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LO:	
  Simple	
  Pendulum	
  
	
  
You	
  are	
  swinging	
  a	
  coin	
  suspended	
  from	
  a	
  string	
  of	
  length	
  0.5m	
  from	
  side	
  to	
  side	
  
(on	
  a	
  2-­‐dimensional	
  plane).	
  You	
  are	
  in	
  a	
  lab	
  and	
  measure	
  with	
  some	
  instruments	
  
that	
  the	
  net	
  tangential	
  force	
  at	
  a	
  certain	
  point	
  in	
  time	
  is	
  20N	
  and	
  the	
  tension	
  force	
  in	
  
the	
  string	
  at	
  that	
  point	
  in	
  time	
  is	
  10N.	
  Before	
  you	
  do	
  anything	
  else,	
  Joss	
  “The	
  Boss”	
  
Ives	
  (your	
  Physics	
  101	
  professor)	
  jumps	
  in	
  to	
  help	
  you	
  measure	
  the	
  mass	
  of	
  the	
  
coin,	
  but	
  manages	
  to	
  tip	
  over	
  a	
  water-­‐filled	
  graduated	
  cylinder	
  and	
  break	
  the	
  scale.	
  
He	
  quickly	
  apologizes,	
  but	
  you	
  don’t	
  worry	
  because	
  you	
  know	
  how	
  to	
  find	
  the	
  mass	
  
using	
  the	
  whiz-­‐kid	
  physics	
  powers	
  Joss	
  taught	
  you	
  in	
  your	
  lectures	
  (which	
  you	
  
happen	
  to	
  attend	
  with	
  the	
  greatest	
  enthusiasm!).	
  	
  
	
  
Part	
  a)	
  Find	
  the	
  mass	
  of	
  the	
  coin	
  that	
  was	
  suspended	
  from	
  the	
  string.	
  	
  
	
  
Part	
  b)	
  Out	
  of	
  curiosity,	
  you	
  also	
  want	
  to	
  find	
  the	
  displacement	
  at	
  that	
  point.	
  In	
  
other	
  words,	
  find	
  s	
  (hint:	
  arc	
  distance).	
  
	
  
Part	
  c)	
  Find	
  the	
  frequency	
  and	
  the	
  angular	
  frequency	
  of	
  oscillation	
  of	
  the	
  pendulum.	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
	
  
Length = 0.5m
s = ?
m = ?
T = 10N
Fnet,t = 20N
 
	
  
Solution:	
  
	
  
Given	
  Information:	
  
FT	
  =	
  10N	
  
Fnet,t	
  =	
  20N	
  
	
  
Relevant	
  Equations:	
  
	
  T	
  =	
  mgcos	
  θ	
  
Fnet,t	
  =	
  -­‐mgsin	
  θ	
  
s	
  =	
  Lθ	
  
f	
  	
  =	
  ω/2π	
  =	
  (1/2π)*sqrt(g/L)	
  
	
  
Part	
  a)	
  
|
𝐹!"#,!
𝑇
| = |
−mgsin 𝜃
mgcos 𝜃
| = | −
sin 𝜃
cos 𝜃
| = tan 𝜃	
  
	
  
𝜃 = tan!!
𝐹!"#,!
𝑇
	
  
	
  
𝐹!"#,! = −𝑚𝑔 sin 𝜃	
  
𝑚 = −
𝐹!"#,!
𝑔 sin 𝜃
	
  
	
  
𝜃 = tan!!
20𝑁
10𝑁
≅   1.11°	
  
	
  
𝑚 =
20𝑁
(9.8)(sin 1.11°)
≅ 2.29𝑘𝑔	
  
	
  
Part	
  b)	
  
	
  
𝑠 = 𝐿𝜃	
  
𝑠 = 0.5𝑚 1.11° ≅ 0.56𝑚	
  
	
  
Part	
  c)	
  
𝑓 =  
1
2𝜋
𝑔
𝐿
=
1
2𝜋
9.8
0.5𝑚
≅ 0.71  𝐻𝑧	
  
𝜔 = 2𝜋𝑓 ≅ 4.46
𝑟𝑎𝑑
𝑠
  	
  

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Learning object #2

  • 1. LO:  Simple  Pendulum     You  are  swinging  a  coin  suspended  from  a  string  of  length  0.5m  from  side  to  side   (on  a  2-­‐dimensional  plane).  You  are  in  a  lab  and  measure  with  some  instruments   that  the  net  tangential  force  at  a  certain  point  in  time  is  20N  and  the  tension  force  in   the  string  at  that  point  in  time  is  10N.  Before  you  do  anything  else,  Joss  “The  Boss”   Ives  (your  Physics  101  professor)  jumps  in  to  help  you  measure  the  mass  of  the   coin,  but  manages  to  tip  over  a  water-­‐filled  graduated  cylinder  and  break  the  scale.   He  quickly  apologizes,  but  you  don’t  worry  because  you  know  how  to  find  the  mass   using  the  whiz-­‐kid  physics  powers  Joss  taught  you  in  your  lectures  (which  you   happen  to  attend  with  the  greatest  enthusiasm!).       Part  a)  Find  the  mass  of  the  coin  that  was  suspended  from  the  string.       Part  b)  Out  of  curiosity,  you  also  want  to  find  the  displacement  at  that  point.  In   other  words,  find  s  (hint:  arc  distance).     Part  c)  Find  the  frequency  and  the  angular  frequency  of  oscillation  of  the  pendulum.                                                 Length = 0.5m s = ? m = ? T = 10N Fnet,t = 20N
  • 2.     Solution:     Given  Information:   FT  =  10N   Fnet,t  =  20N     Relevant  Equations:    T  =  mgcos  θ   Fnet,t  =  -­‐mgsin  θ   s  =  Lθ   f    =  ω/2π  =  (1/2π)*sqrt(g/L)     Part  a)   | 𝐹!"#,! 𝑇 | = | −mgsin 𝜃 mgcos 𝜃 | = | − sin 𝜃 cos 𝜃 | = tan 𝜃     𝜃 = tan!! 𝐹!"#,! 𝑇     𝐹!"#,! = −𝑚𝑔 sin 𝜃   𝑚 = − 𝐹!"#,! 𝑔 sin 𝜃     𝜃 = tan!! 20𝑁 10𝑁 ≅  1.11°     𝑚 = 20𝑁 (9.8)(sin 1.11°) ≅ 2.29𝑘𝑔     Part  b)     𝑠 = 𝐿𝜃   𝑠 = 0.5𝑚 1.11° ≅ 0.56𝑚     Part  c)   𝑓 =   1 2𝜋 𝑔 𝐿 = 1 2𝜋 9.8 0.5𝑚 ≅ 0.71  𝐻𝑧   𝜔 = 2𝜋𝑓 ≅ 4.46 𝑟𝑎𝑑 𝑠