1. Matlab code
%matlab code of composite structure
%chapter four code
%michromechanics composite material
%calculation of material properties
%inputs: Em,Ef,Vm,Vf,Gm,Gf,alpha m, alpha f, neu
f, neu m
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Ef=230;
Em=4.6;
Vf=0.4;
Vm=0.6;
Gm=1.769;
Gf=92;
alpham=30*10^-6;
alphaf=15*10^-6;
neuf=0.25;
neum=0.3;
E1=(Ef*Vf)+(Em*Vm)
E2=(Em*Ef)/((Vf*Em)+(Vm*Ef))
alpha1=((Ef*Vf*alphaf)+(Em*Vm*alpham))/E1
alpha2=(alphaf*Vf)+(alpham*Vm)
G12=(Gm*Gf)/((Gf*Vm)+(Gm*Vf))
neu12=(neuf*Vf)+(neum*Vm)

2. Example 4.5
We will use the data of this example
Ef=230 Gpa
Em= 4.6 Gpa
Gm= 1.769 GPA
Gf= 92 Gpa
alpham=30*10^-6
alphaf=15*10^-6
results:
G12 2.911 Gpa
E1 94.76
E2 7.565
υ 12 0.28
Alpha 1 1.5437e-05
Alpha 2 2.4000e-05
MAtlab code results :
E1 94.7600
E2 7.5658
G12 2.9110
υ 12 0.2800
Alpha 1 1.5437e-05
Alpha 2 2.4000e-05
So the code is work correctly