6. • 24 transistors, few resistors and only
one capacitor
• Two power supplies
• Short-circuit protection
General Description
7. • The input stage consists of transistors Q1
through Q7.
• Q1-Q4 is the differential version of CC and
CB configuration.
• High input resistance.
• Current source (Q5-Q7) is the active load of
input stage. It not only provides a high-
resistance load but also converts the signal
from differential to single-ended form with no
loss in gain or common-mode rejection.
The Input Stage
8. • The intermediate stage is composed of
Q16, Q17 and Q13B.
• Common-collector configuration for Q16
gives this stage a high input resistance
as well as reduces the load effect on
the input stage.
• Common-emitter configuration for Q17
provides high voltage gain because of
the active load Q13B.
The Intermediate Stage
9. • The output stage is the efficient circuit called class
AB output stage.
• Voltage source composed of Q18 and Q19 supplies
the DC voltage for Q14 and Q20 in order to reduce
the cross-over distortion.
• Q23 is the CC configuration to reduce the load
effect on intermediate stage.
The Output Stage
10. (a) The emitter follower is a class A output stage.
(b) (b) Class B output stage.
The Output Stage
11. Wave of a class B output stage
fed with an input sinusoid.
Positive and negative cycles are
unable to connect perfectly due to
the turn-on voltage of the
transistors.
This wave form has the nonlinear
distortion called crossover
distortion.
To reduce the crossover
distortion can be implemented by
supplying the constant DC voltage
at the base terminals.
The Output Stage
12. QN and QP provides
the voltage drop
which equals to the
turn-on voltages of
QN and QP.
This circuit is call
Class AB output
stage.
The Output Stage
13. • Short-circuit protection circuitry
Forward protection is implemented by R6 and
Q15.
Reverse protection is implemented by R7, Q21,
current source(Q24, Q22) and intermediate stage.
Short-circuit protection
14. • Reference current is generated by Q12, Q11
and R5.
• Wilder current provides biasing current in the
order of μA.
• Q13B provides biasing current for intermediate
stage, Q13A for output stage.
• Q5, Q6 and Q7 is composed of the current
source to be an active load for input stage.
The Biasing Circuits
17. Characteristics of the Ideal Op
Amplifier
The ideal OPAMP has the following
characteristic :
Differential Input resistance Ri= ∞
Output resistance Ro = 0
Differential voltage gain Av=- ∞
Bandwidth = ∞
Offset voltage and current is zero.
a) No difference voltage
between inverting and
noninvertying terminals.
b) No input currents.
A
Vo = (A V -A V )
= A (V - V )
+
+
-
-
OP AMP is a direct
coupled high gain
amplifier to which
feedback is added to
control its overall
response
characteristic
18. Operational Amplifier (OP AMP)
Basic and most common circuit building
device. Ideally,
1. No current can enter terminals V+
or V-. Called infinite input
impedance.
2. Vout=A(V+ - V-) with A ∞→
3. In a circuit V+ is forced equal to
V-. This is the virtual ground
property
4. An opamp needs two voltages to
power it Vcc and -Vee. These are
called the rails.
A
Vo = (A V -A V )
= A (V - V )
+
+
-
-
19. OPAMP: COMPARATOR
Vout=A(Vin – Vref)
If Vin>Vref, Vout = +∞ but practically hits
+ve power supply = Vcc
If Vin<Vref, Vout = -∞ but practically hits
–ve power supply = -Vee
Compare the voltage of one input with the voltage with other input
Two types:
inverting comparator when the reference voltage apply to the inverting
terminal
non inverting comparator when the reference voltage apply to the non
inverting terminal
A (gain)
very high
20. 24
(a) The unity-gain buffer or follower amplifier.
(b) Its equivalent circuit model.
V+ = VIN.
By virtual ground, V- = V+
Thus Vout = V- = V+ = VIN !!!!
OPAMP: VOLTAGE FOLLOWER
24. OPAMP: INVERTING AMPLIFIER
1. V- = V+
2. As V+ = 0, V- = 0
3. As no current can
enter V- and from
Kirchoff’s Ist law,
I1=I2.
4. I1 = (VIN - V-)/R1 = VIN/R1
5. I2 = (V- - VOUT)/R2 = -VOUT/R2 => VOUT = -I2R2
6. From 3 and 5, VOUT = -I2R2 = -I1R2 = -VINR2/R1
7. Therefore VOUT = (-R2/R1)VIN
8. Gain = V / V = - R / R
25. SJTU Zhou Lingling 29
The noninverting configuration.
Series-shunt negative feedback.
OPAMP: The Non Inverting
Configuration
27. OPAMP: NON – INVERTING
AMPLIFIER
1. V- = V+
2. As V+ = VIN, V- = VIN
3. As no current can
enter V- and from
Kirchoff’s Ist law,
I1=I2.
4. I1 = VIN/R1
5. I2 = (VOUT - VIN)/R2 => VOUT = VIN + I2R2
6. VOUT = I1R1 + I2R2 = (R1+R2)I1 = (R1+R2)VIN/R1
7. Therefore VOUT = (1 + R2/R1)VIN
28. SUMMING AMPLIFIER
VOUT = -Rf (V1/R1 + V2/R2 + … + Vn/Rn)
If
Recall inverting
amplifier and
If = I1 + I2 + … + In
Summing amplifier is a good example of analog circuits serving as analog
computing amplifiers (analog computers)!
Note: analog circuits can add, subtract, multiply/divide (using
logarithmic components, differentiate and integrate – in real time and
continuously.
31. Difference AMPLIFIER
•This type is of the same characteristic of the
inverting and non inverting OPAMP.
•Vo is the differences between the two inputs
• Rin in both inputs must be
equal, and equal to Rf
Vo = Rf (V1 –V2)/ Rin
Rf
Rin
Rin
V2
V1
Rf
Vo