Students practice problem solving for problems involving perimeter and area of rectangles and trapezoids.

1. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn

2. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. Perimeter is similar to ____________.

3. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment

4. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. Area is similar to ______.

5. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. number of square units needed to cover an object’s surface Area is similar to ______. a plane

6. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________.

7. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure

8. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure.

9. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum

10. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is:

11. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is: 15 ft + 12 ft + 18 ft + 6 ft + 6 ft + 9 ft = 66 ft

12. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. )

13. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. ) (of a rectangle)

14. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 17 ft 8 ft

15. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 34 ft + 16 ft = 50 ft 17 ft 8 ft

16. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 2(17 ft + 8 ft) = 34 ft + 16 ft = 50 ft = 2(25 ft) = 50 ft 17 ft 8 ft

17. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________.

18. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface

19. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6

20. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6

21. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. The area of a rectangle can also be found by multiplying the length and the width. 3 6

22. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle l w 14 in. 10 in.

23. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in.

24. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in. NOTE: units indicate area is being calculated

25. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________.

26. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle

27. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height

28. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height base height

29. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height Base – the bottom of a geometric figure. Height – measured from top to bottom, perpendicular to the base. base height

30. A Plan for Problem Solving Find the area of the parallelogram:

31. A Plan for Problem Solving Find the area of the parallelogram:

32. A Plan for Problem Solving Find the area of the parallelogram:

33. §1.6 A Plan for Problem Solving End of Lesson