PERCENTILE : MEASURES OF POSITION FOR GROUPED DATA

Chuckry Maunes
Chuckry MaunesInstructor at School of Taughts :D à Department of Education
PERCENTILE : MEASURES OF POSITION FOR GROUPED DATA
OBJECTIVES
•ILLUSTRATE THE FOLLOWING MEASURES OF
POSITION: QUARTILES, DECILES AND PERCENTILES
•CALCULATE SPECIFIED MEASURE OF POSITION (E.G.
90TH PERCENTILE) OF A SET OF DATA.
PERCENTILE FOR GROUPED DATA
•THE PERCENTILE OF GROUPED DATA IS USED TO
CHARACTERIZE VALUES ACCORDING TO THE
PERCENTAGE BELOW THEM.
THE PERCENTILE FOR GROUPED DATA
1. THE FOLLOWING FORMULA IS USED IN FINDING THE PERCENTILE
OF GROUPED DATA
kN
cfb-
Pk = LB +
100
fPK[ ]i
Where: LB = lower boundary of Pk class
N = total frequency
cfb = cumulative frequency of the
class before the Pk class
fPk = frequency of the Pk class
i = size of the class interval
k = nth quartile, where n = 1, 2, 3, … , 99
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
2. FORMULA TO CALCULATE THE PK CLASS
Pk class=
kN
100
Where: N = total frequency
k = nth quartile, where n = 1, 2, 3, 4, …, 97, 98, & 99
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
EXAMPLE
CALCULATE THE 25TH PERCENTILE AND 82ND PERCENTILE OF
THE MATHEMATICS TEST SCORES OF 50 STUDENTS
SCORES FREQUENCY
46-50 4
41-45 8
36-40 11
31-35 9
26-30 12
21-25 6
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 1.A: DETERMINE THE LOWER BOUNDARIES
SCORES FREQUENCY Lower Boundaries
(LB)
46-50 4
41-45 8
36-40 11
31-35 9
26-30 12 25.5
21-25 6 20.5
To solve for LB
subtract 0.5 to the
smallest number per
class interval
21 – 0.5 = 20.5
30.5
35.5
40.5
45.5
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 1.B: DETERMINE THE CUMULATIVE FREQUENCY
SCORES FREQUENCY Lower Boundaries
(LB)
Less than
Cumulative
Frequency (<cf)
46-50 4 45.5
41-45 8 40.5
36-40 11 35.5
31-35 9 30.5 27
26-30 12 25.5 18
21-25 6 20.5 6 Copied from the frequency
6 + the frequency of the class interval
18 + the frequency of the class interval
38
46
50
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
P25 class=
25N
100
STEP 2.A: CALCULATE THE P25 CLASS
N = 50 k = 25Given:
=
25(50)
100
=12.5
This means that we need to find the class interval where
the 12.5th score is contained
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE P25
CLASS IS SITUATED
SCORES FREQUENCY Lower Boundaries
(LB)
Less thanCumulative
Frequency (<cf)
46-50 4 45.5 50
41-45 8 40.5 46
36-40 11 35.5 38
31-35 9 30.5 27
26-30 12 25.5 18
21-25 6 20.5 6
(7th to 18th score)
P25 class
The P25 class is class interval 26-30
N = 50
cfb = 6
fP25 = 12
LB = 25.5
i = 5
Σ f = 50
Cfb =
fP25 = LB =
i = 5
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 2: SOLVE P25 USING THE FORMULA
25N
cfb-
P25 = LB +
100
fP25[ ]i
N = 50
cfb = 6
fP25 = 12
LB = 25.5
i = 5
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
Therefore, 25% of the students got a score less than or equal to 28.21
25(50)
6-
P25 = 25.5 + 100
12[ ]5
Given: N = 50
cfb = 6
fP25 = 12
LB = 25.5
i = 5
P25 = 28.21 Final answer
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
P82 class=
82N
100
STEP 2.A: CALCULATE THE P82 CLASS
N = 50 k = 82Given:
=
82(50)
100
= 41
This means that we need to find the class interval where
the 41st score is contained
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE P82
CLASS IS SITUATED
SCORES FREQUENCY Lower Boundaries
(LB)
Less thanCumulative
Frequency (<cf)
46-50 4 45.5 50
41-45 8 40.5 46
36-40 11 35.5 38
31-35 9 30.5 27
26-30 12 25.5 18
21-25 6 20.5 6
(39th to 46th score)
P82 class
The P82 class is class interval 41-45
N = 50 cfb = 38
fP82 = 8 LB = 40.5
i = 5
Σ f = 50
Cfb =
fP82 = LB =
i = 5
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
STEP 2: SOLVE P82 USING THE FORMULA
82N
cfb-
P82 = LB +
100
fP82[ ]i
N = 50
cfb = 38
fP82 = 8
LB = 40.5
i = 5
THE MEASURE OF POSITION
PERCENTILE FOR GROUPED DATA
Therefore, 82% of the students got a score less than or equal to 42.38
82(50)
38-
P82 = 40.5 + 100
8[ ]5
Given: N = 50
cfb = 38
fP82 = 8
LB = 40.5
i = 5
P82 = 42.38 Final answer
OBJECTIVES
•ILLUSTRATE THE FOLLOWING MEASURES OF
POSITION: QUARTILES, DECILES AND PERCENTILES
•CALCULATE SPECIFIED MEASURE OF POSITION (E.G.
90TH PERCENTILE) OF A SET OF DATA.
THANK YOU
EDUCATIONAL PROJAMS
1 sur 18

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PERCENTILE : MEASURES OF POSITION FOR GROUPED DATA

  • 2. OBJECTIVES •ILLUSTRATE THE FOLLOWING MEASURES OF POSITION: QUARTILES, DECILES AND PERCENTILES •CALCULATE SPECIFIED MEASURE OF POSITION (E.G. 90TH PERCENTILE) OF A SET OF DATA.
  • 3. PERCENTILE FOR GROUPED DATA •THE PERCENTILE OF GROUPED DATA IS USED TO CHARACTERIZE VALUES ACCORDING TO THE PERCENTAGE BELOW THEM.
  • 4. THE PERCENTILE FOR GROUPED DATA 1. THE FOLLOWING FORMULA IS USED IN FINDING THE PERCENTILE OF GROUPED DATA kN cfb- Pk = LB + 100 fPK[ ]i Where: LB = lower boundary of Pk class N = total frequency cfb = cumulative frequency of the class before the Pk class fPk = frequency of the Pk class i = size of the class interval k = nth quartile, where n = 1, 2, 3, … , 99
  • 5. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA 2. FORMULA TO CALCULATE THE PK CLASS Pk class= kN 100 Where: N = total frequency k = nth quartile, where n = 1, 2, 3, 4, …, 97, 98, & 99
  • 6. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA EXAMPLE CALCULATE THE 25TH PERCENTILE AND 82ND PERCENTILE OF THE MATHEMATICS TEST SCORES OF 50 STUDENTS SCORES FREQUENCY 46-50 4 41-45 8 36-40 11 31-35 9 26-30 12 21-25 6
  • 7. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 1.A: DETERMINE THE LOWER BOUNDARIES SCORES FREQUENCY Lower Boundaries (LB) 46-50 4 41-45 8 36-40 11 31-35 9 26-30 12 25.5 21-25 6 20.5 To solve for LB subtract 0.5 to the smallest number per class interval 21 – 0.5 = 20.5 30.5 35.5 40.5 45.5
  • 8. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 1.B: DETERMINE THE CUMULATIVE FREQUENCY SCORES FREQUENCY Lower Boundaries (LB) Less than Cumulative Frequency (<cf) 46-50 4 45.5 41-45 8 40.5 36-40 11 35.5 31-35 9 30.5 27 26-30 12 25.5 18 21-25 6 20.5 6 Copied from the frequency 6 + the frequency of the class interval 18 + the frequency of the class interval 38 46 50
  • 9. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA P25 class= 25N 100 STEP 2.A: CALCULATE THE P25 CLASS N = 50 k = 25Given: = 25(50) 100 =12.5 This means that we need to find the class interval where the 12.5th score is contained
  • 10. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE P25 CLASS IS SITUATED SCORES FREQUENCY Lower Boundaries (LB) Less thanCumulative Frequency (<cf) 46-50 4 45.5 50 41-45 8 40.5 46 36-40 11 35.5 38 31-35 9 30.5 27 26-30 12 25.5 18 21-25 6 20.5 6 (7th to 18th score) P25 class The P25 class is class interval 26-30 N = 50 cfb = 6 fP25 = 12 LB = 25.5 i = 5 Σ f = 50 Cfb = fP25 = LB = i = 5
  • 11. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 2: SOLVE P25 USING THE FORMULA 25N cfb- P25 = LB + 100 fP25[ ]i N = 50 cfb = 6 fP25 = 12 LB = 25.5 i = 5
  • 12. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA Therefore, 25% of the students got a score less than or equal to 28.21 25(50) 6- P25 = 25.5 + 100 12[ ]5 Given: N = 50 cfb = 6 fP25 = 12 LB = 25.5 i = 5 P25 = 28.21 Final answer
  • 13. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA P82 class= 82N 100 STEP 2.A: CALCULATE THE P82 CLASS N = 50 k = 82Given: = 82(50) 100 = 41 This means that we need to find the class interval where the 41st score is contained
  • 14. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE P82 CLASS IS SITUATED SCORES FREQUENCY Lower Boundaries (LB) Less thanCumulative Frequency (<cf) 46-50 4 45.5 50 41-45 8 40.5 46 36-40 11 35.5 38 31-35 9 30.5 27 26-30 12 25.5 18 21-25 6 20.5 6 (39th to 46th score) P82 class The P82 class is class interval 41-45 N = 50 cfb = 38 fP82 = 8 LB = 40.5 i = 5 Σ f = 50 Cfb = fP82 = LB = i = 5
  • 15. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA STEP 2: SOLVE P82 USING THE FORMULA 82N cfb- P82 = LB + 100 fP82[ ]i N = 50 cfb = 38 fP82 = 8 LB = 40.5 i = 5
  • 16. THE MEASURE OF POSITION PERCENTILE FOR GROUPED DATA Therefore, 82% of the students got a score less than or equal to 42.38 82(50) 38- P82 = 40.5 + 100 8[ ]5 Given: N = 50 cfb = 38 fP82 = 8 LB = 40.5 i = 5 P82 = 42.38 Final answer
  • 17. OBJECTIVES •ILLUSTRATE THE FOLLOWING MEASURES OF POSITION: QUARTILES, DECILES AND PERCENTILES •CALCULATE SPECIFIED MEASURE OF POSITION (E.G. 90TH PERCENTILE) OF A SET OF DATA.