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# Lecture 3 Boyle's law

This ppt is a lecture on Boyle's Law. It contains examples and conversions. It will help you understand the concept more as I simplify the concept intended for the understanding of my science class.

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### Lecture 3 Boyle's law

1. 1. Give description for each pictures 1
2. 2. UNIT 4 Gases Pressure and Volume (Boyle’s Law) 2
3. 3. Robert Boyle -Lived 1627 – 1691 3
4. 4. 4
5. 5. What is Boyle’s Law? •Boyle’s Law is one of the laws in physics that concern with the behaviour of gases •When a gas is under pressure it takes up less space •The higher the pressure, the smaller the volume
6. 6. What is Boyle’s Law?
7. 7. Boyle’s Law Apparatus
8. 8. Boyle’s Law Boyle’s Law states that •the pressure of a gas is inversely related to its volume when T and n are constant. •if volume decreases, the pressure increases. 8
9. 9. PV Constant in Boyle’s Law Boyle’s Law can be stated as: P1V1 = P2V2 (T, n constant) 9
10. 10. 10
11. 11. LET’S USE LEGEND/SYMBOLS: 11 DECREASI INCREASI
12. 12. 12 P R E S S U R E INHALATION V O L U M E OF AIR
13. 13. 13 V O L U M E OF AIR EXHALATION P R E S S U R E
14. 14. Boyles’ Law and Breathing During an inhalation, •the lungs expand. •the pressure in the lungs decreases. •air flows towards the lower pressure in the lungs. 14Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings
15. 15. Boyles’ Law and Breathing During an exhalation, •lung volume decreases. •pressure within the lungs increases. •air flows from the higher pressure in the lungs to the outside. 15 Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings
16. 16. Calculations with Boyle’s Law 16
17. 17. LET’S USE GRASA IN SOLVING: •G •R •A •S •A 17 GIVEN REQUIRE D ANSWER SOLUTION ANALYSIS
18. 18. Calculation with Boyle’s Law Freon-12, CCl2F2, is used in refrigeration systems. What is the new volume (L) of a 8.0 L sample of Freon gas initially at 550 mm Hg after its pressure is changed to 2200 mm Hg at constant T? 1. Set up a data table: Conditions 1 Conditions 2 P1 = 550 mm Hg P2 = 2200 mm Hg V1 = 8.0 L V2 = 18 ?
19. 19. Calculation with Boyle’s Law (Continued) 2. When pressure increases, volume decreases. Solve Boyle’s Law for V2: P1V1 = P2V2 V2 = V1 x P1 P2 V2 = 8.0 L x 550 mm Hg = 2.0 L 2200 mm Hg pressure ratio 19
20. 20. Learning Check For a cylinder containing helium gas indicate if cylinder A or cylinder B represents the new volume for the following changes (n and T are constant). 1) pressure decreases 2) pressure increases 20
21. 21. Solution For a cylinder containing helium gas indicate if cylinder A or cylinder B represents the new volume for the following changes (n and T are constant): 1) Pressure decreases B 2) Pressure increases A 21
22. 22. Learning Check If a sample of helium gas has a volume of 120 mL and a pressure of 850 mm Hg, what is the new volume if the pressure is changed to 425 mm Hg ? 1) 60 mL 2) 120 mL 3) 240 mL 22
23. 23. Solution 3) 240 mL P1 = 850 mm Hg P2 = 425 mm Hg V1 = 120 mL V2 = ?? V2= V1 x P1= 120 mL x 850 mm Hg = 240 mL P2 425 mm Hg Pressure ratio increases volume 23
24. 24. Learning Check A sample of helium gas in a balloon has a volume of 6.4 L at a pressure of 0.70 atm. At 1.40 atm (T constant), is the new volume represented by A, B, or C? 24
25. 25. Solution A sample of helium gas in a balloon has a volume of 6.4 L at a pressure of 0.70 atm. At a higher pressure (T constant), the new volume is represented by the smaller balloon A. 25
26. 26. Learning Check If the sample of helium gas has a volume of 6.4 L at a pressure of 0.70 atm, what is the new volume when the pressure is increased to 1.40 atm (T constant)? A) 3.2 L B) 6.4 L C) 12.8 L 26
27. 27. Solution If the sample of helium gas has a volume of 6.4 L at a pressure of 0.70 atm, what is the new volume when the pressure is increased to 1.40 atm (T constant)? A) 3.2 L V2 = V1 x P1 P2 V2 = 6.4 L x 0.70 atm = 3.2 L 1.40 atm Volume decreases when there is an increase in the pressure (temperature is constant.) 27
28. 28. Learning Check A sample of oxygen gas has a volume of 12.0 L at 600. mm Hg. What is the new pressure when the volume changes to 36.0 L? (T and n constant). 1) 200. mm Hg 2) 400. mm Hg 3) 1200 mm Hg 28
29. 29. Solution 1) 200. mm Hg Data table Conditions 1 Conditions 2 P1 = 600. mm Hg P2 = ??? V1 = 12.0 L V2 = 36.0 L P2 =P1 x V1 V2 600. mm Hg x 12.0 L = 200. mm Hg 36.0 L 29
30. 30. LET’S DO IT! •1. Oxygen gas inside a 1.5 L gas tank has a pressure of 0.95 atm. Provided that the temperature remains constant, how much pressure is needed to reduce by ½? •Required:? •Pressure ₂/P₂ 30
31. 31. LET’S DO IT! •1. Oxygen gas inside a 1.5 L gas tank has a pressure of 0.95 atm. Provided that the temperature remains constant, how much pressure is needed to reduce by ½? •GIVEN: •V₁=1.5L •P₁=0.95atm •V₂=½( V₁) •P₂=? 31
32. 32. LET’S DO IT! •1. Oxygen gas inside a 1.5 L gas tank has a pressure of 0.95 atm. Provided that the temperature remains constant, how much pressure is needed to reduce by ½? •FORMULA: •P2=P1V1/V2 32
33. 33. LET’S DO IT! •1. Oxygen gas inside a 1.5 L gas tank has a pressure of 0.95 atm. Provided that the temperature remains constant, how much pressure is needed to reduce by ½? • FINAL ANSWER: •1.9 atm •The volume is reduced/decreased so pressure increase 33
34. 34. LET’S DO IT! •1.A scuba diver needs a diving tank in order to provide breathing gas while he is underwater. How much pressure is needed for 6L of gas at 1.01 atmospheric pressure to be compressed in a 3L cylinder? •2. a sample of fluorine gas occupies a volume of 600mL at 760 torr. Given that the temperature remains the same, calculate the pressure required to reduce its volume by 1/3? 34
• #### JohnAceChing

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Jan. 21, 2020
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Sep. 1, 2019

This ppt is a lecture on Boyle's Law. It contains examples and conversions. It will help you understand the concept more as I simplify the concept intended for the understanding of my science class.

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