How do I solve this problem? A hot-air balloon 70 meters above the ground is falling at a constat rate of 6 meters per second while another hot-air balloon 10 meters above the ground is rising at a constant rate of 15 meters per second. To the nearest tenth of a second, after how many seconds will the 2 balloons be the same height above the ground? Solution let the height of the first balloon from the ground at any time t be h1 m. then,h1=70-6t similarly,if h2 is the height of balloon 2 from the ground at any time t then, h2=10+15t at some time t,both balloons will be at the same height so,h1=h2 or 70-6t=10+15t or 60=21t or t=60/21 or t=2.8571 sec rounding to nearest tenth,at t=2.9 sec,both the balloons will be at the same height from the ground. .

1. How do I solve this problem?
A hot-air balloon 70 meters above the ground is falling at a constat rate of 6 meters per second
while another hot-air balloon 10 meters above the ground is rising at a constant rate of 15 meters
per second. To the nearest tenth of a second, after how many seconds will the 2 balloons be the
same height above the ground?
Solution
let the height of the first balloon from the ground at any time t be h1 m.
then,h1=70-6t
similarly,if h2 is the height of balloon 2 from the ground at any time t
then, h2=10+15t
at some time t,both balloons will be at the same height
so,h1=h2
or 70-6t=10+15t
or 60=21t
or t=60/21
or t=2.8571 sec
rounding to nearest tenth,at t=2.9 sec,both the balloons will be at the same height from the
ground.