1. Thanks Find and z = x2 - ytanx ; x = u/v; y = u2 v2
Solution
pd(z,u)= 2x*[pd(x,u)]-ysec2x[pd(x,u)]-tanx[pd(y,u)]
pd(x,u)=1/v pd(y,u)=2u v2
=> pd(z,u)=2(u/v)(1/v)-[(uv)2(sec2(u/v)(1/v)]-tan(u/v)(2uv2)
pd(z,v)=2x[pd(x,v)]-ysec2x[pd(x,v)]-tanx[pd(y,v)]
pd(x,v)=-u/v2 pd(y,v)=2vu2
=> pd(z,v)=2(u/v)(-u/v2 )-[(uv)2(sec2(u/v)(-u/v2)]-tan(u/v)2vu2