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Prove the following statement about divisibility of integers:
If d|(a+b) and d|a, then d|b.
Solution
we can write d =(a+b) where is an integer;
also d= 'a where ' is an integer
'a = (a+b) => ('-)a = b => {('-)/}a = b.........(1)
If d is divisible by b then d="b => d=" {('-)/}a [" is an integer] [Putting value of b from (1)]
" {('-)/} is also an integer and thus d is divisible by a as given in the ques.......
Thus our assumption is correct
Thus d is divisible by b........
Hope you understand the explanation

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Prove the following statement about divisibility of integers If d.pdf

  • 1. Prove the following statement about divisibility of integers: If d|(a+b) and d|a, then d|b. Solution we can write d =(a+b) where is an integer; also d= 'a where ' is an integer 'a = (a+b) => ('-)a = b => {('-)/}a = b.........(1) If d is divisible by b then d="b => d=" {('-)/}a [" is an integer] [Putting value of b from (1)] " {('-)/} is also an integer and thus d is divisible by a as given in the ques....... Thus our assumption is correct Thus d is divisible by b........ Hope you understand the explanation