Determine if each relation is a function and if it is one-to-one. a) f(x)= -8x b) g(t)= 1/t^2 c) j(c)= +/- (sqrt c-1) Solution a) f(x) =-8x this is function domain from x=- to x=+ and range from - to + and it is one to one function since for each value of x there is only one value of f(x) b) g(t) =1/t^2 this is a function having domain from t=- to t=+ except o and not defined at t=0 and range from aproax. 0 to + this is not one to one since for two value ( e.g -1 and +1) it has the same value . c) j(c) =± sqrt(c-1) this has domain for all c >= 1 its range is from - to + it is not one to one relation since for one value of c (e.g c=2) it has two value ( +sqrt(1) and - sqrt(1) ).