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Ranjan Kumar Mohanty
1. Irreversible and reversible Reaction 
2. Types of Equilibrium 
3. Other classifications of Equilibrium 
4. Law of Mass Action 
5. Equilibrium Constant 
6. Reaction Quotient or Mass Action ratio 
7. Le-Chartlier Principle 
8. Autoprotolysis of Water 
9. Logarithm Identities 
10. Logarithm Table 
11. PH and POH 
12. Arrhenius theory of electrolysis 
13. Lewis Theory of acid and base 
14. Bronsted & Lowery Theory 
15. Conductor and Electrolyte 
16. Solubility Product 
17. Common ion effect 
18. Buffer Solution
The reaction in which reactant only form the product or the reaction which takes 
place in one direction is called irreversible reaction. 
BaSO4 + 2NaCl 
White ppt. 
Example : BaCl2 + Na2 SO4 
The reaction which takes place in both the direction is called reversible reaction. 
In this type of reaction, reactants combine to form product & again product 
give back reactant. 
Example : N2 + 3H2 
2NH3 
( aq ) 
( g ) ( g ) 
( aq ) ( s ) ( aq ) 
( g )
Equilibrium is state of reversible reaction when rate of forward reaction is 
equal to the rate of backward reaction. 
2NH3 
Example : N2 + 3H2 
( g ) ( g ) ( g ) 
 Homogeneous equilibrium 
 Heterogeneous equilibrium
The equilibrium between species having same physical state is called 
homogeneous equilibrium. 
Example : N2 + 3H2 2NH3 
( g ) ( g ) 
The equilibrium between species having different physical state is called 
homogeneous equilibrium. 
Example : CaCO3 CaO +CO2 
( g ) ( s ) 
( g ) 
( g )
Equilibrium between the same compound & different phases is called physical 
equilibrium. 
Example : HO 
HO 
22Equilibrium between reactant & product is known as chemical equilibrium. 
Example : N2 + 3H2 2NH3 
The equilibrium between ions & unionized molecule is known as ionic 
equilibrium. 
Ag+ + Cl -- 
( l ) ( g ) 
( g ) ( g ) ( g ) 
Example : AgCl 
( s ) ( aq ) ( aq )
Rate of reaction is directly proportional to the molar concentration of reactants 
having power equal to their coefficients in the reactions 
xA + yB + zC Product 
Rate [A]x [B]y [C]z 
Rate = k[A]x [B]y [C]z 
ȣ 
[k = Rate constant]
It is the ratio of molar concentration of product to the molar concentration of 
reactant having power equal to their coefficient in the reaction. 
2NH3 
Example : N2 + 3H2 
( g ) ( g ) ( g ) 
(mol/lit)2 1 
Unit of K = (mol/lit)(mol/lit)3 = (mol/lit)2 = mol 
-2 
lit 
2 
[NH3]2 
K = [N2][H2]3
The value of K obtain by putting the concentration of reactants & products of 
any stage of reaction (other than equilibrium) into the equilibrium constant 
expression is called mass action or Reaction Quotient. It may be Qc or Qp . 
 If Q < K, it means forward reaction becomes faster i.e. more of the product 
are formed. 
 If Q > K, then the backward reaction become faster it means more 
reactants are formed. 
 If Q = K, it means reaction is in equilibrium.
If external stress is applied over equilibrium then the equilibrium shift in such 
a direction, so that external stress become minimize. 
On increasing the temperature, endothermic reaction become fast and exothermic 
reaction become slow. 
2NH3 
Example : N2 + 3H2 
( g ) ( g ) ( g ) 
On increasing the temperature forward reaction become slow and backward 
reaction becomes fast. 
OR 
On increasing the temperature rate formation of ammonia decreases and rate of 
dissociation of ammonia increases.
On increasing the pressure, such reaction becomes fast in which number of moles 
decreases, while those reaction becomes slow in which number of moles increases. 
2NH3 
On increasing the pressure forward reaction become fast and backward reaction 
becomes slow. 
OR 
Example : N2 + 3H2 
1mol 3mol 
4mol 
2mol 
On increasing the pressure rate formation of ammonia increases and rate of 
dissociation of ammonia decreases.
On increasing the concentration of reactants, forward reaction becomes fast and 
on increasing the concentration of product, backward reaction become fast. 
Example : N2 + 3H2 2NH3 
( g ) ( g ) ( g ) 
On increasing the concentration of N2 and H2 , forward reaction becomes fast 
and on increasing the concentration of NH3 ,backward reaction becomes fast.
Catalyst is a substance which affect the rate of reaction but it will not effect the 
equilibrium state. 
Ques : State the conditions which help in increasing the formation of Sulpur - 
trioxide gas in the following reaction? 
2SO2 + O2 
2SO3 + Heat 
Ans : Formation of SO3 can be increased by : 
1.Decreasing the temperature 
2.Increasing the pressure 
3.Increasing the concentration of SO2 and O2.
Autoprotolysis means self ionization of water. Application of autoprotolysis is 
that water can react with acid as well as base. 
H2O + HOH H3O+ + OH- 
( l ) ( l ) ( aq ) ( aq ) 
Kw = [H3O+][OH-] 
[H3O+][OH-] = 1 x 10-14 
[H+ ][OH-] = 10-14 [H3O+ = H+ ]
1. log A x B = log A+ log B 
2. log A / B = log A - log B 
3. log An = n log A 
Example : log 28 x 10-4 
= log 28 + log 10-4 
= log 28 – 4log 10 
= 1.4472 – (4 x 1) 
= – 2.5548
It is reciprocal of logarithm of hydronium ion concentration. 
1 
PH = log[H3O+]3 
PH= -log[H3O+]3 
PH = 7 Neutral 
PH < 7 Acidic 
PH > 7 Alkaline 
It is reciprocal of logarithm of hydroxide ion concentration. 
POH = - log[OH- ]3 
For water : 
PH + POH = 14
Ques : Calculate H3O+, OH-, PH & POH of 0.0001 M HCl solution? 
( aq ) ( aq ) 
0.0001M 
Ans : HCl + H2 
0.0001M 
( g ) ( l ) 
0.0001M 
[H3O+] =10– 4 M ( [H3O+]=[H+] ) 
PH + POH = 14 
4 + POH = 14 
POH = 14 – 4 
POH = 10 
[H+] [OH–] =10–14 
[10- 4] [OH–] =10– 4 
[OH–] =10–10 M 
PH = - log [H+] 
PH = - log 10– 4 
PH = + 4 log 10 
PH = + 4(log 10 = 1) 
ACIDIC MEDIUM 
H+ + Cl –
1. When an electrolyte dissolve in water then it conduct electricity and split up 
into its ions. This process is known as ionization. 
2.Ions have charge over them. Positively charged ions is known as cations and 
negatively charged ions is known as anions. 
3.Total positive charge is equal to the negative charge carried by the ions. 
4.The extinct of dissociation of an electrolyte is called as degree of dissociation 
or degree of ionization. 
Degree of dissociation = number of molecular ionise 
total no. of molecule taken 
5.Degree of ionization for strong electrolyte is 1 because strong electrolyte are 
completely ionized but the degree of dissociation of weak electrolyte are 
partially ionized.
If external stress is applied over equilibrium then the equilibrium 
shift in such a direction, so that external stress become minimize. 
Electron deficient species or the species which accept the electron pair 
is known as Lewis acid. 
Example : BF3 , Al2Cl3 , H+, H3O+ 
The species which can donate electron pair or electron rich species is 
known as Lewis Base. 
Example : NH3 , HOH , Cl –
The substance which donate proton (H+) in water is known as acid. 
Example : H3O+, HCl 
The substance which gain proton (H+) is known as base. 
Example : NH3, Cl – 
HCl + HOH HO + + Cl – 
Acid 1 Base 2 Acid 32 
Base 1 
NH+ HO NH3 24 
Base 1 Acid 2 
+ + OH 
Acid 1 Base 2
2- and NH3 
Ques : Write the conjugate acid of the CO3 
2- HCO3 
Ans : 1. CO3 
- 
+ 
2. NH3 NH4 
- and NH4 
Ques : Write the conjugate base of the HCO3 
- CO3 
Ans : 1. HCO3 
2- 
+ NH3 
2. NH4
It is a substance which allows the electric current to pass through it 
but itself can’t decompose into ions. 
Example : Cu, Al, etc.. 
Electrolyte is a substance which allows the electric current to pass 
through it in molten and aqueous state & itself decompose into ions. 
Example : NaCl, dil. HCl 
Types of Electrolyte : 
1. Strong electrolyte 
2.Weak electrolyte
An electrolyte which completely dissociate into its ions. 
Examples : 
Strong Acid 
HCl H+ + Cl – 
HSO2H + + SO2- 
24 4 
HNOStrong Base 
H+ + NO- 3 3 
NaOH Na+ + OH-KOH 
K+ + OH-Strong 
Salt 
NaCl Na+ + Cl - 
KNO3 K+ + NO3 
- 
( aq ) 
( aq ) 
( aq ) 
( aq ) 
( aq ) 
( aq ) 
( aq )
An electrolyte which completely dissociate into its ions. 
EWxeaakmpAlecsid: 
CHOOH CHCOO- + H+ 
33HCO2H+ + CO2- 
23 3 
HCN H+ + CN- Weak Base 
NH4OH NH4 
+ + OH-Mg 
+ +2OH-Weak 
(OH)2 Mg2 
Salt 
+ + CO3 
(NH4) CO3 2NH4 
2- 
( aq ) 
( aq ) 
( aq ) 
( aq ) 
( aq ) 
( aq )
When a partially soluble salt is dissolved in water to make its 
saturated solution then an equilibrium exist between undissolved 
solid and its ion in the solution. In this case equilibrium constant is 
known as solubility product (Ksp). 
Condition for precipitation : Ionic product > Solubility product 
Ist case : AB 
( s ) 
( aq ) ( aq ) A+ + B – 
s s 
Ksp = [A+] [B-] 
Ksp = s x s (s = solubility) 
Ksp = s2 Example : AgCl
( aq ) ( aq ) A2+ + B – 
Ksp = [A2+] [B-]2 
Ksp = s x (2s)2 
Ksp = 4s3 
Example : PbCl2 
( aq ) ( aq ) A3+ + B – 
Ksp = [A2+] [B-]2 
Ksp = s x (3s)3 
Ksp = 27s4 
Example :Fe(OH)3 
IInd case : A( s )B2 
s 2s 
Ques : Find the solubility product of AB3? 
Ans : AB( s ) 3 
s 3s
Dissociation of weak electrolyte minimize by adding strong 
electrolyte which gives one of the common ion in the solution. 
Example : 
1.Weak Electrolyte : HS 
2H+ + S2- 
2Strong Electrolyte : HCl H+ + Cl - 
Common 
2.Weak Electrolyte : NHOH NH44 
+ + OH-Strong 
+ + Cl - 
Electrolyte : NH4Cl NH4 
Common
The solution whose PH remains unchanged on adding little amount 
of the acid and base is known as buffer solution. 
Example : Blood is also a buffer solution having PH 7.4 
Acidic buffer solution 
Basic buffer solution
PKa = - log Ka 
(equilibrium constant of acid) 
[salt] 
PH= PKa + 
[acid] 
PKb = - log Kb 
(equilibrium constant of base) 
[salt] 
POH= PKb + 
[base]
It is prepared by mixing equimolar amount of weak acid and its 
salt of strong base. 
Example : CH3COOH and CH3COONa 
It is prepared by mixing equimolar amount of weak base and its 
salt of strong acid. 
Example : NH4OH and NH4Cl
Ranjan Kumar Mohanty

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Equilibrium

  • 2. 1. Irreversible and reversible Reaction 2. Types of Equilibrium 3. Other classifications of Equilibrium 4. Law of Mass Action 5. Equilibrium Constant 6. Reaction Quotient or Mass Action ratio 7. Le-Chartlier Principle 8. Autoprotolysis of Water 9. Logarithm Identities 10. Logarithm Table 11. PH and POH 12. Arrhenius theory of electrolysis 13. Lewis Theory of acid and base 14. Bronsted & Lowery Theory 15. Conductor and Electrolyte 16. Solubility Product 17. Common ion effect 18. Buffer Solution
  • 3. The reaction in which reactant only form the product or the reaction which takes place in one direction is called irreversible reaction. BaSO4 + 2NaCl White ppt. Example : BaCl2 + Na2 SO4 The reaction which takes place in both the direction is called reversible reaction. In this type of reaction, reactants combine to form product & again product give back reactant. Example : N2 + 3H2 2NH3 ( aq ) ( g ) ( g ) ( aq ) ( s ) ( aq ) ( g )
  • 4. Equilibrium is state of reversible reaction when rate of forward reaction is equal to the rate of backward reaction. 2NH3 Example : N2 + 3H2 ( g ) ( g ) ( g )  Homogeneous equilibrium  Heterogeneous equilibrium
  • 5. The equilibrium between species having same physical state is called homogeneous equilibrium. Example : N2 + 3H2 2NH3 ( g ) ( g ) The equilibrium between species having different physical state is called homogeneous equilibrium. Example : CaCO3 CaO +CO2 ( g ) ( s ) ( g ) ( g )
  • 6. Equilibrium between the same compound & different phases is called physical equilibrium. Example : HO HO 22Equilibrium between reactant & product is known as chemical equilibrium. Example : N2 + 3H2 2NH3 The equilibrium between ions & unionized molecule is known as ionic equilibrium. Ag+ + Cl -- ( l ) ( g ) ( g ) ( g ) ( g ) Example : AgCl ( s ) ( aq ) ( aq )
  • 7. Rate of reaction is directly proportional to the molar concentration of reactants having power equal to their coefficients in the reactions xA + yB + zC Product Rate [A]x [B]y [C]z Rate = k[A]x [B]y [C]z ȣ [k = Rate constant]
  • 8. It is the ratio of molar concentration of product to the molar concentration of reactant having power equal to their coefficient in the reaction. 2NH3 Example : N2 + 3H2 ( g ) ( g ) ( g ) (mol/lit)2 1 Unit of K = (mol/lit)(mol/lit)3 = (mol/lit)2 = mol -2 lit 2 [NH3]2 K = [N2][H2]3
  • 9. The value of K obtain by putting the concentration of reactants & products of any stage of reaction (other than equilibrium) into the equilibrium constant expression is called mass action or Reaction Quotient. It may be Qc or Qp .  If Q < K, it means forward reaction becomes faster i.e. more of the product are formed.  If Q > K, then the backward reaction become faster it means more reactants are formed.  If Q = K, it means reaction is in equilibrium.
  • 10. If external stress is applied over equilibrium then the equilibrium shift in such a direction, so that external stress become minimize. On increasing the temperature, endothermic reaction become fast and exothermic reaction become slow. 2NH3 Example : N2 + 3H2 ( g ) ( g ) ( g ) On increasing the temperature forward reaction become slow and backward reaction becomes fast. OR On increasing the temperature rate formation of ammonia decreases and rate of dissociation of ammonia increases.
  • 11. On increasing the pressure, such reaction becomes fast in which number of moles decreases, while those reaction becomes slow in which number of moles increases. 2NH3 On increasing the pressure forward reaction become fast and backward reaction becomes slow. OR Example : N2 + 3H2 1mol 3mol 4mol 2mol On increasing the pressure rate formation of ammonia increases and rate of dissociation of ammonia decreases.
  • 12. On increasing the concentration of reactants, forward reaction becomes fast and on increasing the concentration of product, backward reaction become fast. Example : N2 + 3H2 2NH3 ( g ) ( g ) ( g ) On increasing the concentration of N2 and H2 , forward reaction becomes fast and on increasing the concentration of NH3 ,backward reaction becomes fast.
  • 13. Catalyst is a substance which affect the rate of reaction but it will not effect the equilibrium state. Ques : State the conditions which help in increasing the formation of Sulpur - trioxide gas in the following reaction? 2SO2 + O2 2SO3 + Heat Ans : Formation of SO3 can be increased by : 1.Decreasing the temperature 2.Increasing the pressure 3.Increasing the concentration of SO2 and O2.
  • 14. Autoprotolysis means self ionization of water. Application of autoprotolysis is that water can react with acid as well as base. H2O + HOH H3O+ + OH- ( l ) ( l ) ( aq ) ( aq ) Kw = [H3O+][OH-] [H3O+][OH-] = 1 x 10-14 [H+ ][OH-] = 10-14 [H3O+ = H+ ]
  • 15. 1. log A x B = log A+ log B 2. log A / B = log A - log B 3. log An = n log A Example : log 28 x 10-4 = log 28 + log 10-4 = log 28 – 4log 10 = 1.4472 – (4 x 1) = – 2.5548
  • 16.
  • 17. It is reciprocal of logarithm of hydronium ion concentration. 1 PH = log[H3O+]3 PH= -log[H3O+]3 PH = 7 Neutral PH < 7 Acidic PH > 7 Alkaline It is reciprocal of logarithm of hydroxide ion concentration. POH = - log[OH- ]3 For water : PH + POH = 14
  • 18. Ques : Calculate H3O+, OH-, PH & POH of 0.0001 M HCl solution? ( aq ) ( aq ) 0.0001M Ans : HCl + H2 0.0001M ( g ) ( l ) 0.0001M [H3O+] =10– 4 M ( [H3O+]=[H+] ) PH + POH = 14 4 + POH = 14 POH = 14 – 4 POH = 10 [H+] [OH–] =10–14 [10- 4] [OH–] =10– 4 [OH–] =10–10 M PH = - log [H+] PH = - log 10– 4 PH = + 4 log 10 PH = + 4(log 10 = 1) ACIDIC MEDIUM H+ + Cl –
  • 19. 1. When an electrolyte dissolve in water then it conduct electricity and split up into its ions. This process is known as ionization. 2.Ions have charge over them. Positively charged ions is known as cations and negatively charged ions is known as anions. 3.Total positive charge is equal to the negative charge carried by the ions. 4.The extinct of dissociation of an electrolyte is called as degree of dissociation or degree of ionization. Degree of dissociation = number of molecular ionise total no. of molecule taken 5.Degree of ionization for strong electrolyte is 1 because strong electrolyte are completely ionized but the degree of dissociation of weak electrolyte are partially ionized.
  • 20. If external stress is applied over equilibrium then the equilibrium shift in such a direction, so that external stress become minimize. Electron deficient species or the species which accept the electron pair is known as Lewis acid. Example : BF3 , Al2Cl3 , H+, H3O+ The species which can donate electron pair or electron rich species is known as Lewis Base. Example : NH3 , HOH , Cl –
  • 21. The substance which donate proton (H+) in water is known as acid. Example : H3O+, HCl The substance which gain proton (H+) is known as base. Example : NH3, Cl – HCl + HOH HO + + Cl – Acid 1 Base 2 Acid 32 Base 1 NH+ HO NH3 24 Base 1 Acid 2 + + OH Acid 1 Base 2
  • 22. 2- and NH3 Ques : Write the conjugate acid of the CO3 2- HCO3 Ans : 1. CO3 - + 2. NH3 NH4 - and NH4 Ques : Write the conjugate base of the HCO3 - CO3 Ans : 1. HCO3 2- + NH3 2. NH4
  • 23. It is a substance which allows the electric current to pass through it but itself can’t decompose into ions. Example : Cu, Al, etc.. Electrolyte is a substance which allows the electric current to pass through it in molten and aqueous state & itself decompose into ions. Example : NaCl, dil. HCl Types of Electrolyte : 1. Strong electrolyte 2.Weak electrolyte
  • 24. An electrolyte which completely dissociate into its ions. Examples : Strong Acid HCl H+ + Cl – HSO2H + + SO2- 24 4 HNOStrong Base H+ + NO- 3 3 NaOH Na+ + OH-KOH K+ + OH-Strong Salt NaCl Na+ + Cl - KNO3 K+ + NO3 - ( aq ) ( aq ) ( aq ) ( aq ) ( aq ) ( aq ) ( aq )
  • 25. An electrolyte which completely dissociate into its ions. EWxeaakmpAlecsid: CHOOH CHCOO- + H+ 33HCO2H+ + CO2- 23 3 HCN H+ + CN- Weak Base NH4OH NH4 + + OH-Mg + +2OH-Weak (OH)2 Mg2 Salt + + CO3 (NH4) CO3 2NH4 2- ( aq ) ( aq ) ( aq ) ( aq ) ( aq ) ( aq )
  • 26. When a partially soluble salt is dissolved in water to make its saturated solution then an equilibrium exist between undissolved solid and its ion in the solution. In this case equilibrium constant is known as solubility product (Ksp). Condition for precipitation : Ionic product > Solubility product Ist case : AB ( s ) ( aq ) ( aq ) A+ + B – s s Ksp = [A+] [B-] Ksp = s x s (s = solubility) Ksp = s2 Example : AgCl
  • 27. ( aq ) ( aq ) A2+ + B – Ksp = [A2+] [B-]2 Ksp = s x (2s)2 Ksp = 4s3 Example : PbCl2 ( aq ) ( aq ) A3+ + B – Ksp = [A2+] [B-]2 Ksp = s x (3s)3 Ksp = 27s4 Example :Fe(OH)3 IInd case : A( s )B2 s 2s Ques : Find the solubility product of AB3? Ans : AB( s ) 3 s 3s
  • 28. Dissociation of weak electrolyte minimize by adding strong electrolyte which gives one of the common ion in the solution. Example : 1.Weak Electrolyte : HS 2H+ + S2- 2Strong Electrolyte : HCl H+ + Cl - Common 2.Weak Electrolyte : NHOH NH44 + + OH-Strong + + Cl - Electrolyte : NH4Cl NH4 Common
  • 29. The solution whose PH remains unchanged on adding little amount of the acid and base is known as buffer solution. Example : Blood is also a buffer solution having PH 7.4 Acidic buffer solution Basic buffer solution
  • 30. PKa = - log Ka (equilibrium constant of acid) [salt] PH= PKa + [acid] PKb = - log Kb (equilibrium constant of base) [salt] POH= PKb + [base]
  • 31. It is prepared by mixing equimolar amount of weak acid and its salt of strong base. Example : CH3COOH and CH3COONa It is prepared by mixing equimolar amount of weak base and its salt of strong acid. Example : NH4OH and NH4Cl