • 3. What is the distance between A and C? (You can just count: 7) (USE OF COMMON SENSE, OF WHAT YOU ALREADY KNOW) (If you want to express it already in terms of the y-coordinates: | (-3)-4|=7; but maybe better to first show that you don’t need any ‘complex’ notations…) • So what is the distance between B and C? With use of Pythagorean theorem: (BC)2= 82+72 = 64+49 = 113, so the distance between B and C is 113 = 10.6 (CALCULATE!!) STEP 4: From your first estimation and the drawing, you think 10.6 could be the correct answer? So you did not make any mistakes? (REFLECTION!!) After this, you can give one other example, or you can already let them work. You could even ask the students to give a general formula of the distance between two points, if they have practised enough exercises. You can also ask a CONTEXT-problem in which distance is concerned, for instance:
  • 4. Mark lives 3 km from school and Rona lives 5 km from school. a) What is the maximum possible distance between their two houses and what is the minimum possible distance between their two houses? b) If the situation is as illustrated below, how far do Mark and Rona live apart? Rona school Mark c) If you know that Rona and Mark live 4 km apart, draw in the graph below the possible locations for Mark’s house: Rona school How did you find the locations?