dominos game program. and determine each data after each domino is played.1) the total amount of dots.2) the running total of all the dots played.3) if the running total is divisible by 5 without any remainder. and make it idiot proof please. Thanks
Solution
program :
public class domino
{
public static void main(String args[])
{
ArrayList<int []> tiles = new ArrayList<int []>();
Random gen = new Random();
for(int i=0;i<7;i++)
{
for(int j=0;j<7;j++)
{
tiles.add(new int[]{i,j});
System.out.print(\"(\"+ i + \", \" + j + \") \");
}
System.out.println();
}
int [][] player1_tiles = new int[7][49];
int [][] player2_tiles = new int[7][49];
int [] tile1 = null;
int [] tile2 = null;
for(int i=0;i<player1_tiles.length;i++)
{
tile1 = tiles.get(gen.nextInt(tiles.size()));
tile2 = tiles.get(gen.nextInt(tiles.size()));
tiles.remove(tile1);
tiles.remove(tile2);
player1_tiles[i] = tile1;
player2_tiles[i] = tile2;
}
System.out.println(\"\ Tile\\tPlayer 1\\tPlayer 2\");
for(int i=0;i<player1_tiles.length;i++)
{
System.out.print((i+1) +\": \\t \");
for(int j=0;j<player1_tiles[i].length;j++)
{
System.out.print(player1_tiles[i][j] + \" \");
}
System.out.print(\"\\t\\t\");
for(int j=0;j<player2_tiles[i].length;j++)
{
System.out.print(player2_tiles[i][j] + \" \");
}
System.out.println();
}
System.out.println();
if(tile1[0]>tile2[1] && tile1[1]>tile2[1])
{
System.out.println(\"player 1 drops first\");
}
else{
System.out.println(\"player 2 drops first\");
}
}
}
.
Kodo Millet PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
dominos game program- and determine each data after each domino is pla.docx
1. dominos game program. and determine each data after each domino is played.1) the total amount
of dots.2) the running total of all the dots played.3) if the running total is divisible by 5 without
any remainder. and make it idiot proof please. Thanks
Solution
program :
public class domino
{
public static void main(String args[])
{
ArrayList<int []> tiles = new ArrayList<int []>();
Random gen = new Random();
for(int i=0;i<7;i++)
{
for(int j=0;j<7;j++)
{
tiles.add(new int[]{i,j});
System.out.print("("+ i + ", " + j + ") ");
}
System.out.println();
}
int [][] player1_tiles = new int[7][49];
int [][] player2_tiles = new int[7][49];
int [] tile1 = null;
int [] tile2 = null;
for(int i=0;i<player1_tiles.length;i++)
{
tile1 = tiles.get(gen.nextInt(tiles.size()));
tile2 = tiles.get(gen.nextInt(tiles.size()));
tiles.remove(tile1);
tiles.remove(tile2);
player1_tiles[i] = tile1;
player2_tiles[i] = tile2;
}
![dominos game program. and determine each data after each domino is played.1) the total amount
of dots.2) the running total of all the dots played.3) if the running total is divisible by 5 without
any remainder. and make it idiot proof please. Thanks
Solution
program :
public class domino
{
public static void main(String args[])
{
ArrayList<int []> tiles = new ArrayList<int []>();
Random gen = new Random();
for(int i=0;i<7;i++)
{
for(int j=0;j<7;j++)
{
tiles.add(new int[]{i,j});
System.out.print("("+ i + ", " + j + ") ");
}
System.out.println();
}
int [][] player1_tiles = new int[7][49];
int [][] player2_tiles = new int[7][49];
int [] tile1 = null;
int [] tile2 = null;
for(int i=0;i<player1_tiles.length;i++)
{
tile1 = tiles.get(gen.nextInt(tiles.size()));
tile2 = tiles.get(gen.nextInt(tiles.size()));
tiles.remove(tile1);
tiles.remove(tile2);
player1_tiles[i] = tile1;
player2_tiles[i] = tile2;
}](https://image.slidesharecdn.com/dominosgameprogram-anddetermineeachdataaftereachdominoispla-230131044923-5894a21a/85/dominos-game-program-and-determine-each-data-after-each-domino-is-pla-docx-1-320.jpg)
![System.out.println(" TiletPlayer 1tPlayer 2");
for(int i=0;i<player1_tiles.length;i++)
{
System.out.print((i+1) +": t ");
for(int j=0;j<player1_tiles[i].length;j++)
{
System.out.print(player1_tiles[i][j] + " ");
}
System.out.print("tt");
for(int j=0;j<player2_tiles[i].length;j++)
{
System.out.print(player2_tiles[i][j] + " ");
}
System.out.println();
}
System.out.println();
if(tile1[0]>tile2[1] && tile1[1]>tile2[1])
{
System.out.println("player 1 drops first");
}
else{
System.out.println("player 2 drops first");
}
}
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)