If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar The E.N values are given as follows S - 2.58 Se – 2.55 As – 2.18 N – 3.04 B – 2.04 Solution If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar The E.N values are given as follows S - 2.58 Se – 2.55 As – 2.18 N – 3.04 B – 2.04.
If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar The E.N values are given as follows S - 2.58 Se – 2.55 As – 2.18 N – 3.04 B – 2.04 Solution If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar The E.N values are given as follows S - 2.58 Se – 2.55 As – 2.18 N – 3.04 B – 2.04.