BONUS- Option 2- Dietary lipids (triacylglycerols) can be classified a.docx

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BONUS- Option 2: Dietary lipids (triacylglycerols) can be classified as saturated fats or unsaturated fats. Which is a solid at room temperature? Which is a liquid at room temperature? How is the melting point related to intermolecular forces and structure? Explain. Solution saturated fats are solid at room temperature and unsaturated fats are liquids at room temperature. Saturated fats are long chains of hydrocarbons which pack tightly with each other due to hydrophobic interactions and form high density of intermolecular contacts. So they are solids at room temperature. Unsaturated fats are irregular in shape and cannot pack tightly. So, they are liquids at room temperature. .

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Calculate the cell potential (Ecell for the following lead concentration cell at 298 K. Pb(+) Pb21 [Pb21 Pb21-0.00700 MlI [Pb21-2.75 M Solution For concentration cell, cathode and anode are same electrode So, Eo = 0 Number of electron being transferred in balanced reaction is 2 So, n = 2 right cell is cathode and left cell is anode use: E = Eo - (2.303*RT/nF) log {[Pb2+] at anode/[Pb2+]at cathode} Here: 2.303*R*T/F = 2.303*8.314*298.15/96500 = 0.0592 So, above expression becomes: E = Eo - (0.0592/n) log {[Pb2+] at anode/[Pb2+]at cathode} E = 0 - (0.0592/2) log (0.007/2.75) E = 7.673*10^-2 V Answer: 7.67*10^-2 V .

Calculate the cell potential (Ecell for the following lead concentrati.docx

curtisp2

Calculate [OH-] concentration of solutions with the following pH values. Show your work. (a) 10.66 (b) 2.35 (c) 6.02 (d) 13.42 Solution We know that [H + ][OH - ] = 10 -14 Putting log on both sides, - log [H + ] - log [OH - ] = - log (10 -14 ) pH + pOH = 14 pOH = - log [OH - ] [OH - ] = 10 -pOH 1. pOH = 14 - 10.66 = 3.34 [OH - ] = 0.00046 M 2. pOH = 14 - 2.35 = 11.65 [OH - ] = 2.24 x 10 -12 M 3. pOH = 14 - 6.02 = 7.98 [OH - ] = 1.05 x 10 -8 M 4. pOH = 14 - 13.42 = 0.58 [OH - ] = 0.263 M .

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Cafeteria plan has following advantages: 1.Employees more likely to appreciate value of their benefit package 2.Flexibility of cafeteria plans help meet various employee needs 3.Cafeteria plans can help control employer costs since employees select only the benefits that they want. Could you give me a example for cafeteria plan\'s advantages? Solution Plan Requirements A cafeteria plan is a written benefit plan maintained by an employer for the benefit of its employees. The plan must allow employees to choose between two or more benefits consisting of cash (or a taxable benefit which is treated as cash) and certain \"qualified benefits.\" See, .

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curtisp2

C++ a) What is a null pointer? b) Give an example of a function that returns a pointer. Solution a) A pointer that is assigned NULL is called a null pointer. The NULL pointer is a constant with a value of zero defined in several standard libraries, including iostream. It is always a good practice to assign the pointer NULL to a pointer variable in case you do not have exact address to be assigned. Example : int *ptr = NULL; // integer pointer pointing to NULL b) // function that returns a pointer to integer variable int *add(int a, int b){ int c = a+ b; int *iptr = &c; // pointer that stores address of c return iptr; } .

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By treating a student as a Solution Invitation of appliction for admission into different streams-->Receipt of Applicaton--> Despatch of admit cards for entrance examination--> Administration of entrance test---> Sortlisting of students based on merit--->Intimation to successful candidates for admission--->Collection of admission fee and admission-->Allocation of Roll numbers and Registration Numbers-->Preparation of Time Table and Teaching--->Conducting Class Test and Semester Examinations--->Evaluation,Compilation and Publication of Results--->Calculation of SGPI &CGPI at the end of each smester--->CGPI at the Final Semester--->Award of Degree and Mark sheet-->Campus Placement based on tests/interviews by visiting companies and organizations--->College Leaving Certificate Issuance--->Registration for Alumni--->Needbased Alumni interaction/Communication. .

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By how much will the pH change if 0.025 mol of HCl is added to 1.00 L of the buffer that contains 0.15 M HC 2 H 3 O 2 and 0.25 M C 2 H 3 O 2 â€“ ? Use K a = 1.8 Ã— 10 â€“5 for HC 2 H 3 O 2 . Solution Moles of HC2H3O2 = 0.15M*1L = 0.15moles Moles of C2H3O2- = 0.25M*1L = 0.25moles Moles of HCl added = 0.025moles HCl will react with C2H3O2- to form HC2H3O2 HCl + C2H3O2- --> HC2H3O2 + Cl- So, moles of C2H3O2- = 0.25moles-0.025moles = 0.225moles Moles of HC2H3O2 = 0.15moles + 0.025moles = 0.175moles pH = pKa + log[C2H3O2-]/[HC2H3O2] Ka = 1.8*10 -5 pKa = -logKa = 4.74 pH = 4.74 + log0.225/0.175 = 4.85 .

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curtisp2

Build a trie of the following terms using: a. A pointer representation (each node points to its children) b. A Leftmost-Child-Right-Sibling representation at, ate, attack, atop, amp, amuse, be, bet, bide Construct an expression tree for the following equation: (a * b) + 9d * -e) Solution Answer Construct an expression tree for the following equation (a*b) +(d*-e) Here expression is the Infix expression , we can create expression tree using operands like +,-,* (a*b) +(d*-e) Infix expression tree + * * a b - e .

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