From previous questionMolarity of bleach M1 = 0.762 MVolume of .pdf
From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL Solution From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL.
From previous questionMolarity of bleach M1 = 0.762 MVolume of .pdf
From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL Solution From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL.
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From previous questionMolarity of bleach M1 = 0.762 MVolume of .pdf
- 1. From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL Solution From previous question: Molarity of bleach M1 = 0.762 M Volume of bleach V1 = ? Molarity of final solution M2 = 0.400 M Volume of final solution V2 = 250 mL Since moles of NaClO are the same for both: M1V1 = M2V2 0.762 x V1 = 0.400 x 250 Volume of bleach V1 = 131 mL