The switch in the circuit in the accompanying figure has been closed for a long time and is opened at t = 0. Solve for i(t) for t > 0. Pleas round all numbers to 3 significant digits. i(t) = A Solution A pplying the concept of initial conditions we have at t=0- Inductor acts as short and capacitor acts as open so the total current through the circuit= 27/6=4.5A. Now when the switch is open the equation for current can be written as RI(s)+LsI(s)+I(s)/Cs= V. Sub the values we have I(s)[ R+0.125s+I(s)/0.01s]=27. or sIMPLIFYING I(s)= 27/[S 2 +8S+800]. SOLVING THIS QUADRATIC EQUATION WE WILL GET i(S). FROM THIS WE CAN FIND i(t) .