3. http://m2suidhat.blogspot.com/
3x + 6 = 5x + 20
6 – 20 = 5x – 3x
– 14 = 2x
– 7 = x
x = – 7
K = 2(p + l)
44 = 2(p + l)
22 = (p + l)
22 = (3x + 4) + (2x + 3)
22 = 5x + 7
22 – 7 = 5x
15 = 5x
3 = x
x = 3
p = 3x + 4 = 3(3) + 4 = 9 + 4 = 13
l = 2x + 3 = 2(3) + 3 = 6 + 3 = 9
Banyak anggota D = 6
Banyak himpunan bagian dari D adalah 26
= 64
P C40
12
23-12=11
40 – (11 + 12) = 40 – 23 = 17
Menulis cerpen = 17 + 12 = 29
f(x) = 8 – 2x f(k) = 8 – 2k
–10 = 8 – 2k
–18 = –2k
9 = k
k = 9
Jadi, x + 12 = – 7 + 12 = 5
Paket 1
4. http://m2suidhat.blogspot.com/
m1 =
𝟐−𝟕
𝟎+𝟏
= – 5
m1×m2 = –1
–5 × m2 = –1
m2 =
𝟏
𝟓
m = 2
Memotong sumbu-y di titik (0, 2)
m = −
𝟑
𝟐
Memotong sumbu-y bukan di titik (0, 2)
m =
𝟐
𝟏
= 2
Memotong sumbu-y bukan di titik (0, 2)
m =
𝟏
𝟏
= 1
Memotong sumbu-y bukan di titik (0, 2)
m =
𝟐
𝟏
= 2
Memotong sumbu-y di titik (0, 2)
A. m2 = 5
B. m2 =
𝟏
𝟓
C. m2 = – 5
D. m2 = – 5
m1 =
−𝟏𝟑−𝟏
−𝟒−𝟑
=
−𝟏𝟒
−𝟕
= 2
y – y1 = m(x – x1), (ambil x1 = 3 dan y1 = 1)
y – 1 = 2(x – 3)
y – 1 = 2x – 6
y = 2x – 5
y = 2x – 5 , titik A (10, p)
p = 2(10) – 5
p = 20 – 5
p = 15
x – 3y – 5 = 0 ×2 2x – 6y – 10 = 0
2x – 5y – 9 = 0 ×1 2x – 5y – 9 = 0
–y – 1 = 0
y = –1
sehingga x – 3y – 5 = 0
x – 3(–1) – 5 = 0
x + 3 – 5 = 0
x – 2 = 0
x = 2
Nilai 3x + 2y = 3(2) + 2(–1)
= 6 – 2
= 4
Paket 1
5. http://m2suidhat.blogspot.com/
5a + 3j = 79.000 ×2 10a + 6j = 158.000
3a + 2j = 49.000 ×3 9a + 6j = 147.000
a = 11.000
Panjang tali = 𝟏𝟓𝟎 𝟐 + 𝟏𝟓𝟎 𝟐 = 𝟐 × 𝟏𝟓𝟎 𝟐 =𝟏𝟓𝟎 𝟐
Panjang perkiraan dengan 𝟐 𝟏, 𝟒𝟏 adalah 150 × 1,41 = 211,5 212
K L
N M
B
C
D
A
K L
N M
B
CD
A cm8
cm8
cm10
cm10
cm10
Luas daerah yang diarsir =
𝟏
𝟒
× Luas persegi KLMN
=
𝟏
𝟒
× (8)2
= 16 cm2
Paket 1
6. http://m2suidhat.blogspot. com/
(4 + 4 + 6 + 6) × 2 = (20) × 2 = 40 cm
4 cm
4 cm
6 cm
6 cm
atau
1
2
4
3
(i) 1 dengan 3
(ii) 2 dengan 4
(iii) 12 dengan 34
(iv) 14 dengan 23
ada 4 pasang
x
Q R
P
S
T
R
10 cm
15 cm
6 cm
𝑻𝑹
𝑸𝑹
=
𝑹𝑺
𝑷𝑹
𝑻𝑹
𝟏𝟎
=
𝟔
𝟏𝟓
TR = 𝟏𝟎 ×
𝟔
𝟏𝟓
TR = 4 cm
Jadi, PT = PR – TR
= 15 – 4
PT = 11 cm
Paket 1
7. http://m2suidhat.blogspot.com/
D A
E
B C
E
x x
𝑨𝑫
𝑩𝑪
=
𝑨𝑬
𝑬𝑪
=
𝑫𝑬
𝑩𝑬
A + B = 1800
(2x + 30) + (5x + 10) = 180
7x + 40 = 180
7x = 140
x = 20
K L
M
4
1 2
3
Jadi, B = (5x + 10) = 5(20) + 10
= 100 + 10
B = (5x + 10) = 1100
K L
M
3
(i)
K L
M
2
(ii)
K L
M
1
(iii)
K L
M
4
(iv)
Panjang busur AB =
𝟕𝟐 𝐨
𝟑𝟔𝟎 𝐨
× 2 r =
𝟏
𝟓
× 2 ×
𝟐𝟐
𝟕
× 14
=
𝟏
𝟓
× 44 × 2
=
𝟖𝟖
𝟓
= 17, 6 cm
Paket 1
8. http://m2suidhat.blogspot.com/
d2
= p2
– (r1 + r2)2
p2
= d2
+ (r1 + r2)2
= 162
+ (8 + 4)2
= 256 + (12)2
= 256 + 144
= 400
p = 20
Ada 18 (6×3) rusuk dan 8 (6 + 2) sisi
V = La × t
=
𝟏𝟖+𝟏𝟐
𝟐
× 𝟏𝟎 × 20
= (30 × 5) × 20
= 150 × 20
V = 3000
Dengan menggunakan teorema pythagoras
didapat panajang TE = 10 cm
L = luas alas + 4 × luas sisi tegak
= 122
+ 4 ×
𝟏
𝟐
× 12 × 10
= 144 + 240
L = 384 cm212 cm
8 cm
EO
Paket 1
9. http://m2suidhat.blogspot.com/
LP = Luas tabung tanpa tutup + luas setengah bola
= (πr2
+ 2πrt) + 2πr2
= (
𝟐𝟐
𝟕
×72
+ 2×
𝟐𝟐
𝟕
×7×20) + 2×
𝟐𝟐
𝟕
×72
= (22×7 + 2×22×20) + 2×22×7
LP = 1.342
4, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10
Median =
𝟔+𝟕
𝟐
= 6,5
Bisa jadi, rata-ratanya = 130
Bisa jadi, rata-ratanya = 130
Bisa jadi, rata-ratanya = 130
Bisa dipastikan, rata-ratanya = 130
Rata-rata =
𝟐𝟑×𝟏𝟑𝟎+𝟏𝟑𝟑+𝟏𝟐𝟕
𝟐𝟑+𝟏+𝟏
=
𝟑𝟐𝟓𝟎
𝟐𝟓
= 130
180 130 525 640 360 200 2035
30
Rata-rata =
𝟐𝟎𝟑𝟓
𝟑𝟎
= 67, 83
Banyak siswa yang nilainya lebih dari rata-rata = 30 – 9 = 21
Paket 1
10. http://m2suidhat.blogspot.com/
Senin – Selasa dan Kamis – Jum’at penurunan 1000
Selasa – Rabu kenaikan 2000
Rabu – Kamis dan Jum’at – Sabtu uang saku tetap
Senin – Selasa penurunan 1000
Nomor bola kurang dari 5 1, 2, 3, 4 ada 4
P =
𝒏𝒐𝒎𝒐𝒓 𝒃𝒐𝒍𝒂 𝒌𝒖𝒓𝒂𝒏𝒈 𝒅𝒂𝒓𝒊 𝟓
𝒃𝒂𝒏𝒚𝒂𝒌 𝒏𝒐𝒎𝒐𝒓 𝒃𝒐𝒍𝒂
=
𝟒
𝟗
Disusun oleh : Mohammad Tohir
Jika ada saran, kritik maupun masukan
silahkan kirim ke- My email: mohammadtohir@yahoo.com
Terima kasih.
My blog : http://m2suidhat.blogspot.com/
http://matematohir.wordpress.com/
Paket 1