1. 4
1) 10
2) 28
3) 29
4) 32
5) 33
6) 34
7) 35
6/2

2. 1
2 for
3 while
4
1.
2.
3. for , while ,
do-while
4. for , while ,
do-while
5.
for , while , do-while

3. 1.
1.1 Increment Operator
4.1
++ increment
1

4. b=3 ;
a=b++
1 2 a=b;
a=3
b=b+1; b=3+
1
2. a 3 b 4
b=3 ;
1. 2
b=b+1; b=3+1
a=b; a=4
2. a 4 b 4

5. 1.2 decrement operator
4.2
-- decrement 1
b=3
a = b- - ;
1. 2
a=b; a=3
b=b-1; b=3-1
2. a 3 b 2
a=- -b ;
1. 2

6. b=b-1; b=3-1
a=b; a=2
2. a 2 b 2
1.3 (compound assignment
operators)
4.3
(sym (operat
bol) ors)
= Assignment a=b
+= Addition a+=b (a=a
+b)
-= Subtraction a-=b (a=a-
b)
*= Multiplication a*=b (a=a*
b)
/= Division a/=b (a=a/
b)
%= Remainder a%=b (a=a
%b)

7. &= bitwise AND a&=b (a=a
&b)
|= bitwise Inclusive O a|=b (a=a|
R b)
^= bitwise exclusive O a^=b (a=a^
R b)
<<= right shift a<<2 (a=a
<<2)
>>= left shift a>>3 (a=a
>>3)
1.4
4.1
#include <stdio .h>
/* project_loop//operatorl.c */
main ( )
{
int a = 2 , = 4 ;
printf ( “---------------------- nn ”) ;
printf ( “ * operator *n ”) ;
printf ( “---------------------- nn”) ;
printf ( a = -> %d n “ , a ) ;
printf ( “ a = a + 1 -> %d nn ” , a ) ;
printf (“ b = -> %d n “ , b ) ;
b+=1 ;
printf ( “ b + = 1 -> %d n ” , b ) ;
printf ( “---------------------- nn ”) ;
}

8. a=a+1;
----------------------------------------------------------------
------
* Operator *
----------------------------------------------------------------
------
a= --> 2
a = a+1 --> 3
b= --> 4
b + = 1 -->4.1
5 4.1
---------------------------------------------------------------- = 1 ;
a=a+1; a+
----
Press any 4.2 to continue
key
#include <stdio .h>
/* project_loop//operatorl.c */
main ( )
{
int a = 2 , = 4 ;
printf ( “---------------------- nn ”) ;
printf ( “ * operator *n ”) ;
printf ( “---------------------- nn”) ;
printf ( a = -> %d n “ , a ) ;
printf (“ b = -> %d n “ , b ) ;
printf (“ n “) ;
printf (“ a = b + + n “) ;
printf ( “ a = %d n ” , a ) ;

9. a = b ++ ;
b = ++a ;
----------------------------------------------------------------------
* Operator *
----------------------------------------------------------------------
a= --> 2
b= --> 4
a = b ++
a= 4
b= 5
b = a ++
a= 5
b= 5
4.2 4.2
--------------------------------------------------------------------
a = b ++ ; 2
Press any key to continue
a=b; b a
a=4
--------------------------------------------------------------------

10. a=b+1 ; 4+1 5
b b=5
b = ++ a ;
a=a+1; a 4 4+1
a=5
a=b+1 ; a b
a=5
1.5
implicit type conversion
explicit type conversion
4.3
#include <stdio . h >
/ * file name job6 */
main ( )
{
Int value1 = 10 , result2 ; float value 2 = 3.17 , result ;
Const char line * 40 + = “______________________________” ;
printf ( “ % s nn “ , line) ;
printf ( “ * Implicit type conversion * n “) ;
printf ( “ % s nn “ , line) ;
printf ( “ 10 + 3.17 = % . 2f nn “ , result1) ;

11. result 1 = value1 + value2 ;
result 2 = (int) ( value1 + value2 ) ;
-----------------------------------------------------------------------------------
* Implicit type conversion *
----------------------------------------------------------------------------------
10 + 3.17 =13.17
10 / 3 = 3.00
----------------------------------------------------------------------------------
* Explict type conversion *
<int><10 + 3.17 > = 13
----------------------------------------------------------------------------------
Press any key to continue
4.3 4.3
1. result 1 = value1 + value 2 ;
10 + 3.17 13.17
result 1

12. 2. result 1 = value / 3 ;
/
% .2f
3. result 2 = (int) ( value1 + value2 ) ;
10 + 3.17 13.17 int ()
13 result 1
2 for
:
3
: for
2.1 for
for
For ( = ; ; )
{
statemmnt (s) ;
}

13. : 1 {}
4.1 for
2.2 for
5
4.4
for
#include <stdio . h>
/* project_loop // ex_for1.cpp */
main ( )
{
char name [ 30 ] ; int n ;
printf (“ Report Data n “ ) ;
Printf ( “ **************************************** nn “) ;

14. for ( n = 1 ; n < 6 ; n++ )
{
printf (“ No. => %d “ , n ) ;
printf ( “ Name is = > “ ) ; scanf ( “ %s “ , name ) ;
}
Report Data
****************************************************
NO. =>1 Name is => ANAN ANAN
NO. =>2 Name is => SOMJIT SOMJIT 5
NO. =>3 Name is => UILAI UILAI
NO. =>4 Name is => RUNG RUNG
NO. =>5 Name is => TEERA TEERA For ( n =1 ; n < 6 ; n ++)
****************************************************
End program ………………………….
Press any key to continue
4.4 4.4
1. 5
2. n
1
3. n 6
4. {}
For ( n = 1 ; n < 6 ; n++)
{
Printf ( No . => %d , n ) ;

15. 1 for n
1 6 n = n+1
2.3 for
4.5
for
#include <stdio .h >
/* project_loop // ex_for2_1.cpp */
main ( )
{
char name [ 30 ] ;
int midterm , final ,score , n ,num ;
printf ( “ key loop => “) ; scanf ( “%d” , &num) ;
printf ( “ n Report Score n “ ) ;
printf ( “ ***************************************** nn “ ) ;
For ( n = 1 ; n <= num ; n++)
{
printf ( “ No. => %d “ , n)
printf ( “ Name is => “ ) ; scanf ( “ %s” , name) ;
}
Printf( “ **************************************** n “ ) ;

16. Key loop => 3 3
Report Score
****************************************************
NO. =>1 Name is => ANAN
SOMKIT
NO. =>2 Name is => SOMJIT
LINDA
NO. =>3 Name is => UILAI
KITTI
****************************************************
End program ………………………….
Press any key to continue
for ( n = 1 ; n <num ; n++)
4.5 4.5
1
2. 3 3
3. Printf ( “ key loop => “ ) ; scanf ( “ %d “ , num)
for ( n =1 ; n <= num ; n++)
{
printf ( “ No. => %d “ , n)
printf ( “ Name is => “ ) ; scanf ( “ %s” , name) ;
}

17. 3. while
:
while
{}
while
{} while
>
while
while
> {}

18. while
3.2 while
while

19. Ctrl-Break
n <= 5 n n
3.
while

20. while
while
n <= 5
n = n+1 ; n>5
while n <= 5

21. while
n

22. while n

23. n
num
do-while
>
do – while
do – while

24. do – while
do – while

25. do – while
{}

26. while n <=
5
n>5
n++ : n=n +1: n
n>5
{}
do – while

27. do – while n

28. 5.
5.1
for
For pretest loop 3
2
3
for
compound statement for
while for
for while
20
for

29. n
key loop =>……………
Report Score
****************************
No. => ……………
name is => …………..
midterm is => …………..
Final is => ……………
* Score = ……………
*****************************
*Average Score is = ………….
*****************************
1.
1.1
1.2

30. = 1
=
=
=
1.3
1.4
1.5
num
n
name
midterm
final
score
sum
average
1.6 action)

31. 1 (num)
2) for (n =1; n<=num ; n++)
2.1-2.6
3
2.1) (n)
2.2) (name)
(midterm)
(final)
2.3) (score) = midterm + final
2.4) score
2.5) (sum) = sum + score
2.6) 2
3) (average) = sum / num
4) average
5)

32. 2.
start
num
For (n = 1 ; n <= num ; n++) n >num
n <= num
n Averge = sum / num
name,midterm,final
average
Score = midterm + final end
score
sum = sum + score

33. 3.
#include <stdio.h>
/* file name ex_for3.cpp*/
main ()
{
char name [30] ;
int midterm = 0 , final = 0 , score = 0 ,n , num ;
float sum = 0 , average = 0 ;
printf (“ key loop => “) ; scanf (“%d “,&num) ;
Printf (“n Report Score n”) ;
printf(“*************************n n”) ;
for(n = 1;n <= num ; n++)
{
printf (,“No. => %d n” , n) ;
printf (“Name is => “) ; scanf (“%s”,name) ;
printf (“midterm is => “) ; scanf (“%d”&midterm) ;
printf (“final is => “) ; scanf (“%d”&final) ;
score = midterm =+ final;
printf ( “* score = %dn”,score) ;
sum = sum + score ;
printf (“*****************n”) ;
}
average = sum / num ;
printf (“* Averge score is = %.2f n” , averge) ;
printf (“***********************n) ;
}

34. 3
1.
2.
3.
for
2
3
for

35. 5.2
while
while repetition
control structure) loop)
for
while
endless loop)
while
-
w
hile

36. while
while statement ; while
{
;
;
;
}
while
0
n

37. 0
Report Score
===========================
Student Id => …………… 0
No. => …………….
name is => …………..
midterm is => …………..
Final is => ……………
* Score = ……………
===========================
*Average Score is = ………….
===========================
1.
1.1
1.2
= 1
=
=

38. –1)
=
1.3
1.4
1.5
id
n
name
midterm
final
score
sum
average
1.6 action)
1) (n) 1
2 (id)
3) while (id ! = 0)
3.1-3.8

39. 4
3.1) (n)
3.2) (name)
(midterm)
(final)
3.3) (score) = midterm + final
3.4) score
3.5) (sum) = sum + score
3.6) n
3.7) id)
3.8)
4) (average) = sum / (num-1)
5) average
6)

40. 2.
start
n =1
id
no
While (id !=0)
yes
n Averge = sum / num (n-1)
name,midterm,final
average
Score = midterm + final end
score
sum = sum + score

41. n = n+1
id
3.
#include <stdio.h>
/* file name ex_while4.c*/
main ()
{
char name [30] ;
int midterm = 0 , final = 0 , score = 0 ,n=1 , id ;
float sum = 0 , average = 0 ;
printf (“n Report Score n“) ;
printf(“==========================n n”) ;
Printf (“student id . => ”) ; scanf (“%d”,& id) ;
while (id ! =0)
{
printf (,“No. => %d n” , n) ;
printf (“Name is => “) ; scanf (“%s”,name) ;
printf (“midterm is => “) ; scanf (“%d”&midterm) ;
printf (“final is => “) ; scanf (“%d”&final) ;
score = midterm =+ final;
printf ( “* score = %dn”,score) ;
sum = sum + score ;
printf (“============================n”) ;
printf (“student id . => ”) ; scanf (“%d”,& id) ;
}
average = sum / (n-1) ;
printf end job….. n” ,) ;
printf (“======================n) ;
printf (“* Averge score is = %.2f n” , averge) ;
printf (“======================n) ;
}

42. 1. (averge) =
(sum) (n)-1) ; n
n 3
1 0
2
1
= /
2. scanf (“%d”,& id) ; 2

43. Printf (“student id . => ”) ; scanf (“%d”,& id) ;
while (id ! =0)
{
printf (,“No. => %d n” , n) ;
……….
printf (“student id . => ”) ; scanf (“%d”,& id) ;
}
2 while
(id ! =0)
#include <stdio.h>
int counter , num;
char word[20] = "Bodindecha";

44. num counter
while
counter <= 11
printf("ntcounter = %2d my school is %s print round %d.
",counter,word,++num);
counter = counter + 2 counter

45. counter counter <= 11
5.3
do-while
do while loop)
while
do while
endless loop)
do while
-

46. do while
Do {
;
;
;
}while ;
do while
#include <stdio.h>
intcounter ,num ;
char word[20] = "Bodindecha";

47. counter
do while printf("ntcounter =
%2d my school is %s print round %d. ",counter,word,++num);
counter = counter + 2;
counter < 11

48. counter
/* example4_17.c */
while
Report Score
===========================
No. => …………….
name is => …………..
midterm is => …………..
Final is => ……………
* Score = ……………
===========================
calculate again y/n => ………….
===========================
*Average Score is = …………. y/n
===========================

49. 1.
1.1
1.2
= 1
=
=
–1)
= +
=
1.3
–
1.4
1.5
ans
n
name
midterm

50. final
score
sum
average
1.6 action)
1) (n) 1
2) do
2.1) (n)
2.2) (name)
(midterm)
(final)
2.3) (score) = midterm + final
2.4) score
2.5) (sum) = sum + score
2.6) n = n+1
2.7) (ans)
2.8) while (ans!=’n’)
2
3

51. 3) (average) = sum / (n-1)
4) average
5)

52. start
2.
n =1
do
n
name,midterm,final
Score = midterm + final
score
sum = sum + score
n = n+1
ans
yes
While (ans!=’n’)

53. Averge = sum / num (n-1)
average
3.
end
#include <stdio.h>
/* file name ex_do5.c*/
main ()
{
char ans ;
char name [30] ;
int midterm = 0 , final = 0 , score = 0 ,n=1 , id ;
float sum = 0 , average = 0 ;
printf (“n Report Score n“) ;
printf(“==========================n n”) ;
do {
printf (“n”)
printf (,“No. => %d n” , n) ;
printf (“Name is => “) ; scanf (“%s”,name) ;
printf (“midterm is => “) ; scanf (“%d”&midterm) ;
printf (“final is => “) ; scanf (“%d”&final) ;
score = midterm =+ final;
printf ( “* score = %dn”,score) ;
sum = sum + score ;
n = n+ 1
printf (“============================n”) ;
printf (“n calculate again y/n = > “ ) ;
ans = getche ( ) ;
} while (ans ! = “n”) ;
average = sum / (n-1) ;
printf (“n”,) ;
printf (“======================n) ;
printf (“* Averge score is = %.2f n” , averge) ;
printf (“======================n) ;
printf end job….. n” ,) ;
}

54. 1.
do {
……………………
ans = getche ( ) ;
} while (ans ! = “n”) ;
2. ans = getche ( )
;
ans
3. ans }
while (ans ! = “n”) ;
n

55. 3
for while do-while

56. for
while
{}
{}
do – while
{}
1
while

57. 4
“ ++ ”
2.
3.
for
while

58. loop)
loop) loop)
loop) loop)
loop) loop)
while for
for
6. “--”
2

59. a = 3 , b= 2 7-8
7. a /=b ; a
(a=a/b) a 1
(a=a * b) a 1
(a=a-b) a 1
(a=a+ b) a 5
8. a - =b ; a
(a=a/b) a 1
(a=a * b) a 1
(a=a-b) a 1
(a=a+ b) a 5
9. for
5 4
2 3
10. for