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TITLE :
  URBAN TRANSPORTATION


            ASSIGNMENT 2


NAME        : MUHAMMAD BIN RAMLAN

MATRIX NO   : P 57600

SUBJECT     : KKKA 6564

YEAR        : 2011/2012

LECTURER    : PROF IR DR RIZA ATIQ O.K. RAHMAT
QUESTION ASSIGNMENT 2

In an urban transport study, a city is divided into six zones as shown in Figure 1. The
summarized land use data is given in Table 1.




                                                                        5


                                                        4               1
                                                                            2
                                    6

                                                                    3



                                            Figure 1




                                             Table 1

                              Zone      Residential unit Commercial
                                                          land use
                                                            (m2)

                                1               7,000       6,800,000

                                2             20,000         370,000

                                3             31,000         280,000

                                4             25,000         300,000

                                5             22,000         360,000

                                6             35,000         400,000
Production rate of the residential unit is 1.9 trips per hour and attraction rate of the commercial
premises is 3.25 trips per 100 sq. meter floor area.

a) Compute the production and attraction of each zone.
b) Balance the production and the attraction.
c) Compute O-D trip matrix for the city.
d) Sketch the trip interchanges
SOLUTION ASSIGNMENT 2


a) Compute production and attraction of each zone

 Zone          Land Use           Production rate                 Production
           (Residential Unit)  (person-trip / unit / hr)       (person-trip / hr)
   1             7,000                  1.90                  7000 x 1.9 = 13,300
   2            20,000                  1.90                        38,000
   3            31,000                  1.90                        58,900
   4            25,000                  1.90                        47,500
   5            22,000                  1.90                        41,800
   6            35,000                  1.90                        66,500
                         Total                                     266,000


 Zone          Land Use              Attraction rate              Attraction
             (Commercial          (person-trip / m2 / hr)      (person-trip / hr)
               Premises)
   1          6,800,000                    3.25             6800000 x (3.25/100)=
                                                                  221,000
   2           370,000                     3.25                    12,025
   3           280,000                     3.25                    9,100
   4           300,000                     3.25                    9,750
   5           360,000                     3.25                    11,700
   6           400,000                     3.25                    13,000
                         Total                                    276,575


b) Balance the production and the attraction.


 Zone     Production rate        Attraction rate                    Balanced
                                                       Production rate      Attraction rate
   1          13,300                221,000          (13,300/266,000) x (221,000/276,575)
                                                      271,288 = 13,564       x 271,288 =
                                                                               216,775
   2           38,000              12,025                  38,755               11,795
   3           58,900              9,100                   60,071                8,926
   4           47,500               9,750                  48,444                9,564
   5           41,800              11,700                  42,631               11,476
   6           66,500              13,000                  67,822               12,751
 Total        266,000             276,575                    Nil                  Nil
Average     (266,000 + 276,575) / 2 = 271,288
c) Compute O-D trip matrix for the city.

Zone                        1                  2           3           4         5        6
        Value            216,775             11,795      8,926       9,564     11,476   12,751
 1      13,564      (13,564/271,288) x        590         446         478       574      638
                     216,775 = 10,838
 2      38,755            30,968              1,685      1,275       1,366      1,639   1,822
 3      60,071            48,000              2,612      1,976       2,118      2,541   2,823
 4      48,444            38,710              2,106      1,594       1,708      2,049   2,277
 5      42,631            34,065              1,854      1,403       1,503      1,803   2,004
 6      67,822            54,194              2,949      2,232       2,391      2,869   3,188

The O-D trip matrix value for zone 1 until zone 6 is as per bold in the table above.
d) Sketch the trip interchanges.

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KA6564 Assignment 2

  • 1. TITLE : URBAN TRANSPORTATION ASSIGNMENT 2 NAME : MUHAMMAD BIN RAMLAN MATRIX NO : P 57600 SUBJECT : KKKA 6564 YEAR : 2011/2012 LECTURER : PROF IR DR RIZA ATIQ O.K. RAHMAT
  • 2. QUESTION ASSIGNMENT 2 In an urban transport study, a city is divided into six zones as shown in Figure 1. The summarized land use data is given in Table 1. 5 4 1 2 6 3 Figure 1 Table 1 Zone Residential unit Commercial land use (m2) 1 7,000 6,800,000 2 20,000 370,000 3 31,000 280,000 4 25,000 300,000 5 22,000 360,000 6 35,000 400,000
  • 3. Production rate of the residential unit is 1.9 trips per hour and attraction rate of the commercial premises is 3.25 trips per 100 sq. meter floor area. a) Compute the production and attraction of each zone. b) Balance the production and the attraction. c) Compute O-D trip matrix for the city. d) Sketch the trip interchanges
  • 4. SOLUTION ASSIGNMENT 2 a) Compute production and attraction of each zone Zone Land Use Production rate Production (Residential Unit) (person-trip / unit / hr) (person-trip / hr) 1 7,000 1.90 7000 x 1.9 = 13,300 2 20,000 1.90 38,000 3 31,000 1.90 58,900 4 25,000 1.90 47,500 5 22,000 1.90 41,800 6 35,000 1.90 66,500 Total 266,000 Zone Land Use Attraction rate Attraction (Commercial (person-trip / m2 / hr) (person-trip / hr) Premises) 1 6,800,000 3.25 6800000 x (3.25/100)= 221,000 2 370,000 3.25 12,025 3 280,000 3.25 9,100 4 300,000 3.25 9,750 5 360,000 3.25 11,700 6 400,000 3.25 13,000 Total 276,575 b) Balance the production and the attraction. Zone Production rate Attraction rate Balanced Production rate Attraction rate 1 13,300 221,000 (13,300/266,000) x (221,000/276,575) 271,288 = 13,564 x 271,288 = 216,775 2 38,000 12,025 38,755 11,795 3 58,900 9,100 60,071 8,926 4 47,500 9,750 48,444 9,564 5 41,800 11,700 42,631 11,476 6 66,500 13,000 67,822 12,751 Total 266,000 276,575 Nil Nil Average (266,000 + 276,575) / 2 = 271,288
  • 5. c) Compute O-D trip matrix for the city. Zone 1 2 3 4 5 6 Value 216,775 11,795 8,926 9,564 11,476 12,751 1 13,564 (13,564/271,288) x 590 446 478 574 638 216,775 = 10,838 2 38,755 30,968 1,685 1,275 1,366 1,639 1,822 3 60,071 48,000 2,612 1,976 2,118 2,541 2,823 4 48,444 38,710 2,106 1,594 1,708 2,049 2,277 5 42,631 34,065 1,854 1,403 1,503 1,803 2,004 6 67,822 54,194 2,949 2,232 2,391 2,869 3,188 The O-D trip matrix value for zone 1 until zone 6 is as per bold in the table above.
  • 6. d) Sketch the trip interchanges.