1. A machine makes fuses with an average of 1% defective. If random variable x shows the number
of defective fuses in the sample of 4, find the probability distribution function of random variable
x.
Thanks
Solution
X= number of defective fuses in a sample of size 4 p= probability of making a fuse
= .01 Hence, X is Binomial(n=4, p=.01) P(X=k) = (n!/(k!(n-k)!)) * p^k * (1-p)^(n-k) Where n=4
and p=.01