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Beni Asllani University of Tennessee at Chattanooga Inventory Management Operations Management - 5 th  Edition Chapter 12 Roberta Russell & Bernard W. Taylor, III
Lecture Outline ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
What Is Inventory? ,[object Object],[object Object],[object Object],[object Object]
Types of Inventory ,[object Object],[object Object],[object Object],[object Object],[object Object]
Inventory and Supply Chain Management ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Two Forms of Demand ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Inventory and Quality Management ,[object Object],[object Object]
Inventory Costs ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Inventory Control Systems ,[object Object],[object Object],[object Object],[object Object]
ABC Classification ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
ABC Classification: Example 1 $ 60 90 2 350 40 3 30 130 4 80 60 5 30 100 6 20 180 7 10 170 8 320 50 9 510 60 10 20 120 PART UNIT COST ANNUAL USAGE
ABC Classification: Example (cont.) Example 10.1 1 $ 60 90 2 350 40 3 30 130 4 80 60 5 30 100 6 20 180 7 10 170 8 320 50 9 510 60 10 20 120 PART UNIT COST ANNUAL USAGE TOTAL % OF TOTAL % OF TOTAL PART VALUE VALUE QUANTITY % CUMMULATIVE 9 $30,600 35.9 6.0 6.0 8 16,000 18.7 5.0 11.0 2 14,000 16.4 4.0 15.0 1 5,400 6.3 9.0 24.0 4 4,800 5.6 6.0 30.0 3 3,900 4.6 10.0 40.0 6 3,600 4.2 18.0 58.0 5 3,000 3.5 13.0 71.0 10 2,400 2.8 12.0 83.0 7 1,700 2.0 17.0 100.0 $85,400 A B C % OF TOTAL % OF TOTAL CLASS ITEMS VALUE QUANTITY A 9, 8, 2 71.0 15.0 B 1, 4, 3 16.5 25.0 C 6, 5, 10, 7 12.5 60.0
Economic Order Quantity (EOQ) Models ,[object Object],[object Object],[object Object],[object Object]
Assumptions of Basic EOQ Model ,[object Object],[object Object],[object Object],[object Object]
Inventory Order Cycle Demand rate Time Lead time Lead time Order placed Order placed Order receipt Order receipt Inventory Level Reorder point,  R Order quantity,  Q 0
EOQ Cost Model C o  - cost of placing order D  - annual demand C c  - annual per-unit carrying cost Q  - order quantity Annual ordering cost = C o D Q Annual carrying cost = C c Q 2 Total cost =  + C o D Q C c Q 2
EOQ Cost Model TC =  + C o D Q C c Q 2 =  + C o D Q 2 C c 2  TC  Q 0 =  + C 0 D Q 2 C c 2 Q opt  = 2 C o D C c Deriving  Q opt Proving equality of costs at optimal point = C o D Q C c Q 2 Q 2   = 2 C o D C c Q opt  = 2 C o D C c
EOQ Cost Model (cont.) Order Quantity,  Q Annual cost ($) Total Cost Carrying Cost = C c Q 2 Slope = 0 Minimum total cost Optimal order Q opt Ordering Cost = C o D Q
EOQ Example Orders per year = D / Q opt = 10,000/2,000 = 5 orders/year Order cycle time = 311 days/( D / Q opt ) = 311/5 = 62.2 store days C c  = $0.75 per yard C o  = $150 D  = 10,000 yards Q opt  = 2 C o D C c Q opt  = 2(150)(10,000) (0.75) Q opt  = 2,000 yards TC min  =  + C o D Q C c Q 2 TC min  =  + (150)(10,000) 2,000 (0.75)(2,000) 2 TC min  = $750 + $750 = $1,500
Production Quantity Model ,[object Object],[object Object],[object Object],[object Object],[object Object]
Production Quantity Model (cont.) Q (1- d/p ) Inventory level (1- d/p ) Q 2 Time 0 Order receipt period Begin order receipt End order receipt Maximum inventory level Average inventory level
Production Quantity Model (cont.) p  = production rate d  = demand rate Maximum inventory level = Q  -  d = Q  1 - Q p d p Average inventory level =  1 - Q 2 d p TC  =  +  1 - d p C o D Q C c Q 2 Q opt  = 2 C o D C c   1 -  d p
Production Quantity Model: Example C c  = $0.75 per yard C o  = $150 D  = 10,000 yards d  = 10,000/311 = 32.2 yards per day p  = 150 yards per day Q opt  =  =  = 2,256.8 yards 2 C o D C c   1 -  d p 2(150)(10,000) 0.75  1 -  32.2 150 TC  =  +  1 -  = $1,329 d p C o D Q C c Q 2 Production run =  =  = 15.05 days per order Q p 2,256.8 150
Production Quantity Model: Example (cont.) Number of production runs =  =  = 4.43 runs/year D Q 10,000 2,256.8 Maximum inventory level = Q  1 -  = 2,256.8  1 - = 1,772 yards d p 32.2 150
Quantity Discounts Price per unit decreases as order quantity increases TC  =  +  +  PD C o D Q C c Q 2 where P  = per unit price of the item D  = annual demand
Quantity Discount Model (cont.) Q opt Carrying cost  Ordering cost  Inventory cost ($) Q ( d 1  ) = 100 Q ( d 2  ) = 200 TC  ( d 2  = $6 )  TC  ( d 1  = $8 )   TC  = ($10 )   ORDER SIZE  PRICE 0 - 99   $10 100 – 199  8 ( d 1 ) 200+  6 ( d 2 )
Quantity Discount: Example C o  = $2,500  C c  = $190 per computer  D  = 200 QUANTITY PRICE 1 - 49 $1,400 50 - 89 1,100 90+ 900 Q opt  =  =  = 72.5 PCs 2 C o D C c 2(2500)(200) 190 TC  =  +  +  PD  = $233,784  C o D Q opt C c Q opt 2 For  Q  = 72.5 TC  =  +  +  PD  = $194,105 C o D Q C c Q 2 For  Q  = 90
Reorder Point Level of inventory at which a new order is placed  R  =  dL where d  = demand rate per period L  = lead time
Reorder Point: Example Demand = 10,000 yards/year Store open 311 days/year Daily demand = 10,000 / 311 = 32.154 yards/day Lead time = L = 10 days R = dL = (32.154)(10) = 321.54 yards
Safety Stocks  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Variable Demand with  a Reorder Point Reorder point,  R Q LT Time LT Inventory level 0
Reorder Point with  a Safety Stock Reorder point,  R Q LT Time LT Inventory level 0 Safety Stock
Reorder Point With  Variable Demand R  =  dL  +  z  d   L where d = average daily demand L = lead time  d = the standard deviation of daily demand  z = number of standard deviations corresponding to the service level probability z  d   L = safety stock
Reorder Point for  a Service Level Probability of  meeting demand during  lead time = service level Probability of  a stockout R Safety stock d L Demand z  d   L
Reorder Point for  Variable Demand The carpet store wants a reorder point with a 95% service level and a 5% stockout probability For a 95% service level,  z  = 1.65 d = 30 yards per day L = 10 days  d = 5 yards per day R =  dL  +  z    d   L = 30(10) + (1.65)(5)(  10) = 326.1 yards Safety stock =  z    d   L = (1.65)(5)(  10) = 26.1 yards
Order Quantity for a  Periodic Inventory System Q  =  d ( t b  +  L ) +  z  d   t b  +  L   -  I where d = average demand rate t b = the fixed time between orders L = lead time  d = standard deviation of demand   z  d   t b  +  L = safety stock I = inventory level
Fixed-Period Model with Variable Demand d = 6 bottles per day  d = 1.2 bottles t b = 60 days L = 5 days I = 8 bottles z = 1.65 (for a 95% service level) Q =  d ( t b  +  L ) +  z  d   t b  +  L   -  I = (6)(60 + 5) + (1.65)(1.2)  60 + 5 - 8 = 397.96 bottles
Copyright 2006 John Wiley & Sons, Inc. All rights reserved.  Reproduction or translation of this work beyond that permitted in section 117 of the 1976 United States Copyright Act without express permission of the copyright owner is unlawful.  Request for further information should be addressed to the Permission Department, John Wiley & Sons, Inc.  The purchaser may make back-up copies for his/her own use only and not for distribution or resale.  The Publisher assumes no responsibility for errors, omissions, or damages caused by the use of these programs or from the use of the information herein.

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Inventry..

  • 1. Beni Asllani University of Tennessee at Chattanooga Inventory Management Operations Management - 5 th Edition Chapter 12 Roberta Russell & Bernard W. Taylor, III
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  • 11. ABC Classification: Example 1 $ 60 90 2 350 40 3 30 130 4 80 60 5 30 100 6 20 180 7 10 170 8 320 50 9 510 60 10 20 120 PART UNIT COST ANNUAL USAGE
  • 12. ABC Classification: Example (cont.) Example 10.1 1 $ 60 90 2 350 40 3 30 130 4 80 60 5 30 100 6 20 180 7 10 170 8 320 50 9 510 60 10 20 120 PART UNIT COST ANNUAL USAGE TOTAL % OF TOTAL % OF TOTAL PART VALUE VALUE QUANTITY % CUMMULATIVE 9 $30,600 35.9 6.0 6.0 8 16,000 18.7 5.0 11.0 2 14,000 16.4 4.0 15.0 1 5,400 6.3 9.0 24.0 4 4,800 5.6 6.0 30.0 3 3,900 4.6 10.0 40.0 6 3,600 4.2 18.0 58.0 5 3,000 3.5 13.0 71.0 10 2,400 2.8 12.0 83.0 7 1,700 2.0 17.0 100.0 $85,400 A B C % OF TOTAL % OF TOTAL CLASS ITEMS VALUE QUANTITY A 9, 8, 2 71.0 15.0 B 1, 4, 3 16.5 25.0 C 6, 5, 10, 7 12.5 60.0
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  • 15. Inventory Order Cycle Demand rate Time Lead time Lead time Order placed Order placed Order receipt Order receipt Inventory Level Reorder point, R Order quantity, Q 0
  • 16. EOQ Cost Model C o - cost of placing order D - annual demand C c - annual per-unit carrying cost Q - order quantity Annual ordering cost = C o D Q Annual carrying cost = C c Q 2 Total cost = + C o D Q C c Q 2
  • 17. EOQ Cost Model TC = + C o D Q C c Q 2 = + C o D Q 2 C c 2  TC  Q 0 = + C 0 D Q 2 C c 2 Q opt = 2 C o D C c Deriving Q opt Proving equality of costs at optimal point = C o D Q C c Q 2 Q 2 = 2 C o D C c Q opt = 2 C o D C c
  • 18. EOQ Cost Model (cont.) Order Quantity, Q Annual cost ($) Total Cost Carrying Cost = C c Q 2 Slope = 0 Minimum total cost Optimal order Q opt Ordering Cost = C o D Q
  • 19. EOQ Example Orders per year = D / Q opt = 10,000/2,000 = 5 orders/year Order cycle time = 311 days/( D / Q opt ) = 311/5 = 62.2 store days C c = $0.75 per yard C o = $150 D = 10,000 yards Q opt = 2 C o D C c Q opt = 2(150)(10,000) (0.75) Q opt = 2,000 yards TC min = + C o D Q C c Q 2 TC min = + (150)(10,000) 2,000 (0.75)(2,000) 2 TC min = $750 + $750 = $1,500
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  • 21. Production Quantity Model (cont.) Q (1- d/p ) Inventory level (1- d/p ) Q 2 Time 0 Order receipt period Begin order receipt End order receipt Maximum inventory level Average inventory level
  • 22. Production Quantity Model (cont.) p = production rate d = demand rate Maximum inventory level = Q - d = Q 1 - Q p d p Average inventory level = 1 - Q 2 d p TC = + 1 - d p C o D Q C c Q 2 Q opt = 2 C o D C c 1 - d p
  • 23. Production Quantity Model: Example C c = $0.75 per yard C o = $150 D = 10,000 yards d = 10,000/311 = 32.2 yards per day p = 150 yards per day Q opt = = = 2,256.8 yards 2 C o D C c 1 - d p 2(150)(10,000) 0.75 1 - 32.2 150 TC = + 1 - = $1,329 d p C o D Q C c Q 2 Production run = = = 15.05 days per order Q p 2,256.8 150
  • 24. Production Quantity Model: Example (cont.) Number of production runs = = = 4.43 runs/year D Q 10,000 2,256.8 Maximum inventory level = Q 1 - = 2,256.8 1 - = 1,772 yards d p 32.2 150
  • 25. Quantity Discounts Price per unit decreases as order quantity increases TC = + + PD C o D Q C c Q 2 where P = per unit price of the item D = annual demand
  • 26. Quantity Discount Model (cont.) Q opt Carrying cost Ordering cost Inventory cost ($) Q ( d 1 ) = 100 Q ( d 2 ) = 200 TC ( d 2 = $6 ) TC ( d 1 = $8 ) TC = ($10 ) ORDER SIZE PRICE 0 - 99 $10 100 – 199 8 ( d 1 ) 200+ 6 ( d 2 )
  • 27. Quantity Discount: Example C o = $2,500 C c = $190 per computer D = 200 QUANTITY PRICE 1 - 49 $1,400 50 - 89 1,100 90+ 900 Q opt = = = 72.5 PCs 2 C o D C c 2(2500)(200) 190 TC = + + PD = $233,784 C o D Q opt C c Q opt 2 For Q = 72.5 TC = + + PD = $194,105 C o D Q C c Q 2 For Q = 90
  • 28. Reorder Point Level of inventory at which a new order is placed R = dL where d = demand rate per period L = lead time
  • 29. Reorder Point: Example Demand = 10,000 yards/year Store open 311 days/year Daily demand = 10,000 / 311 = 32.154 yards/day Lead time = L = 10 days R = dL = (32.154)(10) = 321.54 yards
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  • 31. Variable Demand with a Reorder Point Reorder point, R Q LT Time LT Inventory level 0
  • 32. Reorder Point with a Safety Stock Reorder point, R Q LT Time LT Inventory level 0 Safety Stock
  • 33. Reorder Point With Variable Demand R = dL + z  d L where d = average daily demand L = lead time  d = the standard deviation of daily demand z = number of standard deviations corresponding to the service level probability z  d L = safety stock
  • 34. Reorder Point for a Service Level Probability of meeting demand during lead time = service level Probability of a stockout R Safety stock d L Demand z  d L
  • 35. Reorder Point for Variable Demand The carpet store wants a reorder point with a 95% service level and a 5% stockout probability For a 95% service level, z = 1.65 d = 30 yards per day L = 10 days  d = 5 yards per day R = dL + z  d L = 30(10) + (1.65)(5)( 10) = 326.1 yards Safety stock = z  d L = (1.65)(5)( 10) = 26.1 yards
  • 36. Order Quantity for a Periodic Inventory System Q = d ( t b + L ) + z  d t b + L - I where d = average demand rate t b = the fixed time between orders L = lead time  d = standard deviation of demand z  d t b + L = safety stock I = inventory level
  • 37. Fixed-Period Model with Variable Demand d = 6 bottles per day  d = 1.2 bottles t b = 60 days L = 5 days I = 8 bottles z = 1.65 (for a 95% service level) Q = d ( t b + L ) + z  d t b + L - I = (6)(60 + 5) + (1.65)(1.2) 60 + 5 - 8 = 397.96 bottles
  • 38. Copyright 2006 John Wiley & Sons, Inc. All rights reserved. Reproduction or translation of this work beyond that permitted in section 117 of the 1976 United States Copyright Act without express permission of the copyright owner is unlawful. Request for further information should be addressed to the Permission Department, John Wiley & Sons, Inc. The purchaser may make back-up copies for his/her own use only and not for distribution or resale. The Publisher assumes no responsibility for errors, omissions, or damages caused by the use of these programs or from the use of the information herein.