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15-1
Chapter 15
Organic Compounds and the Atomic
Properties of Carbon
15-2
Organic Compounds and the Atomic Properties of Carbon
15.1 The special nature of carbon and the characteristics of
organic molecules
15.2 The structures and classes of hydrocarbons
15.3 Some important classes of organic reactions
15.4 Properties and reactivities of common functional groups
15.5 The monomer-polymer theme I: Synthetic macromolecules
15.6 The monomer-polymer theme II: Biological macromolecules
15-3
Figure 15.1
The position of carbon in the periodic table
15-4
Figure 15.2
The chemical diversity of organic compounds
4 carbons linked with single bonds, 1 oxygen and needed hydrogens.
CH3 CH2 CH2 CH2 OH
CH3 CH2 CH CH3
OH
CH3 CH2 CH2 O CH3
CH3 CH CH2 OH
CH3
CH3 C
OH
CH3
CH3
CH3 CH2 O CH2 CH3
CH3 CH
CH3
O CH3
CH3 CH CH CH3
O
H2
C
H2C CH CH2OH
H2
C
H2C CH CH2OH
CH2
CH2 CH2
CH
OH
CH2
CH CH2
O
CH3
H2C
H2C CH2
CH2
O
15-5
CH3 CH2 CH2 C O
H
CH3 CH2 C CH3
O
CH2 CH CH2 CH3
O
C
H2C CH CH3
OH
H
Figure 15.2 (continued)
H2C
H2C CH
O
CH3
O
H2C C CH3
CH3
CH2
CH2 CH2
C
O
CH2
H2C CH C
H
O
C
H2C CH CH3
O
CH3 CH C
O
CH3
H
15-6
HYDROCARBONS
Carbon skeletons and hydrogen skins
When determining the number of different skeletons, remember that:
 Each carbon forms a maximum of four single bonds, OR two
single and one double bond, OR one single and triple
bond.
 The arrangement of carbon atoms determines the skeleton,
so a straight chain and a bent chain represent the same
skeleton.
 Groups joined by single bonds can rotate, so a branch
pointing down is the same as one pointing up.
15-7
Some five-carbon skeletons
Figure 15.3
single bonds double bonds ring structures
15-8
Adding a H-atom skin to a carbon skeleton
Figure 15.4
15-9
SAMPLE PROBLEM 15.1 Drawing hydrocarbons
PROBLEM: Draw structures that have different atom arrangements for
hydrocarbons with:
PLAN: Start with the longest chain and draw shorter chains until you
are repeating structures.
(a) six C atoms, no multiple bonds, and no rings
(b) four C atoms, one double bond, and no rings
(c) four C atoms, no multiple bonds, and one ring
SOLUTION: (a) six carbons, no rings
C C H
H
H
C
H
H
H
H
C
H
H
C
H
H
C
H
H
H C
H
H
C
C
H
C
H
H
C
H
H
C
H
H
H H
H
H H
C
H
H
C
H
H
C
H
C
H
H
C
H
H
H H
C
H
H H
15-10
SAMPLE PROBLEM 15.1 (continued)
(a) continued:
C
C
C
C
C
C
C
C
C
C
C
C
(b) four carbons, one double bond
C C C C
H
H H H
H
H
H
H
C C C C
H
H H H
H
H
H
H
H C C C
H H
H
H
C H
H
H
(c) four carbons, one ring
C
C C
C
H
H
H
H
H
H
H
H
C
C C
C
H
H
H H
H
H H
H
15-11
Table 15.1 Numerical Roots for Carbon Chains and Branches
number of
carbon atoms
roots
1
2
3
4
5
6
8
7
9
10
meth-
eth-
prop-
but-
hex-
pent-
hept-
oct-
non-
dec-
15-12
15-13
Figure 15.5
Ways to depict formulas and models of an alkane
15-14
Figure 15.6
Depicting cycloalkanes
C
C C
H H
H
H
H
H
C
C C
C
H
H
H
H
H
H H
H
cyclopropane cyclobutane
15-15
Figure 15.6
Depicting cycloalkanes
cyclopentane
cyclohexane
C C
C
C
C
H H
H
H
H
H
H
H
H
H C
C
C
C
C
C
H H
H H
H
H
H
H
H
H
H
H
15-16
15-17
Figure 15.7
Boiling points of the first 10 unbranched alkanes
15-18
Figure 15.8
An analogy for
optical isomers
15-19
Figure 15.9
Two chiral molecules
optical isomers of 3-methylhexane optical isomers of alanine
15-20
Figure 15.10
The rotation of plane-polarized light by an optically active substance
15-21
Figure 15.11
The binding site
of an enzyme
15-22
15-23
Figure B15.1
The initial chemical event in vision
15-24
SAMPLE PROBLEM 15.2 Naming alkanes, alkenes and alkynes
PROBLEM: Give the systematic name for each of the following, indicate
the chiral center in part (d), and draw two geometric isomers
for part (c).
(a)
CH3 C
CH3
CH3
CH2 CH3 CH3 CH2 CH CH
CH3
CH3
CH2
CH3
(b) CH3
CH2CH3
(c)
CH3 CH2 CH CH
CH3
CH2
(d)
CH2 CH C CH
CH3
CH3
CH3
CH3
(e)
PLAN: For (a)-(c), find the longest, continuous chain and give it the base
name (root + suffix). Then number the chain so that the branches
occur on the lowest numbered carbons and name the branches with
the (root + yl). For (d) and (e) the main chain must contain the double
bond and the chain must be numbered such that the double bond
occurs on the lowest numbered carbon.
15-25
SAMPLE PROBLEM 15.2
SOLUTION:
(continued)
(a)
CH3 C
CH3
CH3
CH2 CH3
butane
methyl
methyl
1 4
3
2
2,2-dimethylbutane
CH3 CH2 CH CH
CH3
CH3
CH2
CH3
(b)
hexane
methyl
methyl
1
2
3
4
5
6
3,4-dimethylhexane
(can be numbered in either direction)
CH3
CH2CH3
(c)
cyclopentane
methyl
ethyl
1
2
3
4
5
1-ethyl-2-methylcyclopentane
CH3 CH2 CH CH
CH3
CH2
(d)
methyl
1
2
3
4
5
pentene
1-pentene
3-methyl-1-pentene
chiral center
15-26
SAMPLE PROBLEM 15.2 (continued)
CH2 CH C CH
CH3
CH3
CH3
CH3
(e)
methyl
methyl
1
2
3
4
5
6
3-hexene
CH2
C C
CH
CH3
CH3
CH3
CH3
methyl
methyl
1
2
3
4
5
6
3-hexene
H
cis-2,3-dimethyl-3-hexene
CH2
C C
CH
CH3
CH3
CH3
CH3
methyl
methyl
1
2
3
4
5
6
3-hexene
H
trans-2,3-dimethyl-3-hexene
15-27
Figure 15.12
Representations of benzene
or
15-28
Types of organic reactions
An addition reaction occurs when an unsaturated reactant becomes a
saturated product:
Elimination reactions are the opposite of addition; they occur when a
more saturated reactant becomes a less saturated product:
R CH CH R + X Y R CH CH R
X Y
R CH CH R + X Y
R CH CH R
X Y
A substitution reaction occurs when an atom (or group) from an added
reagent substitutes for one in the organic reactant:
R C X + Y R C Y + X
15-29
Figure 15.13
C C + Br2
A color test for
C=C bonds
15-30
C C
Br
Br
15-31
SAMPLE PROBLEM 15.3 Recognizing the type of organic reaction
PROBLEM: State whether each reaction is an addition, elimination, or
substitution:
(a) CH3 CH2 CH2 Br CH3 CH CH2 + HBr
(b) + H2
CH3 C Br
O
+ CH3CH2OH
(c)
CH3 C OCH2CH3 + HBr
O
PLAN: Look for changes in the number of atoms attached to carbon.
 More atoms bonded to carbon is an addition.
 Fewer atoms bonded to carbon is an elimination.
 Same number of atoms bonded to carbon is a substitution.
15-32
SAMPLE PROBLEM 15.3
SOLUTION:
(continued)
(a) CH3 CH2 CH2 Br CH3 CH CH2 + HBr
Elimination: there are fewer bonds to last two carbons.
(b) + H2
Addition: there are more bonds to the two carbons
in the second structure.
CH3 C Br
O
+ CH3CH2OH
(c)
CH3 C OCH2CH3 + HBr
O
Substitution: the C-Br bond becomes a C-O bond
and the number of bonds to carbon remains the same.
15-33
Figure 15.14
Some molecules with the alcohol functional group
15-34
15-35
15-36
Figure 15.15
General structures of amines
primary (1o) amine secondary( 2o) amine tertiary (3o) amine
C N
the amine functional group
15-37
Figure 15.16
Some biomolecules with the amine functional group
lysine (1o amine)
(amino acid found
in proteins)
adenine (1o amine)
(component of
nucleic acids)
epinephrine
(adrenaline; 2o amine)
(neurotransmitter in
brain; hormone released
during stress)
cocaine (3o amine)
(brain stimulant;
widely abused drug)
15-38
Figure 15.17
Structure of a cationic detergent
CH
N CH3
H3C
H2C
CH2
H2C
CH2
H2C
CH2
H2C
CH2
H2C
CH2
H2C
CH2
H2C
CH2
H2C
CH3
Cl
benzylcetyldimethyl-
ammonium chloride
15-39
SAMPLE PROBLEM 15.4 Predicting the reactions of alcohols, alkyl
halides, and amines
PROBLEM: Determine the reaction type and predict the product(s) in the
following:
(a) CH3 CH2 CH2 I + NaOH
(b) CH3 CH2 Br + 2H3C CH2 CH2 NH2
H3C CH CH3
OH
(c)
Cr2O7
2-
H2SO4
PLAN: Check for functional groups and reagents, then for inorganics added.
In (a) the -OH will substitute in the alkyl halide; in (b) the amine and
alkyl halide will undergo a substitution of amine for halogen; in (c)
the inorganics form a strong oxidizing agent resulting in an
elimination.
15-40
SAMPLE PROBLEM 15.4 (continued)
SOLUTION:
(a) substitution - the products are: CH3 CH2 CH2 OH + NaI
(b) substitution - the products are: CH3 CH2 NHCH2CH2CH3
+ CH3CH2CH2NHBr
(c) elimination - the product is: H3C C CH3
O
15-41
Figure 15.18
Some common aldehydes and ketones
methanal
(formaldehyde)
used to make
resins in
plywood,
dishware,
countertops;
biological
preservative
ethanal
(acetaldehyde)
narcotic product
of ethanol
metabolism;
used to make
perfume,
flavors, plastics,
other chemicals
benzaldehyde
artificial
almond
flavoring
2-propanone
(acetone) solvent
for fat, rubber,
plastic, varnish,
lacquer;
chemical
feedstock
2-butanone
(methyl ethyl
ketone)
important
solvent
15-42
Figure 15.19
The carbonyl group
15-43
SAMPLE PROBLEM 15.5
SOLUTION:
Predicting the steps in a reaction sequence
PROBLEM: Fill in the blanks in the following reaction sequence:
CH3 CH2 CH CH3
Br OH- Cr2O7
2-
H2SO4
CH3Li H2O
PLAN: Look at the functional groups and reagents to determine the type of
reaction.
CH3 CH2 CH CH3
Br
OH-
2-bromobutane
CH3 CH2 CH CH3
OH
2-butanol
Cr2O7
2-
H2SO4
CH3 CH2 C CH3
O
2-butanone
CH3Li
H2O
CH3 CH2 C CH3
OH
CH3
2-methyl-2-butanol
15-44
Figure 15.20
Some molecules with the carboxylic acid functional group
methanoic acid
(formic acid)
(an irritating
component of ant
and bee stings)
butanoic acid
(butyric acid)
(odor of rancid butter;
suspected component
of monkey sex
attractant)
octadecanoic acid
(stearic acid)
(found in animal fats;
used in making
candles and soap)
benzoic acid
(calorimetric
standard; used in
preserving food,
dyeing fabric,
curing tobacco)
15-45
Figure 15.21
Some lipid molecules with the ester functional group
cetyl palmitate
(the most
common lipid in
whale blubber)
lecithin
(phospholipid found in all cell membranes)
tristearin
(typical dietary fat used as an
energy store in animals)
15-46
Figure 15.22
Which reactant contributes which group to the ester?
R C OH
O
R' OH
18
+ R C O
O
R'
18
+ H O H
R C OH
O
R' OH
18
+ R C O
O
R' + H O H
18
R C OH
O
H OR'
+ R C O
O
R' + H O H
H+
General esterification reaction
15-47
lysergic acid diethylamide
(LSD-25)
(a potent hallucinogen)
Figure 15.23
Some molecules with the amide functional group
N,N-dimethylmethanamide
(dimethylformamide)
(major organic solvent;
used in production of
synthetic fibers)
acetaminophen
(active ingredient in
nonaspirin pain relievers;
used to make dyes and
photographic chemicals)
15-48
SAMPLE PROBLEM 15.6
SOLUTION:
Predicting the reactions of the carboxylic
acid family
PROBLEM: Predict the product(s) of the following reactions:
CH3 CH2 CH2 C
O
OH CH3 CH CH3
OH
+
H+
(a)
CH3 CH CH2 CH2
(b)
CH3
C NH
O
CH2 CH3
NaOH
H2O
PLAN: (a) An acid and an alcohol undergo a condensation reaction to form
an ester.
(b) An amide, in the presence of base and water, is hydrolyzed.
CH3 CH2 CH2 C
O
O
(a) CH
CH3
CH3
CH3 CH CH2 CH2
(b)
CH3
C NH2
O
CH2 CH3
O-
+ Na+
+
15-49
Figure 15.24
The formation of
carboxylic,
phosphoric, and
sulfuric acid
anhydrides
15-50
Figure 15.25
An ester and an amide of other non-metals
glucose-6-phosphate sulfanilamide
15-51
SAMPLE PROBLEM 15.7
PROBLEM:
SOLUTION:
Recognizing functional groups
Circle and name the functional groups in the following molecules:
(a)
C
O
O
OH
C CH3
O
(b)
CH
OH
CH2 NH CH3
(c)
Cl
O
PLAN: Use Table 15.5 to identify the functional groups.
(a)
C
O
O
OH
C CH3
O
carboxylic
acid
ester
(b)
CH
OH
CH2 NH CH3
alcohol
2o amine
(c)
Cl
O
ketone
alkene
haloalkane
15-52
Figure 15.26
A summary of the interconversions among the major
organic functional groups
15-53
Figure 15.27
Steps in the free-radical polymerization of ethylene
15-54
15-55
15-56
Figure 15.28
The formation of nylon-66
15-57
Figure 15.29
The structure of glucose in aqueous solution and the
formation of a disaccharide
15-58
Figure 15.30
The common amino acids
15-59
Figure 15.31
A portion of a polypeptide chain
15-60
Figure 15.32
Forces that
maintain
protein
structure
15-61
Figure 15.33
collagen
silk
fibroin
Shapes of
fibrous
proteins
15-62
Figure 15.34
mononucleotide of
ribonucleic acid (RNA)
mononucleotide of
deoxyribonucleic acid
(DNA)
portion of DNA
polynucleotide chain
Mononucleotide monomers and their linkage
15-63
Figure 15.35
The double helix of DNA
1.08 nm
1.08 nm
15-64
Figure 15.36
Key stages in protein synthesis
15-65 Figure 15.37
Key stages of DNA replication

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Organic Compounds and the Atomic Properties of Carbon

  • 1. 15-1 Chapter 15 Organic Compounds and the Atomic Properties of Carbon
  • 2. 15-2 Organic Compounds and the Atomic Properties of Carbon 15.1 The special nature of carbon and the characteristics of organic molecules 15.2 The structures and classes of hydrocarbons 15.3 Some important classes of organic reactions 15.4 Properties and reactivities of common functional groups 15.5 The monomer-polymer theme I: Synthetic macromolecules 15.6 The monomer-polymer theme II: Biological macromolecules
  • 3. 15-3 Figure 15.1 The position of carbon in the periodic table
  • 4. 15-4 Figure 15.2 The chemical diversity of organic compounds 4 carbons linked with single bonds, 1 oxygen and needed hydrogens. CH3 CH2 CH2 CH2 OH CH3 CH2 CH CH3 OH CH3 CH2 CH2 O CH3 CH3 CH CH2 OH CH3 CH3 C OH CH3 CH3 CH3 CH2 O CH2 CH3 CH3 CH CH3 O CH3 CH3 CH CH CH3 O H2 C H2C CH CH2OH H2 C H2C CH CH2OH CH2 CH2 CH2 CH OH CH2 CH CH2 O CH3 H2C H2C CH2 CH2 O
  • 5. 15-5 CH3 CH2 CH2 C O H CH3 CH2 C CH3 O CH2 CH CH2 CH3 O C H2C CH CH3 OH H Figure 15.2 (continued) H2C H2C CH O CH3 O H2C C CH3 CH3 CH2 CH2 CH2 C O CH2 H2C CH C H O C H2C CH CH3 O CH3 CH C O CH3 H
  • 6. 15-6 HYDROCARBONS Carbon skeletons and hydrogen skins When determining the number of different skeletons, remember that:  Each carbon forms a maximum of four single bonds, OR two single and one double bond, OR one single and triple bond.  The arrangement of carbon atoms determines the skeleton, so a straight chain and a bent chain represent the same skeleton.  Groups joined by single bonds can rotate, so a branch pointing down is the same as one pointing up.
  • 7. 15-7 Some five-carbon skeletons Figure 15.3 single bonds double bonds ring structures
  • 8. 15-8 Adding a H-atom skin to a carbon skeleton Figure 15.4
  • 9. 15-9 SAMPLE PROBLEM 15.1 Drawing hydrocarbons PROBLEM: Draw structures that have different atom arrangements for hydrocarbons with: PLAN: Start with the longest chain and draw shorter chains until you are repeating structures. (a) six C atoms, no multiple bonds, and no rings (b) four C atoms, one double bond, and no rings (c) four C atoms, no multiple bonds, and one ring SOLUTION: (a) six carbons, no rings C C H H H C H H H H C H H C H H C H H H C H H C C H C H H C H H C H H H H H H H C H H C H H C H C H H C H H H H C H H H
  • 10. 15-10 SAMPLE PROBLEM 15.1 (continued) (a) continued: C C C C C C C C C C C C (b) four carbons, one double bond C C C C H H H H H H H H C C C C H H H H H H H H H C C C H H H H C H H H (c) four carbons, one ring C C C C H H H H H H H H C C C C H H H H H H H H
  • 11. 15-11 Table 15.1 Numerical Roots for Carbon Chains and Branches number of carbon atoms roots 1 2 3 4 5 6 8 7 9 10 meth- eth- prop- but- hex- pent- hept- oct- non- dec-
  • 12. 15-12
  • 13. 15-13 Figure 15.5 Ways to depict formulas and models of an alkane
  • 14. 15-14 Figure 15.6 Depicting cycloalkanes C C C H H H H H H C C C C H H H H H H H H cyclopropane cyclobutane
  • 15. 15-15 Figure 15.6 Depicting cycloalkanes cyclopentane cyclohexane C C C C C H H H H H H H H H H C C C C C C H H H H H H H H H H H H
  • 16. 15-16
  • 17. 15-17 Figure 15.7 Boiling points of the first 10 unbranched alkanes
  • 18. 15-18 Figure 15.8 An analogy for optical isomers
  • 19. 15-19 Figure 15.9 Two chiral molecules optical isomers of 3-methylhexane optical isomers of alanine
  • 20. 15-20 Figure 15.10 The rotation of plane-polarized light by an optically active substance
  • 21. 15-21 Figure 15.11 The binding site of an enzyme
  • 22. 15-22
  • 23. 15-23 Figure B15.1 The initial chemical event in vision
  • 24. 15-24 SAMPLE PROBLEM 15.2 Naming alkanes, alkenes and alkynes PROBLEM: Give the systematic name for each of the following, indicate the chiral center in part (d), and draw two geometric isomers for part (c). (a) CH3 C CH3 CH3 CH2 CH3 CH3 CH2 CH CH CH3 CH3 CH2 CH3 (b) CH3 CH2CH3 (c) CH3 CH2 CH CH CH3 CH2 (d) CH2 CH C CH CH3 CH3 CH3 CH3 (e) PLAN: For (a)-(c), find the longest, continuous chain and give it the base name (root + suffix). Then number the chain so that the branches occur on the lowest numbered carbons and name the branches with the (root + yl). For (d) and (e) the main chain must contain the double bond and the chain must be numbered such that the double bond occurs on the lowest numbered carbon.
  • 25. 15-25 SAMPLE PROBLEM 15.2 SOLUTION: (continued) (a) CH3 C CH3 CH3 CH2 CH3 butane methyl methyl 1 4 3 2 2,2-dimethylbutane CH3 CH2 CH CH CH3 CH3 CH2 CH3 (b) hexane methyl methyl 1 2 3 4 5 6 3,4-dimethylhexane (can be numbered in either direction) CH3 CH2CH3 (c) cyclopentane methyl ethyl 1 2 3 4 5 1-ethyl-2-methylcyclopentane CH3 CH2 CH CH CH3 CH2 (d) methyl 1 2 3 4 5 pentene 1-pentene 3-methyl-1-pentene chiral center
  • 26. 15-26 SAMPLE PROBLEM 15.2 (continued) CH2 CH C CH CH3 CH3 CH3 CH3 (e) methyl methyl 1 2 3 4 5 6 3-hexene CH2 C C CH CH3 CH3 CH3 CH3 methyl methyl 1 2 3 4 5 6 3-hexene H cis-2,3-dimethyl-3-hexene CH2 C C CH CH3 CH3 CH3 CH3 methyl methyl 1 2 3 4 5 6 3-hexene H trans-2,3-dimethyl-3-hexene
  • 28. 15-28 Types of organic reactions An addition reaction occurs when an unsaturated reactant becomes a saturated product: Elimination reactions are the opposite of addition; they occur when a more saturated reactant becomes a less saturated product: R CH CH R + X Y R CH CH R X Y R CH CH R + X Y R CH CH R X Y A substitution reaction occurs when an atom (or group) from an added reagent substitutes for one in the organic reactant: R C X + Y R C Y + X
  • 29. 15-29 Figure 15.13 C C + Br2 A color test for C=C bonds
  • 31. 15-31 SAMPLE PROBLEM 15.3 Recognizing the type of organic reaction PROBLEM: State whether each reaction is an addition, elimination, or substitution: (a) CH3 CH2 CH2 Br CH3 CH CH2 + HBr (b) + H2 CH3 C Br O + CH3CH2OH (c) CH3 C OCH2CH3 + HBr O PLAN: Look for changes in the number of atoms attached to carbon.  More atoms bonded to carbon is an addition.  Fewer atoms bonded to carbon is an elimination.  Same number of atoms bonded to carbon is a substitution.
  • 32. 15-32 SAMPLE PROBLEM 15.3 SOLUTION: (continued) (a) CH3 CH2 CH2 Br CH3 CH CH2 + HBr Elimination: there are fewer bonds to last two carbons. (b) + H2 Addition: there are more bonds to the two carbons in the second structure. CH3 C Br O + CH3CH2OH (c) CH3 C OCH2CH3 + HBr O Substitution: the C-Br bond becomes a C-O bond and the number of bonds to carbon remains the same.
  • 33. 15-33 Figure 15.14 Some molecules with the alcohol functional group
  • 34. 15-34
  • 35. 15-35
  • 36. 15-36 Figure 15.15 General structures of amines primary (1o) amine secondary( 2o) amine tertiary (3o) amine C N the amine functional group
  • 37. 15-37 Figure 15.16 Some biomolecules with the amine functional group lysine (1o amine) (amino acid found in proteins) adenine (1o amine) (component of nucleic acids) epinephrine (adrenaline; 2o amine) (neurotransmitter in brain; hormone released during stress) cocaine (3o amine) (brain stimulant; widely abused drug)
  • 38. 15-38 Figure 15.17 Structure of a cationic detergent CH N CH3 H3C H2C CH2 H2C CH2 H2C CH2 H2C CH2 H2C CH2 H2C CH2 H2C CH2 H2C CH3 Cl benzylcetyldimethyl- ammonium chloride
  • 39. 15-39 SAMPLE PROBLEM 15.4 Predicting the reactions of alcohols, alkyl halides, and amines PROBLEM: Determine the reaction type and predict the product(s) in the following: (a) CH3 CH2 CH2 I + NaOH (b) CH3 CH2 Br + 2H3C CH2 CH2 NH2 H3C CH CH3 OH (c) Cr2O7 2- H2SO4 PLAN: Check for functional groups and reagents, then for inorganics added. In (a) the -OH will substitute in the alkyl halide; in (b) the amine and alkyl halide will undergo a substitution of amine for halogen; in (c) the inorganics form a strong oxidizing agent resulting in an elimination.
  • 40. 15-40 SAMPLE PROBLEM 15.4 (continued) SOLUTION: (a) substitution - the products are: CH3 CH2 CH2 OH + NaI (b) substitution - the products are: CH3 CH2 NHCH2CH2CH3 + CH3CH2CH2NHBr (c) elimination - the product is: H3C C CH3 O
  • 41. 15-41 Figure 15.18 Some common aldehydes and ketones methanal (formaldehyde) used to make resins in plywood, dishware, countertops; biological preservative ethanal (acetaldehyde) narcotic product of ethanol metabolism; used to make perfume, flavors, plastics, other chemicals benzaldehyde artificial almond flavoring 2-propanone (acetone) solvent for fat, rubber, plastic, varnish, lacquer; chemical feedstock 2-butanone (methyl ethyl ketone) important solvent
  • 43. 15-43 SAMPLE PROBLEM 15.5 SOLUTION: Predicting the steps in a reaction sequence PROBLEM: Fill in the blanks in the following reaction sequence: CH3 CH2 CH CH3 Br OH- Cr2O7 2- H2SO4 CH3Li H2O PLAN: Look at the functional groups and reagents to determine the type of reaction. CH3 CH2 CH CH3 Br OH- 2-bromobutane CH3 CH2 CH CH3 OH 2-butanol Cr2O7 2- H2SO4 CH3 CH2 C CH3 O 2-butanone CH3Li H2O CH3 CH2 C CH3 OH CH3 2-methyl-2-butanol
  • 44. 15-44 Figure 15.20 Some molecules with the carboxylic acid functional group methanoic acid (formic acid) (an irritating component of ant and bee stings) butanoic acid (butyric acid) (odor of rancid butter; suspected component of monkey sex attractant) octadecanoic acid (stearic acid) (found in animal fats; used in making candles and soap) benzoic acid (calorimetric standard; used in preserving food, dyeing fabric, curing tobacco)
  • 45. 15-45 Figure 15.21 Some lipid molecules with the ester functional group cetyl palmitate (the most common lipid in whale blubber) lecithin (phospholipid found in all cell membranes) tristearin (typical dietary fat used as an energy store in animals)
  • 46. 15-46 Figure 15.22 Which reactant contributes which group to the ester? R C OH O R' OH 18 + R C O O R' 18 + H O H R C OH O R' OH 18 + R C O O R' + H O H 18 R C OH O H OR' + R C O O R' + H O H H+ General esterification reaction
  • 47. 15-47 lysergic acid diethylamide (LSD-25) (a potent hallucinogen) Figure 15.23 Some molecules with the amide functional group N,N-dimethylmethanamide (dimethylformamide) (major organic solvent; used in production of synthetic fibers) acetaminophen (active ingredient in nonaspirin pain relievers; used to make dyes and photographic chemicals)
  • 48. 15-48 SAMPLE PROBLEM 15.6 SOLUTION: Predicting the reactions of the carboxylic acid family PROBLEM: Predict the product(s) of the following reactions: CH3 CH2 CH2 C O OH CH3 CH CH3 OH + H+ (a) CH3 CH CH2 CH2 (b) CH3 C NH O CH2 CH3 NaOH H2O PLAN: (a) An acid and an alcohol undergo a condensation reaction to form an ester. (b) An amide, in the presence of base and water, is hydrolyzed. CH3 CH2 CH2 C O O (a) CH CH3 CH3 CH3 CH CH2 CH2 (b) CH3 C NH2 O CH2 CH3 O- + Na+ +
  • 49. 15-49 Figure 15.24 The formation of carboxylic, phosphoric, and sulfuric acid anhydrides
  • 50. 15-50 Figure 15.25 An ester and an amide of other non-metals glucose-6-phosphate sulfanilamide
  • 51. 15-51 SAMPLE PROBLEM 15.7 PROBLEM: SOLUTION: Recognizing functional groups Circle and name the functional groups in the following molecules: (a) C O O OH C CH3 O (b) CH OH CH2 NH CH3 (c) Cl O PLAN: Use Table 15.5 to identify the functional groups. (a) C O O OH C CH3 O carboxylic acid ester (b) CH OH CH2 NH CH3 alcohol 2o amine (c) Cl O ketone alkene haloalkane
  • 52. 15-52 Figure 15.26 A summary of the interconversions among the major organic functional groups
  • 53. 15-53 Figure 15.27 Steps in the free-radical polymerization of ethylene
  • 54. 15-54
  • 55. 15-55
  • 57. 15-57 Figure 15.29 The structure of glucose in aqueous solution and the formation of a disaccharide
  • 59. 15-59 Figure 15.31 A portion of a polypeptide chain
  • 62. 15-62 Figure 15.34 mononucleotide of ribonucleic acid (RNA) mononucleotide of deoxyribonucleic acid (DNA) portion of DNA polynucleotide chain Mononucleotide monomers and their linkage
  • 63. 15-63 Figure 15.35 The double helix of DNA 1.08 nm 1.08 nm
  • 64. 15-64 Figure 15.36 Key stages in protein synthesis
  • 65. 15-65 Figure 15.37 Key stages of DNA replication