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# Probability.pptx

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# Probability.pptx

Probability is the one of the most important topics in engineering because it helps us to understand some aspects of the future of an event. Probability is not only used in mathematics but also is various domains of engineering.

Probability is the one of the most important topics in engineering because it helps us to understand some aspects of the future of an event. Probability is not only used in mathematics but also is various domains of engineering.

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### Probability.pptx

1. 1. Probability 06-11-2022 1
2. 2. Definition  Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e., how likely they are going to happen, using it. Probability can range from 0 to 1, where 0 means the event to be an impossible one and 1 indicates a certain event.  Note: The probability of all the events in a sample space adds up to 1. 06-11-2022 2
3. 3. For example  when we toss a coin, either we get Head OR Tail, only two possible outcomes are possible (H, T). But when two coins are tossed then there will be four possible outcomes, i.e  {(H, H), (H, T), (T, H), (T, T)}. 06-11-2022 3
4. 4. Terminology of Probability Theory  The following terms in probability help in a better understanding of the concepts of probability.  Experiment: A trial or an operation conducted to produce an outcome is called an experiment.  Sample Space: All the possible outcomes of an experiment together constitute a sample space. For example, the sample space of tossing a coin is head and tail.  Favorable Outcome: An event that has produced the desired result or expected event is called a favorable outcome. For example, when we roll two dice, the possible/favorable outcomes of getting the sum of numbers on the two dice as 4 are (1,3), (2,2), and (3,1). 06-11-2022 4
5. 5.  Trial: A trial denotes doing a random experiment.  Random Experiment: An experiment that has a well-defined set of outcomes is called a random experiment. For example, when we toss a coin, we know that we would get ahead or tail, but we are not sure which one will appear.  Event: The total number of outcomes of a random experiment is called an event. 06-11-2022 5
6. 6.  Equally Likely Events: Events that have the same chances or probability of occurring are called equally likely events. The outcome of one event is independent of the other. For example, when we toss a coin, there are equal chances of getting a head or a tail.  Exhaustive Events: When the set of all outcomes of an experiment is equal to the sample space, we call it an exhaustive event.  Mutually Exclusive Events: Events that cannot happen simultaneously are called mutually exclusive events. For example, the climate can be either hot or cold. We cannot experience the same weather simultaneously. 06-11-2022 6
7. 7. Probability Formula  P(A)=Number of favorable cases/Total number of possible cases 06-11-2022 7
8. 8. Probability formula with addition:  Whenever an event is the union of two other events, say A and B, then  P(A or B) = P(A) + P(B) - P(A∩B)  P(A ∪ B) = P(A) + P(B) - P(A∩B) 06-11-2022 8
9. 9. Probability formula with the complementary rule:  Whenever an event is the complement of another event, specifically, if A is an event, then  P(not A) = 1 - P(A) or P(A') = 1 - P(A). P(A) + P(A′) = 1. OR  Complementary events occur when there are just two events, and one event is exactly opposite to the other event. Hence, A∪A¯= setofsamplespace  For an event with probability P(A), its complement is P(A¯) such that  P(A¯)+P(A)=1 06-11-2022 9
10. 10. Probability formula with the conditional rule:  When event A is already known to have occurred and the probability of event B is desired, then P(B, given A) = P(A and B), P(A, given B). It can be vice versa in the case of event B.  P(B∣A) = P(A∩B)/P(A)  Conditional Probability: This probability of the event E is called the conditional probability of E given that F has already occurred, and is denoted by P (E|F).  P(E|F) = Number of elementary events favorable to E∩F/Number of elementary events which are favorable to F  P(E|F) = n(E∩F)/n(F)  Or  P(E|F) = P(E∩F)/P(F) where P(F) ≠ 0 06-11-2022 10
11. 11. Example:  If P(A) = 7/13, P(B) = 9/13 and P(A∩B) = 4/13, evaluate P(A|B).  Solution: P(A|B) = P(A∩B)/P(B)  = (4/13)/(9/13)  = 4/9. 06-11-2022 11
12. 12. Example:  A coin is tossed 2 times. The toss resulted in one head and one tail. What is the probability that the first throw resulted in a tail?  Solution: The sample space of a coin tossed two times is given as  S = {HH, HT, TH, TT}  Let Event A be the first throw resulting in a tail.  Event B be that one tail and one head occurred. 06-11-2022 12
13. 13.  P(A)=P(TH,TT)/P(HH,HT,TH,TT)  =2/4  =1/2  P(A∩B)=P(TH)/P(HH,HT,TH,TT)  =1/4  So P(A/B)=P(A∩B)P(A)=1/4/1/2  =1/2  = 0.5 06-11-2022 13
14. 14. Probability formula with multiplication rule:  Whenever an event is the intersection of two other events, that is, events A and B need to occur simultaneously. Then P(A and B) = P(A)⋅P(B).  P(A∩B) = P(A)⋅P(B∣A) 06-11-2022 14
15. 15. Example:  A coin is tossed. What is the probability of getting a head?  Total number of equally likely outcomes (n) = 2 (i.e. head or tail)  Number of outcomes favorable to head (m) = 1  P(head)=1/2 06-11-2022 15
16. 16. For Mutually Exclusive Events  The additive theorem of probability states if A and B are two mutually exclusive events then the probability of either A or B is given by  P(A or B)=P(A)+P(B)  P(A∪B)=P(A)+P(B)  In the same way:  P(A∪B∪C) = P(A)+P(B)+P(C) 06-11-2022 16
17. 17. Example:  A card is drawn from a pack of 52, what is the probability that it is a king or a queen?  Let Event (A) = Draw of a card of king  Event (B) Draw of a card of queen  P (card draw is king or queen) = P (card is king) + P (card is queen)  P(A∪B)=P(A)+P(B)=4/52+4/52=1/13+1/13=2/13 06-11-2022 17
18. 18. For Non-Mutually Exclusive Events  In case there is a possibility of both events to occur then the additive theorem is written as:  P(A or B)= P(A)+P(B)−P(A and B)  P(A∪B) = P(A)+P(B)−P(AB) 06-11-2022 18
19. 19. Bayes' Theorem  Bayes' Theorem states that the conditional probability of an event, based on the occurrence of another event, is equal to the likelihood of the second event given the first event multiplied by the probability of the first event. 06-11-2022 19
20. 20. 06-11-2022 20 P(A∣B)= P(B)/P(A⋂B) =P(B)/P(A)⋅P(B∣A) where: P(A)= The probability of A occurring P(B)= The probability of B occurring P(A∣B)=The probability of A given B P(B∣A)= The probability of B given A P(A⋂B))= The probability of both A and B occurring Formula for Bays theorem
21. 21. 06-11-2022 21 Bayes’ Theorem Formula Derivation From conditional probability, the Bayes theorem can be given as follows. P(A|B) = P(A⋂B)/ P(B) Where, P(B) ≠ 0 P(B|A) = P(B⋂A)/ P(A) Where, P(A) ≠ 0 Here, the joint probability P(A ⋂ B) of both events A and B being true such that, P(B ⋂ A) = P(A⋂ B) P(A⋂ B) = P(A | B) P(B) = P(B | A) P(A) P(A|B) = [P(B|A) P(A)]/ P(B) Where, P(B) ≠ 0
22. 22. Types of Probability  There can be different perspectives or types of probabilities based on the nature of the outcome or the approach followed while finding the probability of an event happening. The four types of probabilities are, • Classical Probability • Empirical Probability • Subjective Probability • Axiomatic Probability 06-11-2022 22
23. 23.  . Theoretical Probability  Theoretical probability is based on the possible chances of something happening. It is based on what is expected to happen in an experiment without conducting it. It is the ratio of the number of favorable outcomes to the total number of outcomes.  2. Experimental Probability  Experimental probability is a probability that is determined based on a series of experiments. Therefore, it is based on the data which is obtained after an experiment is carried out. It is the ratio of the number of times an event occurs to the total number of experiments that are conducted. 06-11-2022 23
24. 24.  3. Axiomatic Probability  In axiomatic probability, a set of rules or axioms are set, which applies to all types. In this probability, the chances of occurrence and non-occurrence of the events can be quantified. It is the likelihood of an event or outcome occurring based on the occurrence of a previous event or outcome. 06-11-2022 24
25. 25. 06-11-2022 25 All Probability Formulas Let A and B are two events. The probability formulas are listed below: Range of Probability 0⩽P(A)⩽1 Addition rule of Probability P(A∪B)=P(A)+P(B)−P(A∩B) Complementary event P(A¯)=1–P(A) Mutually exclusive events P(A∩B)=0 Independent events P(A∩B)=P(A)×P(B) Bayes formula P(AB)=P(B/A)×P(A)/P(B)
26. 26.  What is the probability of a sure event?  Ans: The probability of a sure event is one.  P(E)=1  Can a probability be negative?  Ans: The probability value of the event can not be negative. It is a positive value between 0 and 1.  What is the probability of an impossible event?  Ans: The probability of an impossible event is 0. 06-11-2022 26
27. 27. Practice questions: 1)  Two coins are tossed 500 times, and we get:  Two heads: 105 times  One head: 275 times  No head: 120 times  Find the probability of each event to occur.  Solution: Let us say the events of getting two heads, one head and no head by E1, E2 and E3, respectively. 06-11-2022 27
28. 28.  P(E1) = 105/500 = 0.21  P(E2) = 275/500 = 0.55  P(E3) = 120/500 = 0.24  The Sum of probabilities of all elementary events of a random experiment is 1.  P(E1)+P(E2)+P(E3) = 0.21+0.55+0.24 = 1 06-11-2022 28
29. 29. 2)  One card is drawn from a deck of 52 cards, well-shuffled. Calculate the probability that the card will  (i) be an ace,  (ii) not be an ace.  Solution: Well-shuffling ensures equally likely outcomes.  (i) There are 4 aces in a deck.  Let E be the event the card drawn is ace.  The number of favourable outcomes to the event E = 4 06-11-2022 29
30. 30.  The number of possible outcomes = 52  Therefore, P(E) = 4/52 = 1/13  (ii) Let F is the event of ‘card is not an ace’  The number of favorable outcomes to F = 52 – 4 = 48  The number of possible outcomes = 52  Therefore, P(F) = 48/52 = 12/13 06-11-2022 30
31. 31. 3)  Two players, Sangeet and Rashmi, play a tennis match. The probability of Sangeet winning the match is 0.62. What is the probability that Rashmi will win the match?  Solution: Let S and R denote the events that Sangeeta wins the match and Reshma wins the match, respectively.  The probability of Sangeet to win = P(S) = 0.62  The probability of Rashmi to win = P(R) = 1 – P(S)  = 1 – 0.62 = 0.38 06-11-2022 31
32. 32. 4)  Consider the experiment of rolling a die. Let A be the event ‘getting a prime number’, B be the event ‘getting an odd number’. Write the sets representing the events  (i) Aor B  (ii) A and B  (iii) A but not B  (iv) ‘not A’. 06-11-2022 32
33. 33. Solutions:  S = {1, 2, 3, 4, 5, 6}, A = {2, 3, 5} and B = {1, 3, 5}  (i) A or B = A ∪ B = {1, 2, 3, 5}  (ii) A and B = A ∩ B = {3,5}  (iii) A but not B = A – B = {2}  (iv) not A = A′ = {1,4,6} 06-11-2022 33
34. 34. 5) A coin is tossed three times, consider the following events.  P: ‘No head appears’,  Q: ‘Exactly one head appears’ and  R: ‘At Least two heads appear’.  Check whether they form a set of mutually exclusive and exhaustive events 06-11-2022 34
35. 35.  Solution: The sample space of the experiment is:  S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} and  P = {TTT},  Q = {HTT, THT, TTH},  R = {HHT, HTH, THH, HHH}  P ∪ Q ∪ R = {TTT, HTT, THT, TTH, HHT, HTH, THH, HHH} = S  Therefore, P , Q and R are exhaustive events. 06-11-2022 35
36. 36.  And  P ∩ Q = φ,  P ∩ R = φ and  Q ∩ R = φ  Therefore, the events are mutually exclusive.  Hence, P, Q and R form a set of mutually exclusive and exhaustive events. 06-11-2022 36
37. 37. Practice problems:1)  5 cards are drawn successively from a well-shuffled pack of 52 cards with replacement. Determine the probability that (i) all the five cards should be spades? (ii) only 3 cards should be spades? (iii) none of the cards is a spade? 06-11-2022 37
38. 38. 2)  A single card is drawn at random from a standard deck of 52 playing cards. Find the Probability:  1) The card is either a red or an ace  2) The card is not a king  3) The card is a king or queen 06-11-2022 38
39. 39. Practice questions:  A bag contains 2 yellow,3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?  Solutions: Total number of balls =2+3+2=7=2+3+2=7  Let S be the sample space.  n(S) = Total number of ways of drawing 2 balls out of 7 = 7C2  Let E = Event of drawing 2 balls, none of them is blue. 06-11-2022 39
40. 40.  n(E) = Number of ways of drawing 2 balls , none of them is blue= Number of ways of drawing 22 balls from the total 5 (=7−2) balls = 5C2  (∵ There are two blue balls in the total seven balls. Total number of non-blue balls =7−2=5=7−2=5)  P(E)=n(E)/n(S) = 5C2 / 7C2  (5×4/2×1) / (7×6/2×1)=10/21 06-11-2022 40
41. 41. Question:  1) A letter is randomly taken from English alphabets. What is the probability that the letter selected is not a vowel?  Ans: 21/26  2) The probability A getting a job is 1/5 and that of B is 1/7 What is the probability that only one of them gets a job? Ans: 2/7  3) A letter is chosen at random from the word 'ASSASSINATION'. What is the probability that it is a vowel?  Ans: 6/13 06-11-2022 41
42. 42.  4) Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?  Ans: 9/20  Explanation:  Total number of tickets, n(S)=20 To get a multiple of 3 or 5 ticket drawn must be 3,5,6,9,10,12,15,18 or 20 Therefore, number of ways in which we get a multiple of 3 or 5 = 9 P(multiple of 3 or 5) =9/20 06-11-2022 42