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K. Ramya et al Int. Journal of Engineering Research and Applications
ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

RESEARCH ARTICLE

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OPEN ACCESS

A Study on Two-Phase Service Queueing System with Server
Vacations
S.Palaniammal1, C. Vijayalakshmi2 and K. Ramya3
1

Department of Mathematics, Sri Krishna College of Engineering, Coimbatore, India
Department of Mathematics, VIT University, Chennai India
3
Department of Mathematics, Kingston Engineering College, Vellore
2

Abstract
This paper mainly deals with the analysis of queueing system in which customers require services in two stages
are common. Two-phase queueing systems are gaining importance due to their wide variety of applications.
Batch mode service in the first phase followed by individual service in the second phase. Because of the mixed
mode of services, these kinds of two phase queues do not fit into the usual network of queues as a particular
case. The need for this kind of modeling has been greatly discussed in this paper
Keywords: Sojourn time, busy cycle, service cycle, idle time, service time, system size

I.

Introduction

Krishna and Lee (1990) have studied a two phase Markovian queueing system. Customers arrive
according to poisson process and service times are exponentially distributed. Doshi (1991) has generalized the
model studied in Krishna and Lee (1990). In this, the service times in both the first and second phases are
assumed to follow general distributions. Madan(2001 ) studied two similar types of vacation models for
M/G/1 Queueing system. Shahkar and Badamchi (2008) have studied the two phase queueing system with
Bernoulli server vacation .Gautam Choudhury (2011) has generalized the model with delaying repair . JauChuan Ke and Wen Lea Pearn (2011) have studied the analysis of the multi-server system with a modified
Bernoulli vacation schedule.

II.

Methodology

A queueing system with two phase service, customers arrive at the system according to a poisson
process with arrival rate . In the first phase, the server operates on an exhaustive batch mod service in waiting
customers and the arrivals which occur during the batch service. Thus, this batch consists of the waiting
customers at the commencement of the batch service and also those customers who arrive at the system during
the batch service on completion of the batch mode service, the same server takes the entire batch of customers to
the second phase for individual service following. First in first out queue discipline. The customers who arrive
while the server is busy in the second phase, wait in a queue at the first phase for the next batch mode service.
After completing the second phase of individual services exhaustively to the batch, the server returns to the first
phase to start the next batch mode service. If some customers are present at the first phase, he/she starts the
batch mode service immediately. On the other hand if the queue is empty, he/she immediately leaves for a
vacation of random duration and returns to the system at the end of the vacation. If there is at least one
customer waiting in the first phase, he/she immediately starts a batch service, but if the system is empty, he
takes the next vacation and so on.

III.

Model Description

Batch service times are independent and identically distributed random variables following an arbitrary
function B(t), t > 0 and the individual service times are i.i.d. with an arbitrary distribution function F(t), t > 0
and vacation times are i.i.d. according to an arbitrary distribution function V(t), t > 0.
Let the random variables B, S and V denoted batch service times, individual service times and vacation
times respectively. Assume that the system is in steady state and
 =  E(S) < 1
 =  E(B)

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K. Ramya et al Int. Journal of Engineering Research and Applications
ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

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3.1 Busy Cycle
The time interval from the commencement of the batch service at the end of a vacation to the
commencement of the next batch service after availing at least one vacation is a busy cycle.
3.2 Service Cycle
The time interval between two consecutive batch services without any vacation is a service cycle.
Notations
N
 system size at the beginning of a batch service
N1
 system size at the end of the batch service
N2
 system size at the end of individual services to the customers of the batch service
X
 number of customers arrivals during a batch service
Y
 number of customers arrivals  1 during a vacation
P20
 P (the system is empty at the end of the second phase
The random variables N, N1, N2, X and Y are interrelated.
N1 = N + X
N2 = number of customers arrivals during the N1 individual services

N if N 2  0
N 2
Y if N 2  0
Probability generating function of B(t), F(t) and V(t)


B( θ)   e θ t dB(t)
0


F( θ)   e θ t dF(t)
0



V( θ)   e θ t dV(t)
0

aK = P{K poisson arrivals during a time interval having a function A(t)}


e  λ t (λ t) K
dA(t)
K!
0





e  λ t (λ t) K
E(z )   z 
dA(t)
K!
k 0
0


K

K





(λ zt) K
dA(t)
K!
k 0

  e λ t 
0



  e λ t e λ tz dA(t)
0


  e λ t  λ tz dA(t)
0


  e  t(λ λ z) dA(t)
0

 A(λ  λ z)

(1)

where A(0) is the LST of A(t).

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K. Ramya et al Int. Journal of Engineering Research and Applications
ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

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a 0  P (No arrival)
 A(λ )
*
1

*
2

P*(z), P (z) and P (z) denote the PGF’s of N, N1 and N2 respectively.

P1* (z)  E(z N1 )
 E(z NX )
 E(z N .zX )
 E(z N ).E(zX ).
arrival and service are independent

 P* (z) B(λ  λ z)

(2)

Let Xi denote the number of arrivals during the i-th individual service for i = 1, 2, 3, …, N.
*
P2 (z)  E(z N2 )

 E[E(z N2 /N1  K)]


  E(z X1 X2 XK )P(N1  K)
k 1


  (E(zX1 ))K P(N1  K)
k 1

since X i are independent



  (F(λ  λ z))K P(N1  K)
k 1

 P (F(λ  λ z))
*
1

(3)

Since Y denote the number of customer arrivals  1 during a vacation.


P(Y  k)   {(P(Y  k / k customersarrive during the i th vacation)}
i 1


  b i01b k
i 1



bk
1  b0



bk
1  V(λ)
P* (z)  E(z N )


  z k P(N  k)
k 1

But P(N = k) = P(N2 = k) with proba 1 when N 2 > 0
= P(Y = k) with proba P20 when N2 = 0




k 1

k 1

P* (z)   z k P(N2  k)  P20  z k P(Y  k)
 (P(z)  P20 ) 
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P20 (V(λ  λ z)  V(λ)
1  V(λ)
225 | P a g e
K. Ramya et al Int. Journal of Engineering Research and Applications
ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

1  V(λ  λ z)  V(λ) 
*
 P2 (z)  P20 

1  V(λ)



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(4)

Combine (2), (3) and (4) we get

 (V(λ  λ z)  V(λ) 
P* (z)  P* (F(λ  λ z)B(λ  λF(λ  λ z))  P20 1 

1  V(λ)



(5)

Let

g (0) (z)  z
g (1) (z)  g(z)
 F(λ  λ z)

g n (z)  g(gn 1 (z))
 g n 1 (g(z))

n 1

h (z)  h(z)
(1)

 B(λ  λ z)
(V(λ  λ z)  V(λ ))
L(z)  1 
1  V(λ )
For  < 1, z = 1 is the unique solution of the equation z  F(λ  λ z) inside the region |z|  1. g(n)(z)
approaches
z
=
1
as
n


and
L(g(n)(z))
approaches
L(1)
=
0
using

V(λ  λ z)  V(0) = 1.
The quantity P20 can be obtained from the equation (5).

P (z)  P * (g (1) (z))h(g (1) (z))  P20 L(z)
*



 k

P* (z)   h(g(1) (z))  P20   h(g(1) (z))L(g(k) (z))
k 0  i 1
i 1


Since the number of customers at the beginning of a batch service is strictly positive.

P* (0)  P(N  0)  0
P * (F(λ ) B(λ  λ F(λ ))  P20  0
Since g(0)  F( λ)

P20  P* (F(λ) B(λ  λ F(λ))
 P* (g(0) B(λ  λF(λ))
 h(g(0))P* (g(0))



 k

 h(g(0)) h(gi1 (0))  P20   h(gi1 (0) L(gk 1 (0))
k 0  i 1

 i1


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K. Ramya et al Int. Journal of Engineering Research and Applications
ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

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

P20 

h(g(0)) h(gi1 (0))
i 1



1  h(g(0))  h(gi1 (0) L(g k 1 (0))
k 0  i 1



k

 h(g

(i)





i 1



(0))
k 1

1   L(g k 1 (0)) h(gk 1 (0)
k 0

i 1

3.3 The Probability Generating Function of System Size
Let M denote the system size when a random customer leaves the system after his service completion
and M*(z) be the PGF of M.
Let N1 = n1 and K = k where n1 is the size of the batch to which the random customer belongs and k is
his position in that batch, then by using length biased sampling technique

1
P(K  k/N1  n1 )    n1P(N1  n1 )/E(N1 )
n 
 1
 P(N1  n1 )/E(N1 )
The number of customers in the system when a random customer departs is the sum of (n1  k)
customers in the batch and the number of new arrivals that occur during the K service completions.

E(N 1 )  [γ (1  V(λ )  P20 λ E(V)]/(1  ρ)(1  V(λ )]
V(t) = 1, t > 0 when the server does not take any vacation.
B(t) = 1, t > 0 there is no batch service.
Mean and Variance

P20 E(V2 )
λ E(s2 ) E(B2 ) E 2 (B) E(B)
E(w s )  E(S) 



1 ρ 2
2E(N1 ) E(N1 )
λ 2(1  V(λ)E(N1 )
2
2
Var(w s )  E(w s )  (E(w s )) .
3.4 Server Utilization
Let T1 and T2 denote the durations of time the server is busy in the system. Let T1 (θ ) and T2 (θ )
denote the LSTs of T1 and T2 respectively.


T1 (θ)   [B(θ)P1* (F(θ))] r (1  P20 ) r 1 P20
r 1



T2 (θ)   (V(θ)) r (V(λ )) r (1  V(λ ))
r 1

[E(B)  E(N 1 )E(s)]
P20
E(V)
E(T 2 ) 
1  V(λ )

E(T1 ) 

The long run proportion is given by

u

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E(T1 )
E(T1 )  E(T 2 )

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ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

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 E(B)  E(N1 )E(s) 




P20


u
E(B)  E(N1 )E(s)
E(V)

P20
1  V(λ)


P20 (1  V(λ))
E(B)  E(N1 )E(s)

(1  V(λ))  P20 E(V)
P20
(E(B)  E(N1 )E(s))
(E(B)  E(N 1 )E(s))(1  V(λ ))
u
(E(B)  E(N 1 )E(s))(1  V(λ ))  P20 E (V )
IV.

Table

Case (i)  = 5, E(B) = 1/15

1
E(V)

E(ws)

5
4
3
2
1

0.56
0.58
0.6
0.71
1.18

Case (ii)  = 5, E(B) = 1/10

1
E(V)

E(ws)

5
4
3
2
1

0.58
0.59
0.61
0.72
1.18

Case (iii)  = 5, E(B) = 1/2

1
E(V)

E(ws)

5
4
3
2
1

1.41
1.4
1.31
1.3
1.3

Graph
=5

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ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230

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4
3.5
3

E(ws)

2.5

Series3

2

Series2
Series1

1.5
1
0.5
0
1

2

3

4

5

1/E(V)

From the above graph indicates the mean system time decreases with the decrease in the mean vacation time .

V.

Conclusion

In this paper we studied the vacation model of a queuing system in which customers are served in two
phases. Server vacations are introduced to utilize the idle time of the server so that idle times are used to
perform some useful jobs other than the service to the customers in the system . In fact , such jobs may even
include a simple break for taking some rest in serving in some other queue. The study of vacation models of
queuing systems help the effects of server vacations on the system performance .

References
[1]
[2]

[3]
[4]

[5]

[6]
[7]

[8]
[9]
[10]
[11]

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Choudhury, Gautam / Deka, Mitali,: A single server queuing system with two phases of service subject
to server breakdown and Bernoulli vacation: Applied Mathematical Modelling, In Press, Corrected
Proof,Feb 2012
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time under Bernoulli schedule. Applied Mathematics and Computation, 149 (2), p.337-349, Feb 200
Choudhury, Gautam / Tadj, Lotfi / Deka, Kandarpa,: A batch arrival retrial queueing system with two
phases of service and service interruption. Computers & Mathematics with Applications, 59 (1), p.437450,Jan 2010
Choudhury, Gautam / Tadj, Lotfi,: An M / G /1 queue with two phases of service subject to
the serverbreakdown and delayed repair. Applied Mathematical Modelling, 33 (6), p.2699-2709, Jun
2009
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schedule. Applied Mathematics and Computation, 188 (2), p.1455-1466, May 2007
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Cooper, Robert B.: Chapter 10 Queueing theory. Handbooks in Operations Research and Management
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Ah4201223230

  • 1. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 RESEARCH ARTICLE www.ijera.com OPEN ACCESS A Study on Two-Phase Service Queueing System with Server Vacations S.Palaniammal1, C. Vijayalakshmi2 and K. Ramya3 1 Department of Mathematics, Sri Krishna College of Engineering, Coimbatore, India Department of Mathematics, VIT University, Chennai India 3 Department of Mathematics, Kingston Engineering College, Vellore 2 Abstract This paper mainly deals with the analysis of queueing system in which customers require services in two stages are common. Two-phase queueing systems are gaining importance due to their wide variety of applications. Batch mode service in the first phase followed by individual service in the second phase. Because of the mixed mode of services, these kinds of two phase queues do not fit into the usual network of queues as a particular case. The need for this kind of modeling has been greatly discussed in this paper Keywords: Sojourn time, busy cycle, service cycle, idle time, service time, system size I. Introduction Krishna and Lee (1990) have studied a two phase Markovian queueing system. Customers arrive according to poisson process and service times are exponentially distributed. Doshi (1991) has generalized the model studied in Krishna and Lee (1990). In this, the service times in both the first and second phases are assumed to follow general distributions. Madan(2001 ) studied two similar types of vacation models for M/G/1 Queueing system. Shahkar and Badamchi (2008) have studied the two phase queueing system with Bernoulli server vacation .Gautam Choudhury (2011) has generalized the model with delaying repair . JauChuan Ke and Wen Lea Pearn (2011) have studied the analysis of the multi-server system with a modified Bernoulli vacation schedule. II. Methodology A queueing system with two phase service, customers arrive at the system according to a poisson process with arrival rate . In the first phase, the server operates on an exhaustive batch mod service in waiting customers and the arrivals which occur during the batch service. Thus, this batch consists of the waiting customers at the commencement of the batch service and also those customers who arrive at the system during the batch service on completion of the batch mode service, the same server takes the entire batch of customers to the second phase for individual service following. First in first out queue discipline. The customers who arrive while the server is busy in the second phase, wait in a queue at the first phase for the next batch mode service. After completing the second phase of individual services exhaustively to the batch, the server returns to the first phase to start the next batch mode service. If some customers are present at the first phase, he/she starts the batch mode service immediately. On the other hand if the queue is empty, he/she immediately leaves for a vacation of random duration and returns to the system at the end of the vacation. If there is at least one customer waiting in the first phase, he/she immediately starts a batch service, but if the system is empty, he takes the next vacation and so on. III. Model Description Batch service times are independent and identically distributed random variables following an arbitrary function B(t), t > 0 and the individual service times are i.i.d. with an arbitrary distribution function F(t), t > 0 and vacation times are i.i.d. according to an arbitrary distribution function V(t), t > 0. Let the random variables B, S and V denoted batch service times, individual service times and vacation times respectively. Assume that the system is in steady state and  =  E(S) < 1  =  E(B) www.ijera.com 223 | P a g e
  • 2. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 www.ijera.com 3.1 Busy Cycle The time interval from the commencement of the batch service at the end of a vacation to the commencement of the next batch service after availing at least one vacation is a busy cycle. 3.2 Service Cycle The time interval between two consecutive batch services without any vacation is a service cycle. Notations N  system size at the beginning of a batch service N1  system size at the end of the batch service N2  system size at the end of individual services to the customers of the batch service X  number of customers arrivals during a batch service Y  number of customers arrivals  1 during a vacation P20  P (the system is empty at the end of the second phase The random variables N, N1, N2, X and Y are interrelated. N1 = N + X N2 = number of customers arrivals during the N1 individual services N if N 2  0 N 2 Y if N 2  0 Probability generating function of B(t), F(t) and V(t)  B( θ)   e θ t dB(t) 0  F( θ)   e θ t dF(t) 0  V( θ)   e θ t dV(t) 0 aK = P{K poisson arrivals during a time interval having a function A(t)}  e  λ t (λ t) K dA(t) K! 0   e  λ t (λ t) K E(z )   z  dA(t) K! k 0 0  K K   (λ zt) K dA(t) K! k 0   e λ t  0    e λ t e λ tz dA(t) 0    e λ t  λ tz dA(t) 0    e  t(λ λ z) dA(t) 0  A(λ  λ z) (1) where A(0) is the LST of A(t). www.ijera.com 224 | P a g e
  • 3. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 www.ijera.com a 0  P (No arrival)  A(λ ) * 1 * 2 P*(z), P (z) and P (z) denote the PGF’s of N, N1 and N2 respectively. P1* (z)  E(z N1 )  E(z NX )  E(z N .zX )  E(z N ).E(zX ). arrival and service are independent  P* (z) B(λ  λ z) (2) Let Xi denote the number of arrivals during the i-th individual service for i = 1, 2, 3, …, N. * P2 (z)  E(z N2 )  E[E(z N2 /N1  K)]    E(z X1 X2 XK )P(N1  K) k 1    (E(zX1 ))K P(N1  K) k 1 since X i are independent    (F(λ  λ z))K P(N1  K) k 1  P (F(λ  λ z)) * 1 (3) Since Y denote the number of customer arrivals  1 during a vacation.  P(Y  k)   {(P(Y  k / k customersarrive during the i th vacation)} i 1    b i01b k i 1  bk 1  b0  bk 1  V(λ) P* (z)  E(z N )    z k P(N  k) k 1 But P(N = k) = P(N2 = k) with proba 1 when N 2 > 0 = P(Y = k) with proba P20 when N2 = 0   k 1 k 1 P* (z)   z k P(N2  k)  P20  z k P(Y  k)  (P(z)  P20 )  www.ijera.com P20 (V(λ  λ z)  V(λ) 1  V(λ) 225 | P a g e
  • 4. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 1  V(λ  λ z)  V(λ)  *  P2 (z)  P20   1  V(λ)   www.ijera.com (4) Combine (2), (3) and (4) we get  (V(λ  λ z)  V(λ)  P* (z)  P* (F(λ  λ z)B(λ  λF(λ  λ z))  P20 1   1  V(λ)   (5) Let g (0) (z)  z g (1) (z)  g(z)  F(λ  λ z)  g n (z)  g(gn 1 (z))  g n 1 (g(z)) n 1 h (z)  h(z) (1)  B(λ  λ z) (V(λ  λ z)  V(λ )) L(z)  1  1  V(λ ) For  < 1, z = 1 is the unique solution of the equation z  F(λ  λ z) inside the region |z|  1. g(n)(z) approaches z = 1 as n   and L(g(n)(z)) approaches L(1) = 0 using V(λ  λ z)  V(0) = 1. The quantity P20 can be obtained from the equation (5). P (z)  P * (g (1) (z))h(g (1) (z))  P20 L(z) *    k  P* (z)   h(g(1) (z))  P20   h(g(1) (z))L(g(k) (z)) k 0  i 1 i 1  Since the number of customers at the beginning of a batch service is strictly positive. P* (0)  P(N  0)  0 P * (F(λ ) B(λ  λ F(λ ))  P20  0 Since g(0)  F( λ) P20  P* (F(λ) B(λ  λ F(λ))  P* (g(0) B(λ  λF(λ))  h(g(0))P* (g(0))     k   h(g(0)) h(gi1 (0))  P20   h(gi1 (0) L(gk 1 (0)) k 0  i 1   i1  www.ijera.com 226 | P a g e
  • 5. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 www.ijera.com  P20  h(g(0)) h(gi1 (0)) i 1   1  h(g(0))  h(gi1 (0) L(g k 1 (0)) k 0  i 1   k  h(g (i)   i 1  (0)) k 1 1   L(g k 1 (0)) h(gk 1 (0) k 0 i 1 3.3 The Probability Generating Function of System Size Let M denote the system size when a random customer leaves the system after his service completion and M*(z) be the PGF of M. Let N1 = n1 and K = k where n1 is the size of the batch to which the random customer belongs and k is his position in that batch, then by using length biased sampling technique 1 P(K  k/N1  n1 )    n1P(N1  n1 )/E(N1 ) n   1  P(N1  n1 )/E(N1 ) The number of customers in the system when a random customer departs is the sum of (n1  k) customers in the batch and the number of new arrivals that occur during the K service completions. E(N 1 )  [γ (1  V(λ )  P20 λ E(V)]/(1  ρ)(1  V(λ )] V(t) = 1, t > 0 when the server does not take any vacation. B(t) = 1, t > 0 there is no batch service. Mean and Variance P20 E(V2 ) λ E(s2 ) E(B2 ) E 2 (B) E(B) E(w s )  E(S)     1 ρ 2 2E(N1 ) E(N1 ) λ 2(1  V(λ)E(N1 ) 2 2 Var(w s )  E(w s )  (E(w s )) . 3.4 Server Utilization Let T1 and T2 denote the durations of time the server is busy in the system. Let T1 (θ ) and T2 (θ ) denote the LSTs of T1 and T2 respectively.  T1 (θ)   [B(θ)P1* (F(θ))] r (1  P20 ) r 1 P20 r 1  T2 (θ)   (V(θ)) r (V(λ )) r (1  V(λ )) r 1 [E(B)  E(N 1 )E(s)] P20 E(V) E(T 2 )  1  V(λ ) E(T1 )  The long run proportion is given by u www.ijera.com E(T1 ) E(T1 )  E(T 2 ) 227 | P a g e
  • 6. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 www.ijera.com  E(B)  E(N1 )E(s)      P20   u E(B)  E(N1 )E(s) E(V)  P20 1  V(λ)  P20 (1  V(λ)) E(B)  E(N1 )E(s)  (1  V(λ))  P20 E(V) P20 (E(B)  E(N1 )E(s)) (E(B)  E(N 1 )E(s))(1  V(λ )) u (E(B)  E(N 1 )E(s))(1  V(λ ))  P20 E (V ) IV. Table Case (i)  = 5, E(B) = 1/15 1 E(V) E(ws) 5 4 3 2 1 0.56 0.58 0.6 0.71 1.18 Case (ii)  = 5, E(B) = 1/10 1 E(V) E(ws) 5 4 3 2 1 0.58 0.59 0.61 0.72 1.18 Case (iii)  = 5, E(B) = 1/2 1 E(V) E(ws) 5 4 3 2 1 1.41 1.4 1.31 1.3 1.3 Graph =5 www.ijera.com 228 | P a g e
  • 7. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 www.ijera.com 4 3.5 3 E(ws) 2.5 Series3 2 Series2 Series1 1.5 1 0.5 0 1 2 3 4 5 1/E(V) From the above graph indicates the mean system time decreases with the decrease in the mean vacation time . V. Conclusion In this paper we studied the vacation model of a queuing system in which customers are served in two phases. Server vacations are introduced to utilize the idle time of the server so that idle times are used to perform some useful jobs other than the service to the customers in the system . In fact , such jobs may even include a simple break for taking some rest in serving in some other queue. The study of vacation models of queuing systems help the effects of server vacations on the system performance . References [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] Choudhury, Gautam / Deka, Kandarpa. : A batch arrival retrial queue with two phases of service and Bernoulli vacation schedule. Acta Mathematicae Applicatae Sinica, English Series, Nov 2009 Choudhury, Gautam / Deka, Mitali,: A single server queuing system with two phases of service subject to server breakdown and Bernoulli vacation: Applied Mathematical Modelling, In Press, Corrected Proof,Feb 2012 Choudhury, Gautam / Madan, Kailash C.: A two phase batch arrival queueing system with a vacation time under Bernoulli schedule. Applied Mathematics and Computation, 149 (2), p.337-349, Feb 200 Choudhury, Gautam / Tadj, Lotfi / Deka, Kandarpa,: A batch arrival retrial queueing system with two phases of service and service interruption. Computers & Mathematics with Applications, 59 (1), p.437450,Jan 2010 Choudhury, Gautam / Tadj, Lotfi,: An M / G /1 queue with two phases of service subject to the serverbreakdown and delayed repair. Applied Mathematical Modelling, 33 (6), p.2699-2709, Jun 2009 Choudhury, Gautam,: A two phase batch arrival retrial queuing system with Bernoulli vacation schedule. Applied Mathematics and Computation, 188 (2), p.1455-1466, May 2007 Choudhury, Gautam,: Steady state analysis of an M / G /1 queue with linear retrial policy andtwo phase service under Bernoulli vacation schedule. Applied Mathematical Modelling, 32 (12), p.2480-2489, Dec 2008 Cooper, Robert B.: Chapter 10 Queueing theory. Handbooks in Operations Research and Management Science, 2, p.469-518, Jan 1990 Dimitriou, Ioannis / Langaris, Christos.: Analaysis of a retrial queue with two-phase service ad server vacations. Queueing Systems, 60 (1-2), p.111-129, Oct 2008 Doshi, Bharat,: Analysis of a two phase queueing system with general service times. Operations Research Letters, 10 (5), p.265-272,Jul 1991 Fiems, Dieter / Maertens, Tom / Bruneel, Herwig,: Queueing systems with different types of server interruptions. European Journal of Operational Research, 188 (3), p.838-845, Aug 2008 www.ijera.com 229 | P a g e
  • 8. K. Ramya et al Int. Journal of Engineering Research and Applications ISSN : 2248-9622, Vol. 4, Issue 2( Version 1), February 2014, pp.223-230 [12] [13] [14] [15] [16] [17] [18] [19] www.ijera.com Frigui, Imed / Alfa, Attalhiru-Sule,: Analysis of a time-limited polling system. Computer Communications, 21 (6), p.558-571, May 1998 Krishna, C.M. / Lee, Y.-H.: A study of two-phase service. Operations Research Letters, 9 (2), p.9197, Mar 1990 Leung, Kin K. / Lucantoni, David M.: Two vacation models for token-ring networks where service is controlled by timers. Performance Evaluation, 20 (1-3), p.165-184, May 1994 Moreno, P.: An M / G /1 retrial queue with recurrent customers and general retrial times. Applied Mathematics and Computation, 159 (3), p.651-666, Dec 2004 Nadarajan, R. / Jayaraman, D.: Series queue with general bulk service, random breakdown and vacation. Microelectronics Reliability, 31 (5), p.861-863, Jan 1991 Park, Hyun-Min / Kim, Tae-Sung / Chae, Kyung C.: Analysis of a two-phase queuing system with a fixed-size batch policy. European Journal of Operational Research, 206 (1), p.118-122, Oct 2010 Takine, Tetsuya / Matsumoto, Yutaka / Suda, Tatsuya / Hasegawa, Toshiharu,: Mean waiting times in nonpreemptive priority queues with Markovian Arrival and i.i.d. service Processes. Performance Evaluation, 20 (1-3), p.131-149,May 1994 Wang, Jinting,: An M/G/ 1 queue with second optional service and server breakdowns. Computers & Mathematics with Applications, 47 (10-11), p.1713-1723, May 2004 www.ijera.com 230 | P a g e