SlideShare a Scribd company logo
1 of 4
Download to read offline
Question 1.
Find the following products :
Solution:
Question 2.
Evaluate the following :
(i) 102 x 106
(ii) 109 x 107
(iii) 35 x 37
(iv) 53 x 55
(v) 103 x 96
(vi) 34 x 36
(vii) 994 x 1006
Solution:
(i) 102 x 106 = (100 + 2) (100 + 6)
= (100)2
+ (2 + 6) x 100 + 2 x 6
= 10000 + 800 + 12 = 10812
(ii) 109 x 107 = (100 + 9) (100 + 7)
= (100)2
+ (9 + 7) x 100 + 9 x 7
=10000 + 1600 + 63 = 11663
(iii) 35 x 37 = (30 + 5) (30 + 7)
= (30)2
+ (5 + 7) x 30 + 5 x 7
= 900 + 12 x 30 + 35
= 900 + 360 + 35 = 1295
(iv) 53 x 55 = (50 + 3) (50 + 5)
= (50)2
+ (3 + 5) x 50 + 3 x 5
= 2500 + 8 x 50 + 15
= 2500 + 400+ 15 = 2915
(v)103 x 96 = (100 + 3) (100-4)
= (100)2
+ (3 – 4) x 100 + 3 x (-4)
= 10000+ (-1) x 100-12
= 10000 – 100 – 12 = 10000 – 112 = 9888
(vi) 34 x 36 = (30 + 4) (30 + 6)
= (30)2
+ (4 + 6) x 30 + 4 x 6
= 900 + 10 x 30 + 24
= 900 + 300 + 24 = 1224
(vii) 994 x 1006 = (1000 – 6) (1000 + 6)
= (1000)2
+ (-6 + 6) x 1000 + (-6) x 6
= 1000000 + 0-36
= 1000000-36 = 999964

More Related Content

What's hot

1 4 homework
1 4 homework1 4 homework
1 4 homeworkmath123b
 
Elementos finitos
Elementos finitosElementos finitos
Elementos finitosjd
 
Writing quadratic equation
Writing quadratic equationWriting quadratic equation
Writing quadratic equationMartinGeraldine
 
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)Dr. I. Uma Maheswari Maheswari
 
Algebra 2 Section 3-5
Algebra 2 Section 3-5Algebra 2 Section 3-5
Algebra 2 Section 3-5Jimbo Lamb
 
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)Nurkhalifah Anwar
 
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)Dr. I. Uma Maheswari Maheswari
 
X factoring revised
X factoring revisedX factoring revised
X factoring revisedsgriffin01
 
M.2a.01. dai cuong ve ham so
M.2a.01. dai cuong ve ham soM.2a.01. dai cuong ve ham so
M.2a.01. dai cuong ve ham soQuân Trần
 
Lattice points on the homogeneous cone 5(x2+y2) 9xy=23z2
Lattice points on the homogeneous cone 5(x2+y2)  9xy=23z2Lattice points on the homogeneous cone 5(x2+y2)  9xy=23z2
Lattice points on the homogeneous cone 5(x2+y2) 9xy=23z2eSAT Journals
 

What's hot (15)

1 4 homework
1 4 homework1 4 homework
1 4 homework
 
Elementos finitos
Elementos finitosElementos finitos
Elementos finitos
 
Writing quadratic equation
Writing quadratic equationWriting quadratic equation
Writing quadratic equation
 
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)
3a. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.1)
 
drill
drilldrill
drill
 
Algebra 2 Section 3-5
Algebra 2 Section 3-5Algebra 2 Section 3-5
Algebra 2 Section 3-5
 
Leidy rivadeneira deber_1
Leidy rivadeneira deber_1Leidy rivadeneira deber_1
Leidy rivadeneira deber_1
 
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)
Tugas 5.6 kalkulus aplikasi integral tentu (luas bidang datar)
 
Slide share
Slide shareSlide share
Slide share
 
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)
3d. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.4)
 
Alg2 lesson 10-3
Alg2 lesson 10-3Alg2 lesson 10-3
Alg2 lesson 10-3
 
X factoring revised
X factoring revisedX factoring revised
X factoring revised
 
M.2a.01. dai cuong ve ham so
M.2a.01. dai cuong ve ham soM.2a.01. dai cuong ve ham so
M.2a.01. dai cuong ve ham so
 
Factoring2
Factoring2Factoring2
Factoring2
 
Lattice points on the homogeneous cone 5(x2+y2) 9xy=23z2
Lattice points on the homogeneous cone 5(x2+y2)  9xy=23z2Lattice points on the homogeneous cone 5(x2+y2)  9xy=23z2
Lattice points on the homogeneous cone 5(x2+y2) 9xy=23z2
 

More from BGEsp1

C13 13.3
C13 13.3C13 13.3
C13 13.3BGEsp1
 
C14 14.4
C14 14.4C14 14.4
C14 14.4BGEsp1
 
C21 21.3
C21 21.3C21 21.3
C21 21.3BGEsp1
 
C17 17.3
C17 17.3C17 17.3
C17 17.3BGEsp1
 
C18 18.1
C18 18.1C18 18.1
C18 18.1BGEsp1
 
C21 21.2
C21 21.2C21 21.2
C21 21.2BGEsp1
 
C17 17.1
C17 17.1C17 17.1
C17 17.1BGEsp1
 
C19 19.1
C19 19.1C19 19.1
C19 19.1BGEsp1
 
C14 14.3
C14 14.3C14 14.3
C14 14.3BGEsp1
 
C22 22.2
C22 22.2C22 22.2
C22 22.2BGEsp1
 
C17 17.2
C17 17.2C17 17.2
C17 17.2BGEsp1
 
C20 20.1
C20 20.1C20 20.1
C20 20.1BGEsp1
 
C21 21.1
C21 21.1C21 21.1
C21 21.1BGEsp1
 
C12 12.2
C12 12.2C12 12.2
C12 12.2BGEsp1
 
C18 18.3
C18 18.3C18 18.3
C18 18.3BGEsp1
 

More from BGEsp1 (20)

C13 13.3
C13 13.3C13 13.3
C13 13.3
 
C14 14.4
C14 14.4C14 14.4
C14 14.4
 
C26
C26C26
C26
 
C21 21.3
C21 21.3C21 21.3
C21 21.3
 
C17 17.3
C17 17.3C17 17.3
C17 17.3
 
C27.2
C27.2C27.2
C27.2
 
C18 18.1
C18 18.1C18 18.1
C18 18.1
 
C21 21.2
C21 21.2C21 21.2
C21 21.2
 
C17 17.1
C17 17.1C17 17.1
C17 17.1
 
C16
C16C16
C16
 
C15
C15C15
C15
 
C19 19.1
C19 19.1C19 19.1
C19 19.1
 
C14 14.3
C14 14.3C14 14.3
C14 14.3
 
C22 22.2
C22 22.2C22 22.2
C22 22.2
 
C17 17.2
C17 17.2C17 17.2
C17 17.2
 
C20 20.1
C20 20.1C20 20.1
C20 20.1
 
C21 21.1
C21 21.1C21 21.1
C21 21.1
 
C23.1
C23.1C23.1
C23.1
 
C12 12.2
C12 12.2C12 12.2
C12 12.2
 
C18 18.3
C18 18.3C18 18.3
C18 18.3
 

C6 6.6

  • 1. Question 1. Find the following products : Solution:
  • 2.
  • 3. Question 2. Evaluate the following : (i) 102 x 106 (ii) 109 x 107 (iii) 35 x 37 (iv) 53 x 55 (v) 103 x 96 (vi) 34 x 36 (vii) 994 x 1006 Solution: (i) 102 x 106 = (100 + 2) (100 + 6) = (100)2 + (2 + 6) x 100 + 2 x 6 = 10000 + 800 + 12 = 10812 (ii) 109 x 107 = (100 + 9) (100 + 7) = (100)2 + (9 + 7) x 100 + 9 x 7 =10000 + 1600 + 63 = 11663
  • 4. (iii) 35 x 37 = (30 + 5) (30 + 7) = (30)2 + (5 + 7) x 30 + 5 x 7 = 900 + 12 x 30 + 35 = 900 + 360 + 35 = 1295 (iv) 53 x 55 = (50 + 3) (50 + 5) = (50)2 + (3 + 5) x 50 + 3 x 5 = 2500 + 8 x 50 + 15 = 2500 + 400+ 15 = 2915 (v)103 x 96 = (100 + 3) (100-4) = (100)2 + (3 – 4) x 100 + 3 x (-4) = 10000+ (-1) x 100-12 = 10000 – 100 – 12 = 10000 – 112 = 9888 (vi) 34 x 36 = (30 + 4) (30 + 6) = (30)2 + (4 + 6) x 30 + 4 x 6 = 900 + 10 x 30 + 24 = 900 + 300 + 24 = 1224 (vii) 994 x 1006 = (1000 – 6) (1000 + 6) = (1000)2 + (-6 + 6) x 1000 + (-6) x 6 = 1000000 + 0-36 = 1000000-36 = 999964