The fourth longest wavelength in the Lyman series in hydrogen in the figure above corresponds to what transition? The fourth longest wavelength in the Lyman series in hydrogen in the figure above corresponds to what transition? n Ionized atom (continuous energy levels) -0.85 Excited states Paschen series n= Energy-level diagram for the hydrogen atom, showing the transitions for the spectral lines of the Lyman, Balmer, and Paschen series. Balmer series Each vertical arrow represents an atomic transition that gives rise to the photons of one spectral line (a single wavelength or frequency -10 n- Ground state -13.6 Lyman series -15 Solution wavelength=h*c/energy difference so lesser the energy gap, higher is the wavelength so lowest energy gap will be for n=2 to n’=1 then the energy gap will increase gradually hence in terms of energy gp, n=2 to n’=1 < n=3 to n’=1 < n=4 to n’=1 < n=5 to n’=1 and so on. so fourth longest wavelength would be for n=5 to n’=1 .

1. The fourth longest wavelength in the Lyman series in hydrogen in the figure above corresponds
to what transition?
The fourth longest wavelength in the Lyman series in hydrogen in the figure above corresponds
to what transition?
n = 3 to n ? = 1.
n = 2 to n ? = 1.
n = 4 to n ? = 1.
n = 5 to n ? = 1.
n Ionized atom (continuous energy levels) -0.85 Excited states Paschen series n= Energy-level
diagram for the hydrogen atom, showing the transitions for the spectral lines of the Lyman,
Balmer, and Paschen series. Balmer series Each vertical arrow represents an atomic transition
that gives rise to the photons of one spectral line (a single wavelength or frequency -10 n-
Ground state -13.6 Lyman series -15
Solution
wavelength=h*c/energy difference
so lesser the energy gap, higher is the wavelength
so lowest energy gap will be for n=2 to n’=1
then the energy gap will increase gradually
hence in terms of energy gp,
n=2 to n’=1 < n=3 to n’=1 < n=4 to n’=1 < n=5 to n’=1 and so on.
so fourth longest wavelength would be for n=5 to n’=1