1. VOLUME

3. How might we find the volume of
these prisms?
Volume of a prism
= (Area of cross-section) X (Height)
= AH

4. b) Find the height of the
following prism:
b) Find the height of the
following prism:
Area of cross-section, A
Volume
= 1
2(a + b)h
= 1
2(22 + 30)(14)
= 364m2
Examples:
a) Find the volume of the
storage tank below:
= AH
= 364 × 50
= 18200m3
Volume = AH
600 = 30Η
600
30
= Η
Η = 20χµ

5. ×10002
kmkm2
mm2
km3
m3
cm3
mm3
×10003
×1000 ×1003
×103
÷10003
÷1003
Units of volume
÷103

6. km3
×10003
m3
÷10003
×1003
cm3
÷1003
×103
mm3
÷103
Convert to and2.4 ×105
cm3
mm3
m3
2.4 ×105
= (2.4 ×105
×103
)
= 2.4 ×108
cm3
mm3
mm3
2.4 ×105
= (2.4 ×105
÷1003
)
= (2.4 ×105
÷106
)
= 2.4 ×10−1
cm3
m3
m3
m3

7. Capacity
Capacity refers to the maximum amount that a container can
hold
It is usually measured in millilitres (mL), litres (L), kilolitres
(kL), or megalitres (ML)
We usually refer to the volume of liquid and gases in units of
capacity
A 1cm x 1cm x 1cm cube has capacity of 1 mL (1 = 1mL)
A 10cm x 10cm x10cm cube has capacity of 1 L (1000 = 1 L)
cm3
cm3

8. Units of capacity
(m3
)
L mL
×1000
÷1000
×1000 ×1000
÷1000 ÷1000
(cm3
)
kLML
1mL = 1χµ 3
= 1000mL
= 1000cm3
1L 1kL = 1000L
(= 1000000cm3
)
= 1m3
1ML = 1000κΛ

9. Example
Find the capacity, in ML,
of the following storage
tank (correct to 1 d.p.)
Volume = 18200µ 3
×1000
÷1000
ML kL L mL
×1000
÷1000
×1000
÷1000
(m3
) (cm3
)
18200m3
= 18200kL
= (18200 ÷1000)ML
= 18.2ML

10. Example
Find the capacity, in ML,
of the following storage
tank (correct to 1 d.p.)
Volume = 18200µ 3
×1000
÷1000
ML kL L mL
×1000
÷1000
×1000
÷1000
(m3
) (cm3
)
18200m3
= 18200kL
= (18200 ÷1000)ML
= 18.2ML