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Electron

Proton
Neutron
MICHAEL FARADAY

In 1838, Michael Faraday passed current through the
  glass tube filled with rarefied air. Conducting the
  experiment he noticed a strange light arc with its
  beginning at the anode (the positive electrode) and
  its end almost at the cathode (the negative
  electrode). The only place where there was no
  luminescence was just in front of the cathode. The
  place is called "cathode dark space", "Faraday dark
  space", or "Crookes dark space". That was the
  beginning of the long and "turbulent" time of
  researches on that luminescence. And the
  luminescence is called "cathode rays".
In this experiment, Faraday showed
 that the mass of elements was
 proportional to the quantity of
 electricity that passed through
 them.
2. George J. Stoney- he was a
 scientist who first suggested the
 term “ Electron” to refer to a
 negatively charged particle.
   3. Joseph John Thomson-was credited for
    his discovery of the first subatomic particle
    through his work with the discharge tube.
   4. Robert A. Millikan- independently
    measured the electrons charge through his
    OIL-DROP Experiment. He successfully
    attempted to detect and measure the
    effect of an individual subatomic particle.
Using an atomizer, Millikan sprayed
 tiny droplets of oil which passed
 between two charged plates. Given a
 negative charge(-) by the electrons
 released from gas particles by x-rays,
 the oil particles were attracted toward
 the positive plate. He observed the
 speed of the droplets as they moved
 toward the positive plates. The
 smallest possible charge on a droplet
 was taken as the charge of an
 individual atom.
The quantity is considered to be the basic unit
 charge and is given a value of one minus (1-)
When the electron was
  discovered , the scientists
  searched for the positively
  charged particles.
1.Eugene Goldstein-
   Goldstein observed rays passing
    through the hole of a cathode in the
    cathode tube. These rays are made up
    of positive particles. Their
    characteristics depend on the gas
    inside the cathode tube.The lightest
    particle was obtained when Hydrogen
    gas was used.
1.   Sir James Chadwick- discovered
                   the neutron in 1932.
                   He found out that
                   the particle was
                      electrically neutral
         an                   and its mass
         was
                    approximately the
                       same as that of the
                       proton.
Proton

   Symbol                p+

Position in atom   Inside the nucleus

Relative charge          1+
Relative mass            1

Actual mass ( g)
                   1.673x10-24
Neutron

   Symbol                 n

Position in atom     Inside the nucleus

Relative charge           0
Relative mass             1

Actual mass
                   1.675x10     -24
Electron
                              −
    Symbol                e
Position in atom   moving around the nucleus

Relative charge          -1
                          1
  Relative mass              ≈0
                        1840
   Actual mass     9.109x10-28
Atomic structure
                     e - - - - - - - - electron

e
        n (s)
        p (s)   - - - - - - - - - - - - - - - nucleus
                     e

                         e
    e
Atomic content of an atom
           11e −
                   no. of protons = 11

                   no. of electrons =11
     12n
     11p
                   no. of neutrons = 12
                          23
                   Symbol 11   Na
12
Atomic Content of               6   C
   no. of protons = 6

   no. of neutrons = 12 - 6
                     =6

   no. of electrons = 6

   (An atom is neutral in charge)
14
Atomic Content of      :7    N
   no. of protons = 7
   no. of electrons = 7
   no. of neutrons = 14 – 7
                     =7
14
Atomic Content of          6   C
   no. of protons = 6

  no. of neutrons = 14 – 6
                     =8
  no. of electrons = 6
mass number

   14                     12
    6   C                  6   C
          atomic number


Mass number = no. of p + no. of n
atomic number = no. of protons
Isotopes
                                   12
                        14
                         6   C      6   C
  Name of element :     carbon      carbon

  No. of protons :       6            6

  No. of neutrons :      8            6

  No. of electrons :     6              6

Isotopes are atoms of same elements which have the same
atomic number but different mass number
Isotopes
                   14                12
                    6   C             6   C
Burn in air   Carbon dioxide Carbon dioxide

   Mass          14 units          12 units

Radioactivity Give radiation     Does not give
                               radiation (stable)
Extension : Isotopes ( For reference only )

         8n
         6p
                                    7n
                                    7p   + e +γ
                                              −
                                               0
                                               1
  14                        14
   6   C nucleus             7    N nucleus

A neutron in a nucleus of   14
                                 C breaks into 1 p + e −.
                                                    1
Electrons and energy are emitted to the surroundings
  Carbon -14 dating
Properties of isotopes
 Same chemical properties

 Different physical properties
 e.g. mass
        b.p. and m.p.
        radioactivity
Actual mass VS relative mass
          12
Mass of 1
           6   C   atom = 1.993 ×10 −26 kg       Or 12

Which one is more convenience?

Relative mass
                                        mass of 1 12C
                                                    6
Standard reference : 1 is equivalent to
                                              12
                                        = 1.661 × 10 − 27 kg
Simplified rule : We regard
 Relative mass of 1p = 1

 Relative mass of 1n = 1

 Relative mass of 1e = very small
                     =0
Relative mass of isotopes
                 28          29          30
                 14   Si     14   Si     14   Si
Relative mass     28             29           30

% abundance       92%         4.7%        3.1%

Do the three isotopes have the same chemical properties?

                           Yes
Relative atomic mass of isotopes

 It is difficult and not necessary
 to separate the isotopes in most
 of the reactions. Average
 relative mass of silicon is used to
 denote the mass of a silicon
 atom.
Relative atomic mass of silicon ( P.5 e.g.1 )
                28        29         30
                14   Si   14   Si    14   Si
Relative mass    28        29         30
% abundance      92%      4.7%        3.1%

    ( Relative ) Atomic Mass of silicon
           = 28 x 92% + 29 x 4.7% + 30 x 3.1%
           = 28.053
           = 28.05
Ex1. Relative atomic mass of Chlorine
                  35             37
                  17   Cl        17   Cl
  Relative mass      35               37

  % abundance      75.5%          24.5%

Atomic mass of Chlorine = 35 x 75.5% + 37 x 24.5%

                        = 35.5

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The three subatomic particles

  • 2.
  • 3. MICHAEL FARADAY In 1838, Michael Faraday passed current through the glass tube filled with rarefied air. Conducting the experiment he noticed a strange light arc with its beginning at the anode (the positive electrode) and its end almost at the cathode (the negative electrode). The only place where there was no luminescence was just in front of the cathode. The place is called "cathode dark space", "Faraday dark space", or "Crookes dark space". That was the beginning of the long and "turbulent" time of researches on that luminescence. And the luminescence is called "cathode rays".
  • 4.
  • 5. In this experiment, Faraday showed that the mass of elements was proportional to the quantity of electricity that passed through them. 2. George J. Stoney- he was a scientist who first suggested the term “ Electron” to refer to a negatively charged particle.
  • 6. 3. Joseph John Thomson-was credited for his discovery of the first subatomic particle through his work with the discharge tube.
  • 7.
  • 8. 4. Robert A. Millikan- independently measured the electrons charge through his OIL-DROP Experiment. He successfully attempted to detect and measure the effect of an individual subatomic particle.
  • 9.
  • 10.
  • 11. Using an atomizer, Millikan sprayed tiny droplets of oil which passed between two charged plates. Given a negative charge(-) by the electrons released from gas particles by x-rays, the oil particles were attracted toward the positive plate. He observed the speed of the droplets as they moved toward the positive plates. The smallest possible charge on a droplet was taken as the charge of an individual atom.
  • 12. The quantity is considered to be the basic unit charge and is given a value of one minus (1-)
  • 13. When the electron was discovered , the scientists searched for the positively charged particles. 1.Eugene Goldstein-
  • 14. Goldstein observed rays passing through the hole of a cathode in the cathode tube. These rays are made up of positive particles. Their characteristics depend on the gas inside the cathode tube.The lightest particle was obtained when Hydrogen gas was used.
  • 15. 1. Sir James Chadwick- discovered  the neutron in 1932.  He found out that  the particle was  electrically neutral an and its mass was  approximately the  same as that of the  proton.
  • 16.
  • 17. Proton Symbol p+ Position in atom Inside the nucleus Relative charge 1+ Relative mass 1 Actual mass ( g) 1.673x10-24
  • 18. Neutron Symbol n Position in atom Inside the nucleus Relative charge 0 Relative mass 1 Actual mass 1.675x10 -24
  • 19. Electron − Symbol e Position in atom moving around the nucleus Relative charge -1 1 Relative mass ≈0 1840 Actual mass 9.109x10-28
  • 20. Atomic structure e - - - - - - - - electron e n (s) p (s) - - - - - - - - - - - - - - - nucleus e e e
  • 21. Atomic content of an atom 11e − no. of protons = 11 no. of electrons =11 12n 11p no. of neutrons = 12 23 Symbol 11 Na
  • 22. 12 Atomic Content of 6 C  no. of protons = 6  no. of neutrons = 12 - 6 =6  no. of electrons = 6  (An atom is neutral in charge)
  • 23. 14 Atomic Content of :7 N  no. of protons = 7  no. of electrons = 7  no. of neutrons = 14 – 7 =7
  • 24. 14 Atomic Content of 6 C  no. of protons = 6  no. of neutrons = 14 – 6 =8  no. of electrons = 6
  • 25. mass number 14 12 6 C 6 C atomic number Mass number = no. of p + no. of n atomic number = no. of protons
  • 26. Isotopes 12 14 6 C 6 C Name of element : carbon carbon No. of protons : 6 6 No. of neutrons : 8 6 No. of electrons : 6 6 Isotopes are atoms of same elements which have the same atomic number but different mass number
  • 27. Isotopes 14 12 6 C 6 C Burn in air Carbon dioxide Carbon dioxide Mass 14 units 12 units Radioactivity Give radiation Does not give radiation (stable)
  • 28. Extension : Isotopes ( For reference only ) 8n 6p 7n 7p + e +γ − 0 1 14 14 6 C nucleus 7 N nucleus A neutron in a nucleus of 14 C breaks into 1 p + e −. 1 Electrons and energy are emitted to the surroundings Carbon -14 dating
  • 29. Properties of isotopes  Same chemical properties  Different physical properties  e.g. mass b.p. and m.p. radioactivity
  • 30. Actual mass VS relative mass 12 Mass of 1 6 C atom = 1.993 ×10 −26 kg Or 12 Which one is more convenience? Relative mass mass of 1 12C 6 Standard reference : 1 is equivalent to 12 = 1.661 × 10 − 27 kg
  • 31. Simplified rule : We regard Relative mass of 1p = 1 Relative mass of 1n = 1 Relative mass of 1e = very small =0
  • 32. Relative mass of isotopes 28 29 30 14 Si 14 Si 14 Si Relative mass 28 29 30 % abundance 92% 4.7% 3.1% Do the three isotopes have the same chemical properties? Yes
  • 33. Relative atomic mass of isotopes It is difficult and not necessary to separate the isotopes in most of the reactions. Average relative mass of silicon is used to denote the mass of a silicon atom.
  • 34. Relative atomic mass of silicon ( P.5 e.g.1 ) 28 29 30 14 Si 14 Si 14 Si Relative mass 28 29 30 % abundance 92% 4.7% 3.1% ( Relative ) Atomic Mass of silicon = 28 x 92% + 29 x 4.7% + 30 x 3.1% = 28.053 = 28.05
  • 35. Ex1. Relative atomic mass of Chlorine 35 37 17 Cl 17 Cl Relative mass 35 37 % abundance 75.5% 24.5% Atomic mass of Chlorine = 35 x 75.5% + 37 x 24.5% = 35.5