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Determinants
Matrices
• A matrix is an array of
numbers that are
arranged in rows and
columns.
• A matrix is “square” if
it has the same number
of rows as columns.
• We will consider only
2x2 and 3x3 square
matrices
0
-½
3
1
11
180
4
-¾
0
2
¼
8
-3
Determinants
• Every square matrix has
a determinant.
• The determinant of a
matrix is a number.
• We will consider the
determinants only of
2x2 and 3x3 matrices.
1 3
-½ 0
-3 8 ¼
2 0 -¾
4 180 11
Note the difference in the matrix
and the determinant of the
matrix!
Why do we need the determinant
• It is used to help us
calculate the inverse
of a matrix and it is
used when finding
the area of a triangle
Find the determinant:
1.
5 7
11 8 5 8
  7
 11
 
  40  77
 
 37
40  77
2.
3 2
1 5
 3 5
  2
  1
  15 2
 
 17
15 2
3.
10 2
0 3
 10(-3)-(-2)(0)
 -30+ 0 = -30
Finding a 3x3 determinant: Diagonal method
4.
2 3 8
6 7 1
4 5 9
Step 1: Rewrite first two
rows of the matrix.
4.
2 3 8
6 7 1
4 5 9
2 3
6 7
4 5
Step 2: multiply
diagonals going up!
-224 +10+162 = -52
Step 2: multiply
diagonals going down!
-126 +12+240 =126
Step 3: Bottom
minus top!
126 - (-52)
126 + 52
= 178
5.
5 1 2
2 3 5
3 2 3
Step 2: multiply
diagonals going up!
-18 +50+6 = 38
Step 2: multiply
diagonals going down!
45 - 15 + 8 = 38
Step 3: Bottom
minus top!
38 - 38
= 0
5 1
2 3
3 2
4
5
2
3

(3 * 4) - (-5 * 2)
12 - (-10)
22
=
4
5
2
3

Finding Determinants of Matrices
=
=
2
4
1
5
2
1
3
0
2


2
1
-1
0
-2
4
= [(2)(-2)(2) + (0)(5)(-1) + (3)(1)(4)]
[(3)(-2)(-1) + (2)(5)(4) + (0)(1)(2)]
[-8 + 0 +12]
-
- [6 + 40 + 0]
4 – 6 - 40
Finding Determinants of Matrices
=
= = -42






1
0
0
1
Identity matrix: Square matrix with 1’s on the diagonal
and zeros everywhere else
2 x 2 identity matrix










1
0
0
0
1
0
0
0
1
3 x 3 identity matrix
The identity matrix is to matrix multiplication as
___ is to regular multiplication!!!!
1
Using matrix equations
Multiply:






1
0
0
1





 
4
3
2
5
= 




 
4
3
2
5






1
0
0
1





 
4
3
2
5
= 




 
4
3
2
5
So, the identity matrix multiplied by any matrix
lets the “any” matrix keep its identity!
Mathematically, IA = A and AI = A !!
Inverse Matrix:
Using matrix equations
2 x 2






d
c
b
a
In words:
•Take the original matrix.
•Switch a and d.
•Change the signs of b and c.
•Multiply the new matrix by 1 over the determinant of the original matrix.








 a
c
b
d
bc
ad
1

1
A

A





 



 2
4
4
10
)
4
)(
4
(
)
10
)(
2
(
1





 

 2
4
4
10
4
1
=












2
1
1
1
2
5
Using matrix equations
Example: Find the inverse of A.







 10
4
4
2

A

1
A

1
A
Find the inverse matrix.








2
5
3
8
Det A = 8(2) – (-5)(-3) = 16 – 15 = 1
Matrix A
Inverse =










det
1 Matrix
Reloaded






8
5
3
2
1
1
= = 





8
5
3
2
What happens when you multiply a matrix by its inverse?
1st: What happens when you multiply a number by its inverse?
7
1
7 
A & B are inverses. Multiply them.






8
5
3
2
=








2
5
3
8






1
0
0
1
So, AA-1
= I
Why do we need to know all this? To Solve Problems!
Solve for Matrix X.
=








2
5
3
8
X 







1
3
1
4
We need to “undo” the coefficient matrix. Multiply it by its INVERSE!






8
5
3
2
=








2
5
3
8
X 





8
5
3
2








1
3
1
4






1
0
0
1
X = 







3
4
1
1
X =








3
4
1
1
You can take a system of equations and write it with
matrices!!!
3x + 2y = 11
2x + y = 8
becomes 





1
2
2
3






y
x
= 





8
11
Coefficient
matrix
Variable
matrix
Answer matrix
Using matrix equations
Let A be the coefficient matrix.
Multiply both sides of the equation by the inverse of A.










































8
11
8
11
8
11
1
1
1
A
y
x
A
y
x
A
A
y
x
A 





1
2
2
3 -1
= 







 3
2
2
1
1
1
= 







3
2
2
1








3
2
2
1






1
2
2
3






y
x
= 







3
2
2
1






8
11






1
0
0
1






y
x
= 





 2
5






y
x
= 





 2
5
Using matrix equations






1
2
2
3






y
x
= 





8
11
Example: Solve for x and y .

1
A
Wow!!!!
3x + 2y = 11
2x + y = 8
x = 5; y = -2
3(5) + 2(-2) = 11
2(5) + (-2) = 8
It works!!!!
Using matrix equations
Check:
You Try…
Solve:
4x + 6y = 14
2x – 5y = -9
(1/2, 2)
You Try…
Solve:
2x + 3y + z = -1
3x + 3y + z = 1
2x + 4y + z = -2
(2, -1, -2)

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Determinants.ppt

  • 2. Matrices • A matrix is an array of numbers that are arranged in rows and columns. • A matrix is “square” if it has the same number of rows as columns. • We will consider only 2x2 and 3x3 square matrices 0 -½ 3 1 11 180 4 -¾ 0 2 ¼ 8 -3
  • 3. Determinants • Every square matrix has a determinant. • The determinant of a matrix is a number. • We will consider the determinants only of 2x2 and 3x3 matrices. 1 3 -½ 0 -3 8 ¼ 2 0 -¾ 4 180 11 Note the difference in the matrix and the determinant of the matrix!
  • 4. Why do we need the determinant • It is used to help us calculate the inverse of a matrix and it is used when finding the area of a triangle
  • 5. Find the determinant: 1. 5 7 11 8 5 8   7  11     40  77    37 40  77 2. 3 2 1 5  3 5   2   1   15 2    17 15 2
  • 6. 3. 10 2 0 3  10(-3)-(-2)(0)  -30+ 0 = -30 Finding a 3x3 determinant: Diagonal method 4. 2 3 8 6 7 1 4 5 9 Step 1: Rewrite first two rows of the matrix.
  • 7. 4. 2 3 8 6 7 1 4 5 9 2 3 6 7 4 5 Step 2: multiply diagonals going up! -224 +10+162 = -52 Step 2: multiply diagonals going down! -126 +12+240 =126 Step 3: Bottom minus top! 126 - (-52) 126 + 52 = 178
  • 8. 5. 5 1 2 2 3 5 3 2 3 Step 2: multiply diagonals going up! -18 +50+6 = 38 Step 2: multiply diagonals going down! 45 - 15 + 8 = 38 Step 3: Bottom minus top! 38 - 38 = 0 5 1 2 3 3 2
  • 9. 4 5 2 3  (3 * 4) - (-5 * 2) 12 - (-10) 22 = 4 5 2 3  Finding Determinants of Matrices = =
  • 10. 2 4 1 5 2 1 3 0 2   2 1 -1 0 -2 4 = [(2)(-2)(2) + (0)(5)(-1) + (3)(1)(4)] [(3)(-2)(-1) + (2)(5)(4) + (0)(1)(2)] [-8 + 0 +12] - - [6 + 40 + 0] 4 – 6 - 40 Finding Determinants of Matrices = = = -42
  • 11.       1 0 0 1 Identity matrix: Square matrix with 1’s on the diagonal and zeros everywhere else 2 x 2 identity matrix           1 0 0 0 1 0 0 0 1 3 x 3 identity matrix The identity matrix is to matrix multiplication as ___ is to regular multiplication!!!! 1 Using matrix equations
  • 12. Multiply:       1 0 0 1        4 3 2 5 =        4 3 2 5       1 0 0 1        4 3 2 5 =        4 3 2 5 So, the identity matrix multiplied by any matrix lets the “any” matrix keep its identity! Mathematically, IA = A and AI = A !!
  • 13. Inverse Matrix: Using matrix equations 2 x 2       d c b a In words: •Take the original matrix. •Switch a and d. •Change the signs of b and c. •Multiply the new matrix by 1 over the determinant of the original matrix.          a c b d bc ad 1  1 A  A
  • 14.            2 4 4 10 ) 4 )( 4 ( ) 10 )( 2 ( 1          2 4 4 10 4 1 =             2 1 1 1 2 5 Using matrix equations Example: Find the inverse of A.         10 4 4 2  A  1 A  1 A
  • 15. Find the inverse matrix.         2 5 3 8 Det A = 8(2) – (-5)(-3) = 16 – 15 = 1 Matrix A Inverse =           det 1 Matrix Reloaded       8 5 3 2 1 1 = =       8 5 3 2
  • 16. What happens when you multiply a matrix by its inverse? 1st: What happens when you multiply a number by its inverse? 7 1 7  A & B are inverses. Multiply them.       8 5 3 2 =         2 5 3 8       1 0 0 1 So, AA-1 = I
  • 17. Why do we need to know all this? To Solve Problems! Solve for Matrix X. =         2 5 3 8 X         1 3 1 4 We need to “undo” the coefficient matrix. Multiply it by its INVERSE!       8 5 3 2 =         2 5 3 8 X       8 5 3 2         1 3 1 4       1 0 0 1 X =         3 4 1 1 X =         3 4 1 1
  • 18. You can take a system of equations and write it with matrices!!! 3x + 2y = 11 2x + y = 8 becomes       1 2 2 3       y x =       8 11 Coefficient matrix Variable matrix Answer matrix Using matrix equations
  • 19. Let A be the coefficient matrix. Multiply both sides of the equation by the inverse of A.                                           8 11 8 11 8 11 1 1 1 A y x A y x A A y x A       1 2 2 3 -1 =          3 2 2 1 1 1 =         3 2 2 1         3 2 2 1       1 2 2 3       y x =         3 2 2 1       8 11       1 0 0 1       y x =        2 5       y x =        2 5 Using matrix equations       1 2 2 3       y x =       8 11 Example: Solve for x and y .  1 A
  • 20. Wow!!!! 3x + 2y = 11 2x + y = 8 x = 5; y = -2 3(5) + 2(-2) = 11 2(5) + (-2) = 8 It works!!!! Using matrix equations Check:
  • 21. You Try… Solve: 4x + 6y = 14 2x – 5y = -9 (1/2, 2)
  • 22. You Try… Solve: 2x + 3y + z = -1 3x + 3y + z = 1 2x + 4y + z = -2 (2, -1, -2)