Larson Algebra Powerpoints

1. Objective- To find x-intercepts and y-intercepts of lines. x-intercept (5, 0) y-intercept (0, 5) Graph x + y = 5 x y Line is oblique

2. 2 2 Finding Intercepts x-intercept = where the line crosses the x-axis y-intercept = where the line crosses the y-axis Oblique x y y = 2x + 3 x y -3 -2 -1 0 1 2 -3 -1 1 3 5 7 x-intercept y-intercept (set y = 0) y = 2x + 3 0 = 2x + 3 -3 -3 -3 = 2x (set x = 0) y = 2x + 3 y = 2(0) + 3 y = 3

3. 4 4 Find the x-intercept and y-intercept. 1) 4x + 2y = 6 x-intercept y-intercept 4x + 2y = 6 4x + 2(0) = 6 (Set y = 0) 4x = 6 4x + 2y = 6 4(0) + 2y = 6 (Set x = 0) 2y = 6 2 2

4. 3 3 Find the x-intercept and y-intercept. 2) 3x - y = -5 x-intercept y-intercept 3x - y = -5 3x - (0) = -5 (Set y = 0) 3x = -5 3x - y = -5 3(0) - y = -5 (Set x = 0) - y = -5 - 1( - y = -5)

5. Find the x-intercept and y-intercept. 3) x = -3 4) 5) x = 0 x-intercept y-intercept x = -3 or (-3,0) none none (0,0) y-axis

6. -3 -3 -3y = 8 2x = 8 2 2 Graph using the x-intercept and y-intercept. 2x - 3y = 8 x-intercept (Set y = 0) 2x - 3(0) = 8 x = 4 or (4, 0) y-intercept (Set x = 0) 2(0) - 3y = 8 x y

7. -50 -40 -30 -20 -10 0 10 20 30 40 50 5 5 5y = 150 3x = 150 3 3 Graph using the x-intercept and y-intercept. 3x + 5y = 150 x-intercept (Set y = 0) 3x + 5(0) = 150 x = 50 or (50, 0) y-intercept (Set x = 0) 3(0) + 5y = 150 x y 40 30 20 10 -10 -20 -30 -40