1. Y! : ikhwankrisnadi GTalk: krisnadiikhwan
EXECUTE MYSQL QUERY
USING COMMAND
PROMPT
PREPARED BY: IKHWAN KRISNADI –
SOFTWARE ENGINEER

2. ENVIRONMENT
 Using XAMPP version 1.6.7 (included PHP
and MySQL)
 PHP version 5.2.6
 MySQL version 5.0.51b
 Windows 7 Home as OS
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

3. Y! : ikhwankrisnadi GTalk: krisnadiikhwan
STEPS
 Prepare MySQL query file
 For example, add “student” table into “test”

4. STEPS (CONTINUED)
 Save the query with named “student.sql”
 Open phpmyadmin using browser. Check
“student” table is not existed on “test”
database
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

5. STEPS (CONTINUED)
 Open command prompt
 Go to “MySQL” directory installation. For
example, “MySQL” directory in
C:xamppmysql.
 Go to bin directory
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

6. STEPS (CONTINUED)
 Type below:
mysql -u [user_name] -p [database_name] <
[file path of mysql query]
 For example:
mysql -u root –p test < “C:student.sql”
 Press enter
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

7. STEPS (CONTINUED)
 Open phpmyadmin using browser, to check it
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

8. STEPS (CONTINUED)
 Structure of “student” table
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

9. STEPS (CONTINUED)
 Already add “student” table into “test”
database successfully
Y! : ikhwankrisnadi GTalk: krisnadiikhwan

10. THANK YOU
Y! : ikhwankrisnadi GTalk: krisnadiikhwan