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Chemistry Unit Three Atomic Structure
A Brief History of the Atomic Theory
Democritus ,[object Object],[object Object],[object Object],[object Object]
John Dalton ,[object Object],[object Object],[object Object],[object Object],[object Object]
J.J. Thomson ,[object Object],[object Object],[object Object],[object Object],[object Object],Cathode Ray Experiments; discovered the electron.
Ernest Rutherford ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Gold Foil Experiment Rutherford’s
[object Object],[object Object],[object Object],[object Object]
Neils Bohr ,[object Object],[object Object],[object Object],[object Object],Labeled each energy level by a quantum number.
[object Object],[object Object],[object Object],Wave Model
Electron Cloud Model ,[object Object],[object Object],[object Object],Quantum Model
Atomic Structure Found in the  Nucleus Found in the  Nucleus Found  outside  the nucleus Has  1  amu of mass Has  1  amu of mass Has  0  amu of mass Has a  positive  charge Has a  negative  charge Has  no  charge (neutral) Electrons (e-) Neutrons (n) Protons (p+)
Atomic Structure Atom The number of  protons  in an atom never changes. Isotope Atoms of the same element that have different numbers of  neutrons. Ion An atom that has lost or gained  electrons .
Atomic Mass ,[object Object],[object Object]
Atomic Structure ,[object Object],[object Object],[object Object]
6 C 12.011 Atomic Number   = 6 6 protons = 6 electrons 6 p+  =  6 e- (atom is neutral) Atomic Mass  = 12 12 p+ and n -6 p+ 6 neutrons Calculating Numbers of Protons, Neutrons and Electrons.
Practice Calculating p+, n, e- *Atomic # is number of protons so protons = 47 *number (+) charges (p+) must equal (–) charges to make the atom neutral so electrons = 47 *Mass Number is total particles with mass  (p+ and n) so 47 + 61 = 108 47 47 108 61 47 Silver # neutron # electron # proton Mass Number Atomic number Element
B Practice Calculating p+, n, e- *number of protons is the atomic #  so atomic number is 29 *number (+) charges (p+) must equal (–) charges to make the atom neutral so electrons = 29 *Mass Number is total of all particles with mass  (p+ and n) so subtract away the atomic number (#p+) and you will have just neutrons (64 – 29 = 35) 35 29 29 29 64 Copper # neutron # electron # proton Mass Number Atomic number Element
Practice Calculating p+, n, e- ,[object Object],[object Object],[object Object],[object Object],50 50 119 2 2 2 5 5 5 Is # p+ + = - (neutral) + = - (neutral) p +  + n Is # p+ Mass # - atomic # Mass #- n + = - (neutral) Is # p+ 6 11 Boron 2 4 Helium 69 50 Tin # neutron # electron # proton Mass Number Atomic number Element
Bohr Models ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],e -  e - e -  e - e -  e - e -   e -   e -   e -   e -   e -   e -   e -   e -   e -   e -   e -
Bohr Model of Lithium 3 4 e - e - e - 3 Li 6.941
Bohr Model of Argon 18 22 e - e - e - 18 Ar 39.948 e - e - e - e - e - e - e - e - e - e - e - e - e - e - e -
Electron Configuration ,[object Object],[object Object]
Rules for Electron Configuration ,[object Object],[object Object],[object Object]
Determining Electron Configurations ,[object Object],[object Object],[object Object]
Number of Electrons per Sublevel ,[object Object],[object Object],s 1 2 p 3 6 d 5 10 f 7 14
s and p Orbital Electrons
d Orbital Electrons
f Orbital Electrons
Periodic Table to remember order s 1 s 2 s 2 p 1 p 2 p 3 p 4 p 5 p 6 d 1 d 2 d 3 d 4 d 5 d 6 d 7 d 8 d 9 d 10 f 1 f 2 f 3 f 4 f 5 f 6 f 7 f 8 f 9 f 10 f 11 f 12 f 13 f 14 Sublevels (s,p,d,f) by columns - Energy levels by rows (1,2,3,4,5,6,7 except d(row-1) & f(row-2))  1 2 3 4 5 6 7 X – 1s 2 2s 2 2p 6 3s 2 3p 4   (16 e-) Y – 1s 2 2s 2 2p 6 3s 2 3p 6  4s 2 3d 10 4p 6 5s 1 (36 e-)  X Y
Example 1 ,[object Object],[object Object],He
Example 2 ,[object Object],[object Object],Li
Example 3 ,[object Object],[object Object],Be
Example 4 ,[object Object],[object Object],[object Object],Si
Lewis Dot Structures ,[object Object],[object Object],[object Object],[object Object],[object Object]
Lewis Dot Structures Con’t B B = Kernel   (The protons, neutrons and full electron shells.) Valence shell electrons
You can use the Electron Configuration to get the Lewis Dot Structure… ,[object Object],[object Object],[object Object],[object Object],Ca
One Final Example ,[object Object],[object Object],[object Object],[object Object],Sn
How to place electrons on a Lewis Dot ,[object Object],[object Object]
Ne 1 2 3 4 5 6 7 8 So, it goes like this…
Percent Abundance ,[object Object],[object Object],[object Object],[object Object]
Average Atomic Mass (How the number ends up on the periodic table!!) 1 st      Mass of one isotope x % abundance in decimal form (watch SIG FIGS!!) 2 nd     Do this for each isotope of that element  3 rd     Then add all individual isotopes together to get the average atomic  mass.
1. Calculate the average atomic mass of potassium using the following data: Potassium-39   38.964 amu x   0.9312 =   36.28 amu Potassium-41   40.962 amu x   0.0688 2.82 amu =   +   Average atomic mass for K =   39.10 amu 6.88 % 40.962 amu Potassium-41  93.12% 38.964 amu Potassium-39 % abundance Mass Isotope
2. Calculate the average atomic mass of magnesium using the following data: Magnesium-24 23.985 amu x   0.7870 =   18.88 amu Magnesium-25 24.986 amu x   0.1013 2.531 amu =   +   Average atomic mass for K =   24.31 amu +   Magnesium-26 25.983 amu x   0.1117 =   2.902 amu 11.17 % 25.983 amu Magnesium-26 10.13 % 24.986 amu Magnesium-25 78.70% 23.985 amu Magnesium-24 % abundance Mass Isotope

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Unit three notes s05

  • 1. Chemistry Unit Three Atomic Structure
  • 2. A Brief History of the Atomic Theory
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  • 7. Gold Foil Experiment Rutherford’s
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  • 12. Atomic Structure Found in the Nucleus Found in the Nucleus Found outside the nucleus Has 1 amu of mass Has 1 amu of mass Has 0 amu of mass Has a positive charge Has a negative charge Has no charge (neutral) Electrons (e-) Neutrons (n) Protons (p+)
  • 13. Atomic Structure Atom The number of protons in an atom never changes. Isotope Atoms of the same element that have different numbers of neutrons. Ion An atom that has lost or gained electrons .
  • 14.
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  • 16. 6 C 12.011 Atomic Number = 6 6 protons = 6 electrons 6 p+ = 6 e- (atom is neutral) Atomic Mass = 12 12 p+ and n -6 p+ 6 neutrons Calculating Numbers of Protons, Neutrons and Electrons.
  • 17. Practice Calculating p+, n, e- *Atomic # is number of protons so protons = 47 *number (+) charges (p+) must equal (–) charges to make the atom neutral so electrons = 47 *Mass Number is total particles with mass (p+ and n) so 47 + 61 = 108 47 47 108 61 47 Silver # neutron # electron # proton Mass Number Atomic number Element
  • 18. B Practice Calculating p+, n, e- *number of protons is the atomic # so atomic number is 29 *number (+) charges (p+) must equal (–) charges to make the atom neutral so electrons = 29 *Mass Number is total of all particles with mass (p+ and n) so subtract away the atomic number (#p+) and you will have just neutrons (64 – 29 = 35) 35 29 29 29 64 Copper # neutron # electron # proton Mass Number Atomic number Element
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  • 21. Bohr Model of Lithium 3 4 e - e - e - 3 Li 6.941
  • 22. Bohr Model of Argon 18 22 e - e - e - 18 Ar 39.948 e - e - e - e - e - e - e - e - e - e - e - e - e - e - e -
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  • 27. s and p Orbital Electrons
  • 30. Periodic Table to remember order s 1 s 2 s 2 p 1 p 2 p 3 p 4 p 5 p 6 d 1 d 2 d 3 d 4 d 5 d 6 d 7 d 8 d 9 d 10 f 1 f 2 f 3 f 4 f 5 f 6 f 7 f 8 f 9 f 10 f 11 f 12 f 13 f 14 Sublevels (s,p,d,f) by columns - Energy levels by rows (1,2,3,4,5,6,7 except d(row-1) & f(row-2)) 1 2 3 4 5 6 7 X – 1s 2 2s 2 2p 6 3s 2 3p 4 (16 e-) Y – 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 1 (36 e-) X Y
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  • 36. Lewis Dot Structures Con’t B B = Kernel (The protons, neutrons and full electron shells.) Valence shell electrons
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  • 40. Ne 1 2 3 4 5 6 7 8 So, it goes like this…
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  • 42. Average Atomic Mass (How the number ends up on the periodic table!!) 1 st  Mass of one isotope x % abundance in decimal form (watch SIG FIGS!!) 2 nd  Do this for each isotope of that element 3 rd  Then add all individual isotopes together to get the average atomic mass.
  • 43. 1. Calculate the average atomic mass of potassium using the following data: Potassium-39 38.964 amu x 0.9312 = 36.28 amu Potassium-41 40.962 amu x 0.0688 2.82 amu = + Average atomic mass for K = 39.10 amu 6.88 % 40.962 amu Potassium-41 93.12% 38.964 amu Potassium-39 % abundance Mass Isotope
  • 44. 2. Calculate the average atomic mass of magnesium using the following data: Magnesium-24 23.985 amu x 0.7870 = 18.88 amu Magnesium-25 24.986 amu x 0.1013 2.531 amu = + Average atomic mass for K = 24.31 amu + Magnesium-26 25.983 amu x 0.1117 = 2.902 amu 11.17 % 25.983 amu Magnesium-26 10.13 % 24.986 amu Magnesium-25 78.70% 23.985 amu Magnesium-24 % abundance Mass Isotope