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Philip Dutton
University of Windsor, Canada
N9B 3P4
Prentice-Hall © 2002
General Chemistry
Principles and Modern Applications
Petrucci • Harwood • Herring
8th
Edition
Chapter 20: Spontaneous Change:
Entropy and Free Energy
Prentice-Hall General Chemistry: Chapter 20Slide 2 of 37
Contents
20-1 Spontaneity: The Meaning of Spontaneous Change
20-2 The Concept of Entropy
20-3 Evaluating Entropy and Entropy Changes
20-4 Criteria for Spontaneous Change:
The Second Law of Thermodynamics
20-5 Standard Fee Energy Change, ΔG°
20-6 Free Energy Change and Equilibrium
20-7 ΔG° and Keqas Functions of Temperature
20-8 Coupled Reactions
Focus On Coupled Reactions in Biological Systems
Prentice-Hall General Chemistry: Chapter 20Slide 3 of 37
20-1 Spontaneity: The Meaning of
Spontaneous Change
Prentice-Hall General Chemistry: Chapter 20Slide 4 of 37
Spontaneous Process
• A process that occurs in a system left to itself.
– Once started, no external actions is necessary to make
the process continue.
• A non-spontaneous process will not occur without
external action continuously applied.
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)
H2O(s)  H2O(l)
Prentice-Hall General Chemistry: Chapter 20Slide 5 of 37
Spontaneous Process
• Potential energy decreases.
• For chemical systems the internal energy U is
equivalent to potential energy.
• Berthelot and Thomsen 1870’s
– Spontaneous change occurs in the direction in which
the enthalpy of a system decreases.
– Mainly true but there are exceptions.
Prentice-Hall General Chemistry: Chapter 20Slide 6 of 37
20-2 The Concept of Entropy
• Entropy, S.
– The greater the number
of configurations of the
microscopic particles
among the energy
levels in a particular
system, the greater the
entropy of the system.
ΔS > 0 spontaneous
ΔU = ΔH = 0
Prentice-Hall General Chemistry: Chapter 20Slide 7 of 37
The Boltzmann Equation for Entropy
• States, S.
– The microscopic energy levels
available in a system.
• Microstates, W.
– The particular way in which particles are distributed
amongst the states. Number of microstates = W.
• The Boltzmann constant, k.
– Effectively the gas constant per molecule = R/NA.
S = k lnW
Prentice-Hall General Chemistry: Chapter 20Slide 8 of 37
Boltzmann Distribution
Prentice-Hall General Chemistry: Chapter 20Slide 9 of 37
Entropy Change
ΔS =
qrev
T
Prentice-Hall General Chemistry: Chapter 20Slide 10 of 37
20-3 Evaluating Entropy and
Entropy Changes
• Phase transitions.
– Exchange of heat can be carried out reversibly.
ΔS =
ΔH
Ttr
H2O(s, 1 atm)  H2O(l, 1 atm) ΔHfus° = 6.02 kJ at 273.15 K
ΔSfus =
ΔHfus
Ttr
°
=
6.02 kJ mol-1
273.15 K
= 2.2010-2
kJ mol-1
K-1
Prentice-Hall General Chemistry: Chapter 20Slide 11 of 37
Trouton’s Rule
ΔS =
ΔHvap
Tbp
 87 kJ mol-1
K-1
Prentice-Hall General Chemistry: Chapter 20Slide 12 of 37
Raoult’s Law
°PA = χ APA
Prentice-Hall General Chemistry: Chapter 20Slide 13 of 37
Absolute Entropies
• Third law of thermodynamics.
– The entropy of a pure perfect crystal at 0 K is zero.
• Standard molar entropy.
– Tabulated in Appendix D.
ΔS = [ νpS°(products) - νrS°(reactants)]
Prentice-Hall General Chemistry: Chapter 20Slide 14 of 37
Entropy as a Function of Temperature
Prentice-Hall General Chemistry: Chapter 20Slide 15 of 37
Vibrational Energy and Entropy
Prentice-Hall General Chemistry: Chapter 20Slide 16 of 37
20-4 Criteria for Spontaneous Change:
The Second Law of Thermodynamics.
ΔStotal = ΔSuniverse = ΔSsystem + ΔSsurroundings
The Second Law of Thermodynamics:
ΔSuniverse = ΔSsystem + ΔSsurroundings > 0
All spontaneous processes produce an
increase in the entropy of the universe.
Prentice-Hall General Chemistry: Chapter 20Slide 17 of 37
Free Energy and Free Energy Change
• Hypothetical process:
– only pressure-volume work, at constant T and P.
qsurroundings = -qp = -ΔHsys
• Make the enthalpy change reversible.
– large surroundings, infinitesimal change in temperature.
• Under these conditions we can calculate entropy.
Prentice-Hall General Chemistry: Chapter 20Slide 18 of 37
Free Energy and Free Energy Change
TΔSuniv. = TΔSsys – ΔHsys = -(ΔHsys – TΔSsys)
-TΔSuniv. = ΔHsys – TΔSsys
G = H - TS
ΔG = ΔH - TΔS
For the universe:
For the system:
ΔGsys = - TΔSuniverse
Prentice-Hall General Chemistry: Chapter 20Slide 19 of 37
Criteria for Spontaneous Change
ΔGsys < 0 (negative), the process is spontaneous.
ΔGsys = 0 (zero), the process is at equilibrium.
ΔGsys > 0 (positive), the process is non-spontaneous.
Prentice-Hall General Chemistry: Chapter 20Slide 20 of 37
Table 20.1 Criteria for Spontaneous
Change
Prentice-Hall General Chemistry: Chapter 20Slide 21 of 37
20-5 Standard Free Energy Change, ΔG°
• The standard free energy of formation, ΔGf°.
– The free energy change for a reaction in which a
substance in its standard state is formed from its
elements in reference forms in their standard states.
• The standard free energy of reaction, ΔG°.
ΔG° = [ νp ΔGf°(products) - νr ΔGf°(reactants)]
Prentice-Hall General Chemistry: Chapter 20Slide 22 of 37
20-6 Free Energy Change and Equilibrium
Prentice-Hall General Chemistry: Chapter 20Slide 23 of 37
Free Energy Change and Equilibrium
Prentice-Hall General Chemistry: Chapter 20Slide 24 of 37
Relationship of ΔG° to ΔG for
Nonstandard Conditions
2 N2(g) + 3 H2(g)  2 NH3(g)
ΔG = ΔH - TΔS ΔG° = ΔH° - TΔS°
For ideal gases ΔH = ΔH°
ΔG = ΔH° - TΔS
Prentice-Hall General Chemistry: Chapter 20Slide 25 of 37
Relationship Between S and S°
qrev = -w = RT ln
Vf
Vi
ΔS =
qrev
T
= R ln
Vf
Vi
ΔS = Sf – Si = R ln
Vf
Vi
= R ln
Pi
Pf
= -R ln
Pf
Pi
S = S° - R ln
P
P°
= S°- R ln
P
1
= S° - R ln P
Prentice-Hall General Chemistry: Chapter 20Slide 26 of 37
2 N2(g) + 3 H2(g)  2 NH3(g)
SNH3
=
SNH3
– Rln PNH3
SN2
=
SN2
– Rln PN2
SH2
=
SH2
– Rln PH2
ΔSrxn = 2(SNH3
– Rln PNH3
) – 2(SN2
– Rln PN2
) –3(SH2
– Rln PH2
)
ΔSrxn = 2 SNH3
– 2SN2
–3SH2
+ Rln
PN2
PH2
PNH3
2
2
3
ΔSrxn = ΔS°rxn + Rln
PN2
PH2
PNH3
2
2
3
Prentice-Hall General Chemistry: Chapter 20Slide 27 of 37
ΔG Under Non-standard Conditions
ΔG = ΔH° - TΔS ΔSrxn = ΔS°rxn + Rln
PN2
PH2
PNH3
2
2
3
ΔG = ΔH° - TΔS°rxn – TR ln
PN2
PH2
PNH3
2
2
3
ΔG = ΔG° + RT ln
PN2
PH2
2
PNH3
2
3
ΔG = ΔG° + RT ln Q
Prentice-Hall General Chemistry: Chapter 20Slide 28 of 37
ΔG and the Equilibrium Constant Keq
ΔG = ΔG° + RT ln Q
ΔG = ΔG° + RT ln Keq= 0
If the reaction is at equilibrium then:
ΔG° = -RT ln Keq
Prentice-Hall General Chemistry: Chapter 20Slide 29 of 37
Criteria for Spontaneous Change
Every chemical reaction consists of both a
forward and a reverse reaction.
The direction of spontaneous change is the direction
in which the free energy decreases.
Prentice-Hall General Chemistry: Chapter 20Slide 30 of 37
Significance of the Magnitude of ΔG
Prentice-Hall General Chemistry: Chapter 20Slide 31 of 37
The Thermodynamic Equilibrium
Constant: Activities
S = S° - R ln
P
P°
= S°- R ln
P
1
For ideal gases at 1.0 bar:
S = S° - R ln
c
c°
= S°- R ln a
Therefore, in solution:
PV=nRT or P=(n/V)RT, pressure is an effective concentration
The effective concentration in the standard
state for an ideal solution is c° = 1 M.
Prentice-Hall General Chemistry: Chapter 20Slide 32 of 37
Activities
• For pure solids and liquids:
»a = 1
• For ideal gases:
»a = P (in bars, 1 bar = 0.987 atm)
• For ideal solutes in aqueous solution:
»a = c (in mol L-1
)
Prentice-Hall General Chemistry: Chapter 20Slide 33 of 37
The Thermodynamic Equilibrium
Constant, Keq
• A dimensionless equilibrium constant expressed
in terms of activities.
• Often Keq = Kc
• Must be used to determine ΔG.
ΔG = ΔG° + RT ln
agah…
aaab…
Prentice-Hall General Chemistry: Chapter 20Slide 34 of 37
20-7 ΔG° and Keq as Functions
of Temperature
ΔG° = ΔH° -TΔS° ΔG° = -RT ln Keq
ln Keq =
-ΔG°
RT
=
-ΔH°
RT
TΔS°
RT
+
ln Keq =
-ΔH°
RT
ΔS°
R
+
ln =
-ΔH°
RT2
ΔS°
R
+
-ΔH°
RT1
ΔS°
R
+- =
-ΔH°
R
1
T2
1
T1
-
Keq1
Keq2
Prentice-Hall General Chemistry: Chapter 20Slide 35 of 37
Temperature Dependence of Keq
ln Keq =
-ΔH°
RT
ΔS°
R
+
slope =
-ΔH°
R
-ΔH° = R  slope
= -8.3145 J mol-1
K-1
 2.2104
K
= -1.8102
kJ mol-1
Prentice-Hall General Chemistry: Chapter 20Slide 36 of 37
20-8 Coupled Reactions
• In order to drive a non-spontaneous reactions we
changed the conditions (i.e. temperature or
electrolysis)
• Another method is to couple two reactions.
– One with a positive ΔG and one with a negative ΔG.
– Overall spontaneous process.
Prentice-Hall General Chemistry: Chapter 20Slide 37 of 37
Smelting Copper Ore
Cu2O(s) → 2 Cu(s) + ½ O2(g)ΔG°673K = +125 kJΔ
Cu2O(s) + C(s) → 2 Cu(s) + CO(g)
Spontaneous reaction!
Cu2O(s) → 2 Cu(s) + ½ O2(g)Non-spontaneous reaction: +125 kJ
C(s) + ½ O2(g) → CO(g)Spontaneous reaction: -175 kJ
-50 kJ
Prentice-Hall General Chemistry: Chapter 20Slide 38 of 37
Focus On Coupled Reactions in
Biological Systems
ADP3-
+ HPO4
2-
+ H+
→ ATP4-
+ H2O
ΔG° = -9.2 kJ mol-1
ΔG = ΔG° + RT ln
aATPaH2O
aADPaPi
aH3O+
But [H3O+
] = 10-7
M not 1.0 M.
ΔG = -9.2 kJ mol-1
+ 41.6 kJ mol-1
= +32.4 kJ mol-1
= ΔG°'The biological standard state:
Prentice-Hall General Chemistry: Chapter 20Slide 39 of 37
Focus On Coupled Reactions in
Biological Systems
Glucose → 2 lactate + 2 H+
-218 kJ
2 ADP3-
+ 2 HPO4
2-
+ 2 H+
→ 2 ATP4-
+ 2 H2O +64 kJ
2 ADP3-
+ 2 HPO4
2-
+ glucose → 2 ATP4-
+ 2 H2O + 2 lactate -153 kJ
Prentice-Hall General Chemistry: Chapter 20Slide 40 of 37
Chapter 20 Questions
Develop problem solving skills and base your strategy not
on solutions to specific problems but on understanding.
Choose a variety of problems from the text as examples.
Practice good techniques and get coaching from people who
have been here before.

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Ch20 130105201707-phpapp02

  • 1. Philip Dutton University of Windsor, Canada N9B 3P4 Prentice-Hall © 2002 General Chemistry Principles and Modern Applications Petrucci • Harwood • Herring 8th Edition Chapter 20: Spontaneous Change: Entropy and Free Energy
  • 2. Prentice-Hall General Chemistry: Chapter 20Slide 2 of 37 Contents 20-1 Spontaneity: The Meaning of Spontaneous Change 20-2 The Concept of Entropy 20-3 Evaluating Entropy and Entropy Changes 20-4 Criteria for Spontaneous Change: The Second Law of Thermodynamics 20-5 Standard Fee Energy Change, ΔG° 20-6 Free Energy Change and Equilibrium 20-7 ΔG° and Keqas Functions of Temperature 20-8 Coupled Reactions Focus On Coupled Reactions in Biological Systems
  • 3. Prentice-Hall General Chemistry: Chapter 20Slide 3 of 37 20-1 Spontaneity: The Meaning of Spontaneous Change
  • 4. Prentice-Hall General Chemistry: Chapter 20Slide 4 of 37 Spontaneous Process • A process that occurs in a system left to itself. – Once started, no external actions is necessary to make the process continue. • A non-spontaneous process will not occur without external action continuously applied. 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) H2O(s)  H2O(l)
  • 5. Prentice-Hall General Chemistry: Chapter 20Slide 5 of 37 Spontaneous Process • Potential energy decreases. • For chemical systems the internal energy U is equivalent to potential energy. • Berthelot and Thomsen 1870’s – Spontaneous change occurs in the direction in which the enthalpy of a system decreases. – Mainly true but there are exceptions.
  • 6. Prentice-Hall General Chemistry: Chapter 20Slide 6 of 37 20-2 The Concept of Entropy • Entropy, S. – The greater the number of configurations of the microscopic particles among the energy levels in a particular system, the greater the entropy of the system. ΔS > 0 spontaneous ΔU = ΔH = 0
  • 7. Prentice-Hall General Chemistry: Chapter 20Slide 7 of 37 The Boltzmann Equation for Entropy • States, S. – The microscopic energy levels available in a system. • Microstates, W. – The particular way in which particles are distributed amongst the states. Number of microstates = W. • The Boltzmann constant, k. – Effectively the gas constant per molecule = R/NA. S = k lnW
  • 8. Prentice-Hall General Chemistry: Chapter 20Slide 8 of 37 Boltzmann Distribution
  • 9. Prentice-Hall General Chemistry: Chapter 20Slide 9 of 37 Entropy Change ΔS = qrev T
  • 10. Prentice-Hall General Chemistry: Chapter 20Slide 10 of 37 20-3 Evaluating Entropy and Entropy Changes • Phase transitions. – Exchange of heat can be carried out reversibly. ΔS = ΔH Ttr H2O(s, 1 atm)  H2O(l, 1 atm) ΔHfus° = 6.02 kJ at 273.15 K ΔSfus = ΔHfus Ttr ° = 6.02 kJ mol-1 273.15 K = 2.2010-2 kJ mol-1 K-1
  • 11. Prentice-Hall General Chemistry: Chapter 20Slide 11 of 37 Trouton’s Rule ΔS = ΔHvap Tbp  87 kJ mol-1 K-1
  • 12. Prentice-Hall General Chemistry: Chapter 20Slide 12 of 37 Raoult’s Law °PA = χ APA
  • 13. Prentice-Hall General Chemistry: Chapter 20Slide 13 of 37 Absolute Entropies • Third law of thermodynamics. – The entropy of a pure perfect crystal at 0 K is zero. • Standard molar entropy. – Tabulated in Appendix D. ΔS = [ νpS°(products) - νrS°(reactants)]
  • 14. Prentice-Hall General Chemistry: Chapter 20Slide 14 of 37 Entropy as a Function of Temperature
  • 15. Prentice-Hall General Chemistry: Chapter 20Slide 15 of 37 Vibrational Energy and Entropy
  • 16. Prentice-Hall General Chemistry: Chapter 20Slide 16 of 37 20-4 Criteria for Spontaneous Change: The Second Law of Thermodynamics. ΔStotal = ΔSuniverse = ΔSsystem + ΔSsurroundings The Second Law of Thermodynamics: ΔSuniverse = ΔSsystem + ΔSsurroundings > 0 All spontaneous processes produce an increase in the entropy of the universe.
  • 17. Prentice-Hall General Chemistry: Chapter 20Slide 17 of 37 Free Energy and Free Energy Change • Hypothetical process: – only pressure-volume work, at constant T and P. qsurroundings = -qp = -ΔHsys • Make the enthalpy change reversible. – large surroundings, infinitesimal change in temperature. • Under these conditions we can calculate entropy.
  • 18. Prentice-Hall General Chemistry: Chapter 20Slide 18 of 37 Free Energy and Free Energy Change TΔSuniv. = TΔSsys – ΔHsys = -(ΔHsys – TΔSsys) -TΔSuniv. = ΔHsys – TΔSsys G = H - TS ΔG = ΔH - TΔS For the universe: For the system: ΔGsys = - TΔSuniverse
  • 19. Prentice-Hall General Chemistry: Chapter 20Slide 19 of 37 Criteria for Spontaneous Change ΔGsys < 0 (negative), the process is spontaneous. ΔGsys = 0 (zero), the process is at equilibrium. ΔGsys > 0 (positive), the process is non-spontaneous.
  • 20. Prentice-Hall General Chemistry: Chapter 20Slide 20 of 37 Table 20.1 Criteria for Spontaneous Change
  • 21. Prentice-Hall General Chemistry: Chapter 20Slide 21 of 37 20-5 Standard Free Energy Change, ΔG° • The standard free energy of formation, ΔGf°. – The free energy change for a reaction in which a substance in its standard state is formed from its elements in reference forms in their standard states. • The standard free energy of reaction, ΔG°. ΔG° = [ νp ΔGf°(products) - νr ΔGf°(reactants)]
  • 22. Prentice-Hall General Chemistry: Chapter 20Slide 22 of 37 20-6 Free Energy Change and Equilibrium
  • 23. Prentice-Hall General Chemistry: Chapter 20Slide 23 of 37 Free Energy Change and Equilibrium
  • 24. Prentice-Hall General Chemistry: Chapter 20Slide 24 of 37 Relationship of ΔG° to ΔG for Nonstandard Conditions 2 N2(g) + 3 H2(g)  2 NH3(g) ΔG = ΔH - TΔS ΔG° = ΔH° - TΔS° For ideal gases ΔH = ΔH° ΔG = ΔH° - TΔS
  • 25. Prentice-Hall General Chemistry: Chapter 20Slide 25 of 37 Relationship Between S and S° qrev = -w = RT ln Vf Vi ΔS = qrev T = R ln Vf Vi ΔS = Sf – Si = R ln Vf Vi = R ln Pi Pf = -R ln Pf Pi S = S° - R ln P P° = S°- R ln P 1 = S° - R ln P
  • 26. Prentice-Hall General Chemistry: Chapter 20Slide 26 of 37 2 N2(g) + 3 H2(g)  2 NH3(g) SNH3 = SNH3 – Rln PNH3 SN2 = SN2 – Rln PN2 SH2 = SH2 – Rln PH2 ΔSrxn = 2(SNH3 – Rln PNH3 ) – 2(SN2 – Rln PN2 ) –3(SH2 – Rln PH2 ) ΔSrxn = 2 SNH3 – 2SN2 –3SH2 + Rln PN2 PH2 PNH3 2 2 3 ΔSrxn = ΔS°rxn + Rln PN2 PH2 PNH3 2 2 3
  • 27. Prentice-Hall General Chemistry: Chapter 20Slide 27 of 37 ΔG Under Non-standard Conditions ΔG = ΔH° - TΔS ΔSrxn = ΔS°rxn + Rln PN2 PH2 PNH3 2 2 3 ΔG = ΔH° - TΔS°rxn – TR ln PN2 PH2 PNH3 2 2 3 ΔG = ΔG° + RT ln PN2 PH2 2 PNH3 2 3 ΔG = ΔG° + RT ln Q
  • 28. Prentice-Hall General Chemistry: Chapter 20Slide 28 of 37 ΔG and the Equilibrium Constant Keq ΔG = ΔG° + RT ln Q ΔG = ΔG° + RT ln Keq= 0 If the reaction is at equilibrium then: ΔG° = -RT ln Keq
  • 29. Prentice-Hall General Chemistry: Chapter 20Slide 29 of 37 Criteria for Spontaneous Change Every chemical reaction consists of both a forward and a reverse reaction. The direction of spontaneous change is the direction in which the free energy decreases.
  • 30. Prentice-Hall General Chemistry: Chapter 20Slide 30 of 37 Significance of the Magnitude of ΔG
  • 31. Prentice-Hall General Chemistry: Chapter 20Slide 31 of 37 The Thermodynamic Equilibrium Constant: Activities S = S° - R ln P P° = S°- R ln P 1 For ideal gases at 1.0 bar: S = S° - R ln c c° = S°- R ln a Therefore, in solution: PV=nRT or P=(n/V)RT, pressure is an effective concentration The effective concentration in the standard state for an ideal solution is c° = 1 M.
  • 32. Prentice-Hall General Chemistry: Chapter 20Slide 32 of 37 Activities • For pure solids and liquids: »a = 1 • For ideal gases: »a = P (in bars, 1 bar = 0.987 atm) • For ideal solutes in aqueous solution: »a = c (in mol L-1 )
  • 33. Prentice-Hall General Chemistry: Chapter 20Slide 33 of 37 The Thermodynamic Equilibrium Constant, Keq • A dimensionless equilibrium constant expressed in terms of activities. • Often Keq = Kc • Must be used to determine ΔG. ΔG = ΔG° + RT ln agah… aaab…
  • 34. Prentice-Hall General Chemistry: Chapter 20Slide 34 of 37 20-7 ΔG° and Keq as Functions of Temperature ΔG° = ΔH° -TΔS° ΔG° = -RT ln Keq ln Keq = -ΔG° RT = -ΔH° RT TΔS° RT + ln Keq = -ΔH° RT ΔS° R + ln = -ΔH° RT2 ΔS° R + -ΔH° RT1 ΔS° R +- = -ΔH° R 1 T2 1 T1 - Keq1 Keq2
  • 35. Prentice-Hall General Chemistry: Chapter 20Slide 35 of 37 Temperature Dependence of Keq ln Keq = -ΔH° RT ΔS° R + slope = -ΔH° R -ΔH° = R  slope = -8.3145 J mol-1 K-1  2.2104 K = -1.8102 kJ mol-1
  • 36. Prentice-Hall General Chemistry: Chapter 20Slide 36 of 37 20-8 Coupled Reactions • In order to drive a non-spontaneous reactions we changed the conditions (i.e. temperature or electrolysis) • Another method is to couple two reactions. – One with a positive ΔG and one with a negative ΔG. – Overall spontaneous process.
  • 37. Prentice-Hall General Chemistry: Chapter 20Slide 37 of 37 Smelting Copper Ore Cu2O(s) → 2 Cu(s) + ½ O2(g)ΔG°673K = +125 kJΔ Cu2O(s) + C(s) → 2 Cu(s) + CO(g) Spontaneous reaction! Cu2O(s) → 2 Cu(s) + ½ O2(g)Non-spontaneous reaction: +125 kJ C(s) + ½ O2(g) → CO(g)Spontaneous reaction: -175 kJ -50 kJ
  • 38. Prentice-Hall General Chemistry: Chapter 20Slide 38 of 37 Focus On Coupled Reactions in Biological Systems ADP3- + HPO4 2- + H+ → ATP4- + H2O ΔG° = -9.2 kJ mol-1 ΔG = ΔG° + RT ln aATPaH2O aADPaPi aH3O+ But [H3O+ ] = 10-7 M not 1.0 M. ΔG = -9.2 kJ mol-1 + 41.6 kJ mol-1 = +32.4 kJ mol-1 = ΔG°'The biological standard state:
  • 39. Prentice-Hall General Chemistry: Chapter 20Slide 39 of 37 Focus On Coupled Reactions in Biological Systems Glucose → 2 lactate + 2 H+ -218 kJ 2 ADP3- + 2 HPO4 2- + 2 H+ → 2 ATP4- + 2 H2O +64 kJ 2 ADP3- + 2 HPO4 2- + glucose → 2 ATP4- + 2 H2O + 2 lactate -153 kJ
  • 40. Prentice-Hall General Chemistry: Chapter 20Slide 40 of 37 Chapter 20 Questions Develop problem solving skills and base your strategy not on solutions to specific problems but on understanding. Choose a variety of problems from the text as examples. Practice good techniques and get coaching from people who have been here before.

Notes de l'éditeur

  1. Ludwig Boltzmann. Associated the number of energy levels in a system with the number of ways of arranging the particles in these levels.
  2. Failures of this rule are understandable: Water and hydrogen bonding. Sliquid is lower than expected so ΔS is larger than 87.
  3.  are the stoichiometric coefficients.
  4. Want to evaluate the system only, not the surroundings.
  5. Activity is the effective concentration divided by the effective concentration in the standard state.