2. A bsorption - D istribution -M etabolism -E xcretion ABSORPTION i.v. DISTRIBUTION DISTRIBUTION LIVER: M + BE KIDNEY: Ur. E

7. Distribution Drug distribution means the reversible transfer of drug from one location to another within the body. Once a drug has entered the vascular system it becomes distributed throughout the various tissues and body fluids in a pattern that reflects the physico-chemical nature of the drug and the ease with which it penetrates different membranes.

13. Rapid (bolus) i.v. injection and uniform mixing of the amount administered throughout the volume of total body water: V d =V total body water V d = 0.6 L/kg BW Dose = c plasma . V d V d =Dose/c plasma Fat !!! 0,2-0,35 L water per 1 kg of weight

15. Volumes of some compartments of the adult human body in relation to V D : Total body water 0.6 L/kg BW Intracellular water 0.4 L/kg BW Extracellular water 0.2 L/kg BW Plasma 0.04 L/kg BW V D 0.05 L/kg the drug remains in the blood (heparine) V D 0.1-0.3 L/kg distribution from blood into extracellular fluid (gentamicin - polar drugs). V D 0.6 L/kg distribution from blood into intracelular and extracellular fluid (methotrexate) V D >>0.6 L/kg distribution intracellularly and high binding in tissues ( amiodarone - 350 L/kg)

17. L. Dose Loading dose = C P x V D

18. Use of Vd: EXAMPLE: J.K.(TBW = 90 kg)was admitted to the ICU for pneumonia caused by Gram-negative bacteria. Calculate the loading dose of tobramycin for this patient to achieve the target average concentration of 4 mg/l. Tobramycin V D is 0.2 l/kg of TBW. Loading Dose = ? Loading Dose = 0.2 . TBW . Concentration Loading Dose = 0.2 . 90 . 4 = 72 mg

23. Rate of elimination Elimination of most drugs from the body after therapeutically relevant doses follows first-order kinetics. To illustrate first order kinetics we might consider what would happen if we were to give a drug by i.v. bolus injection, collect blood samples at various times and measure the plasma concentrations of the drug. We might see a decrease in concentration as the drug is eliminated.

24. Rate of elimination Elimination which follows first-order kinetics: dC/dt = - k el . C k el …. rate constant of elimination rate of change is proportional to concentration and is therefore decreasing with time as the conc. decreases

25. Rate of elimination half-life : t 1/2 C= C 0 / 2 t= t 1/2 = ln2 / kel = 0.693/ kel after 4 half-lives: 6% remaining, 94% eliminated monoexponential decay: C(t) = C 0 . e - kel . t

26. Rate of elimination Elimination which follows first-order kinetics: semi-log graph. t 1/2 = 0.693/ k el k el can be estimated by means of the linear-regression analysis

28. The principle of linear pharmacokinetics Linear (first-order) pharmacokinetics: For most drugs, clearance is constant over the plasma concentration range used in clinical practice. Elimination is not saturable (non-capacity-limited) and the rate of drug elimination is directly proporcionate to the concentration: Rate of elimin. = CL . Concentration

29. Nonlinear pharmacokinetics Nonlinear pharmacokinetics: (capacity-limited, dose or concentration dependent, saturable) CL varies depending on the concentration of a drug. Rate of elimination = Vmax . C /Michaelis- Menten/ K m + C CL = Vmax K m + C ethanol, phenytoin, theofylline

33. Calculation of the maintenance dose J.K.was admitted to the ICU for pneumonia caused by Gram-negative bacteria. Calculate the maintenance dose (i.v.-infusion in 6 h intervals)of tobramycin for this patient to achive the target average concentration of 4 mg/l. Clearance of tobramycin was estimated to be 70 ml/min. Rate of dosing = Dose / Interval Rate of dosing = Rate of elimination = CL.c T Rate of dosing = 4.70.60 / 1000 = 16.8 mg/h Dose = Rate of dosing . Interval = 6 . 16.8 = 101 mg

34. Multiple i.v. bolus dose administration : drug accu- mulation in plasma until the steady state is achieved

39. Renal clearance CL R Amount excreted = V U . C U KIDNEY CL R = rate of elim. / C in plasma = V U . C U / C in plasma GFR , C in plasma V U , C U GFR 100 -150 ml/min URINE V U = volume collected / urine collection period

40. Renal clearance CL R CL R = rate of elim. / C in plasma = V U . C U / C in plasma Renal clearance of a drug is the ratio of the rate of elimination of the drug by the kidney divided by its concentration in plasma.

41. Renal clearance of the drug CL R = GFR x f unbound + Tubular secretion - Tubular reabsorption Glomerular filtration rate is measured using endogenous creatinine: GFR  creatinine clearance = 100 - 150 ml/min 1/ CL R > GFR x f unbound : filtration + Tubular secretion 2/ CL R < GFR x f unbound : filtration - Tubular reabsorption 3/ CL R  GFR x f unbound : filtration

42. Elimination half-life (t 1/2 ) Definition: Elimination half-life is the time it takes the drug concentration in the blood to decline to one half of its initial value. It is a secondary parameter : The elimination half-life is dependent on the ratio of V D and CL. Unit : time (min, h, day)

43. Use of t 1/2 : 1/ t 1/2 can be used to predict how long it will take for the drug to be eliminated from plasma.

44. Use of t 1/2 : 2/ t 1/2 can be used to predict how long it will take from the start of dosing to reach steady-state levels during multiple dosing or continuous i.v. infusion. No. of t 1/2 Concentration achieved (% of steady conc.) 1 50 2 75 3 87.5 4 94 5 97

46. Important During continuous (infusion) or continuous intermittent dosing (oral dosing): The steady-concentration depends on the rate of dosing (the dose/dosing interval) and the clearance. Time required to achieve steady-state depends on the half-life and is independent of the rate of dosing and the clearance..

47. Use of t 1/2 : 3/ the relationship between t 1/2 and dosing interval  can be used to predict the degree of accumulation of a drug in the blood. The longer t 1/2 and the shorter  , the more drug accumulates.   t 1/2 Moderate accumulation during dosing 2-times)  < t 1/2 Significant accumulation during dosing ( > 2-times)  > t 1/2 Insignificant accumulation during dosing ( < 2-times)

48. Use of t 1/2 : 4/ t 1/2 (the relationship between t 1/2 and dosing interval  ) can be used to predict the degree of fluctuation of a drug concentration within a dosing interval.   t 1/2 C ss,min levels at steady state are aprox. 50% of C ss,max . Moderate fluctuation.  < t 1/2 C ss,min levels at steady state are more than 50% of C ss,max . Small fluctuation.  > t 1/2 C ss,min levels at steady state are less than 50% of C ss,max . Wide fluctuation.

49. Multiple short i.v. infusions of amikacin: the rate of dosing is constant but interdose interval is changing, t 1/2 = 6 h

50. Multiple short i.v. infusions of amikacin: the rate of dosing is constant but interdose interval is changing, t 1/2 = 6 h

51. Use of t 1/2 : 5/ t 1/2 can be used to predict how long it will take a drug concentration to decline from one specific value to another. t = t 1/2 . ln(C1/C2) / 0.7 It can be usefull in overdoses and dosage adjustments.

52. Fundamental relationships between various PK parameters Elimination which follows first-order kinetics can be described by rate constants (or half-lives). If we assume rapid transfer of drug from other parts of the body into plasma, the drug is cleared from its total distribution volume in the body: Rate of elimination = V D . Rate of removal from the unit volume = V D . dC/dt = V d . k el . C CL = Rate of elimination / C = V d . k el = V d . 0.7 / t 1/2

53. Fundamental relationships between various PK parameters Elimination which follows first-order kinetics can be described by rate constants (or half-lives). If we assume rapid transfer of drug from other parts of the body into plasma, the drug is cleared from its total distribution volume in the body: Rate of elimination = Distr. Volume . Rate of removal from the unit volume = V d . dC/dt = V d . k el . C Clearance = Rate of elimination / C = V d . k el = V d . 0.7 / t 1/2 AUC = Dose / (V d . k el )  Clearance = Dose / AUC

54. Area under the curve, AUC C = C 0 . e - k.t monoexponential decay AUC is an integral AUC = Dose / (V . k el ) AUC = Dose / CL CL= Dose / AUC (i.v.) CL= F. Dose / AUC The AUC value is very useful for calculating the amount of drug which reaches the systemic circulation (the absolute bioavailability F) after administration of different drug products.

55. Pharmacokinetics after extravascular administration Most of the routes of administration are extravascular; for example IM, SC, and most importantly oral. With this type of drug administration the drug isn't placed in the systemic circulation but must be absorbed through at least one membrane. This has a considerable effect on drug pharmacokinetics and may cause a reduction in the actual amount of drug which is absorbed and reaches the systemic circulation.

56. Pharmacokinetics after extravascular administration Bioavailable dose = F . Dose F…absolute bioavailability (0 < F < 1) … .after i.v. administration F = 1 Most commonly the absorption process follows first order kinetics. Even though many oral dosage forms are solids, which must dissolve before being absorbed, the overall absorption process can often be considered to be a single first order process.

57. Pharmacokinetics after extravascular administration. Bioavailability AUC C max T max

58. Absorption rate constant (k a )

59. Bioavailable fraction of the dose (F)

60. Bioavailability F must be determined by comparison with another dose administration. If the other dosage form is an intravenous form then the F value is termed the absolute bioavailability. In the case where the reference dosage form is another oral product, the value for F R is termed the relative bioavailability. CL = (D/AUC) i.v. = F. (D/AUC) oral

61. Bioavailability Bioavailability indicates a measurement of the rate and extent (amount) of therapeutically active drug which reaches the general circulation. Absolute bioavailability is the absolute fraction of dose which is available from a drug formulation in general circulation. It is measured by comparing AUC after i.v. and extravascular administration. Relative bioavailability is a relative amount and relative rate of availability if two formulations (other than i.v.) are compared.

62. Bioequivalence Two drug formulations are bioequivalent if the extent and rate of bioavailability of a drug is comparable (within certain limits). Bioequivalence study: new drug formulation of a known active drug is compared to the reference (original formulation or another marketed formulation) in a study with healthy volunteers. Original product, Generic copies

63. Bioequivalence Two drug formulations are bioequivalent if the extent and rate of bioavailability of a drug is comparable (within certain limits). Cross-over study with 2 periods Group 1: Test Reference Group 2: Reference Test AUC, c max , T max ,

64. Some definitions Brand Name is the trade name of the drug. Chemical Name is the name used by the organic chemist to indicate the chemical structure of the drug. Drug Product means a finished dosage form, e.g., tablet, capsule, or solution, that contains the active drug ingredient, generally, but not necessarily, in association with inactive ingredients. Generic Name is the established, common name of the active drug in a drug product.