1. Today
Welcome Back
No Warm up: Practice Problems Only
Test Friday on Equations
Important Notes for this Week
v6math.blogspot.com --Videos & Power Points
Class Work
2. This Week:
Khan Academy: Please switch topics for Oct. 13, and Oct. 20
October 20 topics due this week, October 13, next week.
Equations Test This Friday: Today, Solve individually or in
pairs. Thursday, Review as class.
Terror Drill Awareness: Clarify Instructions
Students without internet access: Your only option now is
the library until a router is delivered. Even then, you'll need a
laptop, as we cannot put any desktops in the room. (Security)
Please go to Practice Problems Section of Notebook:
3. Equations Week!!
All Equations, All the time
And More!!!!
Translating, Solving, Writing
4. Solving Equations is the foundation of
Algebra. You cannot do Algebra if you
can't solve equations. But you can do
Algebra if you can do equations!!
Understanding what we do today and
tomorrow will determine your entire year.
It will make or break you. But they're
really not hard, if you pay attention, do the
practice problems, believe in yourself and
just get it done. Let's do it.
5. How to Solve More Complex Equations
A. - 8x + 14 = 2(3x - 7) + 10
1. Distribute if available; both sides if necessary
6x - 14
2. Combine like terms on same side of equation if possible
= 6x - 14 + 10 = 6x - 4
3. Combine like terms across equation using Inverse Property
- 8x - 6x = - 4 - 14; - 14x = -18
4. Eliminate the coefficient thru division. Solve
- 14x/-14 = -18/-14; x = 1 2/14; = 1 1/7
7. How to Solve Fractional Equations
There are several ways fractions can appear in equations, but the goal
is always to clear the fractions the easiest way possible.
C. 1/3x - 1/3 = 9 The steps:
1. Combine like terms if easier. Are there like terms?
Yes, there are, but let's not combine them now.
2. Instead, let's clear the fractions by multiplying each term by the
number which cancels the denominator
(3/1) (⅓x) - (3/1) (⅓) = 9(3/1); x - 1 = 27
3. Isolate the variable on the left using the inverse property, and
divide by the coefficient.
x = 28
8. Your Turn: Write Every Step Needed to Solve
C. 1/2x - 3 = 1/5x + 3
1. Since combining like terms is easy this time, do that first.
1/2x = 1/5x + 6
2. Here we have 2 different denominators, so we find the Least Common
Denominator (LCD); The LCD of 2 and 5 is 10. Now we have:
5/10x = 2/10x + 6.
Why didn't we multiply the 6 by 10 also? Because we did not change the
size of the fractions at all! ½ and 5/10 is the same number.
What is our next step?
Multiply all three terms by 10/1; Our equation now looks like:
5x = 2x + 60; Completing the steps we get:
5x - 2x = 3x = 60; x = 20
Finally, checking our work: 10 - 3 = 4 + 3; 7 = 7
10. Your Turn: Write Every Step Needed to Solve
D. - 13 = - |x + 3|
1. In other words, the opposite of 13 = the opposite of |x + 3|
The first equation: |x + 3| = 13; solve this and the second equation
2. For the first equation, x = 10
The second equation is: .......
11. Friday's Test Also Includes
Translating Equations
Decimal Equations
Writing Equations
Everything Else on Today's Review
12. Class Work
Work independently or in pairs, all problems
You Must Show Each Step for Every Problem to
get Credit.
Example: x + 5 = - 7
x = -7 - 5
x = - 12