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11.6 The Binomial Theorem



Matthew 7:7 "Ask, and it shall be given you; seek, and ye
shall find; knock, and it shall be opened unto you."
How do we expand ( a + b ) ?
                         n
How do we expand ( a + b ) ?
                         n




We will explore two methods:
How do we expand ( a + b ) ?
                           n




We will explore two methods:
1) Using Pascal’s Triangle (a recursive method)
How do we expand ( a + b ) ?
                           n




We will explore two methods:
1) Using Pascal’s Triangle (a recursive method)
2) Using the Binomial Theorem (an explicit
   method that uses combinatorics)
Pascal’s Triangle
Pascal’s Triangle

    Recall from last year ...
Pascal’s Triangle
   Provides coefficients for expansion of a binomial
Pascal’s Triangle
   Provides coefficients for expansion of a binomial
       0
 (a + b) =                                 1
        1
 (a + b) =                             1a + 1b
        2                          2                       2
 (a + b) =                       1a + 2ab + 1b
        3                    3         2               2               3
 (a + b) =           1a + 3a b + 3ab + 1b
        4            4            3              2 2                   3   4
 (a + b) =         1a + 4a b + 6a b + 4ab + 1b
        5      5         4                 3 2                 2   3       4   5
 (a + b) =   1a + 5a b + 10a b + 10a b + 5ab + 1b
Pascal’s Triangle
   Provides coefficients for expansion of a binomial
       0
 (a + b) =                                 1
        1
 (a + b) =                             1a + 1b
        2                          2                       2
 (a + b) =                       1a + 2ab + 1b
        3                    3         2               2               3
 (a + b) =           1a + 3a b + 3ab + 1b
        4            4            3              2 2                   3   4
 (a + b) =         1a + 4a b + 6a b + 4ab + 1b
        5      5         4                 3 2                 2   3       4   5
 (a + b) =   1a + 5a b + 10a b + 10a b + 5ab + 1b

      Also notice the pattern of the exponents!
Pascal’s Triangle
   Provides coefficients for expansion of a binomial
       0
 (a + b) =                                    1
        1
 (a + b) =                                1a + 1b
        2                             2                        2
 (a + b) =                       1a + 2ab + 1b
        3                    3            2                2               3
 (a + b) =            1a + 3a b + 3ab + 1b
        4            4               3               2 2                   3   4
 (a + b) =         1a + 4a b + 6a b + 4ab + 1b
        5      5         4                    3 2                  2   3       4   5
 (a + b) =   1a + 5a b + 10a b + 10a b + 5ab + 1b

      Also notice the pattern of the exponents!
                    Let’s expand ( a + b ) .
                                                           6

                                 (do on the board)
Let’s expand ( 3 − xy )
                          4
Let’s expand ( 3 − xy )
                          4




First, write out ( a + b ) in expanded form.
                      4
Let’s expand ( 3 − xy )
                           4




First, write out ( a + b ) in expanded form.
                      4


        4     3      2 2       3   4
       a + 4a b + 6a b + 4ab + b
Let’s expand ( 3 − xy )
                           4




First, write out ( a + b ) in expanded form.
                      4


        4     3      2 2       3   4
       a + 4a b + 6a b + 4ab + b
Then substitute 3 for a and -xy for b
Let’s expand ( 3 − xy )
                                     4




First, write out ( a + b ) in expanded form.
                                 4


               4       3       2 2           3       4
              a + 4a b + 6a b + 4ab + b
Then substitute 3 for a and -xy for b
        4          3                     2       2           3             4
 ( 3)       + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy )
Let’s expand ( 3 − xy )
                                     4




First, write out ( a + b ) in expanded form.
                                 4


               4       3       2 2           3       4
              a + 4a b + 6a b + 4ab + b
Then substitute 3 for a and -xy for b
        4          3                     2       2           3             4
 ( 3)       + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy )

and simplify
Let’s expand ( 3 − xy )
                                     4




First, write out ( a + b ) in expanded form.
                                 4


               4       3       2 2           3         4
              a + 4a b + 6a b + 4ab + b
Then substitute 3 for a and -xy for b
        4          3                     2       2                 3       4
 ( 3)       + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy )

and simplify
                                     2 2             3 3   4   4
              81− 108xy + 54x y − 12x y + x y
Pascal’s Triangle works great when n is
small in ( a + b )
                   n




The Binomial Theorem is better when n
is large. Let’s take a look at that now.
The Binomial Theorem
The Binomial Theorem

                  a, b ∈ ° ; n ∈ positive integers

          n     ⎛ n ⎞ n ⎛ n ⎞ n−1 ⎛ n ⎞ n−2 2  ⎛ n ⎞ n−1 ⎛ n ⎞ n
(a + b)       = ⎜ ⎟ a + ⎜ ⎟ a b + ⎜ ⎟ a b +K + ⎜      ⎟ ab + ⎜ n ⎟ b
                ⎝ 0 ⎠   ⎝ 1 ⎠     ⎝ 2 ⎠        ⎝ n − 1⎠      ⎝ ⎠
The Binomial Theorem

                  a, b ∈ ° ; n ∈ positive integers

          n     ⎛ n ⎞ n ⎛ n ⎞ n−1 ⎛ n ⎞ n−2 2  ⎛ n ⎞ n−1 ⎛ n ⎞ n
(a + b)       = ⎜ ⎟ a + ⎜ ⎟ a b + ⎜ ⎟ a b +K + ⎜      ⎟ ab + ⎜ n ⎟ b
                ⎝ 0 ⎠   ⎝ 1 ⎠     ⎝ 2 ⎠        ⎝ n − 1⎠      ⎝ ⎠


Let’s review combinations ... (next slide)
Combinations
           ⎛ n ⎞        n!
           ⎜ r ⎟ = r!( n − r )!
           ⎝ ⎠
Combinations
           ⎛ n ⎞        n!
           ⎜ r ⎟ = r!( n − r )!
           ⎝ ⎠

Example:   ⎛ 5 ⎞        5!
           ⎜ 2 ⎟ = 2!( 5 − 2 )!
           ⎝ ⎠
                    5 ⋅ 4 ⋅ 3⋅ 2 ⋅1
                =
                  ( 2 ⋅1)( 3⋅ 2 ⋅1)
                  5⋅4
                =
                   2
                = 10
Combinations
              ⎛ n ⎞        n!
              ⎜ r ⎟ = r!( n − r )!
              ⎝ ⎠

Example:      ⎛ 5 ⎞        5!
              ⎜ 2 ⎟ = 2!( 5 − 2 )!
              ⎝ ⎠
                       5 ⋅ 4 ⋅ 3⋅ 2 ⋅1
                   =
                     ( 2 ⋅1)( 3⋅ 2 ⋅1)
                     5⋅4
                   =
                      2
                   = 10
Let’s review how your calculator can do this ...
⎛ 5 ⎞
To do ⎜ ⎟ enter 5 nCr 2
      ⎝ 2 ⎠
⎛ 5 ⎞
To do ⎜ ⎟ enter 5 nCr 2
      ⎝ 2 ⎠

For all combinations, you can use your calculator.
In your work, just show the combination notation,
but not the nCr notation.
4
Use the Binomial Theorem to expand ( a + b )
4
Use the Binomial Theorem to expand ( a + b )

  ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4
  ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b
  ⎝ ⎠       ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠
4
Use the Binomial Theorem to expand ( a + b )

  ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4
  ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b
  ⎝ ⎠       ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠
               4       3        2 2         3     4
             a + 4a b + 6a b + 4ab + b
4
Use the Binomial Theorem to expand ( a + b )

  ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4
  ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b
  ⎝ ⎠       ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠
               4       3        2 2         3     4
             a + 4a b + 6a b + 4ab + b

                                                                      n
For more complex binomials, first expand ( a + b )
and then substitute in for a and b ... just like we
did with the Pascal’s Triangle method.
6
Use the Binomial Theorem to expand   (   x −2   )
6
 Use the Binomial Theorem to expand                             (   x −2   )
⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6
⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b
⎝ ⎠       ⎝ ⎠         ⎝ ⎠         ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠
6
 Use the Binomial Theorem to expand                             (   x −2   )
⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6
⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b
⎝ ⎠       ⎝ ⎠         ⎝ ⎠         ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠

                                  a= x        b = −2
6
 Use the Binomial Theorem to expand                             (   x −2   )
⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6
⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b
⎝ ⎠       ⎝ ⎠         ⎝ ⎠         ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠

                                  a= x            b = −2
         6         5                 4        2            3    3              2   4
   1 x + 6 x ( −2 ) + 15 x           ( −2 )       + 20 x ( −2 ) + 15 x ( −2 )
                            5          6
             +6     x ( −2 ) + 1( −2 )
6
 Use the Binomial Theorem to expand                             (   x −2    )
⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6
⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b
⎝ ⎠       ⎝ ⎠         ⎝ ⎠         ⎝ ⎠        ⎝ ⎠         ⎝ ⎠        ⎝ ⎠

                                    a= x          b = −2
         6         5                 4        2            3    3               2   4
   1 x + 6 x ( −2 ) + 15 x           ( −2 )       + 20 x ( −2 ) + 15 x ( −2 )
                            5          6
             +6     x ( −2 ) + 1( −2 )
                    5                         3                         1
        3                       2
      x − 12x + 60x − 160x + 240x − 192x + 64
                    2                         2                         2
HW #11

“I am a little pencil in the hand of a writing God who is
sending a love letter to the world.”
                                Mother Teresa

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1114 ch 11 day 14

  • 1. 11.6 The Binomial Theorem Matthew 7:7 "Ask, and it shall be given you; seek, and ye shall find; knock, and it shall be opened unto you."
  • 2. How do we expand ( a + b ) ? n
  • 3. How do we expand ( a + b ) ? n We will explore two methods:
  • 4. How do we expand ( a + b ) ? n We will explore two methods: 1) Using Pascal’s Triangle (a recursive method)
  • 5. How do we expand ( a + b ) ? n We will explore two methods: 1) Using Pascal’s Triangle (a recursive method) 2) Using the Binomial Theorem (an explicit method that uses combinatorics)
  • 7. Pascal’s Triangle Recall from last year ...
  • 8. Pascal’s Triangle Provides coefficients for expansion of a binomial
  • 9. Pascal’s Triangle Provides coefficients for expansion of a binomial 0 (a + b) = 1 1 (a + b) = 1a + 1b 2 2 2 (a + b) = 1a + 2ab + 1b 3 3 2 2 3 (a + b) = 1a + 3a b + 3ab + 1b 4 4 3 2 2 3 4 (a + b) = 1a + 4a b + 6a b + 4ab + 1b 5 5 4 3 2 2 3 4 5 (a + b) = 1a + 5a b + 10a b + 10a b + 5ab + 1b
  • 10. Pascal’s Triangle Provides coefficients for expansion of a binomial 0 (a + b) = 1 1 (a + b) = 1a + 1b 2 2 2 (a + b) = 1a + 2ab + 1b 3 3 2 2 3 (a + b) = 1a + 3a b + 3ab + 1b 4 4 3 2 2 3 4 (a + b) = 1a + 4a b + 6a b + 4ab + 1b 5 5 4 3 2 2 3 4 5 (a + b) = 1a + 5a b + 10a b + 10a b + 5ab + 1b Also notice the pattern of the exponents!
  • 11. Pascal’s Triangle Provides coefficients for expansion of a binomial 0 (a + b) = 1 1 (a + b) = 1a + 1b 2 2 2 (a + b) = 1a + 2ab + 1b 3 3 2 2 3 (a + b) = 1a + 3a b + 3ab + 1b 4 4 3 2 2 3 4 (a + b) = 1a + 4a b + 6a b + 4ab + 1b 5 5 4 3 2 2 3 4 5 (a + b) = 1a + 5a b + 10a b + 10a b + 5ab + 1b Also notice the pattern of the exponents! Let’s expand ( a + b ) . 6 (do on the board)
  • 12. Let’s expand ( 3 − xy ) 4
  • 13. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4
  • 14. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b
  • 15. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b Then substitute 3 for a and -xy for b
  • 16. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b Then substitute 3 for a and -xy for b 4 3 2 2 3 4 ( 3) + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy )
  • 17. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b Then substitute 3 for a and -xy for b 4 3 2 2 3 4 ( 3) + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy ) and simplify
  • 18. Let’s expand ( 3 − xy ) 4 First, write out ( a + b ) in expanded form. 4 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b Then substitute 3 for a and -xy for b 4 3 2 2 3 4 ( 3) + 4 ( 3) ( −xy ) + 6 ( 3) ( −xy ) + 4 ( 3) ( −xy ) + ( −xy ) and simplify 2 2 3 3 4 4 81− 108xy + 54x y − 12x y + x y
  • 19. Pascal’s Triangle works great when n is small in ( a + b ) n The Binomial Theorem is better when n is large. Let’s take a look at that now.
  • 21. The Binomial Theorem a, b ∈ ° ; n ∈ positive integers n ⎛ n ⎞ n ⎛ n ⎞ n−1 ⎛ n ⎞ n−2 2 ⎛ n ⎞ n−1 ⎛ n ⎞ n (a + b) = ⎜ ⎟ a + ⎜ ⎟ a b + ⎜ ⎟ a b +K + ⎜ ⎟ ab + ⎜ n ⎟ b ⎝ 0 ⎠ ⎝ 1 ⎠ ⎝ 2 ⎠ ⎝ n − 1⎠ ⎝ ⎠
  • 22. The Binomial Theorem a, b ∈ ° ; n ∈ positive integers n ⎛ n ⎞ n ⎛ n ⎞ n−1 ⎛ n ⎞ n−2 2 ⎛ n ⎞ n−1 ⎛ n ⎞ n (a + b) = ⎜ ⎟ a + ⎜ ⎟ a b + ⎜ ⎟ a b +K + ⎜ ⎟ ab + ⎜ n ⎟ b ⎝ 0 ⎠ ⎝ 1 ⎠ ⎝ 2 ⎠ ⎝ n − 1⎠ ⎝ ⎠ Let’s review combinations ... (next slide)
  • 23. Combinations ⎛ n ⎞ n! ⎜ r ⎟ = r!( n − r )! ⎝ ⎠
  • 24. Combinations ⎛ n ⎞ n! ⎜ r ⎟ = r!( n − r )! ⎝ ⎠ Example: ⎛ 5 ⎞ 5! ⎜ 2 ⎟ = 2!( 5 − 2 )! ⎝ ⎠ 5 ⋅ 4 ⋅ 3⋅ 2 ⋅1 = ( 2 ⋅1)( 3⋅ 2 ⋅1) 5⋅4 = 2 = 10
  • 25. Combinations ⎛ n ⎞ n! ⎜ r ⎟ = r!( n − r )! ⎝ ⎠ Example: ⎛ 5 ⎞ 5! ⎜ 2 ⎟ = 2!( 5 − 2 )! ⎝ ⎠ 5 ⋅ 4 ⋅ 3⋅ 2 ⋅1 = ( 2 ⋅1)( 3⋅ 2 ⋅1) 5⋅4 = 2 = 10 Let’s review how your calculator can do this ...
  • 26. ⎛ 5 ⎞ To do ⎜ ⎟ enter 5 nCr 2 ⎝ 2 ⎠
  • 27. ⎛ 5 ⎞ To do ⎜ ⎟ enter 5 nCr 2 ⎝ 2 ⎠ For all combinations, you can use your calculator. In your work, just show the combination notation, but not the nCr notation.
  • 28. 4 Use the Binomial Theorem to expand ( a + b )
  • 29. 4 Use the Binomial Theorem to expand ( a + b ) ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4 ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠
  • 30. 4 Use the Binomial Theorem to expand ( a + b ) ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4 ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b
  • 31. 4 Use the Binomial Theorem to expand ( a + b ) ⎛ 4 ⎞ 4 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 2 2 ⎛ 4 ⎞ 3 ⎛ 4 ⎞ 4 ⎜ 0 ⎟ a + ⎜ 1⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3 ⎟ ab + ⎜ 4 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ 4 3 2 2 3 4 a + 4a b + 6a b + 4ab + b n For more complex binomials, first expand ( a + b ) and then substitute in for a and b ... just like we did with the Pascal’s Triangle method.
  • 32. 6 Use the Binomial Theorem to expand ( x −2 )
  • 33. 6 Use the Binomial Theorem to expand ( x −2 ) ⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6 ⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠
  • 34. 6 Use the Binomial Theorem to expand ( x −2 ) ⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6 ⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ a= x b = −2
  • 35. 6 Use the Binomial Theorem to expand ( x −2 ) ⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6 ⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ a= x b = −2 6 5 4 2 3 3 2 4 1 x + 6 x ( −2 ) + 15 x ( −2 ) + 20 x ( −2 ) + 15 x ( −2 ) 5 6 +6 x ( −2 ) + 1( −2 )
  • 36. 6 Use the Binomial Theorem to expand ( x −2 ) ⎛ 6 ⎞ 6 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 4 2 ⎛ 6 ⎞ 3 3 ⎛ 6 ⎞ 2 4 ⎛ 6 ⎞ 5 ⎛ 6 ⎞ 6 ⎜ 0 ⎟ a + ⎜ 1 ⎟ a b + ⎜ 2 ⎟ a b + ⎜ 3⎟ a b + ⎜ 4 ⎟ a b + ⎜ 5 ⎟ ab + ⎜ 6 ⎟ b ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ a= x b = −2 6 5 4 2 3 3 2 4 1 x + 6 x ( −2 ) + 15 x ( −2 ) + 20 x ( −2 ) + 15 x ( −2 ) 5 6 +6 x ( −2 ) + 1( −2 ) 5 3 1 3 2 x − 12x + 60x − 160x + 240x − 192x + 64 2 2 2
  • 37. HW #11 “I am a little pencil in the hand of a writing God who is sending a love letter to the world.” Mother Teresa

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