(1) At what points does the helix r(t) = < sin t, cos t, t > intercept the sphere x2 + y2 + z2 = 5 (a) Sketch the plane curve with the given vector equation. (b) Find r\'(t) (c) Sketch the position vector r(t) and the tangent vector r\'(t) for the given value of t. Solution Substitute into the equation of the sphere. (sin t)^2 + (cos t)^2 + t^2 = 5 ==> 1 + t^2 = 5 ==> t = 2 or -2. We have two points of intersection: If t = 2, then r(2) = (sin 2, cos 2, 2). If t = -2, then r(-2) = (sin(-2), cos(-2), -2) = (-sin(2),cos(2),-2) I hope that helps!.