11. Area of triangle A = 𝐵𝐻2 A = 15∗102 = 75𝑚2 Finding the Area 10m 15m
12. What is given? What is needed? How is it found? tan60 = 𝐵10 A =17.32𝑐𝑚∗10𝑐𝑚2 Finding area with trig 60° 10cm B =17.32cm =86.6𝑐𝑚2
13. Given Needed sin50 = 𝐻11 A= 13∗8.432 Non right triangles H= 8.43in 11in A=54.8𝑖𝑛2 50° 13in
14. cos 60 = 𝐻22 Pythagorean theorem for the base A= 19.05∗112 Find area of triangle H=11in 60° 22in A=104.78𝑖𝑛2
15. Given Needed B= X+Y tan 45 = 𝑥16 tan 30 = 𝑦16 B=25.24cm Find area of triangle continued Height = 16cm 16cm 45° 30° X Y X=16cm Y=9.24cm A=16∗25.242 =201.92𝑐𝑚2
16. A 6ft tall man is standing in front of a light. The light is casting a shadow. If the angle of depression at the man’s head is 60° how long is the shadow? Story Problems tan 60 = 𝐿6 L=10.39ft 60° 6ft L
17. Story problems There is a window 33ft up a building and the only ladder is 40ft long. For safety reasons the ladder is leaned against the building at 52°. Will the ladder reach the window? sin 52 = 𝐻40 H=31.52ft 40ft No, the ladder will not reach the window. 52°
18. SOH CAH TOA is key Find the Given and Needed Make own right triangle Draw a picture Wrap up
Editor's Notes
There is a couple ways to do the first problem. Then can use Pythagorean theorem.