1. Chapter 9 Spring 2009

4. Step 1: The longest carbon chain above is 5 carbons long, therefore, the base name of the molecule is pentanol. Step 2: The molecule should be numbered from right to left, placing the –OH group on C2, and the methyl groups on C3 and C4. The name is thus, 3,4-dimethyl-2-pentanol .

5. Naming cyclic alcohols The –OH group is assigned the C1 position. The second substituent then gets the lowest number. The name of the compound is 3-isopropyl-cyclopentanol

7. 4-ethyl-3-isopropyl-2-heptanol 2-ethyl-5,5-dimethylcyclohexanol

8. When an alcohol is a substituent

9. When an alcohol is a substituent 3-(2-hydroxyethyl)cyclohexanol

11. Common alkoxy groups

12. 1. Name the longer chain as the alkane and the shorter chain as the alkoxy group Above the longest chain is a hexane. Longest chain 2. Use IUPAC rules to finish the name. The substituent should have the smallest number possible. Thus, number from right to left. 3-methoxyhexane methoxy

14. 2-methyl-1-ethoxycyclopentane 1-butoxy-2,2-dimethylhexane

15. Cyclic ethers

16. Naming epoxides This is oxirane – the simplest epoxide These are named as substituted oxiranes 1,2-dimethyloxirane 1,1-dimethyloxirane To name an epoxide as a substituent, it is called an epoxy. This is then 1,2-epoxycyclohexane

17. Preparation of alcohols and ethers

19. Draw the product of the following two-step sequence [1] In the first step the base NaH removes the proton from the alcohol [2] In the second step of the process the alkoxide acts as a nucleophile displacing the leaving group in an S N 2 reaction

20. Preparation of epoxides Starting reagent is a halohydrin Two-step process:

24. Recall the Mechanism for an E1 Reaction Again, this the kinetically and thermodynamically favored route

25. Provide the mechanism for the less favored route.

26. Provide the mechanism for the less favored route.

27. Also remember, 1° alcohols will react via an E2 mechanism

29. Think of the possibilities A 1,2-methyl shift occurs during the dehydration of this compound A 1,2-hydride shift occurs during the dehydration of this compound

30. Used curved arrows to show the methyl shift when 3,3-dimethyl-2-butanol is treated with sulfuric acid. Used curved arrows to show the hydride shift when 3-methyl-2-butanol is treated with sulfuric acid.

33. Sometimes it is necessary to use a little more finesse in order to do a dehydration reaction with an alcohol. Reaction conditions

36. 1° alcohols will react via an S N 2 mechanism

37. 2° and 3 ° alcohols will react via an S N 1 mechanism

38. Cl - is the poorest of the halide nucleophiles, and thus, needs help

39. Let’s not forget stereochemistry

41. Predict the product(s)

45. Can be used for all HI ROH  RI Best for CH 3 OH and 1° and 2° alcohols PBr 3 + pyridine ROH  RCBr Can be used for all HBr ROH  RCBr Best for CH 3 OH and 1° and 2° alcohols SOCl 2 + pyridine ROH  RCl Can be used for all HCl ROH  RCl Usefullness reagent reaction

47. Mechanism:

51. Mechanism

53. Use curved arrows to indicate the mechanism.

55. In an unsymmetrical epoxide, the nucleophile attacks at the less substituted carbon atom.

56. Reactions with acids – HX The nucleophile adds here to the more substituted carbon because it is more able to accept a partial positive charge.