Please show steps so i can udnerstand the problem 0 2 pi sin2 x d x Solution The antiderivative of sin is -cos + c -cos^2x |2pi to 0 the value of cosine at 2pi is 1 and that makes it -1 and the value at zero is the same, -1. the points 2pi and 0 are the same coordinate on a unit circle and since you subtract -1 from -1 you get 0. -1--1 is the same as -1+1 WHICH IS 0 PLEASE RATE.