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2. DIODE LOGIC CIRCUITS
        The switch in a logic circuit can be implemented with an electromagnetic relay. However, a
relay is not a fast acting device. Therefore, it is not suitable for high-speed switching action. We
use electronic devices for high-speed switching. The simplest of all electronic devices is the diode.
It operates in one of the two states depending upon the voltage drop across it. An ideal diode acts
as a short circuit (closed switch) when it is forward biased. A reverse biased diode acts as an open
circuit (open switch).
                          A
                                                                   C
                          B


                                                           R




Figure 2.1: A two-diode OR gate


                                    2.1     A Two-Diode OR Gate
        A simplest possible two-diode OR circuit is shown in Figure 2.1. In our discussion, let us
model the diode by an ideal diode in series with a forward voltage drop of 0.7 V. When both the
inputs A and B are zero and the supply voltage is also zero, then the output is also zero and
neither diode is conducting. All possible outcomes for the two-diode OR logic are given below
when the low value of either input is zero and high value is 5 V. Instead of grounding the one end
of the resistor, it could have also been connected to a negative supply as well.


                      Voltages, V             Corresponding                truth table
                 A        B         C                                  A       B         C
                 0        0         0                                  0       0         0
                 0        5         4.3                                0       1         1
                 5        0         4.3                                1       0         1
                 5        5         4.3                                1       1         1

        The truth table is based upon the understanding that the output voltage is considered high
[1] as long as it is at least 4.3 V and low [0] whenever it is less than or equal to 0.7 V.



Guru/LGCkts/DiodeLogic/ March 20, 2006              8                                         Logic Circuits
2.2 A Two-Diode AND Gate
        A two-diode AND gate is shown in Figure 2.2. In this case, let us assume that + VD = + 5
V. The minimum value of each signal is zero and the maximum value is 5 V. Let us assume that
the input signal A is high (5 V) and B is low (0 V). The current can now flow from the 5-V supply
through R and the diode D2. Thus, the output voltage is 0.7 V assuming that the diode voltage drop
is 0.7 V. Likewise the output voltage would also be 0.7 V when A is low and B is high. The current
in the circuit will now complete its path through D1. When both inputs are set at their low values and
the two diodes are identical, the current will divide equally between the two diodes and the output
voltage will be 0.7 V. The output voltage would be 5 V only when both input signals are set at their
high values (5 V). These are the traits of an AND gate and the entire logic is tabulated below.
                                                              + VD = 5 V



                                                                     R
                                                       D1

                                     A                                            C

                                                       D2

                                      B

                                     Figure 2.2: A Diode AND Gate


                      Voltages, V            Corresponding               truth table
                 A        B          C                               A        B        C
                 0        0          0.7                             0        0        0
                 0        5          0.7                             0        1        1
                 5        0          0.7                             1        0        1
                 5        5          5                               1        1        1

        In this case, the truth table is based upon the fact that the output voltage is zero [0] when it
is less than or equal to 0.7 V. Once again, when the output voltage is greater than or equal to 4.3
V, the output voltage is high [1].




Guru/LGCkts/DiodeLogic/ March 20, 2006             9                                        Logic Circuits
2.3 Diode Logic For the Special Distributive Law
        Let us develop the diode circuit for the special distributive law
                          (A + B) (A + C) = A + B C
        Figure 2.3 shows the diode logic circuit based upon the left-hand side of the above
equation. This circuit employs two OR circuits; one for A+B and the other for A+C. The output of
these OR circuits is the input to the AND circuit. The output F of the AND circuit provides us the
desired logic. The truth table is given on Page-7. Let us check for one of the condition in the truth
table to illustrate the technique.
        Let us assume that the minimum voltage of each signal is zero and the maximum is 5 V.
Let us select the condition when A = 0, B = 5 V and C = 0. The expected output should be low. Let
us assume that each diode has a forward voltage drop of 0.7 V when it is conducting.


                                                                               +5V
                                          D1
                                                                D5
                                                       D

                             B                             R
                                          D2                                       R
                 A
                                                                                          F
                                          D3       -5V
                                                       E
                             C
                                                               D6
                                                           R
                                         D4



                                                  -5V
                          Figure 2.3: Diode logic for (A + B) (A + C)


        Since A = 0 and C = 0, D3 and D4 are ON and the voltage level at E is – 0.7 V. Since B =
5 V, the voltage level at D is 4.3 V. Thus, D2 is ON and D1 is OFF. Since the voltage at E is lower
than that at D, D6 is ON; D5 is OFF; and the voltage level at F is 0 V. You can select another
condition from the truth table and verify the outcome.




Guru/LGCkts/DiodeLogic/ March 20, 2006            10                                       Logic Circuits

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Diode logic crkts

  • 1. 2. DIODE LOGIC CIRCUITS The switch in a logic circuit can be implemented with an electromagnetic relay. However, a relay is not a fast acting device. Therefore, it is not suitable for high-speed switching action. We use electronic devices for high-speed switching. The simplest of all electronic devices is the diode. It operates in one of the two states depending upon the voltage drop across it. An ideal diode acts as a short circuit (closed switch) when it is forward biased. A reverse biased diode acts as an open circuit (open switch). A C B R Figure 2.1: A two-diode OR gate 2.1 A Two-Diode OR Gate A simplest possible two-diode OR circuit is shown in Figure 2.1. In our discussion, let us model the diode by an ideal diode in series with a forward voltage drop of 0.7 V. When both the inputs A and B are zero and the supply voltage is also zero, then the output is also zero and neither diode is conducting. All possible outcomes for the two-diode OR logic are given below when the low value of either input is zero and high value is 5 V. Instead of grounding the one end of the resistor, it could have also been connected to a negative supply as well. Voltages, V Corresponding truth table A B C A B C 0 0 0 0 0 0 0 5 4.3 0 1 1 5 0 4.3 1 0 1 5 5 4.3 1 1 1 The truth table is based upon the understanding that the output voltage is considered high [1] as long as it is at least 4.3 V and low [0] whenever it is less than or equal to 0.7 V. Guru/LGCkts/DiodeLogic/ March 20, 2006 8 Logic Circuits
  • 2. 2.2 A Two-Diode AND Gate A two-diode AND gate is shown in Figure 2.2. In this case, let us assume that + VD = + 5 V. The minimum value of each signal is zero and the maximum value is 5 V. Let us assume that the input signal A is high (5 V) and B is low (0 V). The current can now flow from the 5-V supply through R and the diode D2. Thus, the output voltage is 0.7 V assuming that the diode voltage drop is 0.7 V. Likewise the output voltage would also be 0.7 V when A is low and B is high. The current in the circuit will now complete its path through D1. When both inputs are set at their low values and the two diodes are identical, the current will divide equally between the two diodes and the output voltage will be 0.7 V. The output voltage would be 5 V only when both input signals are set at their high values (5 V). These are the traits of an AND gate and the entire logic is tabulated below. + VD = 5 V R D1 A C D2 B Figure 2.2: A Diode AND Gate Voltages, V Corresponding truth table A B C A B C 0 0 0.7 0 0 0 0 5 0.7 0 1 1 5 0 0.7 1 0 1 5 5 5 1 1 1 In this case, the truth table is based upon the fact that the output voltage is zero [0] when it is less than or equal to 0.7 V. Once again, when the output voltage is greater than or equal to 4.3 V, the output voltage is high [1]. Guru/LGCkts/DiodeLogic/ March 20, 2006 9 Logic Circuits
  • 3. 2.3 Diode Logic For the Special Distributive Law Let us develop the diode circuit for the special distributive law (A + B) (A + C) = A + B C Figure 2.3 shows the diode logic circuit based upon the left-hand side of the above equation. This circuit employs two OR circuits; one for A+B and the other for A+C. The output of these OR circuits is the input to the AND circuit. The output F of the AND circuit provides us the desired logic. The truth table is given on Page-7. Let us check for one of the condition in the truth table to illustrate the technique. Let us assume that the minimum voltage of each signal is zero and the maximum is 5 V. Let us select the condition when A = 0, B = 5 V and C = 0. The expected output should be low. Let us assume that each diode has a forward voltage drop of 0.7 V when it is conducting. +5V D1 D5 D B R D2 R A F D3 -5V E C D6 R D4 -5V Figure 2.3: Diode logic for (A + B) (A + C) Since A = 0 and C = 0, D3 and D4 are ON and the voltage level at E is – 0.7 V. Since B = 5 V, the voltage level at D is 4.3 V. Thus, D2 is ON and D1 is OFF. Since the voltage at E is lower than that at D, D6 is ON; D5 is OFF; and the voltage level at F is 0 V. You can select another condition from the truth table and verify the outcome. Guru/LGCkts/DiodeLogic/ March 20, 2006 10 Logic Circuits