SlideShare a Scribd company logo
1 of 17
31

Today:
Warm-Up: (4)

Review Systems of Equations
New Solving Techniques

Monday: Review for Test Tuesday
4th Period: Only 10 Notebooks submitted
Please leave notebooks again before you

leave.
Warm the
a. Write the equation ofUp line
b. Write the inequality an the line. for a line
1. Write of equation
perpendicular to 2x -4y = -2
2. Solve for a: 9a – 2b = c + 4a
4. Write the systems of equations
shown by the graph below.
Review: Solve Systems of Equations by Graphing
1 =

1+0

2 +

( + 0)
1 = 3

(2,1)

Step 1: Put both equations in
slope - intercept form.

Step 2: Graph both equations on
the same coordinate plane.

Step 3: Plot the point where the
graphs intersect.

Step 4: Check to make sure your
solution makes both equations true.
Review: Solve Systems of Equations by Elimination
(addition or subtraction)
 Elimination is easiest when the equations
are in standard form.
1: Put the equations in
Standard Form.
Step 2: Determine which

variable to eliminate.
Step 3: Add or subtract

the equations.
Step 4: Plug back in to

find the other variable.
Step 5: Check your

solution.

Standard Form: Ax + By = C
Look for variables that have
the same coefficient.
Solve for the variable.
Substitute the value of the
variable into the equation.
Substitute your ordered pair
into BOTH equations.
Review: Solve Systems of Equations by Elimination
(addition or subtraction)

2x + 7y = 31
5x - 7y = - 45
7x + 0 = -14

x = -2

Like variables must be lined under each other.

THEN----
Review: Solve Systems of Equations by Elimination
(addition or subtraction)

2X + 7Y = 31
2(-2) + 7y = 31
-4 + 7y = 31
Substitute your
4
4
answer into either
original equation
and solve for the
second variable.

7y = 35; y = 5
Solution

(-2, 5)

Now check our answers in both
equations------
2x + 7y = 31
2(-2) + 7(5) = 31
-4 + 35 = 31
31 = 31
5x – 7y = - 45
5(-2) - 7(5) = - 45

-10 - 35 = - 45
- 45 =- 45
Solve Systems of Equations by Elimination
(Multiplying)

Like variables
must be lined
under each
other.

x + +y1y 4 4
1x = =
2x + 3y = 9

We need to eliminate (get rid of) a variable.
To simply add this time will not eliminate a variable. If there
was a –2x in the 1st equation, the x’s would be eliminated
when we add. So we will multiply the 1st equation by a – 2.
Solve Systems of Equations by Elimination
(Multiplying)

( X + Y = 4) -2
2X + 3Y = 9

-2X - 2 Y = - 8
2X + 3Y = 9

Now add the two
equations and solve.

THEN----

Y=1
Solve Systems of Equations by Elimination
(Multiplying)

X+Y=4

X +1=4
- 1 -1
X=3
Solution

Substitute your
answer into either
original equation
and solve for the
second variable.

(3,1)

Now check our answers in both equations--
x+y=4
3+1=4
4=4

2x + 3y = 9
2(3) + 3(1) = 9
6+3=9

9=9
Solve Systems of Equations by Elimination
(Multiplying)
3x – 2y = -7
2x -5y = 10

Can you multiply either equation
by an integer in order to eliminate
one of the variables?

Here, we must multiply both
equations by a (different)
number in order to easily
eliminate one of the variables.

 Eliminate
 Plug back in
 Solve for other
variable

Multiply the top
equation by 2, and the
bottom equation by -3

Write your solution as
an ordered pair
(-5,-4)
Plug both solutions into
original equations
3x – 2y = -7
-15 – (-8) = -7
-7 = - 7

2x - 5y = 10

-10 – (-20) = 10
10= 10
Solve: By Substitution
Recall that when we 'solve' a point-slope formula,
we end up in slope-intercept form. In much the
same way, the substitution method is closely
related to the elimination method.
After eliminating one variable and solving for the other,
we substitute the value of the variable back into the
equation.
For example: Solve 2x + 3y = -26 using elimination
4x - 3y = 2
What is the
value of x ?

-4

At this point we substitute -4 for
x, and solve for y. This is exactly
what the substitution method is
except it is done at the beginning.
Solve: By Substitution
Example 1: y = 2x
4x - y = -4

Since the first equation tells us
that y = 2x, replace the y with 2x
in the second equation.

4x - 2x = -4; 2x = -4; x = -2

Then, substitute -2 for x in the first equation:
y = 2(-2); y = -4
Finally, plug both values in and check for equality.
-4 = 2(-2); True;
4(-2) - (-4) = -4; -8 + 4 = -4; True
Class Work:

More Related Content

What's hot

Final presentation
Final presentationFinal presentation
Final presentation
paezp
 
Quadratic Equation
Quadratic EquationQuadratic Equation
Quadratic Equation
itutor
 
February 5, 2014
February 5, 2014February 5, 2014
February 5, 2014
khyps13
 
Ultimate guide to systems of equations
Ultimate guide to systems of equationsUltimate guide to systems of equations
Ultimate guide to systems of equations
khyps13
 
Solving Systems of Linear Inequalities
Solving Systems of Linear InequalitiesSolving Systems of Linear Inequalities
Solving Systems of Linear Inequalities
swartzje
 
linear equation system with 2 and 3 variables
linear equation system with 2 and 3 variableslinear equation system with 2 and 3 variables
linear equation system with 2 and 3 variables
Wanda Sari
 
5.4 write linear equations in standard form day 1
5.4 write linear equations in standard form   day 15.4 write linear equations in standard form   day 1
5.4 write linear equations in standard form day 1
bweldon
 
Linear Equations and Inequalities in One Variable
Linear Equations and Inequalities in One VariableLinear Equations and Inequalities in One Variable
Linear Equations and Inequalities in One Variable
misey_margarette
 
7.7 Solving Radical Equations
7.7 Solving Radical Equations7.7 Solving Radical Equations
7.7 Solving Radical Equations
swartzje
 
Solving systems of Linear Equations
Solving systems of Linear EquationsSolving systems of Linear Equations
Solving systems of Linear Equations
swartzje
 

What's hot (20)

System of linear equations and their solution
System of linear equations and their solutionSystem of linear equations and their solution
System of linear equations and their solution
 
Final presentation
Final presentationFinal presentation
Final presentation
 
6.3 presentation
6.3 presentation6.3 presentation
6.3 presentation
 
Quadratic Equation
Quadratic EquationQuadratic Equation
Quadratic Equation
 
Linear Equations in Two Variables
Linear Equations in Two VariablesLinear Equations in Two Variables
Linear Equations in Two Variables
 
February 5, 2014
February 5, 2014February 5, 2014
February 5, 2014
 
Pair of linear equation in two variables
Pair of linear equation in two variables Pair of linear equation in two variables
Pair of linear equation in two variables
 
Ultimate guide to systems of equations
Ultimate guide to systems of equationsUltimate guide to systems of equations
Ultimate guide to systems of equations
 
Solving Systems of Linear Equations in Two Variables by Graphing
Solving Systems of Linear Equations in Two Variables by GraphingSolving Systems of Linear Equations in Two Variables by Graphing
Solving Systems of Linear Equations in Two Variables by Graphing
 
Pair of linear equations in two variables for classX
Pair of linear equations in two variables for classXPair of linear equations in two variables for classX
Pair of linear equations in two variables for classX
 
Solving Systems of Linear Inequalities
Solving Systems of Linear InequalitiesSolving Systems of Linear Inequalities
Solving Systems of Linear Inequalities
 
linear equation system with 2 and 3 variables
linear equation system with 2 and 3 variableslinear equation system with 2 and 3 variables
linear equation system with 2 and 3 variables
 
9.1 Systems of Linear Equations
9.1 Systems of Linear Equations9.1 Systems of Linear Equations
9.1 Systems of Linear Equations
 
5.4 write linear equations in standard form day 1
5.4 write linear equations in standard form   day 15.4 write linear equations in standard form   day 1
5.4 write linear equations in standard form day 1
 
Linear Equations and Inequalities in One Variable
Linear Equations and Inequalities in One VariableLinear Equations and Inequalities in One Variable
Linear Equations and Inequalities in One Variable
 
M1 L5 Remediation Notes
M1 L5 Remediation NotesM1 L5 Remediation Notes
M1 L5 Remediation Notes
 
Systems of Linear Equations Graphing
 Systems of Linear Equations Graphing  Systems of Linear Equations Graphing
Systems of Linear Equations Graphing
 
7.7 Solving Radical Equations
7.7 Solving Radical Equations7.7 Solving Radical Equations
7.7 Solving Radical Equations
 
Linear Equations
Linear EquationsLinear Equations
Linear Equations
 
Solving systems of Linear Equations
Solving systems of Linear EquationsSolving systems of Linear Equations
Solving systems of Linear Equations
 

Viewers also liked

January 15
January 15January 15
January 15
khyps13
 
February 15
February 15February 15
February 15
khyps13
 
December13, 2013
December13, 2013December13, 2013
December13, 2013
khyps13
 
January 14, 2014
January 14, 2014January 14, 2014
January 14, 2014
khyps13
 
November 30
November 30November 30
November 30
khyps13
 
November 22, 2013
November 22, 2013November 22, 2013
November 22, 2013
khyps13
 
Fri. sept 28
Fri. sept 28Fri. sept 28
Fri. sept 28
khyps13
 
January 23
January 23January 23
January 23
khyps13
 

Viewers also liked (9)

January 15
January 15January 15
January 15
 
Feb 14
Feb 14Feb 14
Feb 14
 
February 15
February 15February 15
February 15
 
December13, 2013
December13, 2013December13, 2013
December13, 2013
 
January 14, 2014
January 14, 2014January 14, 2014
January 14, 2014
 
November 30
November 30November 30
November 30
 
November 22, 2013
November 22, 2013November 22, 2013
November 22, 2013
 
Fri. sept 28
Fri. sept 28Fri. sept 28
Fri. sept 28
 
January 23
January 23January 23
January 23
 

Similar to January 31, 2014

January18
January18January18
January18
khyps13
 
Systems equations two varibles
Systems equations two variblesSystems equations two varibles
Systems equations two varibles
Jessica Garcia
 
January 29, 2014
January 29, 2014January 29, 2014
January 29, 2014
khyps13
 
7 3 by linear combinations - day 1
7 3 by linear combinations - day 17 3 by linear combinations - day 1
7 3 by linear combinations - day 1
bweldon
 
February 12, 2015
February 12, 2015 February 12, 2015
February 12, 2015
khyps13
 
Solving systems of equations
Solving systems of equationsSolving systems of equations
Solving systems of equations
billingssr
 
Solving Linear Equations
Solving Linear EquationsSolving Linear Equations
Solving Linear Equations
taco40
 
7 4 multiply to eliminate - day 1
7 4 multiply to eliminate - day 17 4 multiply to eliminate - day 1
7 4 multiply to eliminate - day 1
bweldon
 
February 7, 2014
February 7, 2014February 7, 2014
February 7, 2014
khyps13
 
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimbozaFolleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
luisdin2729
 

Similar to January 31, 2014 (20)

January18
January18January18
January18
 
Systems equations two varibles
Systems equations two variblesSystems equations two varibles
Systems equations two varibles
 
January 29, 2014
January 29, 2014January 29, 2014
January 29, 2014
 
Linear equation in two variables
Linear equation in two variablesLinear equation in two variables
Linear equation in two variables
 
Analytic Geometry Period 1
Analytic Geometry Period 1Analytic Geometry Period 1
Analytic Geometry Period 1
 
Maths
MathsMaths
Maths
 
Equations Revision
Equations RevisionEquations Revision
Equations Revision
 
7 3 by linear combinations - day 1
7 3 by linear combinations - day 17 3 by linear combinations - day 1
7 3 by linear combinations - day 1
 
LecturePresentation.pptx
LecturePresentation.pptxLecturePresentation.pptx
LecturePresentation.pptx
 
February 12, 2015
February 12, 2015 February 12, 2015
February 12, 2015
 
Solving systems of equations
Solving systems of equationsSolving systems of equations
Solving systems of equations
 
Solving Systems by Graphing and Substitution
Solving Systems by Graphing and SubstitutionSolving Systems by Graphing and Substitution
Solving Systems by Graphing and Substitution
 
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by FactoringSolving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
 
Solving Linear Equations
Solving Linear EquationsSolving Linear Equations
Solving Linear Equations
 
Theory of Equation
Theory of EquationTheory of Equation
Theory of Equation
 
Linear Equations
Linear Equations Linear Equations
Linear Equations
 
7 4 multiply to eliminate - day 1
7 4 multiply to eliminate - day 17 4 multiply to eliminate - day 1
7 4 multiply to eliminate - day 1
 
Linear Equations
Linear EquationsLinear Equations
Linear Equations
 
February 7, 2014
February 7, 2014February 7, 2014
February 7, 2014
 
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimbozaFolleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
Folleto de matematicas, primero bgu, proyecto ebja. ing luis panimboza
 

More from khyps13 (20)

August 23, 2016
August 23, 2016August 23, 2016
August 23, 2016
 
August 22, 2016
August 22, 2016August 22, 2016
August 22, 2016
 
August 19, 2016
August 19, 2016August 19, 2016
August 19, 2016
 
August 18, 2016
August 18, 2016August 18, 2016
August 18, 2016
 
Aug 17, 2016
Aug 17, 2016Aug 17, 2016
Aug 17, 2016
 
March 31, 2016
March 31, 2016March 31, 2016
March 31, 2016
 
March 30, 2016
March 30, 2016March 30, 2016
March 30, 2016
 
March 21, 2016
March 21, 2016March 21, 2016
March 21, 2016
 
April 5, 2016
April 5, 2016April 5, 2016
April 5, 2016
 
April 4, 2016
April 4, 2016April 4, 2016
April 4, 2016
 
April 6, 2016
April 6, 2016April 6, 2016
April 6, 2016
 
April 1, 2016
April 1, 2016April 1, 2016
April 1, 2016
 
February 17 2015
February 17 2015February 17 2015
February 17 2015
 
February 18 2016
February 18 2016February 18 2016
February 18 2016
 
February 16 2016
February 16 2016February 16 2016
February 16 2016
 
February 9 2016
February 9 2016February 9 2016
February 9 2016
 
February 10 2016
February 10 2016February 10 2016
February 10 2016
 
February 8 2016
February 8 2016February 8 2016
February 8 2016
 
February 11 2016
February 11 2016February 11 2016
February 11 2016
 
February 12 2016
February 12 2016February 12 2016
February 12 2016
 

January 31, 2014

  • 1. 31 Today: Warm-Up: (4) Review Systems of Equations New Solving Techniques Monday: Review for Test Tuesday 4th Period: Only 10 Notebooks submitted Please leave notebooks again before you leave.
  • 2. Warm the a. Write the equation ofUp line b. Write the inequality an the line. for a line 1. Write of equation perpendicular to 2x -4y = -2 2. Solve for a: 9a – 2b = c + 4a
  • 3. 4. Write the systems of equations shown by the graph below.
  • 4. Review: Solve Systems of Equations by Graphing 1 = 1+0 2 + ( + 0) 1 = 3 (2,1) Step 1: Put both equations in slope - intercept form. Step 2: Graph both equations on the same coordinate plane. Step 3: Plot the point where the graphs intersect. Step 4: Check to make sure your solution makes both equations true.
  • 5. Review: Solve Systems of Equations by Elimination (addition or subtraction)  Elimination is easiest when the equations are in standard form. 1: Put the equations in Standard Form. Step 2: Determine which variable to eliminate. Step 3: Add or subtract the equations. Step 4: Plug back in to find the other variable. Step 5: Check your solution. Standard Form: Ax + By = C Look for variables that have the same coefficient. Solve for the variable. Substitute the value of the variable into the equation. Substitute your ordered pair into BOTH equations.
  • 6. Review: Solve Systems of Equations by Elimination (addition or subtraction) 2x + 7y = 31 5x - 7y = - 45 7x + 0 = -14 x = -2 Like variables must be lined under each other. THEN----
  • 7. Review: Solve Systems of Equations by Elimination (addition or subtraction) 2X + 7Y = 31 2(-2) + 7y = 31 -4 + 7y = 31 Substitute your 4 4 answer into either original equation and solve for the second variable. 7y = 35; y = 5 Solution (-2, 5) Now check our answers in both equations------
  • 8. 2x + 7y = 31 2(-2) + 7(5) = 31 -4 + 35 = 31 31 = 31 5x – 7y = - 45 5(-2) - 7(5) = - 45 -10 - 35 = - 45 - 45 =- 45
  • 9. Solve Systems of Equations by Elimination (Multiplying) Like variables must be lined under each other. x + +y1y 4 4 1x = = 2x + 3y = 9 We need to eliminate (get rid of) a variable. To simply add this time will not eliminate a variable. If there was a –2x in the 1st equation, the x’s would be eliminated when we add. So we will multiply the 1st equation by a – 2.
  • 10. Solve Systems of Equations by Elimination (Multiplying) ( X + Y = 4) -2 2X + 3Y = 9 -2X - 2 Y = - 8 2X + 3Y = 9 Now add the two equations and solve. THEN---- Y=1
  • 11. Solve Systems of Equations by Elimination (Multiplying) X+Y=4 X +1=4 - 1 -1 X=3 Solution Substitute your answer into either original equation and solve for the second variable. (3,1) Now check our answers in both equations--
  • 12. x+y=4 3+1=4 4=4 2x + 3y = 9 2(3) + 3(1) = 9 6+3=9 9=9
  • 13. Solve Systems of Equations by Elimination (Multiplying) 3x – 2y = -7 2x -5y = 10 Can you multiply either equation by an integer in order to eliminate one of the variables? Here, we must multiply both equations by a (different) number in order to easily eliminate one of the variables.  Eliminate  Plug back in  Solve for other variable Multiply the top equation by 2, and the bottom equation by -3 Write your solution as an ordered pair (-5,-4) Plug both solutions into original equations
  • 14. 3x – 2y = -7 -15 – (-8) = -7 -7 = - 7 2x - 5y = 10 -10 – (-20) = 10 10= 10
  • 15. Solve: By Substitution Recall that when we 'solve' a point-slope formula, we end up in slope-intercept form. In much the same way, the substitution method is closely related to the elimination method. After eliminating one variable and solving for the other, we substitute the value of the variable back into the equation. For example: Solve 2x + 3y = -26 using elimination 4x - 3y = 2 What is the value of x ? -4 At this point we substitute -4 for x, and solve for y. This is exactly what the substitution method is except it is done at the beginning.
  • 16. Solve: By Substitution Example 1: y = 2x 4x - y = -4 Since the first equation tells us that y = 2x, replace the y with 2x in the second equation. 4x - 2x = -4; 2x = -4; x = -2 Then, substitute -2 for x in the first equation: y = 2(-2); y = -4 Finally, plug both values in and check for equality. -4 = 2(-2); True; 4(-2) - (-4) = -4; -8 + 4 = -4; True