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Using Equations in Solving Age Problem e-math  Elementary Algebra By: Karla Mae S. Glavez SPCP
[object Object]
[object Object]
[object Object],[object Object],[object Object]
example 1 ,[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object]
EQUATE:  Using the vsecong relationship: In 8 years, Alvin’s age is twice his son’s age, we have x + 29 = 2 ( x + 8) SOLVE:  Manipulating the equation, we have x + 29 = 2(x + 8) x + 29 = 2x + 16 x = 13 x + 29 x + 21 Alvin x + 8 x son FUTURE ( 8 YEARS FROM NOW) NOW
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Example 2 ,[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],50 - x 58 - x Patrick x - 8 x Mako Past ( 8 Years Ago) NOW
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Example 3 ,[object Object],[object Object],[object Object],[object Object],[object Object]
Half of Aries’ age 6 years ago was 3 les than one-half the sum of Rico’s age in 4 years and Jake’s present age: ½ (2x – 6) = ½ [(x + 4) + (2x – 24)] – 3   2x -6 = x + 4 + 2x – 24 -6   2x – 6 = 3x -26 x = 20 2x – 20  2x – 30  2x - 24  Jake  2x + 4  2x – 6  2x Aries  x + 4  x – 6  x Rico  Future ( Years From Now) Past (6 Years Ago) Now
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Example 4 ,[object Object],[object Object],[object Object],[object Object],[object Object]
Mother will be twice as old as her eldest daughter: 40 + x = 2(12 + x ) 40 + x = 24 + 2x Proof: Mother’s age in 16 years:   40 + 16 = 56 Daughter’s age in 16 years:  12 + 16 = 28   56 = 2 (28) 56 = 56 12 + x  12 Daughter 40 + x  40 Mother FUTURE ( X YEARS FROM NOW)  Now
EXERCISES: 1.)  Mercy is 17 years old now. Represent her age – a. 2 years from now c. x years from now e. x + 7 years hence b. 3 years ago d. 2x years ago 2.)  Melchor is  m  years old now. Represent his age – a. 15 years from now  c. a years ago e. 5x years from now b. 11 years ago d. n + 5 years ago 3.)  Mr. Matthew Matics is y + 5 years old now. Represent his age – a. 3 years ago d. 5y years from now b. 8 years from now e. 3y – 5 years from now c. 2y + 3 years ago 4.)  In 4 years, Mr5. Parabola will be 17 years old. Represent his age – a. now c. 6 years from now e. a – 3 from now b. 8 years ago d. x years ago
5.)  Arielle will be 57 years old p years from now. Represent her age – a. now c. 4 years from now e.  m  years ago b. 3 years ago d.  m  years from now 6.)  Five years ago, Edwin was 27 years old. Represent his age – a. at present c. 5 years from now e.  q  years from now b. 3 years from now d.  q  years ago 7.)  P years ago, Mr. Reyes was Q years old. Represent his age – a. at present c. 5 years ago e.  P  + 4 years ago b. 2 years from now d.  R  years from now
ANSWERS ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Solve each of the following ,[object Object]
 

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Algebra "Age Problem"

  • 1. Using Equations in Solving Age Problem e-math Elementary Algebra By: Karla Mae S. Glavez SPCP
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7. EQUATE: Using the vsecong relationship: In 8 years, Alvin’s age is twice his son’s age, we have x + 29 = 2 ( x + 8) SOLVE: Manipulating the equation, we have x + 29 = 2(x + 8) x + 29 = 2x + 16 x = 13 x + 29 x + 21 Alvin x + 8 x son FUTURE ( 8 YEARS FROM NOW) NOW
  • 8.
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14. Half of Aries’ age 6 years ago was 3 les than one-half the sum of Rico’s age in 4 years and Jake’s present age: ½ (2x – 6) = ½ [(x + 4) + (2x – 24)] – 3 2x -6 = x + 4 + 2x – 24 -6 2x – 6 = 3x -26 x = 20 2x – 20 2x – 30 2x - 24 Jake 2x + 4 2x – 6 2x Aries x + 4 x – 6 x Rico Future ( Years From Now) Past (6 Years Ago) Now
  • 15.
  • 16.
  • 17. Mother will be twice as old as her eldest daughter: 40 + x = 2(12 + x ) 40 + x = 24 + 2x Proof: Mother’s age in 16 years: 40 + 16 = 56 Daughter’s age in 16 years: 12 + 16 = 28 56 = 2 (28) 56 = 56 12 + x 12 Daughter 40 + x 40 Mother FUTURE ( X YEARS FROM NOW) Now
  • 18. EXERCISES: 1.) Mercy is 17 years old now. Represent her age – a. 2 years from now c. x years from now e. x + 7 years hence b. 3 years ago d. 2x years ago 2.) Melchor is m years old now. Represent his age – a. 15 years from now c. a years ago e. 5x years from now b. 11 years ago d. n + 5 years ago 3.) Mr. Matthew Matics is y + 5 years old now. Represent his age – a. 3 years ago d. 5y years from now b. 8 years from now e. 3y – 5 years from now c. 2y + 3 years ago 4.) In 4 years, Mr5. Parabola will be 17 years old. Represent his age – a. now c. 6 years from now e. a – 3 from now b. 8 years ago d. x years ago
  • 19. 5.) Arielle will be 57 years old p years from now. Represent her age – a. now c. 4 years from now e. m years ago b. 3 years ago d. m years from now 6.) Five years ago, Edwin was 27 years old. Represent his age – a. at present c. 5 years from now e. q years from now b. 3 years from now d. q years ago 7.) P years ago, Mr. Reyes was Q years old. Represent his age – a. at present c. 5 years ago e. P + 4 years ago b. 2 years from now d. R years from now
  • 20.
  • 21.
  • 22.