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Solving Linear Equations Using Graphing Substitution and Elimination Need some homework help? Go to:  http://go.hrw.com Keyword: MA1 Homework Help
What’s the Deal? ,[object Object],[object Object]
Three Parts ,[object Object],[object Object],[object Object]
Solving for linear equations answers the question: ,[object Object],[object Object]
Remember - Slope intercept form:  y = mx + b ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
If the slope is ½ ,[object Object],[object Object],[object Object],[object Object]
Graphing Systems of equations ,[object Object],[object Object],[object Object],[object Object]
Graph y=3x + 1 ,[object Object],[object Object]
y  =  x + 1 y-intercept
Let’s add y = -x + 5 The slope is -1. Or down one And right one.
The coordinates of the intersecting point is your solution. The lines inter- cept at (1, 4) so the solution is x=1, y =4. The lines inter- cept at (1, 4) so the solution is x=1, y =4.
Solve by graphing ,[object Object],[object Object],[object Object]
The coordinates of the intersecting point is your solution. The lines inter- cept at (-20,-12) so the solution is x= -20, y = -12.
Now solve equations in standard form. ,[object Object],[object Object],[object Object],[object Object]
Change 3x + 2y = -6 to y-intercept form ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Subtract -3x  from both sides
Change -3x + 2y = 6 to y-intercept form ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Add 3x  to both sides
Graph the equations: y = - 3 / 2 x -3 and  y =  3 / 2 x + 3 x = 2, y = 0 The solution is (2,0)
End of Part One
Part Two – Solve linear equations by substitution Need Help? Go online to go.hrw.com See your textbook’s “internet connect” notes
Here’s what will happen ,[object Object],[object Object],[object Object],[object Object]
Solve for the following equations. ,[object Object],[object Object],[object Object],[object Object],[object Object]
Step 2) Insert the  isolated value  into the equation, this allows you to solve for one variable at a time. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Careful! You are only half done. You still have to solve for the other variable!
Solve for: 2x + 8y = 1 and x = 2y ,[object Object],[object Object],[object Object],[object Object],[object Object],The solution is (1/6, 1/12)
Try one. ,[object Object],[object Object]
x is given as 7. Insert 7 for any occurrence of x to solve for y. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Solve for x and y.  3x + y = 4 and  5x – 7y = 11 ,[object Object],[object Object],[object Object],[object Object]
Subtract 3x from both sides to isolate y. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
The Distributive Property is used. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Continuing… ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
3( 3 / 2 ) + y = 4 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Part Three – Solving equations by Elimination Need some homework help? Go to:  http:// go.hrw.com Keyword: MA1 Homework Help
Solve using substitution after manipulating equations in standard form. ,[object Object],[object Object],[object Object],[object Object]
Let’s solve by elimination. ,[object Object],[object Object],[object Object],[object Object]
2x + 3y = 21 -3x – 3y = -12 ,[object Object],[object Object],[object Object]
The steps and explanations ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
2x + 3y = 21 -3x – 3y = -12 You may pick either one. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Try One. ,[object Object],[object Object]
Eliminate the x values.  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
4x = 21 / 9 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Ready to go one more step? ,[object Object],[object Object]
Let’s try 11x + 2y = -8 and   8x + 3y = 5 ,[object Object],[object Object],[object Object]
Multiply both sides ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Results of the First Steps ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
-17x = 34,  x = -2 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
One more for practice ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
One more for practice ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Which way of solving works best for you? ,[object Object],[object Object],[object Object],[object Object]
You have reviewed the first three parts of Chapter 7.

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Solving Linear Equations Presentation

  • 1. Solving Linear Equations Using Graphing Substitution and Elimination Need some homework help? Go to: http://go.hrw.com Keyword: MA1 Homework Help
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8.
  • 9. y = x + 1 y-intercept
  • 10. Let’s add y = -x + 5 The slope is -1. Or down one And right one.
  • 11. The coordinates of the intersecting point is your solution. The lines inter- cept at (1, 4) so the solution is x=1, y =4. The lines inter- cept at (1, 4) so the solution is x=1, y =4.
  • 12.
  • 13. The coordinates of the intersecting point is your solution. The lines inter- cept at (-20,-12) so the solution is x= -20, y = -12.
  • 14.
  • 15.
  • 16.
  • 17. Graph the equations: y = - 3 / 2 x -3 and y = 3 / 2 x + 3 x = 2, y = 0 The solution is (2,0)
  • 18. End of Part One
  • 19. Part Two – Solve linear equations by substitution Need Help? Go online to go.hrw.com See your textbook’s “internet connect” notes
  • 20.
  • 21.
  • 22.
  • 23.
  • 24.
  • 25.
  • 26.
  • 27.
  • 28.
  • 29.
  • 30.
  • 31. Part Three – Solving equations by Elimination Need some homework help? Go to: http:// go.hrw.com Keyword: MA1 Homework Help
  • 32.
  • 33.
  • 34.
  • 35.
  • 36.
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  • 39.
  • 40.
  • 41.
  • 42.
  • 43.
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  • 45.
  • 46.
  • 47.
  • 48. You have reviewed the first three parts of Chapter 7.